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This deck focuses on Introduction To Acid Base Reactions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Introduction To Acid Base Reactions in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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State the formula for calculating pOH.
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pOH=−log[OH−]. Negative logarithm converts hydroxide concentration to pOH scale.
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This deck focuses on Introduction To Acid Base Reactions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: pOH=−log[OH−]. Negative logarithm converts hydroxide concentration to pOH scale.
Answer: The OH− ion is responsible for the basicity of a solution. Higher [OH−] means higher pH and greater basicity.
Answer: The conjugate base of H2SO4 is HSO4−. Sulfuric acid loses one proton to form bisulfate ion.
Answer: A large Kb value indicates a strong base. Large Kb means extensive ionization and stronger basicity.
Answer: Kb=[NH3][NH4+][OH−]. Equilibrium expression for weak base ionization.
Answer: Ka=3.16×10−4. Use formula: Ka=10−pKa=10−3.5.
Answer: pH=1. Strong acid: pH=−log(0.1)=1.
Answer: pOH=11. Use relationship: pH+pOH=14.
Answer: The conjugate base forms when an acid donates a proton. Result of proton donation in acid-base reactions.
Answer: A strong acid completely ionizes in solution. Nearly 100% ionization in aqueous solution.
Answer: A salt and water are the products of a neutralization reaction. General form: acid + base → salt + water.
Answer: Kw=[H+][OH−]=1.0×10−14 at 25°C. This equilibrium constant applies to pure water at 25°C.
Answer: The conjugate base forms when an acid donates a proton. Result of proton donation in acid-base reactions.
Answer: pH=2. Strong acid: pH=−log(0.01)=2.
Answer: Ka=[CH3COOH][CH3COO−][H+]. Equilibrium expression for weak acid ionization.
Answer: A strong base completely dissociates in solution. Nearly 100% dissociation in aqueous solution.
Answer: The conjugate acid of OH− is H2O. Hydroxide ion gains one proton to form water.
Answer: A large Ka value indicates a strong acid. Large Ka means extensive ionization and stronger acidity.
Answer: Ka×Kb=Kw. Fundamental relationship for conjugate acid-base pairs.
Answer: The conjugate base of H2SO4 is HSO4−. Sulfuric acid loses one proton to form bisulfate ion.
Answer: A strong base completely dissociates in solution. Nearly 100% dissociation in aqueous solution.
Answer: The term is Kw, the ion-product constant for water. Represents autoionization equilibrium of pure water.
Answer: An acid is a substance that increases the concentration of H+ ions in aqueous solution. Arrhenius theory focuses on H+ ion production in water.
Answer: pH=10. Use relationship: pH+pOH=14.
Answer: The term is Kw, the ion-product constant for water. Represents autoionization equilibrium of pure water.
Answer: Ka=[CH3COOH][CH3COO−][H+]. Equilibrium expression for weak acid ionization.
Answer: A Lewis base is an electron pair donor. Lewis theory focuses on electron pair interactions.
Answer: A Lewis base is an electron pair donor. Lewis theory focuses on electron pair interactions.
Answer: pOH=−log[OH−]. Negative logarithm converts hydroxide concentration to pOH scale.
Answer: The pH of a neutral solution at 25°C is 7. At neutral pH, [H+]=[OH−] at standard temperature.
Answer: pH=−log[H+]. Negative logarithm converts concentration to pH scale.
Answer: pOH=11. Use relationship: pH+pOH=14.
Answer: Ka=[CH3COOH][CH3COO−][H+]. Equilibrium expression for weak acid ionization.
Answer: A large Kb value indicates a strong base. Large Kb means extensive ionization and stronger basicity.
Answer: pH=8. Direct application: pH=−log(1×10−8)=8.
Answer: Ka=3.16×10−4. Use formula: Ka=10−pKa=10−3.5.
Answer: A base is a substance that increases the concentration of OH− ions in aqueous solution. Arrhenius theory focuses on OH− ion production in water.
Answer: A large Ka value indicates a strong acid. Large Ka means extensive ionization and stronger acidity.
Answer: pH+pOH=14. Derived from the water equilibrium constant at 25°C.
Answer: A Lewis acid is an electron pair acceptor. Lewis theory focuses on electron pair interactions.
Answer: A large Kb value indicates a strong base. Large Kb means extensive ionization and stronger basicity.
Answer: Ka=3.16×10−4. Use formula: Ka=10−pKa=10−3.5.
Answer: A salt and water are the products of a neutralization reaction. General form: acid + base → salt + water.
Answer: HCl is a stronger acid than acetic acid. HCl completely ionizes; acetic acid only partially ionizes.
Answer: A base is a substance that increases the concentration of OH− ions in aqueous solution. Arrhenius theory focuses on OH− ion production in water.
Answer: pH=8. Direct application: pH=−log(1×10−8)=8.
Answer: pH=−log[H+]. Negative logarithm converts concentration to pH scale.
Answer: A Bronsted-Lowry base is a proton (H+) acceptor. Bronsted-Lowry theory emphasizes proton transfer reactions.
Answer: pOH=6. Direct application: pOH=−log(1×10−6)=6.
