AP Biology Quiz: Cell Structure And Function
20 questions · exam conditions
0:00
Cell Structure And FunctionQuestion 1 of 20

A plant cell is placed in a concentrated salt solution. The plasma membrane pulls away from the cell wall, and the cytoplasm shrinks inward. The cell wall remains rigid and retains its shape. Which feature best explains why the wall does not shrink with the cytoplasm?

The cell wall is a rigid extracellular structure that resists changes in volume
The cell wall is a lipid bilayer that collapses when water exits the cell
The cell wall is composed of microtubules that depolymerize in salt solutions
The cell wall is a nuclear membrane that detaches during osmotic stress
The cell wall is made of phospholipids that dissolve in hypertonic solutions
← Back to quizzes

AP Biology Quiz

AP Biology Quiz: Cell Structure And Function

Practice Cell Structure And Function in AP Biology with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Cell Structure And Function, giving you a quick way to practice the rules, question types, and explanations that matter most for AP Biology.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A plant cell is placed in a concentrated salt solution. The plasma membrane pulls away from the cell wall, and the cytoplasm shrinks inward. The cell wall remains rigid and retains its shape. Which feature best explains why the wall does not shrink with the cytoplasm?

  1. The cell wall is a rigid extracellular structure that resists changes in volume (correct answer)
  2. The cell wall is a lipid bilayer that collapses when water exits the cell
  3. The cell wall is composed of microtubules that depolymerize in salt solutions
  4. The cell wall is a nuclear membrane that detaches during osmotic stress
  5. The cell wall is made of phospholipids that dissolve in hypertonic solutions

Explanation: This question assesses the skill of analyzing cell structure-function relationships. The rigid cell wall, composed of cellulose and other polysaccharides, resists deformation and maintains its shape even as the plasma membrane pulls away in the hypertonic salt solution. This extracellular structure prevents the wall from shrinking with the cytoplasm, as observed in the stimulus during plasmolysis. In AP Biology, the cell wall's rigidity counters osmotic pressures in plant cells. A tempting distractor is B, claiming the wall is a lipid bilayer, but this is incorrect due to structure-function confusion, as cell walls are carbohydrate-based, not lipid membranes. When assessing osmotic responses, distinguish between intracellular and extracellular components' behaviors.

Question 2

A cell is exposed to a toxin that disrupts actin filament polymerization. The cell can still synthesize proteins normally, but it shows reduced formation of membrane protrusions and slower engulfment of large particles. Which outcome is most likely due to the disrupted structure?

  1. Decreased phagocytosis because actin supports changes in cell shape and membrane movement (correct answer)
  2. Decreased ATP production because actin filaments form the inner mitochondrial membrane
  3. Decreased DNA replication because actin filaments unwind the double helix in the nucleus
  4. Decreased protein translation because actin filaments are the catalytic core of ribosomes
  5. Decreased water transport because actin filaments create aquaporin channels in membranes

Explanation: This question assesses the skill of analyzing cell structure-function relationships. Disrupting actin filament polymerization impairs phagocytosis, as actin supports membrane protrusions and shape changes needed to engulf particles, while protein synthesis continues unaffected since it occurs on ribosomes. This highlights actin's role in the cytoskeleton for AP Biology, enabling dynamic processes like cell motility and endocytosis through polymerization-driven force generation. Reduced protrusions and slower engulfment directly result from the inability to form actin networks at the membrane. A tempting distractor is choice B, which is incorrect due to structure-function confusion, as actin does not form mitochondrial membranes; those are lipid bilayers with embedded proteins. To approach similar questions, link specific cytoskeletal components to their primary functions and exclude unrelated cellular processes.

Question 3

In a lab, a cell type shows abundant rough ER membranes studded with ribosomes and a large Golgi apparatus. When these cells are treated with a drug that prevents vesicles from fusing with the Golgi, newly made proteins accumulate in small transport vesicles near the ER, and very little protein appears outside the cell. Which feature best explains why secretion decreases when Golgi fusion is blocked?

