AP Chemistry Flashcards: Free Energy Of Dissolution

Study Free Energy Of Dissolution in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Chemistry

Free Energy Of Dissolution

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QUESTION
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Calculate G\triangle G given H=10 kJ/mol\triangle H = 10 \text{ kJ/mol}, T=298 KT = 298 \text{ K}, S=50 J/mol\cdotpK\triangle S = 50 \text{ J/mol·K}.

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ANSWER

G=4.9 kJ/mol\triangle G = -4.9 \text{ kJ/mol}. G=10000298(50)=1000014900=4900\triangle G = 10000 - 298(50) = 10000 - 14900 = -4900 J/mol.

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Flashcard 1: Calculate G\triangle G given H=10 kJ/mol\triangle H = 10 \text{ kJ/mol}, T=298 KT = 298 \text{ K}, S=50 J/mol\cdotpK\triangle S = 50 \text{ J/mol·K}.

Answer: G=4.9 kJ/mol\triangle G = -4.9 \text{ kJ/mol}. G=10000298(50)=1000014900=4900\triangle G = 10000 - 298(50) = 10000 - 14900 = -4900 J/mol.

Flashcard 2: Which quantity becomes zero at the dissolution equilibrium point?

Answer: G\triangle G. Free energy equals zero when forward and reverse rates are equal.

Flashcard 3: What is the sign of G\triangle G when H<0\triangle H < 0 and S>0\triangle S > 0?

Answer: G<0\triangle G < 0. Both terms favor spontaneity, making G\triangle G always negative.

Flashcard 4: What is the primary driver of dissolution for ionic solids in water?

Answer: Entropy increase. Breaking crystal lattice increases disorder despite ion-water interactions.

Flashcard 5: Calculate G\triangle G with H=20 kJ/mol\triangle H = 20 \text{ kJ/mol}, T=350 KT = 350 \text{ K}, S=70 J/mol\cdotpK\triangle S = 70 \text{ J/mol·K}.

Answer: G=4.5 kJ/mol\triangle G = -4.5 \text{ kJ/mol}. G=20000350(70)=2000024500=4500\triangle G = 20000 - 350(70) = 20000 - 24500 = -4500 J/mol.

Flashcard 6: Which parameter is zero for a process at equilibrium?

Answer: G\triangle G. At equilibrium, the free energy change equals zero.

Flashcard 7: Determine the spontaneity: H=5 kJ/mol\triangle H = 5 \text{ kJ/mol}, T=298 KT = 298 \text{ K}, S=30 J/mol\cdotpK\triangle S = 30 \text{ J/mol·K}.

Answer: Spontaneous. G=5000298(30)=50008940=3940\triangle G = 5000 - 298(30) = 5000 - 8940 = -3940 J/mol, so spontaneous.

Flashcard 8: What is the sign of H\triangle H if dissolution absorbs heat?

Answer: H>0\triangle H > 0. Positive enthalpy indicates an endothermic heat-absorbing process.

Flashcard 9: What does a positive S\triangle S indicate about entropy in dissolution?

Answer: Entropy increases. Positive S\triangle S means the system becomes more disordered.

Flashcard 10: What is indicated by a positive G\triangle G in dissolution?

Answer: Non-spontaneous process. Positive free energy means the process is thermodynamically unfavorable.

Flashcard 11: What determines the spontaneity of a dissolution process?

Answer: Sign of G\triangle G. Negative G\triangle G means spontaneous, positive means non-spontaneous.

Flashcard 12: Determine the spontaneity: ΔH=5 kJ/mol\Delta H = 5 \text{ kJ/mol}, T=298 KT = 298 \text{ K}, ΔS=30 J/mol\cdotpK\Delta S = 30 \text{ J/mol·K}.

Answer: Spontaneous. ΔG=5000298(30)=50008940=3940\Delta G = 5000 - 298(30) = 5000 - 8940 = -3940 J/mol, so spontaneous.

Flashcard 13: What is the sign of G\triangle G when H<0\triangle H < 0 and S>0\triangle S > 0?

