Study Specific Heat And Thermal Conductivity in AP Physics 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards
Flashcard 1: What is the specific heat if q=200 J, m=4 kg, ΔT=2∘C?
Answer: 25 J/kg\cdotpK. c=q/(mΔT)=200/(4×2)=25
Flashcard 2: State Fourier's Law of Heat Conduction.
Answer: Heat transfer rate q=−kAΔxΔT. Fundamental equation for conductive heat transfer.
Flashcard 3: What does the negative sign in q=−kAΔxΔT indicate?
Answer: Heat flows from high to low temperature. Heat flows down temperature gradient naturally.
Flashcard 4: What is the specific heat of water?
Answer: 4.18 J/g°C. High value gives water thermal stability.
Flashcard 5: What does the negative sign in q=−kAΔxΔT indicate?
Answer: Heat flows from high to low temperature. Heat flows down temperature gradient naturally.
Flashcard 6: Find the specific heat capacity if q=500 J, m=2 kg, ΔT=5∘C.
Answer: 50 J/kg\cdotpK. c=q/(mΔT)=500/(2×5)=50
Flashcard 7: What is the thermal conductivity of copper?
Answer: Approximately 385 W/m\cdotpK. High thermal conductivity metal.
Flashcard 8: What is the role of area A in the thermal conductivity equation?
Answer: Cross-sectional area through which heat flows. Larger area increases heat transfer proportionally.
Flashcard 9: What is the thermal conductivity of air?
Answer: Approximately 0.024 W/m\cdotpK. Air is good thermal insulator.
Flashcard 10: State Fourier's Law of Heat Conduction.
Answer: Heat transfer rate q=−kAΔxΔT. Fundamental equation for conductive heat transfer.
Flashcard 11: Which material typically has higher thermal conductivity: metal or wood?
Answer: Metal. Metals conduct heat much better than wood.
Flashcard 12: Define specific heat capacity.
Answer: Amount of heat required to raise 1 kg of substance by 1∘C. Intensive property measuring thermal inertia.
Flashcard 13: Find c if q=750 J, m=3 kg, ΔT=10∘C.
Answer: 25 J/kg\cdotpK. c=q/(mΔT)=750/(3×10)=25
Flashcard 14: What is the specific heat if q=200 J, m=4 kg, ΔT=2∘C?
Answer: 25 J/kg\cdotpK. c=q/(mΔT)=200/(4×2)=25
Flashcard 15: State the formula for thermal conductivity.
Answer: q=−kAΔxΔT. Fourier's Law relates heat flow to material properties.
Flashcard 16: Define specific heat capacity.
Answer: Amount of heat required to raise 1 kg of substance by 1∘C. Intensive property measuring thermal inertia.
Flashcard 17: What is the thermal conductivity of air?
Answer: Approximately 0.024 W/m\cdotpK. Air is good thermal insulator.
Flashcard 18: What is the formula for specific heat capacity?
Answer: c=mΔTq. Rearranged from q=mcΔT.
Flashcard 19: What is thermal conductivity?
Answer: Measure of a material's ability to conduct heat. Material property for heat conduction efficiency.
Flashcard 20: Which material typically has higher thermal conductivity: metal or wood?
Answer: Metal. Metals conduct heat much better than wood.
Flashcard 21: What is the temperature change if 1000 J is added to 2 kg of aluminum (c=900 J/kg\cdotpK)?
Answer: 0.56∘C. ΔT=q/(mc)=1000/(2×900)=0.56
Flashcard 22: Find c if q=750 J, m=3 kg, ΔT=10∘C.
Answer: 25 J/kg\cdotpK. c=q/(mΔT)=750/(3×10)=25
Flashcard 23: Identify the meaning of Δx in thermal conductivity.
Answer: Thickness of the material. Greater thickness reduces heat transfer rate.
Flashcard 24: What is the effect of high specific heat on temperature change?
Answer: Smaller temperature change for given heat input. More energy needed for same temperature rise.
Flashcard 25: Calculate ΔT if q=500 J, m=1 kg, c=250 J/kg\cdotpK.
Answer: 2∘C. ΔT=q/(mc)=500/(1×250)=2
Flashcard 26: What is the unit of specific heat capacity in SI?
Answer: Joules per kilogram per Kelvin (J/kg·K). Energy per mass per temperature change.
Flashcard 27: What does k represent in the thermal conductivity formula?
Answer: Thermal conductivity. Material's intrinsic heat conduction property.
