Study Vectors And Motion In Two Dimensions in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: State the formula for angular displacement. Answer: θ = ω t \theta = \omega t θ = ω t . Angle equals rate times time.
Flashcard 2: State the formula for the magnitude of a vector ( x , y ) (x, y) ( x , y ) . Answer: Magnitude = x 2 + y 2 \text{Magnitude} = \sqrt{x^2 + y^2} Magnitude = x 2 + y 2 . Pythagorean theorem for vector length.
Flashcard 3: What is the horizontal component of velocity for a projectile at launch speed v v v and angle θ \theta θ ? Answer: v cos θ v \cos \theta v cos θ . Horizontal component stays constant.
Flashcard 4: What is the formula for the cross product magnitude of ( a 1 , b 1 ) (a_1, b_1) ( a 1 , b 1 ) and ( a 2 , b 2 ) (a_2, b_2) ( a 2 , b 2 ) ? Answer: ∣ a 1 b 2 − a 2 b 1 ∣ |a_1 b_2 - a_2 b_1| ∣ a 1 b 2 − a 2 b 1 ∣ . 2D cross product magnitude formula.
Flashcard 5: What is the resultant vector of ( 3 , 4 ) (3, 4) ( 3 , 4 ) and ( 1 , 2 ) (1, 2) ( 1 , 2 ) ? Answer: ( 4 , 6 ) (4, 6) ( 4 , 6 ) . Add corresponding components.
Flashcard 6: Identify the unit vector in the direction of ( 6 , 8 ) (6, 8) ( 6 , 8 ) . Answer: ( 0.6 , 0.8 ) (0.6, 0.8) ( 0.6 , 0.8 ) . Divide by magnitude 6 2 + 8 2 = 10 \sqrt{6^2 + 8^2} = 10 6 2 + 8 2 = 10 .
Flashcard 7: What is the effect of air resistance on projectile motion? Answer: It decreases range and height. Air drag opposes motion.
Flashcard 8: What is the definition of a vector quantity? Answer: A quantity with both magnitude and direction. Combines size and direction info.
Flashcard 9: State the formula for the maximum height of a projectile. Answer: h = v 2 sin 2 θ 2 g h = \frac{v^2 \sin^2 \theta}{2g} h = 2 g v 2 s i n 2 θ . From energy or kinematics.
Flashcard 10: What is the direction of centripetal force in circular motion? Answer: Toward the center of the circle. Keeps object in circular path.
Flashcard 11: State the formula for centripetal acceleration. Answer: a c = v 2 r a_c = \frac{v^2}{r} a c = r v 2 . Acceleration toward center.
Flashcard 12: What is the relationship between period and frequency? Answer: T = 1 f T = \frac{1}{f} T = f 1 . Period and frequency are reciprocals.
Flashcard 13: What variable represents angular velocity? Answer: ω \omega ω . Greek omega represents rotation rate.
Flashcard 14: Identify the unit of angular acceleration. Answer: rad/s 2 \text{rad/s}^2 rad/s 2 . Angular acceleration measured in radians.
Flashcard 15: What is the range formula for a projectile launched at v v v and angle θ \theta θ ? Answer: R = v 2 sin 2 θ g R = \frac{v^2 \sin 2\theta}{g} R = g v 2 s i n 2 θ . Uses sin ( 2 θ ) \sin(2\theta) sin ( 2 θ ) identity.
Flashcard 16: Which factor remains constant in a projectile's horizontal motion? Answer: Horizontal velocity. No horizontal acceleration exists.
Flashcard 17: What is the angle between vectors ( 1 , 0 ) (1, 0) ( 1 , 0 ) and ( 0 , 1 ) (0, 1) ( 0 , 1 ) ? Answer: 90 ∘ 90^{\circ} 9 0 ∘ . Unit vectors along axes are perpendicular.
Flashcard 18: What is the two-dimensional motion with constant acceleration called? Answer: Projectile motion. Motion under gravity in two dimensions.
Flashcard 19: Define the term 'scalar quantity'. Answer: A quantity with magnitude only. No directional information included.
