AP Physics 2 Flashcards: Magnetic Fields

Study Magnetic Fields in AP Physics 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 2

Magnetic Fields

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QUESTION
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What is the direction of the magnetic force on a positive charge moving in a magnetic field?

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ANSWER

Perpendicular to both velocity and magnetic field. Cross product in Lorentz force creates perpendicular direction.

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This deck focuses on Magnetic Fields, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 2.

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Flashcard 1: What is the direction of the magnetic force on a positive charge moving in a magnetic field?

Answer: Perpendicular to both velocity and magnetic field. Cross product in Lorentz force creates perpendicular direction.

Flashcard 2: State the formula for the magnetic field inside a toroid.

Answer: B=μ0nI2πrB = \frac{\mu_0 n I}{2\pi r}. Toroidal geometry confines field within the torus structure.

Flashcard 3: Choose the correct expression for the force between two parallel conductors carrying current.

Answer: F/L=μ0I1I22πdF/L = \frac{\mu_0 I_1 I_2}{2\pi d}. Force per unit length between parallel current-carrying conductors.

Flashcard 4: State the formula for the magnetic field inside a solenoid.

Answer: B=μ0nIB = \mu_0 n I. Field is uniform inside; nn is turns per unit length.

Flashcard 5: State the formula for the magnetic field inside a solenoid.

Answer: B=μ0nIB = \mu_0 n I. Field is uniform inside; nn is turns per unit length.

Flashcard 6: What is the definition of a Tesla?

Answer: 1 Tesla = 1 N/(A·m). Force per unit current per unit length in magnetic field.

Flashcard 7: State the expression for the force on a moving charge in an electric and magnetic field.

Answer: F=q(E+v×B)F = q(E + v \times B). Complete Lorentz force including both electric and magnetic components.

Flashcard 8: What is the Lorentz force equation?

Answer: F=q(E+v×B)F = q(E + v \times B). Combined electric and magnetic forces on a charged particle.

Flashcard 9: What is the formula for the cyclotron frequency of a charged particle?

Answer: f=qB2πmf = \frac{qB}{2\pi m}. Frequency of circular motion in uniform magnetic field.

Flashcard 10: What is the formula for the energy stored in a magnetic field?

Answer: U=12LI2U = \frac{1}{2}LI^2. Energy stored depends on inductance LL and current squared.

Flashcard 11: Determine the magnetic force on a wire if I=3AI = 3 \, A, L=2mL = 2 \, m, and B=0.5TB = 0.5 \, T.

Answer: 3 N. Using F=ILBF = ILB for perpendicular orientation: 3×2×0.53 \times 2 \times 0.5.

Flashcard 12: State the formula for the magnetic field at the center of a circular loop of wire.

Answer: B=μ0I2RB = \frac{\mu_0 I}{2R}. Field at center is half that of infinite solenoid.

Flashcard 13: Identify the main factor that affects the magnitude of the magnetic force on a conductor.

Answer: Current (I). Force is directly proportional to current flowing through conductor.

Flashcard 14: What is the Lorentz force equation?

Answer: F=q(E+v×B)F = q(E + v \times B). Combined electric and magnetic forces on a charged particle.

Flashcard 15: State the unit of magnetic field strength in the SI system.

Answer: Tesla (T). Named after Nikola Tesla; equivalent to Wb/m2\text{Wb/m}^2.

Flashcard 16: State the formula for the magnetic field at a point on the axis of a current loop.

Answer: B=μ0IR22(x2+R2)3/2B = \frac{\mu_0 I R^2}{2(x^2 + R^2)^{3/2}}. Field strength decreases rapidly with distance from loop center.

Flashcard 17: Calculate the magnetic field strength 1 m away from a 5 A current-carrying wire.

Answer: 1×106 T1 \times 10^{-6} \text{ T}. Using B=μ0I2πrB = \frac{\mu_0 I}{2\pi r} with given values.

Flashcard 18: Identify the force direction if a proton moves south in a magnetic field pointing upwards.

Answer: West. Using right-hand rule: velocity south, field up gives force west.

Flashcard 19: Find the direction of force on an electron moving north in a magnetic field directed east.

Answer: Downward. Electron has negative charge; force opposes right-hand rule direction.

Flashcard 20: What is the formula for the magnetic field due to a long, straight current-carrying wire?

Answer: B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}. Field decreases as 1/r1/r with distance from wire.

Flashcard 21: What is the principle behind the operation of a galvanometer?

Answer: Torque on a current loop in a magnetic field. Current loop rotates in magnetic field producing measurable deflection.

Flashcard 22: Find the magnetic field strength inside a solenoid with n=1000turns/mn = 1000 \, \text{turns/m} and I=0.01AI = 0.01 \, \text{A}.

Answer: 1.26×105 T1.26 \times 10^{-5} \text{ T}. Using B=μ0nIB = \mu_0 n I with given turn density and current.

