Study Ph And Solubility in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Flashcard 1: Identify the pH of a neutral solution at 25°C.
Answer: pH = 7. Equal concentrations of [H+] and [OH−].
Flashcard 2: What is the pH of a solution with [H+]=1×10−7 M?
Answer: pH = 7. pH=−log(10−7)=7
Flashcard 3: Determine the pOH of a solution with [OH−]=1×10−4 M.
Answer: pOH = 4. pOH=−log(10−4)=4
Flashcard 4: What is the solubility product constant for PbI2?
Answer: Ksp=[Pb2+][I−]2. Iodide ion squared due to formula stoichiometry.
Flashcard 5: What is the pH of a 0.1 M NaOH solution?
Answer: pH = 13. Strong base: [OH−]=0.1, pOH=1
Flashcard 6: Identify the pH of a neutral solution at 25°C.
Answer: pH = 7. Equal concentrations of [H+] and [OH−].
Flashcard 7: State the Ksp expression for ZnS.
Answer: Ksp=[Zn2+][S2−]. 1:1 stoichiometry for ion products.
Flashcard 8: What is the solubility product constant for PbI2?
Answer: Ksp=[Pb2+][I−]2. Iodide ion squared due to formula stoichiometry.
Flashcard 9: What is the definition of the solubility product constant (Ksp)?
Answer: Ksp is the equilibrium constant for a solid dissolving in water. Represents dissolution equilibrium of ionic solids.
Flashcard 10: What is the definition of the solubility product constant (Ksp)?
Answer: Ksp is the equilibrium constant for a solid dissolving in water. Represents dissolution equilibrium of ionic solids.
Flashcard 11: What is the Ksp expression for CuS?
Answer: Ksp=[Cu2+][S2−]. 1:1 stoichiometry for ion products.
Flashcard 12: State the formula for calculating pOH from [OH−].
Answer: pOH=−log[OH−]. Take negative log of hydroxide ion concentration.
Flashcard 13: Determine the pH of a 0.025 M HBr solution.
Answer: pH = 1.6. pH=−log(0.025)=1.6
Flashcard 14: Which solution has a higher pH: 0.1 M HCl or 0.1 M NaOH?
Answer: 0.1 M NaOH. NaOH is basic with higher pH value.
Flashcard 15: Find the pH of a 0.075 M Ba(OH)2 solution.
Answer: pH = 13.18. Diprotic base: [OH−]=0.15, pOH=0.82
Flashcard 16: Calculate the pH of pure water at 25°C.
Answer: pH = 7. [H+]=1.0×10−7 at equilibrium.
Flashcard 17: What is the Ksp expression for CaF2?
Answer: Ksp=[Ca2+][F−]2. Fluoride ion squared due to formula stoichiometry.
Flashcard 18: State the formula for converting pOH to pH.
Answer: pH=14−pOH. Derived from pH+pOH=14 relationship.
Flashcard 19: What is the Ksp expression for CuS?
Answer: Ksp=[Cu2+][S2−]. 1:1 stoichiometry for ion products.
Flashcard 20: What is the pH of a 0.02 M KOH solution?
Answer: pH = 12.3. [OH−]=0.02, pOH=1.7
Flashcard 21: What is the Ksp expression for PbSO4?
Answer: Ksp=[Pb2+][SO42−]. 1:1 stoichiometry for ion products.
Flashcard 22: What is the Ksp expression for Mg(OH)2?
Answer: Ksp=[Mg2+][OH−]2. Hydroxide ion squared due to formula stoichiometry.
Flashcard 23: What is the pH of a solution with [H+]=1×10−3 M?
Answer: pH = 3. pH=−log(10−3)=3
Flashcard 24: State the ion product constant for water (Kw) at 25°C.
Answer: Kw=1.0×10−14. Equilibrium constant for water autoionization.
Flashcard 25: Identify the Ksp expression for BaSO4.
Answer: Ksp=[Ba2+][SO42−]. 1:1 stoichiometry for ion products.
Flashcard 26: Identify the Ksp expression for BaSO4.
