AP Physics 1 Flashcards: Forces And Free Body Diagrams

Study Forces And Free Body Diagrams in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 1

Forces And Free Body Diagrams

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QUESTION
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Identify the main force that acts at a distance without contact.

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ANSWER

Gravitational force. Gravity acts between all masses without physical contact.

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This deck focuses on Forces And Free Body Diagrams, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

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Flashcard 1: Identify the main force that acts at a distance without contact.

Answer: Gravitational force. Gravity acts between all masses without physical contact.

Flashcard 2: What is the unit of force in the International System of Units?

Answer: Newton (N). Named after Isaac Newton; equivalent to kgm/s2\text{kg} \cdot \text{m/s}^2.

Flashcard 3: Calculate the gravitational force on a 10 kg mass on Earth's surface.

Answer: F=98 NF = 98 \text{ N}. Using W=mg=10×9.8=98 NW = mg = 10 \times 9.8 = 98 \text{ N}.

Flashcard 4: What is the unit of gravitational constant GG?

Answer: N m2kg2\text{N m}^2 \text{kg}^{-2}. Units derived from F=Gm1m2r2F = G \frac{m_1 m_2}{r^2} dimensional analysis.

Flashcard 5: What is the effect on acceleration if net force is doubled?

Answer: Acceleration doubles. From F=maF = ma; doubling force doubles acceleration for constant mass.

Flashcard 6: Choose the correct formula for tension in a rope with mass mm accelerating upward.

Answer: T=m(g+a)T = m(g + a). Tension must overcome weight plus provide upward acceleration force.

Flashcard 7: State Newton's First Law of Motion.

Answer: An object in motion stays in motion unless acted on by a net external force. Also called the law of inertia; objects resist changes in motion.

Flashcard 8: What is the effect on net force if two equal forces act in opposite directions?

Answer: Net force is 0 N. Equal and opposite forces cancel completely.

Flashcard 9: State the formula for Newton's Second Law of Motion.

Answer: F=maF = ma. Force equals mass times acceleration; fundamental dynamics equation.

Flashcard 10: Calculate the net force on an object with 8 N right and 3 N left.

Answer: 5 N to the right. Net force: 8 N3 N=5 N8 \text{ N} - 3 \text{ N} = 5 \text{ N} rightward.

Flashcard 11: What is the unit of gravitational constant GG?

Answer: N m2kg2\text{N m}^2 \text{kg}^{-2}. Units derived from F=Gm1m2r2F = G \frac{m_1 m_2}{r^2} dimensional analysis.

Flashcard 12: What is the direction of the net force on an object moving in a circle?

Answer: Towards the center of the circle. Centripetal force always points toward the center of circular motion.

Flashcard 13: How does increasing mass affect gravitational force?

Answer: Gravitational force increases. Force is proportional to both masses in gravitational equation.

Flashcard 14: What is the formula for kinetic frictional force?

Answer: fk=μkNf_k = \text{μ}_k N. Kinetic friction equals coefficient times normal force.

Flashcard 15: Find the net force if an object has forces of 5 N and 3 N in opposite directions.

Answer: Net force is 2 N in the direction of the larger force. Subtract opposing forces: 5 N3 N=2 N5 \text{ N} - 3 \text{ N} = 2 \text{ N}.

Flashcard 16: Identify the force that acts between two charged objects.

Answer: Electrostatic force. Coulomb force between charges; can be attractive or repulsive.

Flashcard 17: Which force is responsible for an object sliding down an inclined plane?

Answer: Component of gravitational force parallel to the plane. Component mgsinθmg \sin \theta acts parallel to inclined surface.

Flashcard 18: What is the resultant force of 10 N and 15 N acting in the same direction?

Answer: 25 N in the direction of both forces. Add forces in same direction: 10 N+15 N=25 N10 \text{ N} + 15 \text{ N} = 25 \text{ N}.

Flashcard 19: What happens to friction if the normal force is doubled?

Answer: Friction doubles. Friction is directly proportional to normal force.

Flashcard 20: Find the value of the normal force on an inclined plane.

Answer: N=mgcosθN = mg \, \cos \theta. Normal force is weight component perpendicular to inclined plane.

Flashcard 21: Find the value of the normal force on an inclined plane.

Answer: N=mgcosθN = mg \, \cos \theta. Normal force is weight component perpendicular to inclined plane.

Flashcard 22: Identify the force that opposes the relative motion of two surfaces.

Answer: Frictional force. Kinetic and static friction resist sliding between contact surfaces.

Flashcard 23: Which force always acts opposite to the direction of motion?

Answer: Frictional force. Friction always opposes relative motion between surfaces in contact.

Flashcard 24: What is the resultant force of 10 N and 15 N acting in the same direction?

Answer: 25 N in the direction of both forces. Add forces in same direction: 10 N+15 N=25 N10 \text{ N} + 15 \text{ N} = 25 \text{ N}.

