AP Precalculus Flashcards: Rates Of Change

Study Rates Of Change in AP Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Precalculus

Rates Of Change

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QUESTION
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If y=3x35xy = 3x^3 - 5x, what is dydx\frac{dy}{dx}?

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ANSWER

dydx=9x25\frac{dy}{dx} = 9x^2 - 5. Use power rule: 33x2513 \cdot 3x^2 - 5 \cdot 1.

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This deck focuses on Rates Of Change, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.

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Flashcard 1: If y=3x35xy = 3x^3 - 5x, what is dydx\frac{dy}{dx}?

Answer: dydx=9x25\frac{dy}{dx} = 9x^2 - 5. Use power rule: 33x2513 \cdot 3x^2 - 5 \cdot 1.

Flashcard 2: What is the derivative of f(x)=loga(x)f(x) = \log_a(x)?

Answer: f(x)=1xln(a)f'(x) = \frac{1}{x \ln(a)}. Change of base gives factor 1ln(a)\frac{1}{\ln(a)}.

Flashcard 3: Find the derivative of f(x)=sec(x)f(x) = \text{sec}(x).

Answer: f(x)=sec(x)tan(x)f'(x) = \text{sec}(x)\text{tan}(x). Product rule applied to sec(x)=1cos(x)\sec(x) = \frac{1}{\cos(x)}.

Flashcard 4: What is the derivative of f(x)=cos2(x)f(x) = \text{cos}^2(x)?

Answer: f(x)=2sin(x)cos(x)f'(x) = -2\text{sin}(x)\text{cos}(x). Chain rule gives negative of sin2(x)\sin^2(x) derivative.

Flashcard 5: State the derivative of f(x)=arcsin(x)f(x) = \text{arcsin}(x).

Answer: f'(x) = \frac{1}{\sqrt{1-x^2)}. Standard inverse trig derivative formula.

Flashcard 6: Identify the derivative of f(x)=tan2(x)f(x) = \text{tan}^2(x).

Answer: f(x)=2tan(x)sec2(x)f'(x) = 2\text{tan}(x)\text{sec}^2(x). Chain rule applied to tan2(x)\tan^2(x).

Flashcard 7: Identify the derivative of f(x)=exf(x) = e^x.

Answer: f(x)=exf'(x) = e^x. Exponential function exe^x is its own derivative.

Flashcard 8: What is the derivative of f(x)=arccsc(x)f(x) = \text{arccsc}(x)?

Answer: f(x)=1xsqrt(x21)f'(x) = -\frac{1}{|x|\text{sqrt}(x^2-1)}. Negative of arcsecant derivative.

Flashcard 9: State the derivative of f(x)=sin2(x)f(x) = \text{sin}^2(x).

Answer: f(x)=2sin(x)cos(x)f'(x) = 2\text{sin}(x)\text{cos}(x). Use chain rule on sin2(x)\sin^2(x).

Flashcard 10: What is the rate of change of f(x)=7f(x) = 7?

Answer: Rate of change is 0. Constant functions have zero rate of change.

Flashcard 11: What is the rate of change of f(x)=x4f(x) = x^4 at x=2x = 2?

Answer: Rate of change is 32. Use f(x)=4x3f'(x) = 4x^3, evaluate at x=2x = 2.

Flashcard 12: What is the rate of change of f(x)=x2+3xf(x) = x^2 + 3x at x=1x=1?

Answer: Rate of change is 5. Use f(x)=2x+3f'(x) = 2x + 3, evaluate at x=1x = 1.

Flashcard 13: What is the derivative of f(x)=1x3f(x) = \frac{1}{x^3}?

Answer: f(x)=3x4f'(x) = -\frac{3}{x^4}. Rewrite as x3x^{-3} and apply power rule.

Flashcard 14: What is the derivative of f(x)=ln(x2)f(x) = \text{ln}(x^2)?

Answer: f(x)=2xf'(x) = \frac{2}{x}. Use chain rule: 1x22x=2x\frac{1}{x^2} \cdot 2x = \frac{2}{x}.

Flashcard 15: Identify the derivative of f(x)=tan(x)f(x) = \text{tan}(x).

Answer: f(x)=sec2(x)f'(x) = \text{sec}^2(x). Tangent differentiates to secant squared.