  1. Golgi cisternae modify and sort proteins from ER vesicles into secretory vesicles for exocytosis (correct answer)
  2. Ribosomes inside the nucleus translate secreted proteins and export them through nuclear pores
  3. Lysosomes synthesize secreted proteins and release them by fusing with the plasma membrane
  4. Mitochondria package proteins into vesicles that bud directly from the outer membrane
  5. Chloroplast thylakoids fold secreted proteins and deliver them to the cell surface

Explanation: This question assesses the skill of analyzing cell structure-function relationships. The abundant rough ER studded with ribosomes indicates active protein synthesis for secretion, and the large Golgi apparatus suggests its role in processing these proteins, as seen when the drug blocks vesicle fusion to the Golgi, causing proteins to accumulate in transport vesicles near the ER. This aligns with the endomembrane system's secretory pathway in AP Biology, where proteins synthesized in the rough ER are transported via vesicles to the Golgi for modification and sorting into secretory vesicles that fuse with the plasma membrane for exocytosis. Blocking fusion prevents this processing, reducing secretion as proteins cannot reach the cell exterior. A tempting distractor is choice B, which is incorrect due to structure-function confusion, as ribosomes are not located inside the nucleus for translating secreted proteins, and nuclear pores export mRNA, not proteins. To approach similar questions, map the sequence of organelles involved in a process and identify how disruptions affect the pathway.

Question 4

A student compares two eukaryotic cell types. Cell X has many mitochondria and an extensive network of folded inner mitochondrial membranes (cristae). Cell Y has fewer mitochondria with less folded inner membranes. Both cell types have similar plasma membrane surface area and similar numbers of ribosomes. When provided the same amount of glucose and oxygen, Cell X produces more ATP per unit time than Cell Y. Which outcome is most likely explained by the difference in mitochondrial structure?

  1. Cell X will have a higher rate of ATP synthesis because cristae increase inner membrane surface area for chemiosmosis (correct answer)
  2. Cell X will have a higher rate of transcription because mitochondria contain chromatin that unwinds on cristae
  3. Cell Y will have a higher rate of glycolysis because fewer cristae increase cytosolic enzyme availability
  4. Cell Y will have a higher rate of protein secretion because cristae are continuous with rough ER membranes
  5. Cell X will have a higher rate of phagocytosis because cristae provide vesicles for endocytosis

Explanation: This question assesses the skill of analyzing cell structure-function relationships. The correct answer, choice A, highlights that Cell X's extensive cristae increase the inner mitochondrial membrane's surface area, enhancing chemiosmosis and ATP synthesis during oxidative phosphorylation. The stimulus notes Cell X has more mitochondria with folded cristae compared to Cell Y, enabling greater electron transport chain activity and proton gradient formation for higher ATP production from the same glucose and oxygen. This directly ties to the AP Biology concept that mitochondrial structure optimizes aerobic respiration efficiency. A tempting distractor is choice C, which wrongly claims Cell Y has higher glycolysis due to fewer cristae freeing cytosolic enzymes, embodying a level-of-organization error by confusing mitochondrial membrane folding with cytosolic metabolic capacity. For such questions, compare organelle structural differences to their functional impacts on specific metabolic pathways like respiration.

Question 5

A plant cell's chloroplasts and mitochondria both contain internal membranes that compartmentalize reactions. In chloroplasts, a proton gradient forms across the thylakoid membrane; in mitochondria, a gradient forms across the inner membrane. Which feature best explains how these gradients can drive ATP synthesis in both organelles?

  1. ATP synthase embedded in the membrane uses proton flow down the gradient to phosphorylate ADP (correct answer)
  2. Ribosomes in the membranes use proton gradients to assemble ATP from amino acids
  3. Proton gradients directly convert glucose into ATP within the membrane bilayer
  4. Proton gradients open nuclear pores to allow ATP to diffuse into the nucleus for storage
  5. Proton gradients increase ATP by thickening the cell wall and trapping phosphate ions

Explanation: This question assesses the skill of analyzing cell structure-function relationships. The internal membranes in chloroplasts and mitochondria create proton gradients across thylakoid and inner membranes, respectively, which drive ATP synthase to phosphorylate ADP into ATP via chemiosmosis. This shared mechanism explains ATP synthesis in both organelles, as compartmentalization isolates the gradients. In AP Biology, chemiosmosis is a universal process in energy-transducing membranes. A tempting distractor is B, suggesting ribosomes use gradients, but this is incorrect due to structure-function confusion, as ribosomes synthesize proteins, not ATP. For energy production questions, identify gradient formation and its coupling to ATP synthesis.