Answer: Ksp=[Ba2+][SO42−]. 1:1 stoichiometry for ion products.
Flashcard 27: What is the pH of a 0.02 M KOH solution?
Answer: pH = 12.3. [OH−]=0.02, pOH=1.7
Flashcard 28: What is the Ksp expression for CaCO3?
Answer: Ksp=[Ca2+][CO32−]. 1:1 stoichiometry for ion products.
Flashcard 29: What is the Ksp expression for Ag2CrO4?
Answer: Ksp=[Ag+]2[CrO42−]. Silver ion squared due to formula stoichiometry.
Flashcard 30: What is the relationship between pH and pOH at 25°C?
Answer: pH+pOH=14. Sum equals 14 at standard temperature.
Flashcard 31: What is the definition of pH?
Answer: pH is the negative logarithm of the hydrogen ion concentration: pH=−log[H+]. It measures acidity using logarithmic scale.
Flashcard 32: What is the pH of a 0.02 M KOH solution?
Answer: pH = 12.3. [OH−]=0.02, pOH=1.7
Flashcard 33: State the formula for calculating pH from [H+].
Answer: pH=−log[H+]. Take negative log of hydrogen ion concentration.
Flashcard 34: If [OH−]=1×10−9 M, what is the pH of the solution?
Answer: pH = 5. pOH=9, so pH=14−9=5
Flashcard 35: What is the solubility product constant for PbI2?
Answer: Ksp=[Pb2+][I−]2. Iodide ion squared due to formula stoichiometry.
Flashcard 36: What is the relationship between pH and pOH at 25°C?
Answer: pH+pOH=14. Sum equals 14 at standard temperature.
Flashcard 37: What is the solubility product constant (Ksp) expression for AgCl?
Answer: Ksp=[Ag+][Cl−]. Products of ion concentrations at equilibrium.
Flashcard 38: What is the Ksp expression for Hg2I2?
Answer: Ksp=[Hg22+][I−]2. Iodide ion squared due to formula stoichiometry.
Flashcard 39: What is the solubility product constant for PbI2?
Answer: Ksp=[Pb2+][I−]2. Iodide ion squared due to formula stoichiometry.
Flashcard 40: What is the Ksp expression for Mg(OH)2?
Answer: Ksp=[Mg2+][OH−]2. Hydroxide ion squared due to formula stoichiometry.
Flashcard 41: Calculate the pH of a 0.001 M HNO3 solution.
Answer: pH = 3. Strong acid: pH=−log(0.001)=3
Flashcard 42: Calculate the pH of a 0.1 M CH3COOH solution, Ka=1.8×10−5.
Answer: pH ≈ 2.87. Weak acid requires ICE table calculation.
Flashcard 43: What is the definition of pH?
Answer: pH is the negative logarithm of the hydrogen ion concentration: pH=−log[H+]. It measures acidity using logarithmic scale.
Flashcard 44: Determine the pOH of a solution with [OH−]=1×10−4 M.
Answer: pOH = 4. pOH=−log(10−4)=4
Flashcard 45: What is the Ksp expression for CuS?
Answer: Ksp=[Cu2+][S2−]. 1:1 stoichiometry for ion products.
Flashcard 46: What is the relationship between pH and pOH at 25°C?
Answer: pH+pOH=14. Sum equals 14 at standard temperature.
Flashcard 47: Find the pH of a 0.03 M LiOH solution.
Answer: pH = 12.5. [OH−]=0.03, pOH=1.52
Flashcard 48: State the ion product constant for water (Kw) at 25°C.
Answer: Kw=1.0×10−14. Equilibrium constant for water autoionization.
Flashcard 49: Determine the pH of a 0.025 M HBr solution.
Answer: pH = 1.6. pH=−log(0.025)=1.6
Flashcard 50: What is the Ksp expression for Ag2CrO4?
Answer: Ksp=[Ag+]2[CrO42−]. Silver ion squared due to formula stoichiometry.
Flashcard 51: Determine the pOH of a solution with [OH−]=1×10−4 M.
