Study Rates Of Change in AP Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Flashcard 1: If y=3x3−5x, what is dxdy?
Answer: dxdy=9x2−5. Use power rule: 3⋅3x2−5⋅1.
Flashcard 2: What is the derivative of f(x)=loga(x)?
Answer: f′(x)=xln(a)1. Change of base gives factor ln(a)1.
Flashcard 3: Find the derivative of f(x)=sec(x).
Answer: f′(x)=sec(x)tan(x). Product rule applied to sec(x)=cos(x)1.
Flashcard 4: What is the derivative of f(x)=cos2(x)?
Answer: f′(x)=−2sin(x)cos(x). Chain rule gives negative of sin2(x) derivative.
Flashcard 5: State the derivative of f(x)=arcsin(x).
Answer: f'(x) = \frac{1}{\sqrt{1-x^2)}. Standard inverse trig derivative formula.
Flashcard 6: Identify the derivative of f(x)=tan2(x).
Answer: f′(x)=2tan(x)sec2(x). Chain rule applied to tan2(x).
Flashcard 7: Identify the derivative of f(x)=ex.
Answer: f′(x)=ex. Exponential function ex is its own derivative.
Flashcard 8: What is the derivative of f(x)=arccsc(x)?
Answer: f′(x)=−∣x∣sqrt(x2−1)1. Negative of arcsecant derivative.
Flashcard 9: State the derivative of f(x)=sin2(x).
Answer: f′(x)=2sin(x)cos(x). Use chain rule on sin2(x).
Flashcard 10: What is the rate of change of f(x)=7?
Answer: Rate of change is 0. Constant functions have zero rate of change.
Flashcard 11: What is the rate of change of f(x)=x4 at x=2?
Answer: Rate of change is 32. Use f′(x)=4x3, evaluate at x=2.
Flashcard 12: What is the rate of change of f(x)=x2+3x at x=1?
Answer: Rate of change is 5. Use f′(x)=2x+3, evaluate at x=1.
Flashcard 13: What is the derivative of f(x)=x31?
Answer: f′(x)=−x43. Rewrite as x−3 and apply power rule.
Flashcard 14: What is the derivative of f(x)=ln(x2)?
Answer: f′(x)=x2. Use chain rule: x21⋅2x=x2.
Flashcard 15: Identify the derivative of f(x)=tan(x).
Answer: f′(x)=sec2(x). Tangent differentiates to secant squared.
Flashcard 16: Calculate dxd[5x2].
Answer: 10x. Factor out constant 5, apply power rule.
Flashcard 17: State the constant rule for derivatives.
Answer: Derivative of a constant is 0. Constants have zero slope everywhere.
Flashcard 18: What is the derivative of f(x)=loga(x)?
Answer: f′(x)=xln(a)1. Change of base gives factor ln(a)1.
Flashcard 19: Determine the derivative of f(x)=5x.
Answer: f′(x)=5xln(5). General formula ax derivative includes ln(a) factor.
Flashcard 20: Find f′(x) for f(x)=sin(x).
Answer: f′(x)=cos(x). Sine differentiates to cosine.
Flashcard 21: What is the derivative of f(x)=arccos(x)?
Answer: f′(x)=−sqrt(1−x2)1. Negative of arcsine derivative.
Flashcard 22: What is the derivative of f(x)=xx?
Answer: f′(x)=xx(ln(x)+1). Use logarithmic differentiation for variable base and exponent.
Flashcard 23: State the constant rule for derivatives.
Answer: Derivative of a constant is 0. Constants have zero slope everywhere.
Flashcard 24: What is the rate of change of f(x)=x2+3x at x=1?
Answer: Rate of change is 5. Use f′(x)=2x+3, evaluate at x=1.
Flashcard 25: Determine the derivative of f(x)=5x.
Answer: f′(x)=5xln(5). General formula ax derivative includes ln(a) factor.
Flashcard 26: What is the derivative of f(x)=cos(x)?
Answer: f′(x)=−sin(x). Cosine differentiates to negative sine.
Flashcard 27: What is the derivative of f(x)=arccos(x)?
Answer: f′(x)=−sqrt(1−x2)1. Negative of arcsine derivative.
Flashcard 28: Calculate dxd[x5−2x3].
Answer: 5x4−6x2. Apply power rule to each term separately.
Flashcard 29: If y=3x3−5x, what is dxdy?
Answer: dxdy=9x2−5. Use power rule: 3⋅3x2−5⋅1.
Flashcard 30: Calculate dxd[5x2].
Answer: 10x. Factor out constant 5, apply power rule.
Flashcard 31: Define average rate of change of a function f(x) over [a,b].
Answer: b−af(b)−f(a). Slope formula between two points on the function.
Flashcard 32: What is the derivative of f(x)=csc(x)?
Answer: f′(x)=−csc(x)cot(x). Quotient rule applied to csc(x)=sin(x)1.
Flashcard 33: What is the rate of change of f(x)=x4 at x=2?
Answer: Rate of change is 32. Use f′(x)=4x3, evaluate at x=2.
Flashcard 34: What is the instantaneous rate of change at x=a?
Answer: The derivative f′(a). Limit of average rate of change as interval approaches zero.
Flashcard 35: State the derivative of f(x)=sin2(x).
