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This deck focuses on Lewis Diagrams, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Lewis Diagrams in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Identify the Lewis Diagram for sulfur dioxide (SO2).
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O=S-O with one lone pair on S and two on each O. Bent structure due to lone pair repulsion on sulfur.
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This deck focuses on Lewis Diagrams, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: O=S-O with one lone pair on S and two on each O. Bent structure due to lone pair repulsion on sulfur.
Answer: F-S-F with four additional F atoms bonded to S. Octahedral structure utilizing sulfur's expanded octet.
Answer: H-C=C-H with additional H atoms bonded to each C. Planar molecule with carbon-carbon double bond.
Answer: Two lone pairs. Oxygen has 6 valence electrons, forms 2 bonds, leaves 4 as lone pairs.
Answer: H-P-H with one lone pair on P and an additional H. Trigonal pyramidal shape with phosphorus as central atom.
Answer: Three pairs of shared electrons. Triple bonds involve six electrons in three pairs.
Answer: As pairs of dots around the atom. Dots show unshared electrons around atomic symbols.
Answer: H-Cl with three lone pairs on Cl. Polar molecule with chlorine having three lone pairs.
Answer: To show the bonding between atoms and lone pairs of electrons. Visualizes electron distribution and chemical bonding patterns.
Answer: By using double-headed arrows between structures. Shows electron delocalization across multiple structures.
Answer: Dots around the atom. Two dots represent an unshared electron pair.
Answer: With more than eight electrons around the central atom. Shows atoms with more than 8 valence electrons.
Answer: One lone pair. Nitrogen uses three electrons for bonds, two remain as lone pair.
Answer: H-C-Cl with an additional H and Cl bonded to C. Tetrahedral carbon with two hydrogen and two chlorine atoms.
Answer: Three pairs of shared electrons. Triple bonds involve six electrons in three pairs.
Answer: As pairs of dots around the atom. Dots show unshared electrons around atomic symbols.
Answer: Phosphorus. Third period elements can use d orbitals for bonding.
Answer: By using double-headed arrows between structures. Shows electron delocalization across multiple structures.
Answer: N=O with one lone pair on N and two on O. Radical molecule with unpaired electron on nitrogen.
Answer: O=O-O with one lone pair on the central O and two on the others. Bent molecule showing resonance between oxygen atoms.
Answer: By using double-headed arrows between structures. Shows electron delocalization across multiple structures.
Answer: Missing two lone pairs on the oxygen. Oxygen needs two lone pairs to complete its octet.
Answer: With a single line between two atoms. One line equals one electron pair shared between atoms.
Answer: One lone pair. Nitrogen uses three electrons for bonds, two remain as lone pair.
Answer: N≡N. Triple bond forms when nitrogen atoms share three electron pairs.
Answer: Chlorine. Cl is the chemical symbol for this halogen element.
Answer: To show the bonding between atoms and lone pairs of electrons. Visualizes electron distribution and chemical bonding patterns.
Answer: Three pairs of shared electrons. Triple bonds involve six electrons in three pairs.
Answer: F-B-F with one additional F atom bonded to B. Trigonal planar with boron having incomplete octet.
Answer: Dots around the atom. Two dots represent an unshared electron pair.
Answer: :O::O: or O=O. Double bond between oxygens with two lone pairs each.
Answer: N≡N. Triple bond forms when nitrogen atoms share three electron pairs.
Answer: :O::O: or O=O. Double bond between oxygens with two lone pairs each.
Answer: H-C≡C-H. Linear molecule with carbon-carbon triple bond.
Answer: Three covalent bonds. Uses three of its five valence electrons for bonding.
Answer: H-C=O with an additional H on C and two lone pairs on O. Planar molecule with carbon-oxygen double bond.
Answer: H-O-O-H with two lone pairs on each O. Chain structure with oxygen-oxygen single bond.
Answer: H-Cl with three lone pairs on Cl. Polar molecule with chlorine having three lone pairs.
Answer: O=C=O. Linear molecule with carbon forming two double bonds.
Answer: With a single line between two atoms. One line equals one electron pair shared between atoms.
Answer: Five. Nitrogen is in group 15 of the periodic table.
Answer: Cl-C-Cl with two additional Cl atoms bonded to C. Tetrahedral structure with carbon bonded to four chlorines.
Answer: H-P-H with one lone pair on P and an additional H. Trigonal pyramidal shape with phosphorus as central atom.
Answer: Two lone pairs. Oxygen has 6 valence electrons, forms 2 bonds, leaves 4 as lone pairs.
Answer: O=S-O with one lone pair on S and two on each O. Bent structure due to lone pair repulsion on sulfur.
Answer: :O::O: or O=O. Double bond between oxygens with two lone pairs each.
Answer: H-C=C-H with additional H atoms bonded to each C. Planar molecule with carbon-carbon double bond.
Answer: F-S-F with four additional F atoms bonded to S. Octahedral structure utilizing sulfur's expanded octet.
