AP Physics 1 Flashcards: Rotational Kinematics

Study Rotational Kinematics in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 1

Rotational Kinematics

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QUESTION
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Find the angular acceleration for a 1010 kg disk with 11 m radius and 55 N·m torque.

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ANSWER

α=1.25\text{α} = 1.25 rad/s². Use τ=Iα\tau = I\alpha where I=12mr2I = \frac{1}{2}mr^2 for disk.

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This deck focuses on Rotational Kinematics, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

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Flashcard 1: Find the angular acceleration for a 1010 kg disk with 11 m radius and 55 N·m torque.

Answer: α=1.25\text{α} = 1.25 rad/s². Use τ=Iα\tau = I\alpha where I=12mr2I = \frac{1}{2}mr^2 for disk.

Flashcard 2: What is the formula for rotational work done by a torque through an angle?

Answer: W=τθW = \tau\theta. Work done equals torque times angular displacement.

Flashcard 3: Determine rotational kinetic energy of a 22 kg·m² disk rotating at 44 rad/s.

Answer: K=16K = 16 J. Use K=12Iω2K = \frac{1}{2}I\omega^2 formula.

Flashcard 4: State the relationship between torque and angular momentum change.

Answer: τ=dLdt\tau = \frac{dL}{dt}. Torque equals the time rate of change of angular momentum.

Flashcard 5: State the relationship between linear velocity (vv) and angular velocity (ω\text{ω}).

Answer: v=rωv = r\text{ω}. Linear velocity equals radius times angular velocity.

Flashcard 6: What is the new angular velocity if a 22 kg·m² object increases its moment of inertia to 44 kg·m²?

Answer: ωnew=12ωinitial\text{ω}_{\text{new}} = \frac{1}{2}\text{ω}_{\text{initial}}. Conservation of angular momentum: I1ω1=I2ω2I_1\omega_1 = I_2\omega_2.

Flashcard 7: Identify the formula for angular velocity in terms of angular displacement and time.

Answer: Angular velocity=θt\text{Angular velocity} = \frac{\theta}{t}. Angular velocity equals angular displacement divided by time.

Flashcard 8: What is the unit of angular velocity in the International System of Units (SI)?

Answer: Radians per second (rad/s). Standard SI unit for rotational motion rate.

Flashcard 9: Which quantity measures an object's resistance to changes in rotational motion?

Answer: Moment of Inertia. Inertia determines how hard it is to change rotation.

Flashcard 10: What is the unit of angular velocity in the International System of Units (SI)?

Answer: Radians per second (rad/s). Standard SI unit for rotational motion rate.

Flashcard 11: Find the centripetal acceleration of a point on a wheel 0.20.2 m from the center, rotating at 1010 rad/s.

Answer: ac=20a_c = 20 m/s². Use ac=rω2a_c = r\omega^2 formula.

Flashcard 12: What is the relationship between frequency (ff) and period (TT) of rotation?

Answer: f=1Tf = \frac{1}{T}. Frequency is the reciprocal of period.

Flashcard 13: State the relationship between torque and angular momentum change.

Answer: τ=dLdt\tau = \frac{dL}{dt}. Torque equals the time rate of change of angular momentum.

Flashcard 14: What is the formula for the torque (τ\tau) acting on a rotating object?

Answer: τ=rFsin(θ)\tau = rF\text{sin}(\theta). Torque depends on force, distance, and angle.

Flashcard 15: What is the relationship between centripetal acceleration and angular velocity?

Answer: ac=rω2a_c = r \omega^2. Alternative form using angular velocity and radius.

Flashcard 16: Calculate the moment of inertia of a 22 kg mass at 33 m from the axis.

Answer: I=18I = 18 kg·m². Use I=mr2I = mr^2 with given mass and distance.

Flashcard 17: What is the relationship between frequency (ff) and period (TT) of rotation?

Answer: f=1Tf = \frac{1}{T}. Frequency is the reciprocal of period.

Flashcard 18: Identify the formula relating tangential speed and angular speed.

Answer: vtangential=rωv_{\text{tangential}} = r \omega. Tangential speed at distance rr from rotation axis.

Flashcard 19: What is the term for the rate of change of angular velocity?