Flashcard 16: Calculate ddx[5x2]\frac{d}{dx}[5x^2].

Answer: 10x10x. Factor out constant 5, apply power rule.

Flashcard 17: State the constant rule for derivatives.

Answer: Derivative of a constant is 0. Constants have zero slope everywhere.

Flashcard 18: What is the derivative of f(x)=loga(x)f(x) = \text{log}_a(x)?

Answer: f(x)=1xln(a)f'(x) = \frac{1}{x\text{ln}(a)}. Change of base gives factor 1ln(a)\frac{1}{\ln(a)}.

Flashcard 19: Determine the derivative of f(x)=5xf(x) = 5^x.

Answer: f(x)=5xln(5)f'(x) = 5^x\text{ln}(5). General formula axa^x derivative includes ln(a)\ln(a) factor.

Flashcard 20: Find f(x)f'(x) for f(x)=sin(x)f(x) = \text{sin}(x).

Answer: f(x)=cos(x)f'(x) = \text{cos}(x). Sine differentiates to cosine.

Flashcard 21: What is the derivative of f(x)=arccos(x)f(x) = \text{arccos}(x)?

Answer: f(x)=1sqrt(1x2)f'(x) = -\frac{1}{\text{sqrt}(1-x^2)}. Negative of arcsine derivative.

Flashcard 22: What is the derivative of f(x)=xxf(x) = x^x?

Answer: f(x)=xx(ln(x)+1)f'(x) = x^x(\text{ln}(x)+1). Use logarithmic differentiation for variable base and exponent.

Flashcard 23: State the constant rule for derivatives.

Answer: Derivative of a constant is 0. Constants have zero slope everywhere.

Flashcard 24: What is the rate of change of f(x)=x2+3xf(x) = x^2 + 3x at x=1x=1?

Answer: Rate of change is 5. Use f(x)=2x+3f'(x) = 2x + 3, evaluate at x=1x = 1.

Flashcard 25: Determine the derivative of f(x)=5xf(x) = 5^x.

Answer: f(x)=5xln(5)f'(x) = 5^x \ln(5). General formula axa^x derivative includes ln(a)\ln(a) factor.

Flashcard 26: What is the derivative of f(x)=cos(x)f(x) = \text{cos}(x)?

Answer: f(x)=sin(x)f'(x) = -\text{sin}(x). Cosine differentiates to negative sine.

Flashcard 27: What is the derivative of f(x)=arccos(x)f(x) = \text{arccos}(x)?

Answer: f(x)=1sqrt(1x2)f'(x) = -\frac{1}{\text{sqrt}(1-x^2)}. Negative of arcsine derivative.

Flashcard 28: Calculate ddx[x52x3]\frac{d}{dx}[x^5 - 2x^3].

Answer: 5x46x25x^4 - 6x^2. Apply power rule to each term separately.

Flashcard 29: If y=3x35xy = 3x^3 - 5x, what is dydx\frac{dy}{dx}?

Answer: dydx=9x25\frac{dy}{dx} = 9x^2 - 5. Use power rule: 33x2513 \cdot 3x^2 - 5 \cdot 1.

Flashcard 30: Calculate ddx[5x2]\frac{d}{dx}[5x^2].

Answer: 10x10x. Factor out constant 5, apply power rule.

Flashcard 31: Define average rate of change of a function f(x)f(x) over [a,b][a, b].

Answer: f(b)f(a)ba\frac{f(b) - f(a)}{b - a}. Slope formula between two points on the function.

Flashcard 32: What is the derivative of f(x)=csc(x)f(x) = \text{csc}(x)?

Answer: f(x)=csc(x)cot(x)f'(x) = -\text{csc}(x)\text{cot}(x). Quotient rule applied to csc(x)=1sin(x)\csc(x) = \frac{1}{\sin(x)}.

Flashcard 33: What is the rate of change of f(x)=x4f(x) = x^4 at x=2x = 2?

Answer: Rate of change is 32. Use f(x)=4x3f'(x) = 4x^3, evaluate at x=2x = 2.

Flashcard 34: What is the instantaneous rate of change at x=ax = a?

Answer: The derivative f(a)f'(a). Limit of average rate of change as interval approaches zero.

