Study Trigonometry And Polar Coordinates in AP Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: State the angle addition formula for cosine. Answer: cos ( a + b ) = cos a cos b − sin a sin b \cos(a + b) = \cos a \cos b - \sin a \sin b cos ( a + b ) = cos a cos b − sin a sin b . Used to find cosine of sum of two angles.
Flashcard 2: What is the secant of an angle in terms of cosine? Answer: Secant = 1 cos θ \frac{1}{\cos \theta} c o s θ 1 . Reciprocal function of cosine.
Flashcard 3: What is the double angle formula for tangent? Answer: tan ( 2 θ ) = 2 tan θ 1 − tan 2 θ \tan(2\theta) = \frac{2\tan \theta}{1 - \tan^2 \theta} tan ( 2 θ ) = 1 − t a n 2 θ 2 t a n θ . Derived from angle addition formulas.
Flashcard 4: State the Pythagorean identity. Answer: sin 2 θ + cos 2 θ = 1 \sin^2 \theta + \cos^2 \theta = 1 sin 2 θ + cos 2 θ = 1 . Fundamental trigonometric identity from unit circle.
Flashcard 5: What is the half-angle formula for tangent? Answer: tan ( θ 2 ) = ± 1 − cos θ 1 + cos θ \tan(\frac{\theta}{2}) = \pm \sqrt{\frac{1 - \cos \theta}{1 + \cos \theta}} tan ( 2 θ ) = ± 1 + c o s θ 1 − c o s θ . Sign depends on quadrant of θ 2 \frac{\theta}{2} 2 θ .
Flashcard 6: What is the polar form of the complex number − 1 + i 3 -1 + i\sqrt{3} − 1 + i 3 ? Answer: 2 ( cos 2 π 3 + i sin 2 π 3 ) 2(\cos \frac{2\pi}{3} + i \sin \frac{2\pi}{3}) 2 ( cos 3 2 π + i sin 3 2 π ) . Magnitude 2 2 2 , argument 2 π 3 \frac{2\pi}{3} 3 2 π .
Flashcard 7: What is the polar form of the complex number − 2 − 2 i -2 - 2i − 2 − 2 i ? Answer: 2 2 ( cos 5 π 4 + i sin 5 π 4 ) 2\sqrt{2}(\cos \frac{5\pi}{4} + i \sin \frac{5\pi}{4}) 2 2 ( cos 4 5 π + i sin 4 5 π ) . Magnitude 2 2 2\sqrt{2} 2 2 , argument 5 π 4 \frac{5\pi}{4} 4 5 π .
Flashcard 8: What are the polar coordinates of the origin? Answer: ( 0 , 0 ) (0, 0) ( 0 , 0 ) . The pole has radius 0 0 0 and undefined angle.
Flashcard 9: What is the double angle formula for tangent? Answer: tan ( 2 θ ) = 2 tan θ 1 − tan 2 θ \tan(2\theta) = \frac{2\tan \theta}{1 - \tan^2 \theta} tan ( 2 θ ) = 1 − t a n 2 θ 2 t a n θ . Derived from angle addition formulas.
Flashcard 10: What is the half-angle formula for sine? Answer: sin ( θ 2 ) = ± 1 − cos θ 2 \sin(\frac{\theta}{2}) = \pm \sqrt{\frac{1 - \cos \theta}{2}} sin ( 2 θ ) = ± 2 1 − c o s θ . Sign depends on quadrant of θ 2 \frac{\theta}{2} 2 θ .
Flashcard 11: What is the half-angle formula for cosine? Answer: cos ( θ 2 ) = ± 1 + cos θ 2 \cos(\frac{\theta}{2}) = \pm \sqrt{\frac{1 + \cos \theta}{2}} cos ( 2 θ ) = ± 2 1 + c o s θ . Sign depends on quadrant of θ 2 \frac{\theta}{2} 2 θ .
Flashcard 12: What is the polar form of the complex number 1 + i 1 + i 1 + i ? Answer: 2 ( cos π 4 + i sin π 4 ) \sqrt{2}(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4}) 2 ( cos 4 π + i sin 4 π ) . Magnitude 2 \sqrt{2} 2 , argument π 4 \frac{\pi}{4} 4 π .
Flashcard 13: What is the cotangent of an angle in terms of tangent? Answer: Cotangent = 1 tan θ \frac{1}{\tan \theta} t a n θ 1 . Reciprocal function of tangent.
Flashcard 14: State the Pythagorean identity. Answer: sin 2 θ + cos 2 θ = 1 \sin^2 \theta + \cos^2 \theta = 1 sin 2 θ + cos 2 θ = 1 . Fundamental trigonometric identity from unit circle.