Flashcard 25: What is the term for the force causing an object to move in a circle?

Answer: Centripetal force. The net inward force required for circular motion.

Flashcard 26: What is the formula for gravitational force between two masses?

Answer: F=Gm1m2r2F = G \frac{m_1 m_2}{r^2}. Newton's law of universal gravitation relates force to masses and distance squared.

Flashcard 27: Calculate the net force on an object with 8 N right and 3 N left.

Answer: 5 N to the right. Net force: 8 N3 N=5 N8 \text{ N} - 3 \text{ N} = 5 \text{ N} rightward.

Flashcard 28: State Newton's Third Law of Motion.

Answer: For every action, there is an equal and opposite reaction. Forces always occur in equal and opposite pairs between objects.

Flashcard 29: Which force is responsible for an object sliding down an inclined plane?

Answer: Component of gravitational force parallel to the plane. Component mgsinθmg \sin \theta acts parallel to inclined surface.

Flashcard 30: Calculate the friction force for μk=0.3μ_k = 0.3 and N=50 NN = 50 \text{ N}.

Answer: fk=15 Nf_k = 15 \text{ N}. Using fk=μkN=0.3×50=15 Nf_k = \text{μ}_k N = 0.3 \times 50 = 15 \text{ N}.

Flashcard 31: Identify the force that opposes the relative motion of two surfaces.

Answer: Frictional force. Kinetic and static friction resist sliding between contact surfaces.

Flashcard 32: Which force always acts opposite to the direction of motion?

Answer: Frictional force. Friction always opposes relative motion between surfaces in contact.

Flashcard 33: State Newton's Third Law of Motion.

Answer: For every action, there is an equal and opposite reaction. Forces always occur in equal and opposite pairs between objects.

Flashcard 34: How does increasing mass affect gravitational force?

Answer: Gravitational force increases. Force is proportional to both masses in gravitational equation.

Flashcard 35: Which force acts on a satellite orbiting Earth?

Answer: Gravitational force. Earth's gravity provides centripetal force for orbital motion.

Flashcard 36: Which force acts on a hanging object in a stationary elevator?

Answer: Tension equal to weight. Tension balances weight when elevator moves at constant velocity.

Flashcard 37: Find the normal force on a 10 kg object on a flat surface.

Answer: N=98 NN = 98 \text{ N}. Normal force equals weight on horizontal surface: N=mgN = mg.

Flashcard 38: What is the formula for gravitational force between two masses?

Answer: F=Gm1m2r2F = G \frac{m_1 m_2}{r^2}. Newton's law of universal gravitation relates force to masses and distance squared.

Flashcard 39: What is the effect on net force if two equal forces act in opposite directions?

Answer: Net force is 0 N. Equal and opposite forces cancel completely.

Flashcard 40: Identify the force exerted by a surface perpendicular to the object.

Answer: Normal force. Normal force acts perpendicular to contact surfaces, preventing penetration.

Flashcard 41: What is the formula for centripetal force?

Answer: Fc=mv2rF_c = \frac{mv^2}{r}. Force needed to maintain circular motion at constant speed.

Flashcard 42: Choose the correct formula for tension in a rope with mass mm accelerating upward.

Answer: T=m(g+a)T = m(g + a). Tension must overcome weight plus provide upward acceleration force.

Flashcard 43: Identify the force that balances the weight of a stationary object on a table.

Answer: Normal force. Normal force provides upward support equal to object's weight.

Flashcard 44: Which force acts on a hanging object in a stationary elevator?

Answer: Tension equal to weight. Tension balances weight when elevator moves at constant velocity.

Flashcard 45: Determine the tension in a rope holding a 5 kg mass at rest.

Answer: T=49 NT = 49 \text{ N}. At rest, tension equals weight: T=mg=5×9.8=49 NT = mg = 5 \times 9.8 = 49 \text{ N}.

Flashcard 46: What is the formula for centripetal force?

Answer: Fc=mv2rF_c = \frac{mv^2}{r}. Force needed to maintain circular motion at constant speed.

Flashcard 47: Identify the force that balances the weight of a stationary object on a table.

Answer: Normal force. Normal force provides upward support equal to object's weight.

Flashcard 48: State the formula for Newton's Second Law of Motion.

Answer: F=maF = ma. Force equals mass times acceleration; fundamental dynamics equation.

Flashcard 49: What is the formula for calculating weight?

Answer: W=mgW = mg. Weight equals mass times gravitational acceleration (g=9.8 m/s2g = 9.8 \text{ m/s}^2).

Flashcard 50: What is the formula for static frictional force?

Answer: fsμsNf_s \, \leq \, \text{μ}_s N. Static friction can vary up to maximum value μsN\text{μ}_s N.

Flashcard 51: What is the formula for restoring force in a spring?

