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This deck focuses on Reaction Mechanisms And Rate Law, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Reaction Mechanisms And Rate Law in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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How do you find the overall order of a reaction?
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Sum the exponents in the rate law. Add all concentration exponents in rate law.
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This deck focuses on Reaction Mechanisms And Rate Law, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Sum the exponents in the rate law. Add all concentration exponents in rate law.
Answer:
Answer: Rate = k[A]m[B]n. General form where m and n are determined experimentally, not from coefficients.
Answer: The slowest step. This step controls the overall reaction rate.
Answer: s−1. First-order reactions have units of reciprocal time.
Answer: Controls the overall rate of the reaction. Determines how fast products form overall.
Answer: Sum the exponents in the rate law. Add all concentration exponents in rate law.
Answer: A series of elementary steps that describe the pathway from reactants to products. Shows how reactants transform through specific elementary steps.
Answer: A reaction involving three reacting species in one step. Rare due to low probability of three-body collisions.
Answer: A single reaction step with a single transition state. Cannot be broken down into simpler mechanistic steps.
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Answer:
Answer: Rate = k[A2][B]. Stoichiometry directly gives rate law for elementary steps.
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Answer: A reaction involving three reacting species in one step. Rare due to low probability of three-body collisions.
Answer: A species formed and consumed during the reaction mechanism. Temporary species that doesn't appear in overall equation.
Answer: Intermediate. Formed during mechanism but cancels out overall.
Answer: Termolecular. Count total molecules: 1 A + 2 B = 3 molecules.
Answer:
Answer: Rate = k[A2][B]. Stoichiometry directly gives rate law for elementary steps.
Answer: Controls the overall rate of the reaction. Determines how fast products form overall.
Answer: The minimum energy required for a reaction to occur. Energy barrier that must be overcome for reaction.
Answer: It lowers the activation energy of the rate-determining step. Reduces energy barrier of the limiting step.
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Answer: Intermediates are produced and consumed; catalysts are not consumed. Key distinction: intermediates appear then disappear in the mechanism.
Answer: A reaction that occurs in a single step. Proceeds directly without intermediate steps.
Answer: The rate law can provide insights into the mechanism, particularly the rate-determining step. Rate law reflects the slowest step's kinetics.
Answer: M−1s−1. Second-order reactions have units of reciprocal concentration per time.
Answer: It lowers the activation energy, increasing reaction rate. Provides alternative pathway with lower energy barrier.
Answer: Termolecular. Three molecules participate in a single elementary step.
Answer: Rate = k[NO]2[O2]. For elementary reactions, stoichiometry equals rate law exponents.
Answer: Unimolecular. Only one molecule undergoes reaction in the step.
Answer: Rate = k[A]m[B]n. General form where m and n are determined experimentally, not from coefficients.
Answer: A substance that increases the reaction rate without being consumed. Speeds up reaction but remains unchanged overall.
Answer: A reaction that occurs in a single step. Proceeds directly without intermediate steps.
Answer: The slowest step. This step controls the overall reaction rate.
Answer: Each step represents a single molecular event. Each step occurs as written without sub-steps.
Answer: Rate = k[A]2. Stoichiometry gives exponents for elementary reactions.
Answer: A single reaction step with a single transition state. Cannot be broken down into simpler mechanistic steps.
Answer: A reaction involving three reacting species in one step. Rare due to low probability of three-body collisions.
Answer: Identify the overall balanced chemical equation. Foundation for proposing elementary steps.
Answer: To provide a detailed step-by-step description of a reaction. Explains the molecular pathway from reactants to products.
Answer: Rate = k[A][B]. Elementary steps follow stoichiometry in rate laws.
Answer: M⋅s−1. Zero-order has units of concentration per time.
Answer: Bimolecular. Two different molecules react in one step.
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Answer: M−2s−1. Third-order has units M−2s−1.
Answer: A species formed and consumed during the reaction mechanism. Temporary species that doesn't appear in overall equation.
Answer:
Answer: A reaction involving one reactant molecule in a single step. Single molecule breaks down or rearranges.
Answer: Intermediate. Formed during mechanism but cancels out overall.
Answer: It lowers the activation energy, increasing reaction rate. Provides alternative pathway with lower energy barrier.
Answer: Rate = k[NO]2[O2]. For elementary reactions, stoichiometry equals rate law exponents.
Answer: Bimolecular. Two different molecules react in one step.
Answer: Bimolecular. Two reactants means molecularity equals 2.
Answer: Rate = k[A]. Unimolecular means first order in the single reactant.
Answer: Termolecular. Count total molecules: 1 A + 2 B = 3 molecules.
Answer: s−1. First-order reactions have units of reciprocal time.