Flashcard 15: State the formula for converting Cartesian to polar coordinates. Answer: r = x 2 + y 2 , θ = tan − 1 ( y x ) r = \sqrt{x^2 + y^2}, \theta = \tan^{-1}(\frac{y}{x}) r = x 2 + y 2 , θ = tan − 1 ( x y ) . Distance formula and arctangent function.
Flashcard 16: Convert ( 1 , π 3 ) (1, \frac{\pi}{3}) ( 1 , 3 π ) from polar to Cartesian coordinates. Answer: ( 0.5 , 0.866 ) (0.5, 0.866) ( 0.5 , 0.866 ) . Use x = r cos θ x = r\cos\theta x = r cos θ , y = r sin θ y = r\sin\theta y = r sin θ .
Flashcard 17: What is the sine of an angle in a right triangle? Answer: Sine = Opposite side / Hypotenuse. Basic trigonometric ratio in right triangles.
Flashcard 18: Find the exact value of cos ( 60 ∘ ) \cos(60^\circ) cos ( 6 0 ∘ ) . Answer: 1 2 \frac{1}{2} 2 1 . Standard unit circle value.
Flashcard 19: What is the half-angle formula for tangent? Answer: tan ( θ 2 ) = ± 1 − cos θ 1 + cos θ \tan(\frac{\theta}{2}) = \pm \sqrt{\frac{1 - \cos \theta}{1 + \cos \theta}} tan ( 2 θ ) = ± 1 + c o s θ 1 − c o s θ . Sign depends on quadrant of θ 2 \frac{\theta}{2} 2 θ .
Flashcard 20: What is the cosecant of an angle in terms of sine? Answer: Cosecant = 1 sin θ \frac{1}{\sin \theta} s i n θ 1 . Reciprocal function of sine.
Flashcard 21: Find the exact value of sin ( 30 ∘ ) \sin(30^\circ) sin ( 3 0 ∘ ) . Answer: 1 2 \frac{1}{2} 2 1 . Standard unit circle value.
Flashcard 22: Convert ( 1 , π 3 ) (1, \frac{\pi}{3}) ( 1 , 3 π ) from polar to Cartesian coordinates. Answer: ( 0.5 , 0.866 ) (0.5, 0.866) ( 0.5 , 0.866 ) . Use x = r cos θ x = r\cos\theta x = r cos θ , y = r sin θ y = r\sin\theta y = r sin θ .
Flashcard 23: What is the double angle formula for sine? Answer: sin ( 2 θ ) = 2 sin θ cos θ \sin(2\theta) = 2\sin \theta \cos \theta sin ( 2 θ ) = 2 sin θ cos θ . Derived from angle addition formulas.
Flashcard 24: What is the law of cosines? Answer: c 2 = a 2 + b 2 − 2 a b cos C c^2 = a^2 + b^2 - 2ab\cos C c 2 = a 2 + b 2 − 2 ab cos C . Relates all three sides and one angle.
Flashcard 25: What is the double angle formula for cosine? Answer: cos ( 2 θ ) = cos 2 θ − sin 2 θ \cos(2\theta) = \cos^2 \theta - \sin^2 \theta cos ( 2 θ ) = cos 2 θ − sin 2 θ . Derived from angle addition formulas.
Flashcard 26: What is the polar equation of a circle centered at the origin? Answer: r = a r = a r = a . All points equidistant from origin.
Flashcard 27: State the angle addition formula for sine. Answer: sin ( a + b ) = sin a cos b + cos a sin b \sin(a + b) = \sin a \cos b + \cos a \sin b sin ( a + b ) = sin a cos b + cos a sin b . Used to find sine of sum of two angles.
Flashcard 28: What is the cosecant of an angle in terms of sine? Answer: Cosecant = 1 sin θ \frac{1}{\sin \theta} s i n θ 1 . Reciprocal function of sine.
Flashcard 29: State the angle addition formula for tangent. Answer: tan ( a + b ) = tan a + tan b 1 − tan a tan b \tan(a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b} tan ( a + b ) = 1 − t a n a t a n b t a n a + t a n b . Used to find tangent of sum of two angles.
Flashcard 30: What is the tangent of an angle in a right triangle? Answer: Tangent = Opposite side / Adjacent side. Basic trigonometric ratio in right triangles.
Flashcard 31: Find the exact value of sin ( 30 ∘ ) \sin(30^\circ) sin ( 3 0 ∘ ) . Answer: 1 2 \frac{1}{2} 2 1 . Standard unit circle value.
