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This deck focuses on Representations Of Solutions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Representations Of Solutions in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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What is Raoult's Law formula?
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PA=XAPA0, where PA is vapor pressure of component A. Law relates vapor pressure to mole fraction in ideal solutions.
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This deck focuses on Representations Of Solutions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: PA=XAPA0, where PA is vapor pressure of component A. Law relates vapor pressure to mole fraction in ideal solutions.
Answer: Depends on the number of solute particles, not their identity. Properties determined by particle count, not chemical identity.
Answer: Lowers the freezing point. Solute particles interfere with crystal formation at normal freezing point.
Answer: A solution that can dissolve more solute at a given temperature. Solution can still accept additional solute below saturation point.
Answer: New concentration is 2 M. Apply dilution equation: 6×1=M2×3, so M2=2.
Answer: A solution that contains more solute than can dissolve at the current temperature. Metastable state containing excess solute that can crystallize out.
Answer: System at equilibrium will adjust to counteract disturbances. Fundamental principle describing system response to external changes.
Answer: Molarity is the number of moles of solute per liter of solution. This is the fundamental concentration unit relating solute amount to solution volume.
Answer: New concentration is 2 M. Apply dilution equation: 6×1=M2×3, so M2=2.
Answer: M1V1=M2V2, where M is molarity and V is volume. Conservation equation for dilutions where moles remain constant.
Answer: ΔTf=iKfm, where i is van't Hoff factor. Formula accounts for number of particles formed when solute dissolves.
Answer: Pressure required to stop osmosis. External pressure needed to prevent solvent flow across membrane.
Answer: Molality is the number of moles of solute per kilogram of solvent. Uses solvent mass instead of solution volume, making it temperature-independent.
Answer: Increased pressure increases gas solubility. Henry's Law: higher pressure forces more gas molecules into solution.
Answer: New concentration is 2 M. Apply dilution equation: 6×1=M2×3, so M2=2.
Answer: Depends on the number of solute particles, not their identity. Properties determined by particle count, not chemical identity.
Answer: Freezing point depression is 0.6°C. Apply formula: ΔTf=3×1×0.2=0.6.
Answer: Raises the boiling point. Solute particles disrupt solvent vaporization, requiring higher temperature.
Answer: Solution with lower solute concentration than another. Comparative term indicating lesser solute concentration relative to reference.
Answer: m=msolventn, where n is moles of solute and msolvent is kg of solvent. Formula uses kilograms of solvent in the denominator.
Answer: System at equilibrium will adjust to counteract disturbances. Fundamental principle describing system response to external changes.
Answer: Molality is the number of moles of solute per kilogram of solvent. Uses solvent mass instead of solution volume, making it temperature-independent.
Answer: Increased pressure increases gas solubility. Henry's Law: higher pressure forces more gas molecules into solution.
Answer: A solution in which no more solute can dissolve at a given temperature. Maximum solubility reached at equilibrium for given conditions.
Answer: C=kP, where C is solubility and P is pressure. Linear relationship where k is Henry's law constant.
Answer: XA=ntotalnA, where nA is moles of component A. Ratio formula where all mole fractions sum to 1.
Answer: Molality is the number of moles of solute per kilogram of solvent. Uses solvent mass instead of solution volume, making it temperature-independent.
Answer: Osmotic pressure is 12.315 atm. Apply formula: π=1×0.5×0.0821×300.
Answer: ΔTb=iKbm, where i is van't Hoff factor. Formula includes van't Hoff factor for ionic dissociation effects.
Answer: Solubility of gas in liquid is proportional to the pressure of gas above the liquid. Direct proportionality between gas pressure and dissolution concentration.
Answer: Depends on the number of solute particles, not their identity. Properties determined by particle count, not chemical identity.
Answer: System at equilibrium will adjust to counteract disturbances. Fundamental principle describing system response to external changes.
Answer: A solution in which no more solute can dissolve at a given temperature. Maximum solubility reached at equilibrium for given conditions.
Answer: Depends on the number of solute particles, not their identity. Properties determined by particle count, not chemical identity.
Answer: New concentration is 2 M. Apply dilution equation: 6×1=M2×3, so M2=2.
Answer: Boiling point elevation is 1°C. Apply formula: ΔTb=2×0.5×1=1.
Answer: Boiling point elevation is 1°C. Apply formula: ΔTb=2×0.5×1=1.
Answer: Solutions with equal solute concentrations. No net osmotic pressure difference exists between the solutions.
Answer: M=Vn, where n is moles of solute and V is volume in liters. Standard formula relating moles of solute to liters of solution.
Answer: Mole fraction is the ratio of moles of one component to the total moles in the mixture. Represents the fraction of total moles contributed by one component.
Answer: Boiling point elevation is 1°C. Apply formula: ΔTb=2×0.5×1=1.
Answer: A solution in which no more solute can dissolve at a given temperature. Maximum solubility reached at equilibrium for given conditions.
Answer: System at equilibrium will adjust to counteract disturbances. Fundamental principle describing system response to external changes.
Answer: Vapor pressure decreases. Raoult's Law: solute particles reduce solvent's tendency to vaporize.
Answer: Moles per kilogram (mol/kg). Units reflect moles of solute per mass of solvent.
Answer: ΔTf=iKfm, where i is van't Hoff factor. Formula accounts for number of particles formed when solute dissolves.
Answer: A solution in which no more solute can dissolve at a given temperature. Maximum solubility reached at equilibrium for given conditions.
Answer: Molality is the number of moles of solute per kilogram of solvent. Uses solvent mass instead of solution volume, making it temperature-independent.
Answer: Boiling point elevation is 1°C. Apply formula: ΔTb=2×0.5×1=1.
Answer: ΔTf=iKfm, where i is van't Hoff factor. Formula accounts for number of particles formed when solute dissolves.
Answer: Percent mass = mass of solutionmass of solute×100%. Mass percentage formula multiplied by 100 for percentage.
Answer: Decrease in solubility of an ionic compound by adding a common ion. Added common ions shift equilibrium, reducing compound solubility.
Answer: ΔTf=iKfm, where i is van't Hoff factor. Formula accounts for number of particles formed when solute dissolves.
Answer: Molarity is the number of moles of solute per liter of solution. This is the fundamental concentration unit relating solute amount to solution volume.
Answer: 1.5 mol/kg. Divide moles by solvent mass: 3÷2=1.5.
Answer: i is the number of particles the solute dissociates into. Represents degree of dissociation for ionic compounds in solution.
Answer: Solution with higher solute concentration than another. Comparative term indicating greater solute concentration relative to reference.
Answer: 0.5 mol/L. Divide moles by volume: 2÷4=0.5.
Answer: Moles per liter (mol/L). Standard SI unit for concentration in chemistry.
Answer: Hypertonic inside, hypotonic outside. Higher concentration inside makes it hypertonic relative to outside.
Answer: π=iMRT, where π is osmotic pressure. Van't Hoff equation incorporating gas law principles for osmosis.
Answer: Mole fraction of A is 0.4. Divide component moles by total: 2÷(2+3)=0.4.