Answer: G<0\triangle G < 0. Both terms favor spontaneity, making G\triangle G always negative.

Flashcard 14: Calculate G\triangle G when H=15 kJ/mol\triangle H = 15 \text{ kJ/mol}, T=300 KT = 300 \text{ K}, S=60 J/mol\cdotpK\triangle S = 60 \text{ J/mol·K}.

Answer: G=3 kJ/mol\triangle G = -3 \text{ kJ/mol}. G=15000300(60)=1500018000=3000\triangle G = 15000 - 300(60) = 15000 - 18000 = -3000 J/mol.

Flashcard 15: What does a positive S\triangle S indicate about entropy in dissolution?

Answer: Entropy increases. Positive S\triangle S means the system becomes more disordered.

Flashcard 16: Determine the spontaneity: H=5 kJ/mol\triangle H = 5 \text{ kJ/mol}, T=298 KT = 298 \text{ K}, S=30 J/mol\cdotpK\triangle S = 30 \text{ J/mol·K}.

Answer: Spontaneous. G=5000298(30)=50008940=3940\triangle G = 5000 - 298(30) = 5000 - 8940 = -3940 J/mol, so spontaneous.

Flashcard 17: State the condition for a dissolution to be spontaneous at all temperatures.

Answer: H<0\triangle H < 0, S>0\triangle S > 0. Exothermic enthalpy and positive entropy ensure spontaneity.

Flashcard 18: What is the sign of G\triangle G when dissolution is at equilibrium?

Answer: G=0\triangle G = 0. Zero free energy indicates the system has reached equilibrium.

Flashcard 19: Find the entropy change: G=10 kJ/mol\triangle G = 10 \text{ kJ/mol}, H=15 kJ/mol\triangle H = 15 \text{ kJ/mol}, T=298 KT = 298 \text{ K}.

Answer: S=16.78 J/mol\cdotpK\triangle S = 16.78 \text{ J/mol·K}. S=(HG)/T=(1500010000)/298=16.78\triangle S = (\triangle H - \triangle G)/T = (15000 - 10000)/298 = 16.78 J/mol·K.

Flashcard 20: What does a positive S\triangle S indicate about entropy in dissolution?

Answer: Entropy increases. Positive S\triangle S means the system becomes more disordered.

Flashcard 21: What is the relationship between H\triangle H and S\triangle S in spontaneous dissolution?

Answer: H<TS\triangle H < T\triangle S. For spontaneity, the entropy term must overcome unfavorable enthalpy.

Flashcard 22: What is the unit of Gibbs free energy change?

Answer: Joules (J) or kilojoules (kJ). Energy units for thermodynamic quantities in the SI system.

Flashcard 23: State the effect on G\triangle G if both H\triangle H and S\triangle S are positive.

Answer: Depends on TT. Sign depends on whether TST\triangle S is greater or less than H\triangle H.

Flashcard 24: Which factor affects the sign of G\triangle G at constant pressure and temperature?

Answer: Enthalpy and entropy. Both enthalpy and entropy contributions determine free energy sign.

Flashcard 25: What effect does increased pressure have on gas solubility in liquids?

Answer: Increases solubility. Henry's law: gas solubility is directly proportional to pressure.

Flashcard 26: Identify the factor that primarily affects S\triangle S in dissolution.

Answer: Molecular disorder. Dissolution typically increases randomness as molecules spread out.

Flashcard 27: What does a negative S\triangle S for dissolution indicate?

Answer: Entropy decreases. Negative entropy change indicates decreased molecular disorder.

Flashcard 28: What is the formula for Gibbs free energy change?

Answer: G=HTS\triangle G = \triangle H - T\triangle S. Fundamental thermodynamic equation relating free energy to enthalpy and entropy.

Flashcard 29: Identify the formula for entropy change.

Answer: S=HGT\triangle S = \frac{\triangle H - \triangle G}{T}. Rearranged form of the Gibbs free energy equation.

