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This deck focuses on Inverses Of Exponential Functions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.
Study Inverses Of Exponential Functions in AP Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Identify the inverse of f(x)=73x−1.
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The inverse is f−1(x)=31(log7(x)+1). Factor out coefficient from both terms in exponent.
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This deck focuses on Inverses Of Exponential Functions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: The inverse is f−1(x)=31(log7(x)+1). Factor out coefficient from both terms in exponent.
Answer: The inverse is f−1(x)=loga(x). Base-a logarithm undoes base-a exponentiation.
Answer: The inverse operation is taking the logarithm. Logarithm is the inverse operation of exponentiation.
Answer: The inverse is f−1(x)=loga(x). Base-a logarithm undoes base-a exponentiation.
Answer: The inverse is f−1(x)=log9(x)+4. Subtract 4 from exponent, so add 4 to inverse.
Answer: The inverse is f−1(x)=ln(x)−2. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is f−1(x)=21log12(x)−21. Factor out coefficient from exponent terms.
Answer: The inverse is f−1(x)=21logb(x)−21. Factor out coefficient and shift from exponent.
Answer: The inverse is f−1(x)=31log10(x). Coefficient 3 in exponent becomes divisor 31.
Answer: The inverse is f−1(x)=21ln(x). Coefficient in exponent becomes divisor in inverse.
Answer: The inverse is f−1(x)=log4(x)+3. Subtract 3 from exponent, so add 3 to inverse.
Answer: The inverse is the natural logarithm function. Natural log ln(x) undoes ex.
Answer: The inverse is f−1(x)=21logb(x)−21. Factor out coefficient and shift from exponent.
Answer: The inverse is f−1(x)=log2(x)−3. Addition in exponent becomes subtraction in inverse.
Answer: Switch x and y, solve for y. Result: y=loga(x). Standard method for finding inverse functions.
Answer: The inverse is f−1(x)=log2(x). Base-2 logarithm undoes base-2 exponentiation.
Answer: The inverse is f−1(x)=log15(x)+2. Subtract 2 from exponent, so add 2 to inverse.
Answer: The inverse is f−1(x)=log7(x)+1. Subtract 1 from exponent, so add 1 to inverse.
Answer: The inverse is y=log2(x)+5. Subtract 5 from exponent, so add 5 to inverse.
Answer: The inverse is f−1(x)=log7(x)+1. Subtract 1 from exponent, so add 1 to inverse.
Answer: The inverse is the natural logarithm function. Natural log ln(x) undoes ex.
Answer: The inverse is f−1(x)=31log10(x). Coefficient 3 in exponent becomes divisor 31.
Answer: The inverse is f−1(x)=log6(x)−1. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is f−1(x)=ln(x). Natural log undoes the natural exponential function.
Answer: The inverse is f−1(x)=log5(x). Base-5 logarithm undoes base-5 exponentiation.
Answer: The inverse is f−1(x)=log9(x)+2. Subtract 2 from exponent, so add 2 to inverse.
Answer: The inverse is y=log2(x)+5. Subtract 5 from exponent, so add 5 to inverse.
Answer: Exponential and logarithmic functions are inverses. Each function undoes the other's operation.
Answer: The inverse is f−1(x)=ln(x). Natural log undoes the natural exponential function.
Answer: The inverse is f−1(x)=log5(x). Base-5 logarithm undoes base-5 exponentiation.
Answer: The inverse is f−1(x)=31log2(x). Coefficient 3 in exponent becomes divisor 31.
Answer: Exponential and logarithmic functions are inverses. Each function undoes the other's operation.
Answer: The inverse is y=ln(x)+1. Subtract 1 from exponent, so add 1 to inverse.
Answer: The inverse is f−1(x)=log9(x)+4. Subtract 4 from exponent, so add 4 to inverse.
Answer: The inverse is f−1(x)=21ln(x). Coefficient in exponent becomes divisor in inverse.
Answer: The inverse operation is taking the logarithm. Logarithm is the inverse operation of exponentiation.
Answer: The inverse is f−1(x)=ln(x)−2. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is f−1(x)=log15(x)+2. Subtract 2 from exponent, so add 2 to inverse.
Answer: The inverse is f−1(x)=21log8(x). Coefficient 2 in exponent becomes divisor 21.
Answer: The inverse is f−1(x)=logb(x). General base-b logarithm undoes base-b exponentiation.
Answer: The inverse is y=log5(x)+4. Subtract 4 from exponent, so add 4 to inverse.
Answer: The inverse is f−1(x)=31(log7(x)+1). Factor out coefficient from both terms in exponent.
Answer: The inverse is f−1(x)=log13(x). Base-13 logarithm undoes base-13 exponentiation.
Answer: The inverse is f−1(x)=21log3(x). Coefficient 2 in exponent becomes divisor 21.
Answer: The inverse is f−1(x)=log13(x). Base-13 logarithm undoes base-13 exponentiation.
Answer: The inverse is y=log5(x)+4. Subtract 4 from exponent, so add 4 to inverse.
Answer: The inverse is f−1(x)=log3(x). Base-3 logarithm undoes base-3 exponentiation.
Answer: The inverse is f−1(x)=21log12(x)−21. Factor out coefficient from exponent terms.
Answer: The inverse is x=4y or y=log4(x). Switch variables and solve for y.
Answer: The inverse is f−1(x)=21log8(x). Coefficient 2 in exponent becomes divisor 21.
Answer: The inverse is f−1(x)=logb(x). General base-b logarithm undoes base-b exponentiation.
Answer: The inverse is f−1(x)=log2(x)−3. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is f−1(x)=log3(x)−5. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is f−1(x)=log11(x)−2. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is f−1(x)=log3(x)−5. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is f−1(x)=log4(x)+3. Subtract 3 from exponent, so add 3 to inverse.
Answer: The inverse is f−1(x)=log6(x)−1. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is x=4y or y=log4(x). Switch variables and solve for y.
Answer: The inverse is f−1(x)=log2(x). Base-2 logarithm undoes base-2 exponentiation.
Answer: Switch x and y, solve for y. Result: y=loga(x). Standard method for finding inverse functions.
Answer: The inverse is f−1(x)=21log3(x). Coefficient 2 in exponent becomes divisor 21.
Answer: The inverse is f−1(x)=log11(x)−2. Addition in exponent becomes subtraction in inverse.
Answer: The inverse is f−1(x)=log9(x)+2. Subtract 2 from exponent, so add 2 to inverse.
Answer: The inverse is f−1(x)=log3(x). Base-3 logarithm undoes base-3 exponentiation.
Answer: The inverse is y=ln(x)+1. Subtract 1 from exponent, so add 1 to inverse.
Answer: The inverse is f−1(x)=31log2(x). Coefficient 3 in exponent becomes divisor 31.
Answer: The inverse is f−1(x)=log10(x). Common logarithm undoes base-10 exponentiation.
Answer: The inverse is f−1(x)=log10(x). Common logarithm undoes base-10 exponentiation.