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This deck focuses on Conservation Of Angular Momentum, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Study Conservation Of Angular Momentum in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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What is the formula for angular momentum L of a point mass?
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L=mvrsinθ. For point mass: momentum times radius times sine of angle.
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This deck focuses on Conservation Of Angular Momentum, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: L=mvrsinθ. For point mass: momentum times radius times sine of angle.
Answer: Its moment of inertia changes. Redistributing mass changes the moment of inertia I.
Answer: Spin rate increases. Arms closer reduces I, so ω increases to conserve L.
Answer: Total angular momentum remains constant if no external torque acts. Fundamental principle when no external torques act on system.
Answer: τ=dtdL. Torque equals the time rate of change of angular momentum.
Answer: Remains constant. Conservation applies - only I and ω change, not L.
Answer: A measure of the force that can cause an object to rotate about an axis. Rotational analog of force for linear motion.
Answer: Angular velocity. Rate of rotation measured in radians per second.
Answer: It can change the system's angular momentum. External forces can create torques that change L.
Answer: Angular velocity increases. Since L=Iω=mr2ω, smaller r requires larger ω.
Answer: L=mvrsinθ. For point mass: momentum times radius times sine of angle.
Answer: Angular velocity increases as the star's radius decreases. Conservation requires ω to increase as radius shrinks.
Answer: τ=dtdL. Torque equals the time rate of change of angular momentum.
Answer: ΔL=τt. Impulse-momentum theorem applied to rotational motion.
Answer: Its moment of inertia changes. Redistributing mass changes the moment of inertia I.
Answer: No effect; moment of inertia is mass and shape dependent. Moment of inertia depends only on mass distribution.
Answer: Remains constant. Conservation principle applies when no external torques present.
Answer: Angular velocity decreases. Since L=Iω, larger I requires smaller ω.
Answer: ΔL=τt. Impulse-momentum theorem applied to rotational motion.
Answer: Angular momentum is the rotational analog of linear momentum. Both describe inertial motion in their respective domains.
Answer: Spin rate increases. Arms closer reduces I, so ω increases to conserve L.
Answer: Moment of inertia. Rotational inertia - resistance to angular acceleration.
Answer: I=31mL2. Standard formula for rod rotating about one end.
Answer: Angular momentum changes. External torque causes rate of change in angular momentum.
Answer: Zero. Since L=Iω, zero angular velocity gives zero L.
Answer: Angular velocity. Rate of rotation measured in radians per second.
Answer: The top spins with constant angular momentum if no external torque acts. Applies when friction and air resistance are negligible.
Answer: τ=rFsinθ. Force times lever arm times sine of angle between them.
Answer: Remains constant. Conservation principle applies when no external torques present.
Answer: ω. Greek omega represents angular velocity in physics.
Answer: Angular momentum triples. Angular momentum is directly proportional to angular velocity.
Answer: τ=rFsinθ. Force times lever arm times sine of angle between them.
Answer: L=52mr2ω. Uses solid sphere's moment of inertia I=52mr2.
Answer: No net external torque. Zero net torque is required for conservation.
Answer: Angular velocity decreases. Since L=Iω, larger I requires smaller ω.
Answer: L=Iω. For rigid bodies: moment of inertia times angular velocity.
Answer: Angular momentum triples. Angular momentum is directly proportional to angular velocity.
Answer: Angular velocity quadruples. Since I=mr2, halving r quarters I, so ω quadruples.
Answer: L=Iω. For rigid bodies: moment of inertia times angular velocity.
Answer: Angular momentum doubles. Since L=Iω and I=mr2, doubling m doubles L.
Answer: ω. Greek omega represents angular velocity in physics.
Answer: Stability increases. Larger I resists changes in rotational motion.
Answer: Planets conserve angular momentum unless acted upon by external forces. Kepler's laws follow from angular momentum conservation.
Answer: Planets conserve angular momentum unless acted upon by external forces. Kepler's laws follow from angular momentum conservation.
Answer: Total angular momentum remains constant if no external torque acts. Fundamental principle when no external torques act on system.
Answer: Friction can reduce angular momentum by exerting external torque. Creates external torque that opposes rotational motion.
Answer: L=4 kg⋅m2/s. L=mvr=2×4×0.5=4 units.
Answer: I=31mL2. Standard formula for rod rotating about one end.
Answer: The top spins with constant angular momentum if no external torque acts. Applies when friction and air resistance are negligible.
Answer: Friction can reduce angular momentum by exerting external torque. Creates external torque that opposes rotational motion.
Answer: Zero. Since L=Iω, zero angular velocity gives zero L.
Answer: It can change the system's angular momentum. External forces can create torques that change L.
Answer: Moment of inertia. Rotational inertia - resistance to angular acceleration.
Answer: I=mr2. Mass times distance squared from rotation axis.
Answer: Stability increases. Larger I resists changes in rotational motion.
Answer: Kilogram meter squared per second (kg⋅m2/s). Derived from L=mvr with standard SI base units.
Answer: Kilogram meter squared per second (kg⋅m2/s). Derived from L=mvr with standard SI base units.
Answer: Angular momentum doubles. Since L=Iω and I=mr2, doubling m doubles L.
Answer: Angular velocity increases as the star's radius decreases. Conservation requires ω to increase as radius shrinks.
Answer: L=52mr2ω. Uses solid sphere's moment of inertia I=52mr2.
Answer: I=mr2. Mass times distance squared from rotation axis.
Answer: L=4 kg⋅m2/s. L=mvr=2×4×0.5=4 units.
Answer: No net external torque. Zero net torque is required for conservation.
Answer: Angular velocity quadruples. Since I=mr2, halving r quarters I, so ω quadruples.
Answer: No effect; moment of inertia is mass and shape dependent. Moment of inertia depends only on mass distribution.
Answer: Angular velocity increases. Since L=Iω=mr2ω, smaller r requires larger ω.
Answer: Angular momentum changes. External torque causes rate of change in angular momentum.