Answer: F=kxF = -kx. Hooke's law; negative sign indicates force opposes displacement.

Flashcard 52: What is the formula for static frictional force?

Answer: fsμsNf_s \, \leq \, \mu_s N. Static friction can vary up to maximum value μsN\mu_s N.

Flashcard 53: What is the direction of the net force on an object moving in a circle?

Answer: Towards the center of the circle. Centripetal force always points toward the center of circular motion.

Flashcard 54: Identify the main force that acts at a distance without contact.

Answer: Gravitational force. Gravity acts between all masses without physical contact.

Flashcard 55: What happens to friction if the normal force is doubled?

Answer: Friction doubles. Friction is directly proportional to normal force.

Flashcard 56: What is the formula for kinetic frictional force?

Answer: fk=μkNf_k = \mu_k N. Kinetic friction equals coefficient times normal force.

Flashcard 57: What is the effect on acceleration if net force is doubled?

Answer: Acceleration doubles. From F=maF = ma; doubling force doubles acceleration for constant mass.

Flashcard 58: Determine the tension in a rope holding a 5 kg mass at rest.

Answer: T=49 NT = 49 \text{ N}. At rest, tension equals weight: T=mg=5×9.8=49 NT = mg = 5 \times 9.8 = 49 \text{ N}.

Flashcard 59: Identify the net force on an object in equilibrium.

Answer: Net force is 0 N. In equilibrium, all forces cancel out, resulting in zero net force.

Flashcard 60: What is the unit of force in the International System of Units?

Answer: Newton (N). Named after Isaac Newton; equivalent to kgm/s2\text{kg} \cdot \text{m/s}^2.

Flashcard 61: What is the formula for net force on an inclined plane?

Answer: Fnet=mgsinθfF_{\text{net}} = mg \, \sin \theta - f. Gravity component minus friction determines net acceleration down plane.

Flashcard 62: Calculate the friction force for μk=0.3μ_k = 0.3 and N=50 NN = 50 \text{ N}.

Answer: fk=15 Nf_k = 15 \text{ N}. Using fk=μkN=0.3×50=15 Nf_k = \mu_k N = 0.3 \times 50 = 15 \text{ N}.

Flashcard 63: Identify the force exerted by a surface perpendicular to the object.

Answer: Normal force. Normal force acts perpendicular to contact surfaces, preventing penetration.

Flashcard 64: What is the formula for net force on an inclined plane?

Answer: Fnet=mgsinθfF_{\text{net}} = mg \, \sin \theta - f. Gravity component minus friction determines net acceleration down plane.

Flashcard 65: What is the relationship between acceleration and net force?

Answer: Directly proportional. From Newton's second law: a=Fma = \frac{F}{m}.

Flashcard 66: State the relationship between mass and weight.

Answer: Weight is mass times gravitational acceleration. Mass is intrinsic; weight depends on gravitational field strength.

Flashcard 67: State the relationship between mass and weight.

Answer: Weight is mass times gravitational acceleration. Mass is intrinsic; weight depends on gravitational field strength.

Flashcard 68: Find the normal force on a 10 kg object on a flat surface.

Answer: N=98 NN = 98 \text{ N}. Normal force equals weight on horizontal surface: N=mgN = mg.

Flashcard 69: What is the term for the force causing an object to move in a circle?

Answer: Centripetal force. The net inward force required for circular motion.

Flashcard 70: Which force acts on a satellite orbiting Earth?

Answer: Gravitational force. Earth's gravity provides centripetal force for orbital motion.

Flashcard 71: What is the formula for restoring force in a spring?

Answer: F=kxF = -kx. Hooke's law; negative sign indicates force opposes displacement.

Flashcard 72: Identify the net force on an object in equilibrium.

Answer: Net force is 0 N. In equilibrium, all forces cancel out, resulting in zero net force.

Flashcard 73: Calculate the gravitational force on a 10 kg mass on Earth's surface.

Answer: F=98 NF = 98 \text{ N}. Using W=mg=10×9.8=98 NW = mg = 10 \times 9.8 = 98 \text{ N}.

Flashcard 74: What is the formula for calculating weight?

Answer: W=mgW = mg. Weight equals mass times gravitational acceleration (g=9.8 m/s2g = 9.8 \text{ m/s}^2).

Flashcard 75: Identify the force that acts between two charged objects.

Answer: Electrostatic force. Coulomb force between charges; can be attractive or repulsive.

Flashcard 76: Find the net force if an object has forces of 5 N and 3 N in opposite directions.

Answer: Net force is 2 N in the direction of the larger force. Subtract opposing forces: 5 N3 N=2 N5 \text{ N} - 3 \text{ N} = 2 \text{ N}.

Flashcard 77: What is the relationship between acceleration and net force?

Answer: Directly proportional. From Newton's second law: a=Fma = \frac{F}{m}.