Flashcard 35: State the derivative of f(x)=sin2(x)f(x) = \text{sin}^2(x).

Answer: f(x)=2sin(x)cos(x)f'(x) = 2\text{sin}(x)\text{cos}(x). Use chain rule on sin2(x)\sin^2(x).

Flashcard 36: What is the derivative of f(x)=xxf(x) = x^x?

Answer: f(x)=xx(ln(x)+1)f'(x) = x^x(\text{ln}(x)+1). Use logarithmic differentiation for variable base and exponent.

Flashcard 37: Determine the derivative of f(x)=cot(x)f(x) = \text{cot}(x).

Answer: f(x)=csc2(x)f'(x) = -\text{csc}^2(x). Cotangent is cos(x)sin(x)\frac{\cos(x)}{\sin(x)}, use quotient rule.

Flashcard 38: What is the derivative of f(x)=x2f(x) = x^2?

Answer: f(x)=2xf'(x) = 2x. Apply power rule: bring down exponent 2, reduce power by 1.

Flashcard 39: What is the derivative of f(x)=ln(x2)f(x) = \text{ln}(x^2)?

Answer: f(x)=2xf'(x) = \frac{2}{x}. Use chain rule: 1x22x=2x\frac{1}{x^2} \cdot 2x = \frac{2}{x}.

Flashcard 40: What is the derivative of f(x)=1xf(x) = \frac{1}{x}?

Answer: f(x)=1x2f'(x) = -\frac{1}{x^2}. Rewrite as x1x^{-1} and apply power rule.

Flashcard 41: State the derivative of f(x)=arcsin(x)f(x) = \text{arcsin}(x).

Answer: f(x)=1sqrt(1x2)f'(x) = \frac{1}{\text{sqrt}(1-x^2)}. Standard inverse trig derivative formula.

Flashcard 42: State the power rule for derivatives.

Answer: ddx[xn]=nxn1\frac{d}{dx}[x^n] = nx^{n-1}. Multiply by exponent, then decrease exponent by 1.

Flashcard 43: Calculate the derivative of f(x)=e2xf(x) = \text{e}^{2x}.

Answer: f(x)=2e2xf'(x) = 2\text{e}^{2x}. Chain rule: multiply by inner derivative 2.

Flashcard 44: What is the rate of change of f(x)=7f(x) = 7?

Answer: Rate of change is 0. Constant functions have zero rate of change.

Flashcard 45: What is the rate of change for f(x)=x3f(x) = x^3 at x=1x = 1?

Answer: Rate of change is 3. Use f(x)=3x2f'(x) = 3x^2, evaluate at x=1x = 1.

Flashcard 46: Identify the derivative of f(x)=arctan(x)f(x) = \text{arctan}(x).

Answer: f(x)=11+x2f'(x) = \frac{1}{1+x^2}. Standard inverse trig derivative for arctangent.

Flashcard 47: Find the rate of change of f(x)=4x7f(x) = 4x - 7 at x=2x = 2.

Answer: Rate of change is 4. Linear function has constant slope 4.

Flashcard 48: Find the derivative of f(x)=sec(x)f(x) = \text{sec}(x).

Answer: f(x)=sec(x)tan(x)f'(x) = \text{sec}(x)\text{tan}(x). Product rule applied to sec(x)=1cos(x)\sec(x) = \frac{1}{\cos(x)}.

Flashcard 49: Determine f(x)f'(x) for f(x)=ln(x)f(x) = \text{ln}(x).

Answer: f(x)=1xf'(x) = \frac{1}{x}. Natural log derivative is reciprocal function.

Flashcard 50: Determine the derivative of f(x)=arcsec(x)f(x) = \text{arcsec}(x).

Answer: f(x)=1xsqrt(x21)f'(x) = \frac{1}{|x|\text{sqrt}(x^2-1)}. Involves absolute value for proper domain.

Flashcard 51: Calculate ddx[x52x3]\frac{d}{dx}[x^5 - 2x^3].

Answer: 5x46x25x^4 - 6x^2. Apply power rule to each term separately.

Flashcard 52: Identify the derivative of f(x)=tan2(x)f(x) = \text{tan}^2(x).