Answer: Angular Acceleration. The rate of change of angular velocity.

Flashcard 20: What is the new angular velocity if a 22 kg·m² object increases its moment of inertia to 44 kg·m²?

Answer: ωnew=12ωinitial\text{ω}_{\text{new}} = \frac{1}{2}\text{ω}_{\text{initial}}. Conservation of angular momentum: I1ω1=I2ω2I_1\omega_1 = I_2\omega_2.

Flashcard 21: What is the linear displacement of a point 11 m from the axis after a 22 rad rotation?

Answer: s=2s = 2 m. Arc length equals radius times angle in radians.

Flashcard 22: Identify the formula for angular velocity in terms of angular displacement and time.

Answer: Angular velocity=θt\text{Angular velocity} = \frac{\theta}{t}. Angular velocity equals angular displacement divided by time.

Flashcard 23: What is the formula for angular momentum (LL) of a rotating object?

Answer: L=IωL = I\text{ω}. Angular momentum equals moment of inertia times angular velocity.

Flashcard 24: What is the rotational analog of mass in linear motion?

Answer: Moment of Inertia. Rotational inertia measures resistance to angular acceleration.

Flashcard 25: What is the formula for rotational work done by a torque through an angle?

Answer: W=τθW = \tau\theta. Work done equals torque times angular displacement.

Flashcard 26: State the formula for the period of a rotating object in terms of angular velocity.

Answer: T=2πωT = \frac{2\text{π}}{\text{ω}}. Period is 2π2\pi divided by angular velocity.

Flashcard 27: What is the rotational analog of mass in linear motion?

Answer: Moment of Inertia. Rotational inertia measures resistance to angular acceleration.

Flashcard 28: Identify the angular displacement if a wheel turns 44 revolutions.

Answer: θ=8π\theta = 8\text{π} rad. One revolution equals 2π2\pi radians.

Flashcard 29: Calculate the angular momentum of a 33 kg·m² object rotating at 1010 rad/s.

Answer: L=30L = 30 kg·m²/s. Angular momentum equals II times ω\omega.

Flashcard 30: State the equation of rotational kinetic energy.

Answer: K=12Iω2K = \frac{1}{2}I\text{ω}^2. Rotational analog of linear kinetic energy.

Flashcard 31: State the formula for the centripetal force required for circular motion.

Answer: Fc=mv2rF_c = \frac{mv^2}{r}. Force needed to maintain circular motion.

Flashcard 32: What is the relationship between centripetal acceleration and angular velocity?

Answer: ac=rω2a_c = r \omega^2. Alternative form using angular velocity and radius.

Flashcard 33: State the relationship between linear displacement (ss) and angular displacement (θ\theta).

Answer: s=rθs = r\theta. Arc length equals radius times angular displacement.

Flashcard 34: State the formula for the period of a rotating object in terms of angular velocity.

Answer: T=2πωT = \frac{2\text{π}}{\text{ω}}. Period is 2π2\pi divided by angular velocity.

Flashcard 35: Identify the conservation law applicable to a closed system with no external torques.

Answer: Conservation of Angular Momentum. Angular momentum remains constant without external torques.

Flashcard 36: Which principle relates torque to angular acceleration?

Answer: Newton's Second Law for Rotation. States that net torque equals IαI\alpha.

Flashcard 37: What is the formula for angular acceleration in terms of change in angular velocity and time?

Answer: Angular acceleration=Δωt\text{Angular acceleration} = \frac{\Delta \omega}{t}. Rate of change of angular velocity over time.

Flashcard 38: Identify the term for the rate of change of angular displacement.

Answer: Angular Velocity. The rate of change of angular position.

Flashcard 39: Identify the angular displacement if a wheel turns 44 revolutions.

Answer: θ=8π\theta = 8\text{π} rad. One revolution equals 2π2\pi radians.

Flashcard 40: State the formula for angular displacement in terms of initial and final angle.

Answer: θ=θfθi\theta = \theta_f - \theta_i. Angular displacement is the change in angular position.

Flashcard 41: What is the term for the rate of change of angular velocity?

Answer: Angular Acceleration. The rate of change of angular velocity.