Flashcard 32: What is the law of sines? Answer: a sin A = b sin B = c sin C \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} s i n A a = s i n B b = s i n C c . Ratios of sides to opposite angles are equal.
Flashcard 33: State the formula for converting polar to Cartesian coordinates. Answer: x = r cos θ , y = r sin θ x = r \cos \theta, y = r \sin \theta x = r cos θ , y = r sin θ . Use trigonometric definitions.
Flashcard 34: What is the polar equation of a line through the origin? Answer: θ = α \theta = \alpha θ = α . All points on ray from origin at angle α \alpha α .
Flashcard 35: State the angle addition formula for tangent. Answer: tan ( a + b ) = tan a + tan b 1 − tan a tan b \tan(a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b} tan ( a + b ) = 1 − t a n a t a n b t a n a + t a n b . Used to find tangent of sum of two angles.
Flashcard 36: Convert π 4 \frac{\pi}{4} 4 π radians to degrees. Answer: 45 ∘ 45^\circ 4 5 ∘ . Use π 4 × 180 ∘ π \frac{\pi}{4} \times \frac{180^\circ}{\pi} 4 π × π 18 0 ∘ .
Flashcard 37: What is the polar form of the complex number − 2 − 2 i -2 - 2i − 2 − 2 i ? Answer: 2 2 ( cos 5 π 4 + i sin 5 π 4 ) 2\sqrt{2}(\cos \frac{5\pi}{4} + i \sin \frac{5\pi}{4}) 2 2 ( cos 4 5 π + i sin 4 5 π ) . Magnitude 2 2 2\sqrt{2} 2 2 , argument 5 π 4 \frac{5\pi}{4} 4 5 π .
Flashcard 38: What is the polar form of the complex number − 1 + i 3 -1 + i\sqrt{3} − 1 + i 3 ? Answer: 2 ( cos 2 π 3 + i sin 2 π 3 ) 2(\cos \frac{2\pi}{3} + i \sin \frac{2\pi}{3}) 2 ( cos 3 2 π + i sin 3 2 π ) . Magnitude 2 2 2 , argument 2 π 3 \frac{2\pi}{3} 3 2 π .
Flashcard 39: State the formula for arc length. Answer: Arc Length = r θ r \theta r θ . Where θ \theta θ is in radians.
Flashcard 40: Convert 180 ∘ 180^\circ 18 0 ∘ to radians. Answer: π \pi π radians. Use 180 ∘ × π 180 ∘ 180^\circ \times \frac{\pi}{180^\circ} 18 0 ∘ × 18 0 ∘ π .
Flashcard 41: What is the double angle formula for cosine? Answer: cos ( 2 θ ) = cos 2 θ − sin 2 θ \cos(2\theta) = \cos^2 \theta - \sin^2 \theta cos ( 2 θ ) = cos 2 θ − sin 2 θ . Derived from angle addition formulas.
Flashcard 42: What is the tangent of an angle in a right triangle? Answer: Tangent = Opposite side / Adjacent side. Basic trigonometric ratio in right triangles.
Flashcard 43: What is the cosine of an angle in a right triangle? Answer: Cosine = Adjacent side / Hypotenuse. Basic trigonometric ratio in right triangles.
Flashcard 44: What is the half-angle formula for sine? Answer: sin ( θ 2 ) = ± 1 − cos θ 2 \sin(\frac{\theta}{2}) = \pm \sqrt{\frac{1 - \cos \theta}{2}} sin ( 2 θ ) = ± 2 1 − c o s θ . Sign depends on quadrant of θ 2 \frac{\theta}{2} 2 θ .
Flashcard 45: State the formula for arc length. Answer: Arc Length = r θ r \theta r θ . Where θ \theta θ is in radians.
Flashcard 46: State the formula for converting polar to Cartesian coordinates. Answer: x = r cos θ , y = r sin θ x = r \cos \theta, y = r \sin \theta x = r cos θ , y = r sin θ . Use trigonometric definitions.
Flashcard 47: State the formula for sector area. Answer: Sector Area = 1 2 r 2 θ \frac{1}{2} r^2 \theta 2 1 r 2 θ . Where θ \theta θ is in radians.
Flashcard 48: What is the law of cosines? Answer: c 2 = a 2 + b 2 − 2 a b cos C c^2 = a^2 + b^2 - 2ab\cos C c 2 = a 2 + b 2 − 2 ab cos C . Relates all three sides and one angle.
Flashcard 49: State the formula for sector area. Answer: Sector Area = 1 2 r 2 θ \frac{1}{2} r^2 \theta 2 1 r 2 θ . Where θ \theta θ is in radians.