Question 6

A researcher compares two membrane preparations. Membrane A contains a higher proportion of unsaturated phospholipid fatty acid tails than Membrane B, while both have similar cholesterol content. At the same temperature, Membrane A shows greater lateral movement of lipids and embedded proteins. Which feature best explains the increased membrane fluidity in Membrane A?

  1. Unsaturated fatty acid tails have kinks that reduce packing, increasing lateral movement within the bilayer (correct answer)
  2. Unsaturated tails form extra hydrogen bonds that lock phospholipids together more tightly
  3. Higher unsaturation increases covalent cross-linking between phospholipids, decreasing viscosity
  4. Unsaturated tails convert the membrane into a single layer, allowing proteins to float freely
  5. Unsaturated tails increase the number of ribosomes attached to the membrane, raising fluidity

Explanation: This question assesses the skill of analyzing cell structure and function by relating lipid composition to membrane properties. Unsaturated fatty acid tails introduce kinks from double bonds, preventing tight packing of phospholipids and thus increasing bilayer fluidity, which allows greater lateral movement of lipids and proteins in Membrane A. This higher unsaturation disrupts van der Waals interactions compared to saturated tails in Membrane B, explaining the difference at the same temperature without cholesterol variations. The fluid mosaic model supports how tail structure influences membrane viscosity and dynamics. A tempting distractor is choice B, which claims unsaturated tails form extra hydrogen bonds for tighter locking, embodying a misconception of chemical bonding by reversing the effect of unsaturation on packing. When comparing membranes, analyze fatty acid saturation and its impact on molecular interactions to predict fluidity differences.

Question 7

A student compares two cell types. Cell X contains numerous mitochondria with densely folded inner membranes, while Cell Y contains fewer mitochondria with relatively smooth inner membranes. Both cells have similar sizes and similar numbers of ribosomes. Measurements show Cell X consumes oxygen at a higher rate than Cell Y under the same conditions. Which feature best explains Cell X's higher oxygen consumption at the cellular level?

  1. More folding of the mitochondrial inner membrane increases surface area for electron transport proteins (correct answer)
  2. A thicker plasma membrane in Cell X allows more oxygen to diffuse into the cytoplasm per second
  3. Additional lysosomes in Cell X break down oxygen molecules to release energy for the cell
  4. More nucleoli in Cell X synthesize oxygen-binding proteins that directly generate ATP
  5. A larger central vacuole in Cell X stores oxygen and releases it during high energy demand

Explanation: This question assesses the skill of analyzing cell structure and function by relating mitochondrial morphology to metabolic rates. The densely folded inner membranes in Cell X's mitochondria provide increased surface area for embedding electron transport chain proteins, enhancing oxidative phosphorylation and thus higher oxygen consumption as the final electron acceptor. This cristae folding compartmentalizes the proton gradient, optimizing ATP synthesis efficiency, which explains Cell X's greater oxygen use despite similar cell sizes and ribosome numbers. Similar ribosome counts suggest comparable protein synthesis rates, isolating the difference to mitochondrial structure rather than overall cellular activity. A tempting distractor is choice B, which suggests a thicker plasma membrane allows more oxygen diffusion, representing a level-of-organization error by confusing organelle-level respiration with whole-cell membrane properties unrelated to thickness. When comparing cells, focus on the organelle directly involved in the process and quantify how structural adaptations amplify function.

Question 8

Two epithelial cell samples are compared. Sample 1 has many membrane proteins with attached carbohydrate chains projecting into the extracellular space, forming a dense surface coat. Sample 2 has far fewer of these carbohydrate-bearing proteins, but similar phospholipid composition. When mixed, cells from Sample 1 clump together more strongly than cells from Sample 2. Which feature best explains the increased cell-to-cell adhesion in Sample 1?

  1. Carbohydrate chains on glycoproteins enable specific extracellular interactions that increase adhesion between cells (correct answer)
  2. Extra cholesterol forms covalent bonds between adjacent cells, permanently fusing their membranes
  3. More smooth ER in Sample 1 secretes adhesive lipids directly into neighboring cell membranes
  4. Higher cytosolic ribosome density increases membrane thickness, causing cells to stick together
  5. Additional nuclear pores in Sample 1 export adhesion molecules straight into the extracellular matrix

Explanation: This question assesses the skill of analyzing cell structure and function by linking surface modifications to intercellular interactions. The carbohydrate chains on glycoproteins in Sample 1 form a glycocalyx that facilitates specific recognition and binding between cells, enhancing adhesion through extracellular matrix interactions or direct cell-cell contacts like in tissues. This dense surface coat increases clumping compared to Sample 2, despite similar phospholipid compositions, highlighting the functional role of glycosylation in cell signaling and adhesion. The membrane proteins' projections into the extracellular space enable these interactions without altering lipid bilayers. A tempting distractor is choice E, which suggests nuclear pores export adhesion molecules directly, embodying a level-of-organization error by bypassing the endomembrane system's processing pathway. In adhesion-related questions, evaluate extracellular components and their modifications to explain binding behaviors.

