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This deck focuses on Reaction Quotient And Le Chateliers Principle, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Reaction Quotient And Le Chateliers Principle in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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What does Qc=Kc signify?
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The system is at equilibrium. When Qc equals Kc, forward and reverse reaction rates are equal.
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This deck focuses on Reaction Quotient And Le Chateliers Principle, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: The system is at equilibrium. When Qc equals Kc, forward and reverse reaction rates are equal.
Answer: A system at equilibrium will adjust to counteract imposed changes. The system responds to minimize the disturbance and restore balance.
Answer: The reaction will proceed in the reverse direction. When Qc>Kc, excess products convert back to reactants.
Answer: The equilibrium shifts to the right to form more products. System compensates by producing more of the removed product.
Answer: The rate increases, but equilibrium position is unchanged. Catalysts affect kinetics but not the equilibrium position.
Answer: There is no effect on the position of equilibrium. Inert gas doesn't change partial pressures of reactants or products.
Answer: The equilibrium shifts to the left, forming more reactants. System produces more reactant to replace what was removed.
Answer: Kc decreases with a decrease in temperature. Lower temperature opposes endothermic reactions, decreasing Kc.
Answer: Shifts to the side with fewer moles of gas. Higher pressure favors the side with fewer gas molecules.
Answer: The equilibrium shifts towards the side with fewer moles of gas. Higher pressure favors the side with fewer gas molecules.
Answer: Qc=[A]2[B]=0.320.2=2.22. Substitute the given concentrations into the Qc expression.
Answer: Shifts right, forming more products. More reactant drives the equilibrium forward to consume it.
Answer: The equilibrium shifts to the right to produce more product. System compensates by producing more of the removed product.
Answer: The equilibrium shifts to the left, decreasing dissociation. Added acid increases H+ concentration, suppressing weak acid dissociation.
Answer: The equilibrium constant, Kc, decreases. Higher temperature opposes exothermic reactions, reducing Kc.
Answer: Qc=[A][B]2[C][D]=2×321×4=92. Substitute concentrations into Qc expression and calculate.
Answer: Qc=[A][B][C]=1.0×2.01.5=0.75. Apply the Qc formula using the given concentration values.
Answer: The equilibrium shifts to the side with more moles of gas. Increased volume decreases pressure, favoring more gas molecules.
Answer: The equilibrium shifts to the left, producing more reactants. Excess product drives the equilibrium backward to consume it.
Answer: Qc=[A]3[B]2[C]. Products in numerator, reactants in denominator with stoichiometric coefficients.
Answer: The equilibrium shifts to the left, forming more reactants. System compensates by producing more of the depleted reactant.
Answer: Kc decreases with a decrease in temperature. Lower temperature opposes endothermic reactions, decreasing Kc.
Answer: The equilibrium shifts to the side with more solute particles. Dilution favors the side that produces more dissolved particles.
Answer: The equilibrium shifts to the right, forming more products. System responds by consuming the excess reactant to form products.
Answer: Qc=[A][B][C]2=0.5×0.50.12=0.04. Substitute given concentrations into the Qc formula.
Answer: A catalyst increases the rate of reaction without shifting equilibrium. Catalysts only affect reaction kinetics, not thermodynamic equilibrium.
Answer: The reaction proceeds forward to reach equilibrium. When Qc<Kc, forward reaction proceeds to reach equilibrium.
Answer: Kc increases with a decrease in temperature. Lower temperature favors exothermic reactions, increasing Kc.
Answer: A catalyst does not affect the position of equilibrium. Catalysts speed up both forward and reverse reactions equally.
Answer: It changes the equilibrium position depending on moles of gas. At constant pressure, inert gas causes volume expansion affecting equilibrium.
Answer: The equilibrium shifts to the right, favoring product formation. Lower temperature favors the exothermic direction (forward).
Answer: The reaction will proceed forward to reach equilibrium. When Qc<Kc, more products must form to reach equilibrium.
Answer: The reaction will proceed in the reverse direction. When Qc>Kc, excess products convert back to reactants.
Answer: The reaction proceeds forward to reach equilibrium. When Qc<Kc, forward reaction proceeds to reach equilibrium.
Answer: There is no effect on the position of equilibrium. Pressure changes don't affect equilibrium when gas moles are equal.
Answer: The equilibrium shifts to the left, forming more reactants. Increased product concentration drives the reaction backward.
Answer: The ratio of product concentrations to reactant concentrations at any point. Measures current concentration ratio, not necessarily at equilibrium.
Answer: The equilibrium shifts to the right, favoring product formation. Higher temperature favors the endothermic direction (forward).
Answer: Qc=[A]2[B][C]3[D]. Products in numerator with coefficients as exponents, reactants in denominator.
Answer: Kc decreases with an increase in temperature. Higher temperature opposes exothermic reactions, decreasing Kc.
Answer: Kc increases with an increase in temperature. Higher temperature favors endothermic reactions, increasing Kc.