Flashcard 23: Choose the correct expression for the force between two parallel conductors carrying current.

Answer: F/L=μ0I1I22πdF/L = \frac{\mu_0 I_1 I_2}{2\pi d}. Force per unit length between parallel current-carrying conductors.

Flashcard 24: What is the relationship between magnetic moment and torque?

Answer: τ=μ×B\tau = \mu \times B. Torque is cross product of magnetic moment and field vectors.

Flashcard 25: Identify the variable that denotes the number of turns per unit length in a solenoid.

Answer: nn. Turn density determines magnetic field strength in solenoid.

Flashcard 26: What is the formula for the Hall voltage in a conductor?

Answer: VH=IBnetV_H = \frac{IB}{net}. Hall effect: voltage across conductor in magnetic field.

Flashcard 27: What is the definition of magnetic flux density?

Answer: Magnetic flux per unit area. Magnetic field BB represents flux density through a surface.

Flashcard 28: State the formula for the magnetic field at the center of a circular loop of wire.

Answer: B=μ0I2RB = \frac{\mu_0 I}{2R}. Field at center is half that of infinite solenoid.

Flashcard 29: What is the formula for the magnetic torque on a current loop?

Answer: τ=nIABsinθ\tau = nIAB \sin \theta. Torque depends on loop area AA and angle θ\theta with field.

Flashcard 30: State the formula for the magnetic field inside a toroid.

Answer: B=μ0nI2πrB = \frac{\mu_0 n I}{2\pi r}. Toroidal geometry confines field within the torus structure.

Flashcard 31: What is the formula for the magnetic torque on a current loop?

Answer: τ=nIABsinθ\tau = nIAB \sin \theta. Torque depends on loop area AA and angle θ\theta with field.

Flashcard 32: What is the formula for the magnetic force on a moving charge?

Answer: F=q(v×B)F = q(v \times B). Cross product shows force is perpendicular to both vv and BB.

Flashcard 33: What is the value of the permeability of free space (μ0\mu_0)?

Answer: 4π×107Tm/A4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}. Fundamental constant relating magnetic field to current.

Flashcard 34: What is the formula for the energy stored in a magnetic field?

Answer: U=12LI2U = \frac{1}{2}LI^2. Energy stored depends on inductance LL and current squared.

Flashcard 35: What is the formula for the Hall voltage in a conductor?

Answer: VH=IBnetV_H = \frac{IB}{net}. Hall effect: voltage across conductor in magnetic field.

Flashcard 36: Calculate the magnetic field strength 1 m away from a 5 A current-carrying wire.

Answer: 1×106 T1 \times 10^{-6} \text{ T}. Using B=μ0I2πrB = \frac{\mu_0 I}{2\pi r} with given values.

Flashcard 37: State the unit of magnetic field strength in the SI system.

Answer: Tesla (T). Named after Nikola Tesla; equivalent to Wb/m2\text{Wb/m}^2.

Flashcard 38: State the expression for the force on a moving charge in an electric and magnetic field.

Answer: F=q(E+v×B)F = q(E + v \times B). Complete Lorentz force including both electric and magnetic components.

Flashcard 39: Identify the variable that denotes the number of turns per unit length in a solenoid.

Answer: nn. Turn density determines magnetic field strength in solenoid.

Flashcard 40: What is the unit of magnetic flux?

Answer: Weber (Wb). Named after Wilhelm Weber; measures magnetic field through area.

Flashcard 41: Identify the rule used to determine the direction of the magnetic force on a moving charge.

Answer: Right-hand rule. Point fingers along vv, curl toward BB, thumb shows force direction.

Flashcard 42: What is the formula for the magnetic field due to a long, straight current-carrying wire?

Answer: B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}. Field decreases as 1/r1/r with distance from wire.

Flashcard 43: What is the principle behind magnetic levitation?

Answer: Repulsion of like magnetic poles. Like poles repel, creating upward force against gravity.

Flashcard 44: What is the formula for the magnetic force on a current-carrying wire?

Answer: F=I(L×B)F = I(L \times B). Current II and length LL replace charge and velocity in force equation.

Flashcard 45: What is the value of the permeability of free space (μ0\mu_0)?

Answer: 4π×107Tm/A4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}. Fundamental constant relating magnetic field to current.

Flashcard 46: What is the formula for the magnetic force on a current-carrying wire?

Answer: F=I(L×B)F = I(L \times B). Current II and length LL replace charge and velocity in force equation.

Flashcard 47: Identify the main factor that affects the magnitude of the magnetic force on a conductor.

Answer: Current (I). Force is directly proportional to current flowing through conductor.

Flashcard 48: State the formula for the magnetic field at a point on the axis of a current loop.

Answer: B=μ0IR22(x2+R2)3/2B = \frac{\mu_0 I R^2}{2(x^2 + R^2)^{3/2}}. Field strength decreases rapidly with distance from loop center.