Flashcard 20: Define the term 'scalar quantity'. Answer: A quantity with magnitude only. No directional information included.
Flashcard 21: What is the cross product of vectors used to find? Answer: Vector perpendicular to both vectors. Cross product creates perpendicular vector.
Flashcard 22: What is the formula for the gravitational potential energy of an object? Answer: U = m g h U = mgh U = m g h . Height-dependent gravitational energy.
Flashcard 23: Which operation combines two vectors to form a resultant vector? Answer: Vector addition. Forms resultant from two vectors.
Flashcard 24: Which factor remains constant in a projectile's horizontal motion? Answer: Horizontal velocity. No horizontal acceleration exists.
Flashcard 25: Identify the velocity of a projectile at its highest point. Answer: Zero vertical velocity. Instantaneously stops rising.
Flashcard 26: What is the scalar product used for in vector calculations? Answer: Calculating work done. Dot product gives work value.
Flashcard 27: What is the two-dimensional motion with constant acceleration called? Answer: Projectile motion. Motion under gravity in two dimensions.
Flashcard 28: State the component form of vector A \textbf{A} A with magnitude 5 5 5 at 30 ∘ 30^{\circ} 3 0 ∘ . Answer: ( 4.33 , 2.5 ) (4.33, 2.5) ( 4.33 , 2.5 ) . Use x = 5 cos ( 30 ° ) x = 5\cos(30°) x = 5 cos ( 30° ) , y = 5 sin ( 30 ° ) y = 5\sin(30°) y = 5 sin ( 30° ) .
Flashcard 29: State the formula for the dot product of vectors ( a 1 , b 1 ) (a_1, b_1) ( a 1 , b 1 ) and ( a 2 , b 2 ) (a_2, b_2) ( a 2 , b 2 ) . Answer: a 1 a 2 + b 1 b 2 a_1 a_2 + b_1 b_2 a 1 a 2 + b 1 b 2 . Multiply corresponding components and sum.
Flashcard 30: What is the formula for the gravitational potential energy of an object? Answer: U = m g h U = mgh U = m g h . Height-dependent gravitational energy.
Flashcard 31: State the formula for the dot product of vectors ( a 1 , b 1 ) (a_1, b_1) ( a 1 , b 1 ) and ( a 2 , b 2 ) (a_2, b_2) ( a 2 , b 2 ) . Answer: a 1 a 2 + b 1 b 2 a_1 a_2 + b_1 b_2 a 1 a 2 + b 1 b 2 . Multiply corresponding components and sum.
Flashcard 32: Identify the unit vector in the direction of ( 6 , 8 ) (6, 8) ( 6 , 8 ) . Answer: ( 0.6 , 0.8 ) (0.6, 0.8) ( 0.6 , 0.8 ) . Divide by magnitude 6 2 + 8 2 = 10 \sqrt{6^2 + 8^2} = 10 6 2 + 8 2 = 10 .
Flashcard 33: What is the cross product of vectors used to find? Answer: Vector perpendicular to both vectors. Cross product creates perpendicular vector.
Flashcard 34: What is the dot product of vectors ( 2 , 3 ) (2, 3) ( 2 , 3 ) and ( 4 , − 1 ) (4, -1) ( 4 , − 1 ) ? Answer: 5 5 5 . ( 2 ) ( 4 ) + ( 3 ) ( − 1 ) = 8 − 3 = 5 (2)(4) + (3)(-1) = 8 - 3 = 5 ( 2 ) ( 4 ) + ( 3 ) ( − 1 ) = 8 − 3 = 5 .
Flashcard 35: Identify the velocity of a projectile at its highest point. Answer: Zero vertical velocity. Instantaneously stops rising.
Flashcard 36: Identify the vertical component of velocity for a projectile at launch speed v v v and angle θ \theta θ . Answer: v sin θ v \sin \theta v sin θ . Initial vertical velocity component.
Flashcard 37: State the formula for the maximum height of a projectile. Answer: h = v 2 sin 2 θ 2 g h = \frac{v^2 \sin^2 \theta}{2g} h = 2 g v 2 s i n 2 θ . From energy or kinematics.