Question 9

A secretory gland cell is observed to have abundant rough endoplasmic reticulum (RER) with ribosomes attached, a prominent Golgi apparatus, and many small vesicles near the plasma membrane. Shortly after stimulation, the cell releases a burst of protein into the extracellular fluid without losing cytoplasm. Which outcome is most likely enabled by the arrangement of these cellular structures?​​

  1. Proteins are synthesized on RER ribosomes and exported by vesicles that fuse with the membrane. (correct answer)
  2. Proteins are degraded in lysosomes and diffuse through the membrane to the outside.
  3. Proteins are produced in mitochondria and exit through channels in the nuclear envelope.
  4. Proteins are assembled in the smooth ER and released by rupture of the plasma membrane.
  5. Proteins are copied from DNA in the Golgi and transported out through microtubules.

Explanation: This question tests analysis of cell structure-function relationships in protein secretion pathways. The abundant rough endoplasmic reticulum with ribosomes, prominent Golgi apparatus, and vesicles near the plasma membrane form the classic secretory pathway where proteins are synthesized on RER ribosomes, modified in the Golgi, packaged into vesicles, and released by exocytosis when vesicles fuse with the plasma membrane. This mechanism allows protein release without cytoplasm loss, as observed in the stimulus. Option C incorrectly places protein production in mitochondria and suggests exit through nuclear pores, demonstrating a level-of-organization error since mitochondria produce ATP, not secreted proteins, and nuclear pores regulate nucleus-cytoplasm transport, not cell-exterior transport. To solve secretory pathway questions, trace the flow from RER synthesis through Golgi processing to vesicle-mediated exocytosis.

Question 10

A secretory cell produces a large amount of digestive enzyme that is exported from the cell. Electron micrographs show abundant rough endoplasmic reticulum (RER) with ribosomes attached and an extensive Golgi apparatus with many budding vesicles. When cells are treated with a chemical that disrupts Golgi function, enzyme accumulates in intracellular vesicles and little is detected outside the cell. Which feature best explains the role of the Golgi apparatus in enzyme export?

  1. The Golgi modifies and sorts proteins into vesicles that fuse with the plasma membrane for secretion (correct answer)
  2. The Golgi is the site of transcription, producing mRNA needed to build digestive enzymes
  3. The Golgi generates ATP that powers ribosomes on the RER to synthesize secreted proteins
  4. The Golgi degrades misfolded proteins using hydrolytic enzymes at neutral pH in its lumen
  5. The Golgi forms the cell wall, which creates pores through which enzymes exit the cell

Explanation: This question assesses the analysis of cell structure and function, specifically the Golgi apparatus's role in protein processing and secretion. The correct answer is A because the stimulus depicts abundant RER and Golgi with budding vesicles, and Golgi disruption causes intracellular enzyme accumulation, aligning with AP Biology principles where the Golgi modifies, sorts, and packages proteins into secretory vesicles for exocytosis. This explains the export pathway for digestive enzymes. The chemical's effect confirms the Golgi's essential post-RER processing step. A tempting distractor is B, which reflects a level-of-organization error by confusing the Golgi with the nucleus's transcriptional role instead of its modification function. For such questions, trace the secretory pathway and identify bottlenecks when organelles are disrupted.

Question 11

A freshwater protist is placed in a low-solute environment. The cell repeatedly fills a contractile vacuole, which then expels water to the outside. Which feature best explains the need for this organelle in freshwater?