Answer: f(x)=2tan(x)sec2(x)f'(x) = 2\text{tan}(x)\text{sec}^2(x). Chain rule applied to tan2(x)\tan^2(x).

Flashcard 53: Determine the derivative of f(x)=x12f(x) = x^{\frac{1}{2}}.

Answer: f(x)=12x12f'(x) = \frac{1}{2}x^{-\frac{1}{2}}. Power rule with fractional exponent 12\frac{1}{2}.

Flashcard 54: Define instantaneous rate of change.

Answer: The derivative at a specific point. The slope of tangent line at one point.

Flashcard 55: Determine the derivative of f(x)=x12f(x) = x^{\frac{1}{2}}.

Answer: f(x)=12x12f'(x) = \frac{1}{2}x^{-\frac{1}{2}}. Power rule with fractional exponent 12\frac{1}{2}.

Flashcard 56: Identify the derivative of f(x)=tan(x)f(x) = \tan(x).

Answer: f(x)=sec2(x)f'(x) = \sec^2(x). Tangent differentiates to secant squared.

Flashcard 57: Determine the derivative of f(x)=arcsec(x)f(x) = \text{arcsec}(x).

Answer: f(x)=1xsqrt(x21)f'(x) = \frac{1}{|x|\text{sqrt}(x^2-1)}. Involves absolute value for proper domain.

Flashcard 58: What is the derivative of f(x)=arccsc(x)f(x) = \text{arccsc}(x)?

Answer: f(x)=1xsqrt(x21)f'(x) = -\frac{1}{|x|\text{sqrt}(x^2-1)}. Negative of arcsecant derivative.

Flashcard 59: Calculate the derivative of f(x)=e2xf(x) = \text{e}^{2x}.

Answer: f(x)=2e2xf'(x) = 2\text{e}^{2x}. Chain rule: multiply by inner derivative 2.

Flashcard 60: Calculate the derivative of f(x)=arccot(x)f(x) = \text{arccot}(x).

Answer: f(x)=11+x2f'(x) = -\frac{1}{1+x^2}. Negative of arctangent derivative.

Flashcard 61: Calculate the derivative of f(x)=arccot(x)f(x) = \text{arccot}(x).

Answer: f(x)=11+x2f'(x) = -\frac{1}{1+x^2}. Negative of arctangent derivative.

Flashcard 62: Identify the derivative of f(x)=arctan(x)f(x) = \text{arctan}(x).

Answer: f(x)=11+x2f'(x) = \frac{1}{1+x^2}. Standard inverse trig derivative for arctangent.

Flashcard 63: What is the rate of change for f(x)=x3f(x) = x^3 at x=1x = 1?

Answer: Rate of change is 3. Use f(x)=3x2f'(x) = 3x^2, evaluate at x=1x = 1.

Flashcard 64: What is the derivative of f(x)=cos2(x)f(x) = \text{cos}^2(x)?

Answer: f(x)=2sin(x)cos(x)f'(x) = -2\text{sin}(x)\text{cos}(x). Chain rule gives negative of sin2(x)\sin^2(x) derivative.

Flashcard 65: Identify the derivative of f(x)=exf(x) = e^x.

Answer: f(x)=exf'(x) = e^x. Exponential function exe^x is its own derivative.

Flashcard 66: Determine the derivative of f(x)=cot(x)f(x) = \text{cot}(x).

Answer: f(x)=csc2(x)f'(x) = -\text{csc}^2(x). Cotangent is cos(x)sin(x)\frac{\cos(x)}{\sin(x)}, use quotient rule.

Flashcard 67: What is the derivative of f(x)=x2f(x) = x^2?

Answer: f(x)=2xf'(x) = 2x. Apply power rule: bring down exponent 2, reduce power by 1.

Flashcard 68: What is the derivative of f(x)=1xf(x) = \frac{1}{x}?

Answer: f(x)=1x2f'(x) = -\frac{1}{x^2}. Rewrite as x1x^{-1} and apply power rule.

Flashcard 69: What is the derivative of f(x)=csc(x)f(x) = \text{csc}(x)?

Answer: f(x)=csc(x)cot(x)f'(x) = -\text{csc}(x)\text{cot}(x). Quotient rule applied to csc(x)=1sin(x)\csc(x) = \frac{1}{\sin(x)}.