Flashcard 30: What does a positive S\triangle S indicate about entropy in dissolution?

Answer: Entropy increases. Positive S\triangle S means the system becomes more disordered.

Flashcard 31: Identify the term for the heat change during dissolution.

Answer: Enthalpy change (H\triangle H). Enthalpy measures the heat absorbed or released during the process.

Flashcard 32: Identify the factor that primarily affects S\triangle S in dissolution.

Answer: Molecular disorder. Dissolution typically increases randomness as molecules spread out.

Flashcard 33: Which parameter is affected by both enthalpy and entropy in dissolution?

Answer: Gibbs free energy (G\triangle G). Free energy depends on both H\triangle H and TST\triangle S terms.

Flashcard 34: Calculate H\triangle H given G=3 kJ/mol\triangle G = -3 \text{ kJ/mol}, T=310 KT = 310 \text{ K}, S=80 J/mol\cdotpK\triangle S = 80 \text{ J/mol·K}.

Answer: H=21.8 kJ/mol\triangle H = 21.8 \text{ kJ/mol}. H=G+TS=3000+310(80)=21800\triangle H = \triangle G + T\triangle S = -3000 + 310(80) = 21800 J/mol.

Flashcard 35: What type of process occurs when G>0\triangle G > 0?

Answer: Non-spontaneous process. Positive free energy indicates thermodynamically unfavorable conditions.

Flashcard 36: What is the significance of G=0\triangle G = 0 in dissolution?

Answer: Equilibrium state. Zero free energy indicates the system is at thermodynamic equilibrium.

Flashcard 37: Calculate the enthalpy change: ΔG=5 kJ/mol\Delta G = -5 \text{ kJ/mol}, T=298 KT = 298 \text{ K}, ΔS=20 J/mol\cdotpK\Delta S = 20 \text{ J/mol·K}.

Answer: ΔH=1.96 kJ/mol\Delta H = 1.96 \text{ kJ/mol}. ΔH=ΔG+TΔS=5000+298(20)=1960\Delta H = \Delta G + T \Delta S = -5000 + 298(20) = 1960 J/mol.

Flashcard 38: Determine the spontaneity: H=5 kJ/mol\triangle H = 5 \text{ kJ/mol}, T=298 KT = 298 \text{ K}, S=30 J/mol\cdotpK\triangle S = 30 \text{ J/mol·K}.

Answer: Spontaneous. G=5000298(30)=50008940=3940\triangle G = 5000 - 298(30) = 5000 - 8940 = -3940 J/mol, so spontaneous.

Flashcard 39: What is the effect of increasing temperature on an exothermic dissolution?

Answer: Decreases solubility. Le Chatelier's principle: heat addition shifts equilibrium away from products.

Flashcard 40: Which variable increases the dissolution rate in endothermic reactions?

Answer: Temperature. Higher kinetic energy from temperature increases dissolution rate.

Flashcard 41: How does the dissolution of a gas in a liquid typically affect ΔS\Delta S?

Answer: ΔS\Delta S decreases. Gas molecules become more ordered when dissolved in liquid.

Flashcard 42: What is the formula for Gibbs free energy change?

Answer: G=HTS\triangle G = \triangle H - T\triangle S. Fundamental thermodynamic equation relating free energy to enthalpy and entropy.

Flashcard 43: In dissolution, what does a negative H\triangle H imply?

Answer: Exothermic process. Negative enthalpy means heat is released to the surroundings.

Flashcard 44: State the sign of G\triangle G for a spontaneous dissolution.

Answer: G<0\triangle G < 0. Negative free energy indicates a thermodynamically favorable process.

Flashcard 45: Identify the type of dissolution with S>0\triangle S > 0 and H<0\triangle H < 0.

Answer: Spontaneous dissolution. Both favorable enthalpy and entropy make G\triangle G negative at all temperatures.

Flashcard 46: Identify the term for the heat change during dissolution.

Answer: Enthalpy change (H\triangle H). Enthalpy measures the heat absorbed or released during the process.