Flashcard 42: Identify the formula for centripetal acceleration in terms of velocity and radius.

Answer: ac=v2ra_c = \frac{v^2}{r}. Acceleration directed toward the center of circular motion.

Flashcard 43: State the unit of angular acceleration in the International System of Units (SI).

Answer: Radians per second squared (rad/s²). Standard SI unit for rotational acceleration.

Flashcard 44: Calculate the period of rotation for an object rotating at 55 rad/s.

Answer: T=2π5T = \frac{2\text{π}}{5} s. Period equals 2π2\pi divided by angular velocity.

Flashcard 45: What is the formula for angular momentum (LL) of a rotating object?

Answer: L=IωL = I\text{ω}. Angular momentum equals moment of inertia times angular velocity.

Flashcard 46: Calculate the period of rotation for an object rotating at 55 rad/s.

Answer: T=2π5T = \frac{2\text{π}}{5} s. Period equals 2π2\pi divided by angular velocity.

Flashcard 47: State the formula for the centripetal force required for circular motion.

Answer: Fc=mv2rF_c = \frac{mv^2}{r}. Force needed to maintain circular motion.

Flashcard 48: Identify the tangential speed of a point 22 m from the center of a wheel rotating at 33 rad/s.

Answer: v=6v = 6 m/s. Use v=rωv = r\omega relationship.

Flashcard 49: Calculate the angular momentum of a 33 kg·m² object rotating at 1010 rad/s.

Answer: L=30L = 30 kg·m²/s. Angular momentum equals II times ω\omega.

Flashcard 50: What is the formula for angular acceleration in terms of change in angular velocity and time?

Answer: Angular acceleration=Δωt\text{Angular acceleration} = \frac{\text{Δω}}{t}. Rate of change of angular velocity over time.

Flashcard 51: Find the angular velocity if a wheel rotates 180180 degrees in 22 seconds.

Answer: ω=1.57\text{ω} = 1.57 rad/s. Convert 180°180° to π\pi rad, then divide by time.

Flashcard 52: Determine the torque if a 55 N force is applied 0.50.5 m from the pivot.

Answer: τ=2.5\tau = 2.5 N·m. Torque equals force times perpendicular distance.

Flashcard 53: State the relationship between linear velocity (vv) and angular velocity (ω\text{ω}).

Answer: v=rωv = r\text{ω}. Linear velocity equals radius times angular velocity.

Flashcard 54: Identify the term for the rate of change of angular displacement.

Answer: Angular Velocity. The rate of change of angular position.

Flashcard 55: State the equation of rotational kinetic energy.

Answer: K=12Iω2K = \frac{1}{2}I\text{ω}^2. Rotational analog of linear kinetic energy.

Flashcard 56: Identify the conservation law applicable to a closed system with no external torques.

Answer: Conservation of Angular Momentum. Angular momentum remains constant without external torques.

Flashcard 57: Identify the formula for centripetal acceleration in terms of velocity and radius.

Answer: ac=v2ra_c = \frac{v^2}{r}. Acceleration directed toward the center of circular motion.

Flashcard 58: Identify the formula for moment of inertia for a point mass.

Answer: I=mr2I = mr^2. Moment of inertia for a point mass at distance rr.

Flashcard 59: State the unit of angular acceleration in the International System of Units (SI).

Answer: Radians per second squared (rad/s²). Standard SI unit for rotational acceleration.

Flashcard 60: Find the angular acceleration for a 1010 kg disk with 11 m radius and 55 N·m torque.

Answer: α=1.25\text{α} = 1.25 rad/s². Use τ=Iα\tau = I\alpha where I=12mr2I = \frac{1}{2}mr^2 for disk.

Flashcard 61: Identify the formula relating tangential speed and angular speed.

Answer: vtangential=rωv_{\text{tangential}} = r\text{ω}. Tangential speed at distance rr from rotation axis.

Flashcard 62: Calculate the moment of inertia of a 22 kg mass at 33 m from the axis.

Answer: I=18I = 18 kg·m². Use I=mr2I = mr^2 with given mass and distance.

Flashcard 63: Determine the frequency of a rotating object with a period of 0.50.5 seconds.

Answer: f=2f = 2 Hz. Frequency equals one divided by period.