Answer: O=S-O with one lone pair on S and two on each O. Bent structure due to lone pair repulsion on sulfur.
Answer: As pairs of dots around the atom. Dots show unshared electrons around atomic symbols.
Answer: Atoms tend to have eight electrons in their valence shell. Stable electron configuration for most main group elements.
Answer: H-C-Cl with an additional H and Cl bonded to C. Tetrahedral carbon with two hydrogen and two chlorine atoms.
Answer: H-C-H with two additional H atoms bonded to C. Tetrahedral structure with carbon bonded to four hydrogens.
Answer: Two bonds. Oxygen typically forms two covalent bonds to complete octet.
Answer: To show the bonding between atoms and lone pairs of electrons. Visualizes electron distribution and chemical bonding patterns.
Answer: H-P-H with one lone pair on P and an additional H. Trigonal pyramidal shape with phosphorus as central atom.
Answer: Atoms tend to have eight electrons in their valence shell. Stable electron configuration for most main group elements.
Answer: With a line between the two atoms. Line notation represents covalent bonding electrons.
Answer: H-C-H with two additional H atoms bonded to C. Tetrahedral structure with carbon bonded to four hydrogens.
Answer: Four. Carbon is in group 14, giving it 4 valence electrons.
Answer: H-C≡C-H. Linear molecule with carbon-carbon triple bond.
Answer: H-Cl with three lone pairs on Cl. Polar molecule with chlorine having three lone pairs.
Answer: O=C=O. Linear molecule with carbon forming two double bonds.
Answer: With two parallel lines between the bonded atoms. Two parallel lines indicate four shared electrons.
Answer: Five. Nitrogen is in group 15 of the periodic table.
Answer: N=O with one lone pair on N and two on O. Radical molecule with unpaired electron on nitrogen.
Answer: Three covalent bonds. Uses three of its five valence electrons for bonding.
Answer: N=O with one lone pair on N and two on O. Radical molecule with unpaired electron on nitrogen.
Answer: H-N-H with one lone pair on N and an additional H. Trigonal pyramidal with nitrogen forming three bonds.
Answer: Dots around the atom. Two dots represent an unshared electron pair.
Answer: With a line between the two atoms. Line notation represents covalent bonding electrons.
Answer: Chlorine. Cl is the chemical symbol for this halogen element.
Answer: One lone pair. Nitrogen uses three electrons for bonds, two remain as lone pair.
Answer: With a line between the two atoms. Line notation represents covalent bonding electrons.
Answer: H-N-H with one lone pair on N and an additional H. Trigonal pyramidal with nitrogen forming three bonds.
Answer: H-C=O with an additional H on C and two lone pairs on O. Planar molecule with carbon-oxygen double bond.
Answer: A pair of shared electrons. Each line shows a covalent bond of two electrons.
Answer: O=C=O. Linear molecule with carbon forming two double bonds.
Answer: Dots around the atom. Two dots represent an unshared electron pair.
Answer: H-N-H with one lone pair on N and an additional H. Trigonal pyramidal with nitrogen forming three bonds.
Answer: One lone pair. Nitrogen uses three electrons for bonds, two remain as lone pair.
Answer: O=O-O with one lone pair on the central O and two on the others. Bent molecule showing resonance between oxygen atoms.
Answer: Two bonds. Oxygen typically forms two covalent bonds to complete octet.
Answer: With a single line between two atoms. One line equals one electron pair shared between atoms.
Answer: Two bonds. Oxygen typically forms two covalent bonds to complete octet.
Answer: Two bonds. Oxygen typically forms two covalent bonds to complete octet.
Answer: H-C-H with two additional H atoms bonded to C. Tetrahedral structure with carbon bonded to four hydrogens.
Answer: F-B-F with one additional F atom bonded to B. Trigonal planar with boron having incomplete octet.
Answer: H-C≡C-H. Linear molecule with carbon-carbon triple bond.
Answer: H-O-O-H with two lone pairs on each O. Chain structure with oxygen-oxygen single bond.
Answer: Three covalent bonds. Uses three of its five valence electrons for bonding.
Answer: H-C=C-H with additional H atoms bonded to each C. Planar molecule with carbon-carbon double bond.
Answer: H-O-O-H with two lone pairs on each O. Chain structure with oxygen-oxygen single bond.
Answer: H-P-H with one lone pair on P and an additional H. Trigonal pyramidal shape with phosphorus as central atom.
Answer: Phosphorus. Third period elements can use d orbitals for bonding.
Answer: By using double-headed arrows between structures. Shows electron delocalization across multiple structures.
Answer: O=C=O. Linear molecule with carbon forming two double bonds.
Answer: Phosphorus. Third period elements can use d orbitals for bonding.
Answer: H-C=C-H with additional H atoms bonded to each C. Planar molecule with carbon-carbon double bond.
Answer: N≡N. Triple bond forms when nitrogen atoms share three electron pairs.