Answer: f′(x)=2sin(x)cos(x). Use chain rule on sin2(x).
Flashcard 36: What is the derivative of f(x)=xx?
Answer: f′(x)=xx(ln(x)+1). Use logarithmic differentiation for variable base and exponent.
Flashcard 37: Determine the derivative of f(x)=cot(x).
Answer: f′(x)=−csc2(x). Cotangent is sin(x)cos(x), use quotient rule.
Flashcard 38: What is the derivative of f(x)=x2?
Answer: f′(x)=2x. Apply power rule: bring down exponent 2, reduce power by 1.
Flashcard 39: What is the derivative of f(x)=ln(x2)?
Answer: f′(x)=x2. Use chain rule: x21⋅2x=x2.
Flashcard 40: What is the derivative of f(x)=x1?
Answer: f′(x)=−x21. Rewrite as x−1 and apply power rule.
Flashcard 41: State the derivative of f(x)=arcsin(x).
Answer: f′(x)=sqrt(1−x2)1. Standard inverse trig derivative formula.
Flashcard 42: State the power rule for derivatives.
Answer: dxd[xn]=nxn−1. Multiply by exponent, then decrease exponent by 1.
Flashcard 43: Calculate the derivative of f(x)=e2x.
Answer: f′(x)=2e2x. Chain rule: multiply by inner derivative 2.
Flashcard 44: What is the rate of change of f(x)=7?
Answer: Rate of change is 0. Constant functions have zero rate of change.
Flashcard 45: What is the rate of change for f(x)=x3 at x=1?
Answer: Rate of change is 3. Use f′(x)=3x2, evaluate at x=1.
Flashcard 46: Identify the derivative of f(x)=arctan(x).
Answer: f′(x)=1+x21. Standard inverse trig derivative for arctangent.
Flashcard 47: Find the rate of change of f(x)=4x−7 at x=2.
Answer: Rate of change is 4. Linear function has constant slope 4.
Flashcard 48: Find the derivative of f(x)=sec(x).
Answer: f′(x)=sec(x)tan(x). Product rule applied to sec(x)=cos(x)1.
Flashcard 49: Determine f′(x) for f(x)=ln(x).
Answer: f′(x)=x1. Natural log derivative is reciprocal function.
Flashcard 50: Determine the derivative of f(x)=arcsec(x).
Answer: f′(x)=∣x∣sqrt(x2−1)1. Involves absolute value for proper domain.
Flashcard 51: Calculate dxd[x5−2x3].
Answer: 5x4−6x2. Apply power rule to each term separately.
Flashcard 52: Identify the derivative of f(x)=tan2(x).
Answer: f′(x)=2tan(x)sec2(x). Chain rule applied to tan2(x).
Flashcard 53: Determine the derivative of f(x)=x21.
Answer: f′(x)=21x−21. Power rule with fractional exponent 21.
Flashcard 54: Define instantaneous rate of change.
Answer: The derivative at a specific point. The slope of tangent line at one point.
Flashcard 55: Determine the derivative of f(x)=x21.
Answer: f′(x)=21x−21. Power rule with fractional exponent 21.
Flashcard 56: Identify the derivative of f(x)=tan(x).
Answer: f′(x)=sec2(x). Tangent differentiates to secant squared.
Flashcard 57: Determine the derivative of f(x)=arcsec(x).
Answer: f′(x)=∣x∣sqrt(x2−1)1. Involves absolute value for proper domain.
Flashcard 58: What is the derivative of f(x)=arccsc(x)?
Answer: f′(x)=−∣x∣sqrt(x2−1)1. Negative of arcsecant derivative.
Flashcard 59: Calculate the derivative of f(x)=e2x.
Answer: f′(x)=2e2x. Chain rule: multiply by inner derivative 2.
Flashcard 60: Calculate the derivative of f(x)=arccot(x).
Answer: f′(x)=−1+x21. Negative of arctangent derivative.
Flashcard 61: Calculate the derivative of f(x)=arccot(x).
Answer: f′(x)=−1+x21. Negative of arctangent derivative.
Flashcard 62: Identify the derivative of f(x)=arctan(x).
Answer: f′(x)=1+x21. Standard inverse trig derivative for arctangent.
Flashcard 63: What is the rate of change for f(x)=x3 at x=1?
Answer: Rate of change is 3. Use f′(x)=3x2, evaluate at x=1.
Flashcard 64: What is the derivative of f(x)=cos2(x)?
Answer: f′(x)=−2sin(x)cos(x). Chain rule gives negative of sin2(x) derivative.
Flashcard 65: Identify the derivative of f(x)=ex.
Answer: f′(x)=ex. Exponential function ex is its own derivative.
Flashcard 66: Determine the derivative of f(x)=cot(x).
Answer: f′(x)=−csc2(x). Cotangent is sin(x)cos(x), use quotient rule.
Flashcard 67: What is the derivative of f(x)=x2?
Answer: f′(x)=2x. Apply power rule: bring down exponent 2, reduce power by 1.
Flashcard 68: What is the derivative of f(x)=x1?
Answer: f′(x)=−x21. Rewrite as x−1 and apply power rule.
Flashcard 69: What is the derivative of f(x)=csc(x)?
Answer: f′(x)=−csc(x)cot(x). Quotient rule applied to csc(x)=sin(x)1.