AP Physics 2 Flashcards: Electric Potential

Study Electric Potential in AP Physics 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 2

Electric Potential

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QUESTION
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State the relationship between potential difference and electric field.

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ANSWER

E=VdE = -\frac{\triangle V}{d}. Field strength relates to potential gradient.

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This deck focuses on Electric Potential, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 2.

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Flashcard 1: State the relationship between potential difference and electric field.

Answer: E=VdE = -\frac{\triangle V}{d}. Field strength relates to potential gradient.

Flashcard 2: What is the electric potential energy of a 2C2C charge at 3V3V?

Answer: 6 J6 \text{ J}. Using U=qV=2×3=6U = qV = 2 \times 3 = 6.

Flashcard 3: Find the potential difference if the electric field is 5 V/m5 \text{ V/m} across $3m$.

Answer: 15 V15 \text{ V}. Using V=Ed=5×3=15\triangle V = Ed = 5 \times 3 = 15.

Flashcard 4: How is work done related to electric potential difference?

Answer: W=qVW = q \triangle V. Standard work-voltage relationship formula.

Flashcard 5: Calculate the potential difference for a 4V4V and 12V12V junction.

Answer: 8 V8 \text{ V}. Difference equals 124=812 - 4 = 8 volts.

Flashcard 6: Calculate the potential energy of a 2C2C charge in a 10V10V field.

Answer: 20 J20 \text{ J}. Using U=qV=2×10=20U = qV = 2 \times 10 = 20.

Flashcard 7: What is the formula for electric potential energy?

Answer: U=qVU = qV. Energy equals charge times potential.

Flashcard 8: What is the formula for the potential difference in a uniform field?

Answer: V=Ed\triangle V = Ed. Potential difference in uniform electric field.

Flashcard 9: Find the potential energy of 3C3C in a 6V6V field.

Answer: 18 J18 \text{ J}. Using U=qV=3×6=18U = qV = 3 \times 6 = 18.

Flashcard 10: What is the potential difference between two points in a 4V4V and 10V10V field?

Answer: 6 V6 \text{ V}. Difference equals 104=610 - 4 = 6 volts.

Flashcard 11: What is the potential energy of a charge in a uniform electric field?

Answer: U=qEdU = qEd. Energy stored in uniform field configuration.

Flashcard 12: Identify the relationship between electric potential and electric field.

Answer: E=VE = -\nabla V. Electric field is negative gradient of potential.

Flashcard 13: Define electric potential.

Answer: Electric potential is the work done per unit charge. Describes energy per unit charge at a point.

Flashcard 14: Define the term 'electric potential energy'.

Answer: Energy a charge has due to its position in an electric field. Energy stored due to electric field position.

Flashcard 15: Identify the potential difference needed to store 20J20J in 2C2C of charge.

Answer: 10 V10 \text{ V}. From U=qVU = qV, solve for V=Uq=202=10V = \frac{U}{q} = \frac{20}{2} = 10.

Flashcard 16: Calculate the work done in moving a charge of 2C2C through a potential difference of 5V5V.

Answer: 10 J10 \text{ J}. Work equals charge times potential difference: W=qV=2×5=10W = qV = 2 \times 5 = 10.

Flashcard 17: What is the electric potential at a point equidistant from two equal charges?

Answer: Zero. Equal charges create symmetric cancellation.

Flashcard 18: State the relationship between potential difference and electric field.

Answer: E=VdE = -\frac{\triangle V}{d}. Field strength relates to potential gradient.

Flashcard 19: Calculate the potential energy of 5C5C in a 4V4V potential.

Answer: 20 J20 \text{ J}. Using U=qV=5×4=20U = qV = 5 \times 4 = 20.

Flashcard 20: What is the potential energy of a charge in a uniform electric field?

Answer: U=qEdU = qEd. Energy stored in uniform field configuration.

Flashcard 21: Which quantity is measured in volts?

Answer: Electric potential. Voltage measures electric potential difference.

Flashcard 22: State the formula for potential energy in terms of electric field and distance.

