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This deck focuses on Rotational Inertia, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Study Rotational Inertia in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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What is the rotational inertia of a hoop about a tangent axis?
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I=2mr2. Uses parallel axis theorem: I=Icenter+md2.
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This deck focuses on Rotational Inertia, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: I=2mr2. Uses parallel axis theorem: I=Icenter+md2.
Answer: Use I=m1r12+m2r22. Apply point mass formula to each mass separately.
Answer: I=mr2. Cylindrical shell with all mass at outer radius.
Answer: τ=I×β. Rotational analog of Newton's second law (F=ma).
Answer: Increases rotational inertia. Rotational inertia is directly proportional to mass.
Answer: Increases rotational inertia. Rotational inertia is directly proportional to mass.
Answer: I=32mr2. Thin shell with all mass at surface radius.
Answer: I=Icm+md2. Relates inertia about any axis to center of mass axis.
Answer: I=57mr2. Uses parallel axis theorem with d=r.
Answer: I=31mL2. Rod rotating about perpendicular axis at one end.
Answer: Kilogram meter squared (kg×m2). Derived from [M][L]2 dimensional analysis.
Answer: Higher inertia, lower angular velocity. Conservation of angular momentum: L=Iω=constant.
Answer: I=sum of miri2. Add up mr2 for each individual mass element.
Answer: Quadruples rotational inertia. Radius appears squared in inertia formulas.
Answer: Sum of individual inertias. Add rotational inertias of each component part.
Answer: Distribution of mass relative to axis. Mass farther from axis increases rotational inertia.
Answer: I=mr2. All mass concentrated at radius r from center.
Answer: Higher inertia, more torque needed. From τ=Iα: larger I needs larger τ.
Answer: Quadruples rotational inertia. Radius appears squared in inertia formulas.
Answer: I=2mr2. Uses parallel axis theorem: I=Icenter+md2.
Answer: Higher inertia, lower angular velocity. Conservation of angular momentum: L=Iω=constant.
Answer: Increases rotational inertia. Inertia depends on r2, so larger radius increases it.
Answer: I=32mr2. Hollow spherical shell about any diameter through center.
Answer: I=mr2. All mass concentrated at radius r from center.
Answer: I=52mr2. Standard formula for uniform solid sphere rotating about center.
Answer: I=Icm+md2. Relates inertia about any axis to center of mass axis.
Answer: I=31mL2. Rod rotating about perpendicular axis at one end.
Answer: Distribution of mass relative to axis. Mass farther from axis increases rotational inertia.
Answer: Kilogram meter squared (kg×m2). Derived from [M][L]2 dimensional analysis.
Answer: Further mass increases inertia. Mass farther from rotation axis contributes more.
Answer: I=mr2. All mass concentrated at distance r from axis.
Answer: I=41mr2. Disc rotating about axis through its diameter.
Answer: I=21mr2. Hoop rotating about perpendicular axis through diameter.
Answer: τ=I×β. Rotational analog of Newton's second law (F=ma).
Answer: Further mass increases inertia. Mass farther from rotation axis contributes more.
Answer: Use I=m1r12+m2r22. Treat each mass as point mass at its distance.
Answer: Symbol: I. Standard physics notation for moment of inertia.
Answer: I=57mr2. Uses parallel axis theorem with d=r.
Answer: I=21mr2. Standard formula for uniform solid cylinder about its axis.
Answer: I=21mr2. Flat circular disc rotating about its center axis.
Answer: I=sum of miri2. Add up mr2 for each individual mass element.
Answer: I=23mr2. Uses parallel axis theorem: 21mr2+mr2.
Answer: I=21mr2. Ring rotating about axis through its diameter.
Answer: I=52mr2. Standard formula for uniform solid sphere rotating about center.
Answer: I=mr2. Cylindrical shell with all mass at outer radius.
Answer: I=21mr2. Ring rotating about axis through its diameter.
Answer: Sum of individual inertias. Add rotational inertias of each component part.
Answer: Resistance to angular acceleration. Measures how hard it is to change angular motion.
Answer: Increases rotational inertia. Inertia depends on r2, so larger radius increases it.
Answer: Use I=m1r12+m2r22. Treat each mass as point mass at its distance.
Answer: I=52mr2. Same as solid sphere about any diameter through center.
Answer: Symbol: I. Standard physics notation for moment of inertia.
Answer: I=52mr2. Same as solid sphere about any diameter through center.
Answer: Use I=m1r12+m2r22. Apply point mass formula to each mass separately.
Answer: Resistance to angular acceleration. Measures how hard it is to change angular motion.
Answer: I=21mr2. Standard formula for uniform solid cylinder about its axis.
Answer: I=32mr2. Hollow spherical shell about any diameter through center.
Answer: I=21mr2. Hoop rotating about perpendicular axis through diameter.
Answer: I=121mL2. For uniform rod rotating perpendicular to length at center.
Answer: I=23mr2. Uses parallel axis theorem: 21mr2+mr2.
Answer: I=121mL2. For uniform rod rotating perpendicular to length at center.
Answer: I=mr2. All mass concentrated at distance r from axis.