Flashcard 28: Find ΔT if q=2500 J, m=5 kg, c=500 J/kg\cdotpK.
Answer: 1∘C. ΔT=q/(mc)=2500/(5×500)=1
Flashcard 29: What is the temperature change if 1000 J is added to 2 kg of aluminum (c=900 J/kg\cdotpK)?
Answer: 0.56∘C. ΔT=q/(mc)=1000/(2×900)=0.56
Flashcard 30: What is the thermal conductivity of copper?
Answer: Approximately 385 W/m\cdotpK. High thermal conductivity metal.
Flashcard 31: What is the unit of specific heat capacity in SI?
Answer: Joules per kilogram per Kelvin (J/kg·K). Energy per mass per temperature change.
Flashcard 32: State the formula for calculating heat transfer.
Answer: q=mcΔT. Relates heat to mass, specific heat, and temperature change.
Flashcard 33: What is the effect of high specific heat on temperature change?
Answer: Smaller temperature change for given heat input. More energy needed for same temperature rise.
Flashcard 34: What is the role of area A in the thermal conductivity equation?
Answer: Cross-sectional area through which heat flows. Larger area increases heat transfer proportionally.
Flashcard 35: What is the specific heat of water?
Answer: 4.18 J/g°C. High value gives water thermal stability.
Flashcard 36: What does q represent in heat equations?
Answer: Heat transfer. Heat energy or heat flow rate.
Flashcard 37: Find the specific heat if q=360 J, m=2 kg, ΔT=2∘C.
Answer: 90 J/kg\cdotpK. c=q/(mΔT)=360/(2×2)=90
Flashcard 38: Find the mass if q=1500 J, c=200 J/kg\cdotpK, ΔT=3∘C.
Answer: 2.5 kg. m=q/(cΔT)=1500/(200×3)=2.5
Flashcard 39: Find ΔT if q=2500 J, m=5 kg, c=500 J/kg\cdotpK.
Answer: 1∘C. ΔT=q/(mc)=2500/(5×500)=1
Flashcard 40: Find the mass if q=1500 J, c=200 J/kg\cdotpK, ΔT=3∘C.
Answer: 2.5 kg. m=q/(cΔT)=1500/(200×3)=2.5
Flashcard 41: Find the specific heat if q=360 J, m=2 kg, ΔT=2∘C.
Answer: 90 J/kg\cdotpK. c=q/(mΔT)=360/(2×2)=90
Flashcard 42: What is the unit of thermal conductivity in SI?
Answer: Watts per meter per Kelvin (W/m·K). Power per length per temperature difference.
Flashcard 43: Calculate ΔT if q=500 J, m=1 kg, c=250 J/kg\cdotpK.
Answer: 2∘C. ΔT=q/(mc)=500/(1×250)=2
Flashcard 44: Identify the meaning of Δx in thermal conductivity.
Answer: Thickness of the material. Greater thickness reduces heat transfer rate.
Flashcard 45: What is thermal conductivity?
Answer: Measure of a material's ability to conduct heat. Material property for heat conduction efficiency.
Flashcard 46: State the formula for thermal conductivity.
Answer: q=−kAΔxΔT. Fourier's Law relates heat flow to material properties.
Flashcard 47: What does ΔT represent in heat transfer formulas?
Answer: Change in temperature. Final minus initial temperature.
Flashcard 48: What is the unit of thermal conductivity in SI?
Answer: Watts per meter per Kelvin (W/m·K). Power per length per temperature difference.
Flashcard 49: What does q represent in heat equations?
Answer: Heat transfer. Heat energy or heat flow rate.
Flashcard 50: Find the specific heat capacity if q=500 J, m=2 kg, ΔT=5∘C.
Answer: 50 J/kg\cdotpK. c=q/(mΔT)=500/(2×5)=50
Flashcard 51: What does k represent in the thermal conductivity formula?
Answer: Thermal conductivity. Material's intrinsic heat conduction property.
Flashcard 52: Identify the symbol for specific heat capacity.
Answer: c. Lowercase c is standard notation.
Flashcard 53: What is the formula for specific heat capacity?
Answer: c=mΔTq. Rearranged from q=mcΔT.
Flashcard 54: What does ΔT represent in heat transfer formulas?
Answer: Change in temperature. Final minus initial temperature.
Flashcard 55: State the formula for calculating heat transfer.
Answer: q=mcΔT. Relates heat to mass, specific heat, and temperature change.