Answer: pOH = 4. pOH=−log(10−4)=4
Flashcard 52: What is the Ksp expression for Ca(OH)2?
Answer: Ksp=[Ca2+][OH−]2. Hydroxide ion squared due to formula stoichiometry.
Flashcard 53: What is the Ksp expression for Hg2I2?
Answer: Ksp=[Hg22+][I−]2. Iodide ion squared due to formula stoichiometry.
Flashcard 54: Which solution has a higher pH: 0.1 M HCl or 0.1 M NaOH?
Answer: 0.1 M NaOH. NaOH is basic with higher pH value.
Flashcard 55: Determine the Ksp expression for Fe(OH)3.
Answer: Ksp=[Fe3+][OH−]3. Hydroxide ion cubed due to formula stoichiometry.
Flashcard 56: What is the Ksp expression for Ca(OH)2?
Answer: Ksp=[Ca2+][OH−]2. Hydroxide ion squared due to formula stoichiometry.
Flashcard 57: What is the pH of a 0.01 M HCl solution?
Answer: pH = 2. Strong acid completely ionizes: [H+]=0.01
Flashcard 58: Determine the pOH of a solution with [OH−]=1×10−4 M.
Answer: pOH = 4. pOH=−log(10−4)=4
Flashcard 59: Determine the Ksp expression for Fe(OH)3.
Answer: Ksp=[Fe3+][OH−]3. Hydroxide ion cubed due to formula stoichiometry.
Flashcard 60: Identify the pH of a neutral solution at 25°C.
Answer: pH = 7. Equal concentrations of [H+] and [OH−].
Flashcard 61: What is the Ksp expression for Ag2SO4?
Answer: Ksp=[Ag+]2[SO42−]. Silver ion squared due to formula stoichiometry.
Flashcard 62: Find the pH of a 0.03 M LiOH solution.
Answer: pH = 12.5. [OH−]=0.03, pOH=1.52
Flashcard 63: State the formula for calculating pOH from [OH−].
Answer: pOH=−log[OH−]. Take negative log of hydroxide ion concentration.
Flashcard 64: State the formula for converting pOH to pH.
Answer: pH=14−pOH. Derived from pH+pOH=14 relationship.
Flashcard 65: Calculate the pH of a 0.005 M HCl solution.
Answer: pH = 2.3. pH=−log(0.005)=2.3
Flashcard 66: Which solution has a higher pH: 0.1 M HCl or 0.1 M NaOH?
Answer: 0.1 M NaOH. NaOH is basic with higher pH value.
Flashcard 67: What is the definition of pH?
Answer: pH is the negative logarithm of the hydrogen ion concentration: pH=−log[H+]. It measures acidity using logarithmic scale.
Flashcard 68: What is the pH of a 0.1 M NaOH solution?
Answer: pH = 13. Strong base: [OH−]=0.1, pOH=1
Flashcard 69: What is the Ksp expression for Ca(OH)2?
Answer: Ksp=[Ca2+][OH−]2. Hydroxide ion squared due to formula stoichiometry.
Flashcard 70: What is the Ksp expression for Mg(OH)2?
Answer: Ksp=[Mg2+][OH−]2. Hydroxide ion squared due to formula stoichiometry.
Flashcard 71: Determine the Ksp expression for Fe(OH)3.
Answer: Ksp=[Fe3+][OH−]3. Hydroxide ion cubed due to formula stoichiometry.
Flashcard 72: Calculate the pH of pure water at 25°C.
Answer: pH = 7. [H+]=1.0×10−7 at equilibrium.
Flashcard 73: What is the pH of a 0.02 M KOH solution?
Answer: pH = 12.3. [OH−]=0.02, pOH=1.7
Flashcard 74: Calculate the pH of a 0.001 M HNO3 solution.
Answer: pH = 3. Strong acid: pH=−log(0.001)=3
Flashcard 75: Which is more soluble in water: AgCl or NaCl?
Answer: NaCl. NaCl is highly soluble ionic compound.
Flashcard 76: What is the Ksp expression for Ag2SO4?
