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This deck focuses on Function Model Construction And Application, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.
Study Function Model Construction And Application in AP Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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What is the range of f(x)=ex?
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All positive real numbers. Exponential function always produces positive outputs.
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This deck focuses on Function Model Construction And Application, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: All positive real numbers. Exponential function always produces positive outputs.
Answer: y=4. Horizontal line has constant y-value for all x.
Answer: Vertical shift down by 1 unit. Subtracting constant moves entire graph downward.
Answer: f(x)=a(x−h)2+k. Shows vertex at (h,k) with a controlling width and direction.
Answer: f−1(x)=x1. Function is its own inverse (self-inverse).
Answer: Vertical stretch by a factor of 2. Coefficient 2 multiplies all y-values, stretching vertically.
Answer: f(x)=ax3+bx2+cx+d. Highest degree term ax3 with lower degree terms.
Answer: Vertical stretch by a factor of 2. Coefficient 2 multiplies all y-values, stretching vertically.
Answer: All non-negative real numbers. Cannot take square root of negative numbers in real domain.
Answer: y=10. Evaluate f(0) to find where graph crosses y-axis.
Answer: y=4. Horizontal line has constant y-value for all x.
Answer: y=1. Evaluate f(0)=3(0)2+2(0)+1=1.
Answer: x=2. Set f(x)=0 and solve: 2x−4=0.
Answer: f−1(x)=2x−3. Switch variables and solve: x=2y+3 gives y=2x−3.
Answer: y=1. Evaluate f(0)=3(0)2+2(0)+1=1.
Answer: Vertical compression by a factor of 21. Coefficient 21 reduces all y-values by half.
Answer: Quadratic function. Basic parabola opening upward.
Answer: f(x)=ax3+bx2+cx+d. Highest degree term ax3 with lower degree terms.
Answer: Quadratic function. Basic parabola opening upward.
Answer: (x−h)2+(y−k)2=r2. Center at (h,k) with radius r.
Answer: Amplitude is 3. Coefficient determines maximum displacement from center.
Answer: Horizontal shift right by 3 units. Subtracting inside parentheses shifts graph right.
Answer: Vertical compression by a factor of 21. Coefficient 21 reduces all y-values by half.
Answer: All non-negative real numbers. Cannot take square root of negative numbers in real domain.
Answer: Vertical shift up by 5 units. Adding constant moves entire graph upward.
Answer: All real numbers. Logarithm can output any real number value.
Answer: f(x)=ax2+bx+c. Standard form with leading coefficient a, linear term bx, and constant c.
Answer: Reflection over the x-axis. Negative coefficient flips parabola upside down.
Answer: Rational function. Ratio of polynomials defines rational functions.
Answer: x=2. Use formula x=−2ab=−2(1)−4=2.
Answer: x=2. Use formula x=−2ab=−2(1)−4=2.
Answer: From -1 to 1 inclusive. Cosine oscillates between minimum -1 and maximum 1.
Answer: Vertical shift down by 1 unit. Subtracting constant moves entire graph downward.
Answer: Horizontal shift left by 2 units. Adding inside parentheses shifts graph left.
Answer: All positive real numbers. Exponential function always produces positive outputs.
Answer: All real numbers. Logarithm can output any real number value.
Answer: All real numbers. Linear functions have unlimited output values.
Answer: Rational function. Ratio of polynomials defines rational functions.
Answer: All real numbers except x=2. Denominator cannot equal zero, so x=2.
Answer: (x−h)2+(y−k)2=r2. Center at (h,k) with radius r.
Answer: x=2,x=−2. Set f(x)=0: x2−4=0, so x2=4.
Answer: x=2. Set f(x)=0 and solve: 2x−4=0.
Answer: f(x)=mx+b. Standard slope-intercept form where m is slope and b is y-intercept.
Answer: Amplitude is 3. Coefficient determines maximum displacement from center.
Answer: f(x)=ax2+bx+c. Standard form with leading coefficient a, linear term bx, and constant c.
Answer: Vertical shift up by 5 units. Adding constant moves entire graph upward.
Answer: Slope m=32. Rearrange to y=32x−2 form.
Answer: Reflection over the x-axis. Negative coefficient flips parabola upside down.
Answer: All real numbers. Linear functions have unlimited output values.
Answer: f(x)=a(x−h)2+k. Shows vertex at (h,k) with a controlling width and direction.
Answer: Vertex at (1,3). Vertex form directly shows vertex coordinates (h,k).
Answer: Slope m=32. Rearrange to y=32x−2 form.
Answer: All positive real numbers. Logarithm undefined for zero and negative inputs.
Answer: f−1(x)=x1. Function is its own inverse (self-inverse).
Answer: f(x)=a×bx where b>1. Base b>1 ensures growth; a is initial value.
Answer: 2Period. Coefficient of x doubles frequency, halving period to π.
Answer: f−1(x)=2x−3. Switch variables and solve: x=2y+3 gives y=2x−3.
Answer: x=2,x=−2. Set f(x)=0: x2−4=0, so x2=4.
Answer: All positive real numbers. Logarithm undefined for zero and negative inputs.
Answer: Vertex at (1,3). Vertex form directly shows vertex coordinates (h,k).