Answer: U=qEdU = qEd. Energy from charge, field, and displacement.

Flashcard 23: What is the potential difference between two points in a 4V4V and 10V10V field?

Answer: 6 V6 \text{ V}. Difference equals 104=610 - 4 = 6 volts.

Flashcard 24: Find the electric field from a potential function V(x)=3x2V(x) = 3x^2.

Answer: E=6x V/mE = -6x \text{ V/m}. Field equals negative derivative: E=dVdx=6xE = -\frac{dV}{dx} = -6x.

Flashcard 25: What is the relation between potential difference and energy change?

Answer: U=qV\triangle U = q \triangle V. Energy change equals charge times voltage change.

Flashcard 26: How is potential difference related to work done on a charge?

Answer: W=qVW = q \triangle V. Fundamental relationship between work and voltage.

Flashcard 27: Calculate the potential at a point $3m$ from a 5C5C charge.

Answer: V=k×53V = \frac{k \times 5}{3}. Direct substitution into point charge formula.

Flashcard 28: Calculate the potential energy of 5C5C in a 4V4V potential.

Answer: 20 J20 \text{ J}. Using U=qV=5×4=20U = qV = 5 \times 4 = 20.

Flashcard 29: State the unit of electric potential.

Answer: Volt (V). Standard unit for measuring electric potential.

Flashcard 30: How is work done related to electric potential difference?

Answer: W=qVW = q \triangle V. Standard work-voltage relationship formula.

Flashcard 31: State the unit of electric potential energy.

Answer: Joule (J). Standard unit for measuring energy quantities.

Flashcard 32: Find the electric field from a potential function V(x)=3x2V(x) = 3x^2.

Answer: E=6x V/mE = -6x \text{ V/m}. Field equals negative derivative: E=dVdx=6xE = -\frac{dV}{dx} = -6x.

Flashcard 33: Define the term 'electric potential energy'.

Answer: Energy a charge has due to its position in an electric field. Energy stored due to electric field position.

Flashcard 34: State the formula for potential energy in terms of electric field and distance.

Answer: U=qEdU = qEd. Energy from charge, field, and displacement.

Flashcard 35: Calculate the potential difference for a 4V4V and 12V12V junction.

Answer: 8 V8 \text{ V}. Difference equals 124=812 - 4 = 8 volts.

Flashcard 36: Define the term 'equipotential surface'.

Answer: A surface with constant electric potential. Surface where potential remains constant everywhere.

Flashcard 37: Calculate the work done in moving a charge of 2C2C through a potential difference of 5V5V.

Answer: 10 J10 \text{ J}. Work equals charge times potential difference: W=qV=2×5=10W = qV = 2 \times 5 = 10.

Flashcard 38: What is the formula for electric potential difference?

Answer: V=VfVi\triangle V = V_f - V_i. Change in potential equals final minus initial.

Flashcard 39: How is electric potential related to electric potential energy?

Answer: V=UqV = \frac{U}{q}. Potential equals energy per unit charge.

Flashcard 40: State the formula for the potential energy of a system of two charges.

Answer: U=kq1q2rU = \frac{kq_1q_2}{r}. Interaction energy between two point charges.

Flashcard 41: State the formula for the electric potential due to a point charge.

Answer: V=kqrV = \frac{kq}{r}. Coulomb's law for potential from point charge.

Flashcard 42: What is the electric potential at infinity?

Answer: Zero. Reference point for electric potential measurements.

Flashcard 43: State the formula for the potential energy of a system of two charges.

Answer: U=kq1q2rU = \frac{kq_1q_2}{r}. Interaction energy between two point charges.

Flashcard 44: Define electric potential.

Answer: Electric potential is the work done per unit charge. Describes energy per unit charge at a point.

Flashcard 45: Which quantity is measured in volts?

Answer: Electric potential. Voltage measures electric potential difference.

Flashcard 46: How is potential difference related to work done on a charge?

Answer: W=qVW = q \triangle V. Fundamental relationship between work and voltage.

Flashcard 47: Identify the potential energy formula for a system of charges.