Flashcard 38: Identify the unit of angular acceleration. Answer: rad/s 2 \text{rad/s}^2 rad/s 2 . Angular acceleration measured in radians.
Flashcard 39: What is the angle between vectors ( 1 , 0 ) (1, 0) ( 1 , 0 ) and ( 0 , 1 ) (0, 1) ( 0 , 1 ) ? Answer: 90 ∘ 90^{\circ} 9 0 ∘ . Unit vectors along axes are perpendicular.
Flashcard 40: What is the projection of vector A \textbf{A} A onto vector B \textbf{B} B ? Answer: A ⋅ B ∣ ∣ B ∣ ∣ \frac{\textbf{A} \cdot \textbf{B}}{||\textbf{B}||} ∣∣ B ∣∣ A ⋅ B . Component of A along B direction.
Flashcard 41: What is the formula for the velocity of an object in circular motion? Answer: v = r ω v = r \omega v = r ω . Links linear and angular motion.
Flashcard 42: What is the direction of centripetal force in circular motion? Answer: Toward the center of the circle. Keeps object in circular path.
Flashcard 43: What is the relationship between period and frequency? Answer: T = 1 f T = \frac{1}{f} T = f 1 . Period and frequency are reciprocals.
Flashcard 44: What is the projection of vector A \textbf{A} A onto vector B \textbf{B} B ? Answer: A ⋅ B ∣ ∣ B ∣ ∣ \frac{\textbf{A} \cdot \textbf{B}}{||\textbf{B}||} ∣∣ B ∣∣ A ⋅ B . Component of A along B direction.
Flashcard 45: What is the resultant vector of ( 3 , 4 ) (3, 4) ( 3 , 4 ) and ( 1 , 2 ) (1, 2) ( 1 , 2 ) ? Answer: ( 4 , 6 ) (4, 6) ( 4 , 6 ) . Add corresponding components.
Flashcard 46: State the relationship between linear speed and angular speed. Answer: v = r ω v = r \omega v = r ω . Fundamental circular motion relationship.
Flashcard 47: What is the formula for the velocity of an object in circular motion? Answer: v = r ω v = r \omega v = r ω . Links linear and angular motion.
Flashcard 48: Identify the vertical component of velocity for a projectile at launch speed v v v and angle θ \theta θ . Answer: v sin θ v \sin \theta v sin θ . Initial vertical velocity component.
Flashcard 49: Find the vector sum of ( 1 , 2 , 3 ) (1, 2, 3) ( 1 , 2 , 3 ) and ( 4 , 5 , 6 ) (4, 5, 6) ( 4 , 5 , 6 ) . Answer: ( 5 , 7 , 9 ) (5, 7, 9) ( 5 , 7 , 9 ) . Add components: ( 1 + 4 , 2 + 5 , 3 + 6 ) (1+4, 2+5, 3+6) ( 1 + 4 , 2 + 5 , 3 + 6 ) .
Flashcard 50: State the component form of vector A \textbf{A} A with magnitude 5 5 5 at 30 ∘ 30^{\circ} 3 0 ∘ . Answer: ( 4.33 , 2.5 ) (4.33, 2.5) ( 4.33 , 2.5 ) . Use x = 5 cos ( 30 ° ) x = 5\cos(30°) x = 5 cos ( 30° ) , y = 5 sin ( 30 ° ) y = 5\sin(30°) y = 5 sin ( 30° ) .
Flashcard 51: What does the magnitude of the cross product represent? Answer: Area of the parallelogram formed. Geometric interpretation of cross product.
Flashcard 52: What is the formula for the cross product magnitude of ( a 1 , b 1 ) (a_1, b_1) ( a 1 , b 1 ) and ( a 2 , b 2 ) (a_2, b_2) ( a 2 , b 2 ) ? Answer: ∣ a 1 b 2 − a 2 b 1 ∣ |a_1 b_2 - a_2 b_1| ∣ a 1 b 2 − a 2 b 1 ∣ . 2D cross product magnitude formula.