Answer: Ksp=[Ag+]2[SO42−]. Silver ion squared due to formula stoichiometry.
Flashcard 77: What is the Ksp expression for PbSO4?
Answer: Ksp=[Pb2+][SO42−]. 1:1 stoichiometry for ion products.
Flashcard 78: Find the pH of a 0.075 M Ba(OH)2 solution.
Answer: pH = 13.18. Diprotic base: [OH−]=0.15, pOH=0.82
Flashcard 79: State the formula for calculating pOH from [OH−].
Answer: pOH=−log[OH−]. Take negative log of hydroxide ion concentration.
Flashcard 80: Which solution has a higher pH: 0.1 M HCl or 0.1 M NaOH?
Answer: 0.1 M NaOH. NaOH is basic with higher pH value.
Flashcard 81: State the ion product constant for water (Kw) at 25°C.
Answer: Kw=1.0×10−14. Equilibrium constant for water autoionization.
Flashcard 82: Find the pH of a 0.03 M LiOH solution.
Answer: pH = 12.5. [OH−]=0.03, pOH=1.52
Flashcard 83: What is the definition of pH?
Answer: pH is the negative logarithm of the hydrogen ion concentration: pH=−log[H+]. It measures acidity using logarithmic scale.
Flashcard 84: What is the pH of a 0.1 M NaOH solution?
Answer: pH = 13. Strong base: [OH−]=0.1, pOH=1
Flashcard 85: What is the pH of a solution with [H+]=1×10−3 M?
Answer: pH = 3. pH=−log(10−3)=3
Flashcard 86: Which is more soluble in water: AgCl or NaCl?
Answer: NaCl. NaCl is highly soluble ionic compound.
Flashcard 87: What is the Ksp expression for Ag2CrO4?
Answer: Ksp=[Ag+]2[CrO42−]. Silver ion squared due to formula stoichiometry.
Flashcard 88: Calculate the pH of a 0.1 M CH3COOH solution, Ka=1.8×10−5.
Answer: pH ≈ 2.87. Weak acid requires ICE table calculation.
Flashcard 89: What is the Ksp expression for CaF2?
Answer: Ksp=[Ca2+][F−]2. Fluoride ion squared due to formula stoichiometry.
Flashcard 90: What is the solubility product constant (Ksp) expression for AgCl?
Answer: Ksp=[Ag+][Cl−]. Products of ion concentrations at equilibrium.
Flashcard 91: State the formula for calculating pH from [H+].
Answer: pH=−log[H+]. Take negative log of hydrogen ion concentration.
Flashcard 92: What is the Ksp expression for Ca(OH)2?
Answer: Ksp=[Ca2+][OH−]2. Hydroxide ion squared due to formula stoichiometry.
Flashcard 93: Calculate the pH of a 0.001 M HNO3 solution.
Answer: pH = 3. Strong acid: pH=−log(0.001)=3
Flashcard 94: What is the definition of the solubility product constant (Ksp)?
Answer: Ksp is the equilibrium constant for a solid dissolving in water. Represents dissolution equilibrium of ionic solids.
Flashcard 95: What is the solubility product constant (Ksp) expression for AgCl?
Answer: Ksp=[Ag+][Cl−]. Products of ion concentrations at equilibrium.
Flashcard 96: State the formula for calculating pOH from [OH−].
Answer: pOH=−log[OH−]. Take negative log of hydroxide ion concentration.
Flashcard 97: What is the Ksp expression for CaF2?
Answer: Ksp=[Ca2+][F−]2. Fluoride ion squared due to formula stoichiometry.
Flashcard 98: Determine the Ksp expression for Fe(OH)3.
Answer: Ksp=[Fe3+][OH−]3. Hydroxide ion cubed due to formula stoichiometry.
Flashcard 99: Identify the Ksp expression for BaSO4.
Answer: Ksp=[Ba2+][SO42−]. 1:1 stoichiometry for ion products.
Flashcard 100: Calculate the pH of pure water at 25°C.
Answer: pH = 7. [H+]=1.0×10−7 at equilibrium.