Answer: U=kq1q2rU = \frac{kq_1q_2}{r}. Standard formula for charge interaction energy.

Flashcard 48: How is the work done on a charge related to potential difference?

Answer: W=qVW = q \triangle V. Work done equals charge times voltage change.

Flashcard 49: State the unit of electric potential energy.

Answer: Joule (J). Standard unit for measuring energy quantities.

Flashcard 50: What is the potential energy of a 3C3C charge at a potential of 4V4V?

Answer: 12 J12 \text{ J}. Using U=qV=3×4=12U = qV = 3 \times 4 = 12.

Flashcard 51: How is the work done on a charge related to potential difference?

Answer: W=qVW = q \triangle V. Work done equals charge times voltage change.

Flashcard 52: Define the term 'equipotential surface'.

Answer: A surface with constant electric potential. Surface where potential remains constant everywhere.

Flashcard 53: What is the potential energy of a 3C3C charge at a potential of 4V4V?

Answer: 12 J12 \text{ J}. Using U=qV=3×4=12U = qV = 3 \times 4 = 12.

Flashcard 54: Calculate the potential energy of a 2C2C charge in a 10V10V field.

Answer: 20 J20 \text{ J}. Using U=qV=2×10=20U = qV = 2 \times 10 = 20.

Flashcard 55: What is the electric potential at infinity?

Answer: Zero. Reference point for electric potential measurements.

Flashcard 56: Identify the relationship between electric potential and electric field.

Answer: E=VE = -\nabla V. Electric field is negative gradient of potential.

Flashcard 57: Identify the potential difference needed to store 20J20J in 2C2C of charge.

Answer: 10 V10 \text{ V}. From U=qVU = qV, solve for V=Uq=202=10V = \frac{U}{q} = \frac{20}{2} = 10.

Flashcard 58: What is the potential at a point midway between two equal charges?

Answer: Zero. Symmetric positioning cancels equal contributions.

Flashcard 59: Find the potential energy of 3C3C in a 6V6V field.

Answer: 18 J18 \text{ J}. Using U=qV=3×6=18U = qV = 3 \times 6 = 18.

Flashcard 60: Find the potential difference if the electric field is 5 V/m5 \text{ V/m} across $3m$.

Answer: 15 V15 \text{ V}. Using V=Ed=5×3=15\triangle V = Ed = 5 \times 3 = 15.

Flashcard 61: What is the formula for electric potential energy?

Answer: U=qVU = qV. Energy equals charge times potential.

Flashcard 62: What is the electric potential energy of a 2C2C charge at 3V3V?

Answer: 6 J6 \text{ J}. Using U=qV=2×3=6U = qV = 2 \times 3 = 6.

Flashcard 63: How is electric potential related to electric potential energy?

Answer: V=UqV = \frac{U}{q}. Potential equals energy per unit charge.

Flashcard 64: What is the electric potential at a point equidistant from two equal charges?

Answer: Zero. Equal charges create symmetric cancellation.

Flashcard 65: Calculate the potential at a point $3m$ from a 5C5C charge.

Answer: V=k×53V = \frac{k \times 5}{3}. Direct substitution into point charge formula.

Flashcard 66: State the formula for the electric potential due to a point charge.

Answer: V=kqrV = \frac{kq}{r}. Coulomb's law for potential from point charge.

Flashcard 67: Identify the potential energy formula for a system of charges.

Answer: U=kq1q2rU = \frac{kq_1q_2}{r}. Standard formula for charge interaction energy.

Flashcard 68: What is the formula for the potential difference in a uniform field?

Answer: V=Ed\triangle V = Ed. Potential difference in uniform electric field.

Flashcard 69: What is the relation between potential difference and energy change?

Answer: U=qV\triangle U = q \triangle V. Energy change equals charge times voltage change.

Flashcard 70: State the unit of electric potential.

Answer: Volt (V). Standard unit for measuring electric potential.

Flashcard 71: What is the formula for electric potential difference?

Answer: V=VfVi\triangle V = V_f - V_i. Change in potential equals final minus initial.