  1. Water enters the cell by osmosis, and the contractile vacuole removes excess water to prevent swelling (correct answer)
  2. Water leaves the cell by osmosis, and the contractile vacuole imports water to prevent dehydration
  3. The contractile vacuole produces water during respiration and expels it to maintain ATP levels
  4. The contractile vacuole digests macromolecules and exports wastes through exocytosis
  5. The contractile vacuole stores DNA and releases it to regulate the cell cycle in dilute water

Explanation: This question assesses the skill of analyzing cell structure-function relationships. In hypotonic freshwater, water enters the protist by osmosis due to higher internal solute concentration, and the contractile vacuole expels excess water to prevent bursting, maintaining osmotic balance. This demonstrates osmoregulation in AP Biology, where the vacuole acts as a pump to counteract passive water influx in dilute environments. Repeated filling and expulsion are necessary for survival in low-solute conditions. A tempting distractor is choice B, which is incorrect due to teleology, as water enters, not leaves, in hypotonic conditions, and the vacuole expels, not imports, water. To approach similar questions, assess environmental tonicity relative to the cell and predict organelle functions for volume regulation.

Question 12

A neuron's axon membrane contains many voltage-gated ion channels concentrated at specific regions. When these channels are blocked, electrical signals travel a much shorter distance. Which feature best explains how channel placement affects signal propagation?

  1. Ion channels provide pathways for ions to cross the lipid bilayer, enabling changes in membrane potential (correct answer)
  2. Ion channels convert glucose into ATP, supplying energy for electrical signals along the axon
  3. Ion channels are phospholipids that increase membrane thickness and prevent signal loss
  4. Ion channels are ribosomes that translate proteins needed for action potential movement
  5. Ion channels are part of the cell wall that insulates the axon from the environment

Explanation: This question assesses the skill of analyzing cell structure-function relationships. Voltage-gated ion channels in the axon membrane allow ions to cross the hydrophobic bilayer, generating changes in membrane potential that propagate action potentials along the neuron. This embodies the role of membrane proteins in AP Biology for facilitated diffusion and electrical signaling, with channel placement enabling rapid ion fluxes for signal transmission. Blocking channels shortens signal distance by preventing the regenerative ion flows needed for propagation. A tempting distractor is choice E, which is incorrect due to structure-function confusion, as neurons lack cell walls, and ion channels are embedded in the plasma membrane, not part of a wall. To approach similar questions, focus on how protein structures enable specific transport and relate to broader physiological functions like signaling.

Question 13

In an experiment, a cell is placed in a solution containing a fluorescent ligand that binds a specific receptor. Fluorescence appears in small internal vesicles minutes later. Which outcome is most likely explained by receptor location in the plasma membrane?

  1. Receptor-mediated endocytosis internalizes ligand–receptor complexes into vesicles formed from the plasma membrane (correct answer)
  2. Ligand binding causes the receptor to convert fluorescence into ATP inside mitochondria
  3. Ligand binding causes receptors to move into the nucleus through nuclear pores as intact membrane patches
  4. Ligand binding triggers the cell wall to engulf the ligand and form vesicles in the extracellular matrix
  5. Ligand binding forces the ligand to diffuse through phospholipids because receptors dissolve the bilayer

Explanation: This question assesses the skill of analyzing cell structure-function relationships. Receptor-mediated endocytosis brings fluorescent ligand-receptor complexes into internal vesicles from the plasma membrane, explaining the appearance of fluorescence inside the cell. This process in AP Biology involves clathrin-coated pits forming vesicles for specific uptake, internalizing bound ligands. The plasma membrane location initiates this targeted transport. A tempting distractor is choice C, which is incorrect due to structure-function confusion, as receptors do not move as membrane patches into the nucleus; nuclear pores allow soluble molecules, not membranes. To approach similar questions, trace ligand pathways from binding to internalization and identify endocytic mechanisms.

Question 14

In a plant root cell, the central vacuole occupies most of the cell volume and is bounded by a selectively permeable membrane. When the cell is placed in a dilute solution, water moves into the vacuole and the plasma membrane is pressed against the cell wall. Which outcome is most likely explained by the vacuole's large size and membrane properties?

