AP Physics 2 Flashcards: Compound Direct Current Dc Circuits

What this deck covers

This deck focuses on Compound Direct Current Dc Circuits, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 2.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: Find voltage if $I = 3 \text{A}$ and $R = 5 \text{Ω}$.

Answer: $V = 15 \text{V}$. Apply Ohm's law: $V = 3 \times 5 = 15$.

Flashcard 2: What happens to total resistance when a resistor is added in parallel?

Answer: Total resistance decreases. Parallel paths reduce overall resistance.

Flashcard 3: What is the formula for power using voltage and resistance?

Answer: $P = \frac{V^2}{R}$. Derived from $P = VI$ and $I = \frac{V}{R}$.

Flashcard 4: What is the formula for power using current and resistance?

Answer: $P = I^2R$. Derived from $P = VI$ and $V = IR$.

Flashcard 5: What is the formula for equivalent resistance in series?

Answer: $R_{\text{eq}} = R_1 + R_2 + \text{...} + R_n$. Resistances add directly in series connections.

Flashcard 6: Calculate total resistance for $R_1 = 3 \text{Ω}$ and $R_2 = 6 \text{Ω}$ in parallel.

Answer: $R_{\text{eq}} = 2 \text{Ω}$. $\frac{1}{R_{eq}} = \frac{1}{3} + \frac{1}{6} = \frac{1}{2}$.

Flashcard 7: What is Kirchhoff's Current Law?

Answer: The total current entering a junction equals the total current leaving. Conservation of charge at circuit nodes.

Flashcard 8: Find power dissipated in a resistor if $I = 4 \text{A}$ and $R = 2 \text{Ω}$.

Answer: $P = 32 \text{W}$. Use $P = I^2R = 4^2 \times 2 = 32$.

Flashcard 9: Find energy used in 2 hours if power is $50 \text{W}$.

Answer: $E = 360,000 \text{J}$. $E = 50 \times 7200 = 360,000$ J.

Flashcard 10: What is the formula for equivalent resistance in series?

Answer: $R_{\text{eq}} = R_1 + R_2 + \text{...} + R_n$. Resistances add directly in series connections.

Flashcard 11: Calculate current if $Q = 10 \text{C}$ and $t = 5 \text{s}$.

Answer: $I = 2 \text{A}$. Apply $I = \frac{Q}{t} = \frac{10}{5} = 2$.

Flashcard 12: What is the formula for power using voltage and resistance?

Answer: $P = \frac{V^2}{R}$. Derived from $P = VI$ and $I = \frac{V}{R}$.

Flashcard 13: Define electrical power in terms of voltage and current.

Answer: $P = VI$. Power is the product of voltage and current.

Flashcard 14: What is the formula for voltage across a capacitor?

Answer: $V = \frac{Q}{C}$. Voltage depends on stored charge and capacitance.

Flashcard 15: What is Kirchhoff's Voltage Law?

Answer: The sum of EMFs equals the sum of voltage drops in a loop. Conservation of energy in closed loops.

Flashcard 16: What is the relationship between voltage, current, and resistance?

Answer: Ohm's Law: $V = IR$. Fundamental relationship in electrical circuits.

Flashcard 17: What is the formula for equivalent resistance in parallel?

Answer: $\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \text{...} + \frac{1}{R_n}$. Reciprocals add for parallel resistance calculations.

Flashcard 18: Calculate power if $I = 5 \text{A}$ and $R = 4 \text{Ω}$.

Answer: $P = 100 \text{W}$. Use $P = I^2R = 5^2 \times 4 = 100$.

Flashcard 19: Find power if $V = 10 \text{V}$ and $I = 2 \text{A}$.

Answer: $P = 20 \text{W}$. Power equals voltage times current: $10 \times 2$.

Flashcard 20: State the formula for electrical energy in terms of power and time.

Answer: $E = Pt$. Energy equals power multiplied by time.

Flashcard 21: State the formula for electrical energy in terms of power and time.

Answer: $E = Pt$. Energy equals power multiplied by time.

Flashcard 22: Find power if $V = 10 \text{V}$ and $I = 2 \text{A}$.

Answer: $P = 20 \text{W}$. Power equals voltage times current: $10 \times 2$.

Flashcard 23: What happens to total resistance when a resistor is added in series?

Answer: Total resistance increases. Series resistors add together.

Flashcard 24: Calculate total energy if $P = 60 \text{W}$ for $3 \text{h}$.

Answer: $E = 648,000 \text{J}$. $E = 60 \times 10800 = 648,000$ J.

Flashcard 25: What is the principle of superposition in circuits?

Answer: The voltage/current is the sum of individual contributions. Multiple sources combine linearly in circuit analysis.

Flashcard 26: Calculate total resistance for $R_1 = 4 \text{Ω}$ and $R_2 = 6 \text{Ω}$ in series.

Answer: $R_{\text{eq}} = 10 \text{Ω}$. Add series resistances: $4 + 6 = 10$.

Flashcard 27: What is the effect of adding resistors in parallel on circuit current?

Answer: Current increases. More parallel paths reduce total resistance.

Flashcard 28: Find total current if $V = 12 \text{V}$ and $R = 6 \text{Ω}$.

Answer: $I = 2 \text{A}$. Apply $I = \frac{V}{R} = \frac{12}{6} = 2$.

Flashcard 29: Calculate current if $Q = 10 \text{C}$ and $t = 5 \text{s}$.

Answer: $I = 2 \text{A}$. Apply $I = \frac{Q}{t} = \frac{10}{5} = 2$.

Flashcard 30: What is the effect of adding resistors in series on circuit current?

Answer: Current decreases. More series resistance increases total resistance.

Flashcard 31: Calculate total resistance for $R_1 = 4 \text{Ω}$ and $R_2 = 6 \text{Ω}$ in series.

Answer: $R_{\text{eq}} = 10 \text{Ω}$. Add series resistances: $4 + 6 = 10$.

Flashcard 32: Determine total voltage in series if $V_1 = 5 \text{V}$ and $V_2 = 3 \text{V}$.

Answer: $V_{\text{eq}} = 8 \text{V}$. Series voltages add: $5 + 3 = 8$.

Flashcard 33: Identify the formula for current using charge and time.

Answer: $I = \frac{Q}{t}$. Current is charge flow rate.

Flashcard 34: Find total current if $V = 12 \text{V}$ and $R = 6 \text{Ω}$.

Answer: $I = 2 \text{A}$. Apply $I = \frac{V}{R} = \frac{12}{6} = 2$.

Flashcard 35: What is the effect of adding resistors in series on circuit current?

Answer: Current decreases. More series resistance increases total resistance.

Flashcard 36: Determine total voltage in parallel if $V_1 = 10 \text{V}$ and $V_2 = 10 \text{V}$.

Answer: $V_{\text{eq}} = 10 \text{V}$. Parallel voltages are equal across branches.

Flashcard 37: Find energy used in 2 hours if power is $50 \text{W}$.

Answer: $E = 360,000 \text{J}$. $E = 50 \times 7200 = 360,000$ J.

Flashcard 38: What happens to total resistance when a resistor is added in parallel?

Answer: Total resistance decreases. Parallel paths reduce overall resistance.

Flashcard 39: Calculate total energy if $P = 60 \text{W}$ for $3 \text{h}$.

Answer: $E = 648,000 \text{J}$. $E = 60 \times 10800 = 648,000$ J.