Flashcard 53: What is the range formula for a projectile launched at v v v and angle θ \theta θ ? Answer: R = v 2 sin 2 θ g R = \frac{v^2 \sin 2\theta}{g} R = g v 2 s i n 2 θ . Uses sin ( 2 θ ) \sin(2\theta) sin ( 2 θ ) identity.
Flashcard 54: State the relationship between linear speed and angular speed. Answer: v = r ω v = r \omega v = r ω . Fundamental circular motion relationship.
Flashcard 55: What is the formula for work done by a force in the direction of displacement? Answer: W = F d cos θ W = Fd \cos \theta W = F d cos θ . Force component in displacement direction.
Flashcard 56: What is the formula for work done by a force in the direction of displacement? Answer: W = F d cos θ W = Fd \cos \theta W = F d cos θ . Force component in displacement direction.
Flashcard 57: What is the acceleration due to gravity in projectile motion? Answer: 9.8 m/s 2 9.8 \text{ m/s}^2 9.8 m/s 2 downward. Standard gravity near Earth's surface.
Flashcard 58: Which operation combines two vectors to form a resultant vector? Answer: Vector addition. Forms resultant from two vectors.
Flashcard 59: What is the scalar product used for in vector calculations? Answer: Calculating work done. Dot product gives work value.
Flashcard 60: What is the effect of air resistance on projectile motion? Answer: It decreases range and height. Air drag opposes motion.
Flashcard 61: Find the vector sum of ( 1 , 2 , 3 ) (1, 2, 3) ( 1 , 2 , 3 ) and ( 4 , 5 , 6 ) (4, 5, 6) ( 4 , 5 , 6 ) . Answer: ( 5 , 7 , 9 ) (5, 7, 9) ( 5 , 7 , 9 ) . Add components: ( 1 + 4 , 2 + 5 , 3 + 6 ) (1+4, 2+5, 3+6) ( 1 + 4 , 2 + 5 , 3 + 6 ) .
Flashcard 62: What does the magnitude of the cross product represent? Answer: Area of the parallelogram formed. Geometric interpretation of cross product.
Flashcard 63: State the formula for the magnitude of a vector ( x , y ) (x, y) ( x , y ) . Answer: Magnitude = x 2 + y 2 \text{Magnitude} = \sqrt{x^2 + y^2} Magnitude = x 2 + y 2 . Pythagorean theorem for vector length.
Flashcard 64: What is the definition of a vector quantity? Answer: A quantity with both magnitude and direction. Combines size and direction info.
Flashcard 65: What is the acceleration due to gravity in projectile motion? Answer: 9.8 m/s 2 9.8 \text{ m/s}^2 9.8 m/s 2 downward. Standard gravity near Earth's surface.
Flashcard 66: What is the dot product of vectors ( 2 , 3 ) (2, 3) ( 2 , 3 ) and ( 4 , − 1 ) (4, -1) ( 4 , − 1 ) ? Answer: 5 5 5 . ( 2 ) ( 4 ) + ( 3 ) ( − 1 ) = 8 − 3 = 5 (2)(4) + (3)(-1) = 8 - 3 = 5 ( 2 ) ( 4 ) + ( 3 ) ( − 1 ) = 8 − 3 = 5 .
Flashcard 67: What condition indicates two vectors are perpendicular? Answer: Dot product equals zero. Orthogonal vectors have zero dot product.
Flashcard 68: State the formula for angular displacement. Answer: θ = ω t \theta = \omega t θ = ω t . Angle equals rate times time.
Flashcard 69: What variable represents angular velocity? Answer: ω \omega ω . Greek omega represents rotation rate.
Flashcard 70: What is the horizontal component of velocity for a projectile at launch speed v v v and angle θ \theta θ ? Answer: v cos θ v \cos \theta v cos θ . Horizontal component stays constant.
Flashcard 71: What condition indicates two vectors are perpendicular? Answer: Dot product equals zero. Orthogonal vectors have zero dot product.