  1. Increased turgor pressure that helps the cell maintain rigidity against the cell wall (correct answer)
  2. Higher ATP production because the vacuole contains enzymes for cellular respiration
  3. Faster protein synthesis because the vacuole is continuous with ribosomes
  4. More rapid DNA replication because the vacuole stores nucleotides for the nucleus
  5. Reduced water entry because the vacuole membrane prevents osmosis entirely

Explanation: This question assesses the skill of analyzing cell structure-function relationships. The large central vacuole in the plant root cell, bounded by a selectively permeable membrane, allows water to enter via osmosis when placed in a dilute solution, as described in the stimulus. This influx increases the vacuole's volume, pressing the plasma membrane against the rigid cell wall and generating turgor pressure. In AP Biology, turgor pressure is essential for maintaining plant cell rigidity and overall plant structure in hypotonic environments. A tempting distractor is B, which claims the vacuole produces ATP, but this is incorrect due to structure-function confusion, as vacuoles store water and ions rather than housing respiratory enzymes like mitochondria. To approach similar questions, identify the organelle's primary role and link it to the physiological outcome in the given context.

Question 15

A plant leaf cell contains chloroplasts with stacked thylakoid membranes (grana). When thylakoid membranes are experimentally disrupted, the cell's ability to convert light energy into chemical energy drops sharply. Which feature best explains this decrease?

  1. Thylakoid membranes provide extensive surface area for light-absorbing pigments and electron transport components (correct answer)
  2. Thylakoid membranes store DNA needed to replicate chloroplasts during cell division
  3. Thylakoid membranes are the site of protein digestion that releases energy for photosynthesis
  4. Thylakoid membranes form channels that import glucose into chloroplasts for light reactions
  5. Thylakoid membranes are rigid walls that prevent water loss from chloroplasts in bright light

Explanation: This question assesses the skill of analyzing cell structure-function relationships. Stacked thylakoid membranes in grana provide extensive surface area for embedding pigments and electron transport chains, essential for light-dependent reactions, so disruption sharply reduces energy conversion. This illustrates chloroplast structure in AP Biology, where thylakoids facilitate photon capture and electron flow to generate ATP and NADPH. The stacking increases efficiency by concentrating components for photosynthesis. A tempting distractor is choice E, which is incorrect due to structure-function confusion, as thylakoids are internal membranes, not rigid walls, and chloroplasts have envelopes but rely on other mechanisms for water management. To approach similar questions, evaluate how organelle substructures enhance surface area or compartmentalization for metabolic efficiency.

Question 16

A student compares red blood cells to typical animal cells with nuclei. Red blood cells lack nuclei and most organelles, yet can carry oxygen efficiently. Which feature best explains how their structure supports this function?

  1. Reduced internal organelles increases space for hemoglobin, allowing more oxygen to be carried per cell (correct answer)
  2. Lack of a nucleus increases photosynthesis, providing oxygen directly to the bloodstream
  3. Loss of organelles increases endocytosis of oxygen through vesicle formation at the plasma membrane
  4. Absence of mitochondria allows oxygen to diffuse into the nucleus where it is stored as DNA
  5. Absence of a nucleus makes the plasma membrane impermeable to gases, trapping oxygen inside

Explanation: This question assesses the skill of analyzing cell structure-function relationships. Red blood cells' lack of nuclei and organelles maximizes space for hemoglobin, enhancing oxygen-carrying capacity per cell compared to nucleated cells. This adaptation in AP Biology supports efficient gas transport in circulation, with the biconcave shape aiding diffusion. Reduced internal structures minimize oxygen consumption by the cell itself. A tempting distractor is choice E, which is incorrect due to structure-function confusion, as the plasma membrane remains permeable to gases without a nucleus, facilitating oxygen exchange, not trapping it. To approach similar questions, relate organelle absence to specialized functions and efficiency in resource allocation.

Question 17

A cell's plasma membrane contains many cholesterol molecules interspersed among phospholipids. When temperature decreases, the membrane remains less rigid than a similar membrane lacking cholesterol. Which feature best explains cholesterol's effect under these conditions?

  1. Cholesterol disrupts tight phospholipid packing at low temperatures, reducing rigidity (correct answer)
  2. Cholesterol forms channels that actively pump heat into the cell to maintain fluidity
  3. Cholesterol replaces phospholipids with cellulose fibers that prevent membrane stiffening
  4. Cholesterol covalently bonds phospholipid tails together, increasing membrane flexibility
  5. Cholesterol attaches ribosomes to the membrane, increasing lipid movement

Explanation: This question assesses the skill of analyzing cell structure-function relationships. Cholesterol molecules interspersed among phospholipids disrupt tight packing at low temperatures, preventing the membrane from becoming overly rigid and maintaining fluidity. This buffering effect is observed compared to the cholesterol-lacking membrane in the stimulus. In AP Biology, cholesterol modulates membrane fluidity across temperature ranges. A tempting distractor is D, suggesting covalent bonding, but this is incorrect due to a misconception of molecular interactions, as cholesterol interacts non-covalently. For temperature effects on membranes, consider how sterols influence lipid packing and phase transitions.