Answer: pH=2. Strong acid: pH=−log(0.01)=2.
Answer: NaOH is a stronger base than ammonia. NaOH completely dissociates; ammonia only partially ionizes.
Answer: A large Ka value indicates a strong acid. Large Ka means extensive ionization and stronger acidity.
Answer: The conjugate base of HCl is Cl−.. Formed by removing one proton from the acid.
Answer: pH=−log[H+]. Negative logarithm converts concentration to pH scale.
Answer: A large Kb value indicates a strong base. Large Kb means extensive ionization and stronger basicity.
Answer: The term is Kw, the ion-product constant for water. Represents autoionization equilibrium of pure water.
Answer: The H+ ion is responsible for the acidity of a solution. Higher [H+] means lower pH and greater acidity.
Answer: NaOH is a stronger base than ammonia. NaOH completely dissociates; ammonia only partially ionizes.
Answer: pH=8. Direct application: pH=−log(1×10−8)=8.
Answer: pH=12. Strong base: pOH=2, so pH=14−2=12.
Answer: Kw=[H+][OH−]=1.0×10−14 at 25°C. This equilibrium constant applies to pure water at 25°C.
Answer: An acid is a substance that increases the concentration of H+ ions in aqueous solution. Arrhenius theory focuses on H+ ion production in water.
Answer: A Bronsted-Lowry acid is a proton (H+) donor. Bronsted-Lowry theory emphasizes proton transfer reactions.
Answer: Kw=[H+][OH−]=1.0×10−14 at 25°C. This equilibrium constant applies to pure water at 25°C.
Answer: A strong base completely dissociates in solution. Nearly 100% dissociation in aqueous solution.
Answer: pH+pOH=14. Derived from the water equilibrium constant at 25°C.
Answer: Kb=3.16×10−5. Use formula: Kb=10−pKb=10−4.5.
Answer: The H+ ion is responsible for the acidity of a solution. Higher [H+] means lower pH and greater acidity.
Answer: pH=13. Strong base: pOH=1, so pH=14−1=13.
Answer: An acid is a substance that increases the concentration of H+ ions in aqueous solution. Arrhenius theory focuses on H+ ion production in water.
Answer: pOH=6. Direct application: pOH=−log(1×10−6)=6.
Answer: The term is Kw, the ion-product constant for water. Represents autoionization equilibrium of pure water.
Answer: A strong acid completely ionizes in solution. Nearly 100% ionization in aqueous solution.
Answer: A strong acid completely ionizes in solution. Nearly 100% ionization in aqueous solution.
Answer: Kb=[NH3][NH4+][OH−]. Equilibrium expression for weak base ionization.
Answer: pH=−log[H+]. Negative logarithm converts concentration to pH scale.
Answer: Ka=[CH3COOH][CH3COO−][H+]. Equilibrium expression for weak acid ionization.
Answer: A strong acid completely ionizes in solution. Nearly 100% ionization in aqueous solution.
Answer: An acid is a substance that increases the concentration of H+ ions in aqueous solution. Arrhenius theory focuses on H+ ion production in water.
Answer: A Lewis acid is an electron pair acceptor. Lewis theory focuses on electron pair interactions.
Answer: pH=13. Strong base: pOH=1, so pH=14−1=13.
Answer: A Lewis base is an electron pair donor. Lewis theory focuses on electron pair interactions.
Answer: The conjugate base of HCl is Cl−.. Formed by removing one proton from the acid.
Answer: The conjugate base of HCl is Cl−.. Formed by removing one proton from the acid.
Answer: pH=1. Strong acid: pH=−log(0.1)=1.
Answer: The pH of a neutral solution at 25°C is 7. At neutral pH, [H+]=[OH−] at standard temperature.
Answer: NaOH is a stronger base than ammonia. NaOH completely dissociates; ammonia only partially ionizes.
Answer: pOH=6. Direct application: pOH=−log(1×10−6)=6.
Answer: A Lewis acid is an electron pair acceptor. Lewis theory focuses on electron pair interactions.
Answer: A strong base completely dissociates in solution. Nearly 100% dissociation in aqueous solution.
Answer: A base is a substance that increases the concentration of OH− ions in aqueous solution. Arrhenius theory focuses on OH− ion production in water.
Answer: pH+pOH=14. Derived from the water equilibrium constant at 25°C.
Answer: A large Ka value indicates a strong acid. Large Ka means extensive ionization and stronger acidity.
Answer: Kb=3.16×10−5. Use formula: Kb=10−pKb=10−4.5.
Answer: A Lewis base is an electron pair donor. Lewis theory focuses on electron pair interactions.
Answer: Kb=[NH3][NH4+][OH−]. Equilibrium expression for weak base ionization.
Answer: pOH=11. Use relationship: pH+pOH=14.
Answer: HCl is a stronger acid than acetic acid. HCl completely ionizes; acetic acid only partially ionizes.
Answer: A Lewis acid is an electron pair acceptor. Lewis theory focuses on electron pair interactions.
Answer: pH=12. Strong base: pOH=2, so pH=14−2=12.