Flashcard 49: What is the unit of magnetic flux?

Answer: Weber (Wb). Named after Wilhelm Weber; measures magnetic field through area.

Flashcard 50: Identify the relationship between magnetic flux and magnetic field.

Answer: ΦB=BAcosθ\Phi_B = B \cdot A \cdot \cos \theta. Flux depends on field strength, area, and orientation angle.

Flashcard 51: What is the relationship between magnetic moment and torque?

Answer: τ=μ×B\tau = \mu \times B. Torque is cross product of magnetic moment and field vectors.

Flashcard 52: What is the definition of a Tesla?

Answer: 1 Tesla = 1 N/(A·m). Force per unit current per unit length in magnetic field.

Flashcard 53: What is the principle behind the operation of a galvanometer?

Answer: Torque on a current loop in a magnetic field. Current loop rotates in magnetic field producing measurable deflection.

Flashcard 54: Which device uses magnetic fields to separate charged particles by mass?

Answer: Mass spectrometer. Different masses follow different curved paths in magnetic field.

Flashcard 55: Which option correctly describes the Biot-Savart Law?

Answer: It relates magnetic fields to the currents which produce them. Fundamental law connecting magnetic fields to their current sources.

Flashcard 56: Find the magnetic force on a 2 C charge moving at 3 m/s perpendicular to a 4 T magnetic field.

Answer: 24 N. Using F=qvBF = qvB with perpendicular motion: 2×3×4=242 \times 3 \times 4 = 24.

Flashcard 57: Identify the force direction if a proton moves south in a magnetic field pointing upwards.

Answer: West. Using right-hand rule: velocity south, field up gives force west.

Flashcard 58: Which device uses magnetic fields to separate charged particles by mass?

Answer: Mass spectrometer. Different masses follow different curved paths in magnetic field.

Flashcard 59: Determine the magnetic force on a wire if I=3AI = 3 \, A, L=2mL = 2 \, m, and B=0.5TB = 0.5 \, T.

Answer: 3 N. Using F=ILBF = ILB for perpendicular orientation: 3×2×0.53 \times 2 \times 0.5.

Flashcard 60: What is the formula for the magnetic force on a moving charge?

Answer: F=q(v×B)F = q(v \times B). Cross product shows force is perpendicular to both vv and BB.

Flashcard 61: Find the direction of force on an electron moving north in a magnetic field directed east.

Answer: Downward. Electron has negative charge; force opposes right-hand rule direction.

Flashcard 62: Identify the rule used to determine the direction of the magnetic force on a moving charge.

Answer: Right-hand rule. Point fingers along vv, curl toward BB, thumb shows force direction.

Flashcard 63: What is the direction of the magnetic force on a positive charge moving in a magnetic field?

Answer: Perpendicular to both velocity and magnetic field. Cross product in Lorentz force creates perpendicular direction.

Flashcard 64: What is the expression for the magnetic field of a moving charge?

Answer: B=μ04πq(v×r)r3B = \frac{\mu_0}{4\pi} \frac{q(v \times r)}{r^3}. Biot-Savart law for field produced by moving point charge.

Flashcard 65: What is the formula for the cyclotron frequency of a charged particle?

Answer: f=qB2πmf = \frac{qB}{2\pi m}. Frequency of circular motion in uniform magnetic field.

Flashcard 66: Which option correctly describes the Biot-Savart Law?

Answer: It relates magnetic fields to the currents which produce them. Fundamental law connecting magnetic fields to their current sources.

Flashcard 67: Find the magnetic force on a 2 C charge moving at 3 m/s perpendicular to a 4 T magnetic field.

Answer: 24 N. Using F=qvBF = qvB with perpendicular motion: 2×3×4=242 \times 3 \times 4 = 24.

Flashcard 68: What is the principle behind magnetic levitation?

Answer: Repulsion of like magnetic poles. Like poles repel, creating upward force against gravity.

Flashcard 69: Find the magnetic field strength inside a solenoid with n=1000turns/mn = 1000 \, \text{turns/m} and I=0.01AI = 0.01 \, \text{A}.

Answer: 1.26×105 T1.26 \times 10^{-5} \text{ T}. Using B=μ0nIB = \mu_0 n I with given turn density and current.

Flashcard 70: Identify the relationship between magnetic flux and magnetic field.

Answer: ΦB=BAcosθ\Phi_B = B \cdot A \cdot \cos \theta. Flux depends on field strength, area, and orientation angle.

Flashcard 71: What is the expression for the magnetic field of a moving charge?

Answer: B=μ04πq(v×r)r3B = \frac{\mu_0}{4\pi} \frac{q(v \times r)}{r^3}. Biot-Savart law for field produced by moving point charge.

Flashcard 72: What is the definition of magnetic flux density?

Answer: Magnetic flux per unit area. Magnetic field BB represents flux density through a surface.