Question 18

A cell is observed under a microscope after being placed in a solution with a toxin that inhibits Na+/K+ pumps in the plasma membrane. Over time, the cell swells. Which feature best explains why swelling occurs when the pump is inhibited?

  1. Reduced ion pumping alters solute balance, increasing osmotic water entry into the cell (correct answer)
  2. Reduced ion pumping decreases membrane surface area, so the cell must expand to compensate
  3. Reduced ion pumping causes the cell wall to soften, allowing uncontrolled water diffusion into the cytosol
  4. Reduced ion pumping stops ribosomes, leading to accumulation of proteins that physically push water inward
  5. Reduced ion pumping increases exocytosis, which adds water directly into the cytoplasm from vesicles

Explanation: This question assesses the skill of analyzing cell structure-function relationships. Inhibiting Na+/K+ pumps reduces ion export, altering intracellular solute balance and causing osmotic water influx, leading to cell swelling. This demonstrates active transport's role in AP Biology for maintaining ion gradients and osmotic equilibrium via ATP-driven pumps. The toxin disrupts this homeostasis, increasing internal osmolarity. A tempting distractor is choice C, which is incorrect due to structure-function confusion, as animal cells lack cell walls, and pumps affect solutes, not wall softness. To approach similar questions, analyze how transport proteins influence gradients and predict osmotic consequences of their inhibition.

Question 19

An intestinal epithelial cell has many microvilli, each supported by bundles of actin filaments just beneath the plasma membrane. Compared with a nearby cell lacking microvilli, this cell shows a higher rate of nutrient uptake from the lumen. Which feature best explains the increased uptake?

  1. Microvilli increase membrane surface area, providing more sites for transport proteins (correct answer)
  2. Microvilli contain mitochondria that pump nutrients into the cytosol
  3. Actin filaments in microvilli synthesize nutrients from simple precursors
  4. Microvilli replace the cell wall, allowing nutrients to diffuse through cellulose
  5. Actin bundles in microvilli replicate DNA to speed cell division and uptake

Explanation: This question assesses the skill of analyzing cell structure-function relationships. The microvilli on the intestinal epithelial cell, supported by actin filaments, increase the plasma membrane's surface area, accommodating more transport proteins for nutrient absorption from the lumen. This structural adaptation enhances the rate of uptake compared to cells without microvilli, as observed in the stimulus. In AP Biology, microvilli exemplify how membrane elaborations optimize absorption in epithelial cells. A tempting distractor is B, suggesting microvilli contain mitochondria for pumping, but this is incorrect due to structure-function confusion, as microvilli lack organelles and rely on surface area for passive and active transport. To solve these, link surface modifications to their effects on membrane-bound processes like transport.

Question 20

Two animal cells are compared: Cell 1 has a plasma membrane with a higher proportion of unsaturated phospholipid tails than Cell 2. At the same temperature, Cell 1's membrane is observed to be more fluid. Which feature best explains the increased fluidity in Cell 1?

  1. Unsaturated tails contain double bonds that create kinks, reducing tight packing (correct answer)
  2. Unsaturated tails are longer, increasing van der Waals forces and tight packing
  3. Unsaturated tails form covalent bonds between phospholipids, stiffening the bilayer
  4. Unsaturated tails increase membrane fluidity by converting phospholipids into proteins
  5. Unsaturated tails prevent any lateral movement of lipids within the bilayer

Explanation: This question assesses the skill of analyzing cell structure-function relationships. The higher proportion of unsaturated phospholipid tails in Cell 1 introduces kinks from double bonds, preventing tight packing and maintaining membrane fluidity at the given temperature. This structural feature contrasts with Cell 2's more saturated tails, which pack closely and reduce fluidity, as observed in the stimulus. In AP Biology, fatty acid saturation influences membrane fluidity via packing density. A tempting distractor is B, claiming unsaturated tails increase packing, but this is incorrect due to a misconception of molecular geometry, as double bonds actually disrupt packing. To analyze membrane properties, consider how lipid composition affects intermolecular forces and phase behavior.