Flashcard 50: What is the secant of an angle in terms of cosine? Answer: Secant = 1 cos θ \frac{1}{\cos \theta} c o s θ 1 . Reciprocal function of cosine.
Flashcard 51: What is the polar form of the complex number 1 + i 1 + i 1 + i ? Answer: 2 ( cos π 4 + i sin π 4 ) \sqrt{2}(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4}) 2 ( cos 4 π + i sin 4 π ) . Magnitude 2 \sqrt{2} 2 , argument π 4 \frac{\pi}{4} 4 π .
Flashcard 52: What is the cosine of an angle in a right triangle? Answer: Cosine = Adjacent side / Hypotenuse. Basic trigonometric ratio in right triangles.
Flashcard 53: Find the reference angle for 210 ∘ 210^\circ 21 0 ∘ . Answer: 30 ∘ 30^\circ 3 0 ∘ . Subtract 180 ∘ 180^\circ 18 0 ∘ from third quadrant angle.
Flashcard 54: Convert 180 ∘ 180^\circ 18 0 ∘ to radians. Answer: π \pi π radians. Use 180 ∘ × π 180 ∘ 180^\circ \times \frac{\pi}{180^\circ} 18 0 ∘ × 18 0 ∘ π .
Flashcard 55: What are the polar coordinates of the origin? Answer: ( 0 , 0 ) (0, 0) ( 0 , 0 ) . The pole has radius 0 0 0 and undefined angle.
Flashcard 56: What is the law of sines? Answer: a sin A = b sin B = c sin C \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} s i n A a = s i n B b = s i n C c . Ratios of sides to opposite angles are equal.
Flashcard 57: What is the polar equation of a line through the origin? Answer: θ = α \theta = \alpha θ = α . All points on ray from origin at angle α \alpha α .
Flashcard 58: Find the exact value of cos ( 60 ∘ ) \cos(60^\circ) cos ( 6 0 ∘ ) . Answer: 1 2 \frac{1}{2} 2 1 . Standard unit circle value.
Flashcard 59: What is the double angle formula for sine? Answer: sin ( 2 θ ) = 2 sin θ cos θ \sin(2\theta) = 2\sin \theta \cos \theta sin ( 2 θ ) = 2 sin θ cos θ . Derived from angle addition formulas.
Flashcard 60: Find the exact value of tan ( 45 ∘ ) \tan(45^\circ) tan ( 4 5 ∘ ) . Answer:
Standard unit circle value.
Flashcard 61: Convert π 4 \frac{\pi}{4} 4 π radians to degrees. Answer: 45 ∘ 45^\circ 4 5 ∘ . Use π 4 × 180 ∘ π \frac{\pi}{4} \times \frac{180^\circ}{\pi} 4 π × π 18 0 ∘ .
Flashcard 62: State the formula for converting Cartesian to polar coordinates. Answer: r = x 2 + y 2 , θ = tan − 1 ( y x ) r = \sqrt{x^2 + y^2}, \theta = \tan^{-1}(\frac{y}{x}) r = x 2 + y 2 , θ = tan − 1 ( x y ) . Distance formula and arctangent function.
Flashcard 63: Find the reference angle for 210 ∘ 210^\circ 21 0 ∘ . Answer: 30 ∘ 30^\circ 3 0 ∘ . Subtract 180 ∘ 180^\circ 18 0 ∘ from third quadrant angle.
Flashcard 64: What is the sine of an angle in a right triangle? Answer: Sine = Opposite side / Hypotenuse. Basic trigonometric ratio in right triangles.
Flashcard 65: What is the half-angle formula for cosine? Answer: cos ( θ 2 ) = ± 1 + cos θ 2 \cos(\frac{\theta}{2}) = \pm \sqrt{\frac{1 + \cos \theta}{2}} cos ( 2 θ ) = ± 2 1 + c o s θ . Sign depends on quadrant of θ 2 \frac{\theta}{2} 2 θ .
Flashcard 66: State the angle addition formula for cosine. Answer: cos ( a + b ) = cos a cos b − sin a sin b \cos(a + b) = \cos a \cos b - \sin a \sin b cos ( a + b ) = cos a cos b − sin a sin b . Used to find cosine of sum of two angles.
Flashcard 67: Find the exact value of tan ( 45 ∘ ) \tan(45^\circ) tan ( 4 5 ∘ ) . Answer:
Standard unit circle value.
Flashcard 68: What is the polar equation of a circle centered at the origin? Answer: r = a r = a r = a . All points equidistant from origin.
Flashcard 69: State the angle addition formula for sine. Answer: sin ( a + b ) = sin a cos b + cos a sin b \sin(a + b) = \sin a \cos b + \cos a \sin b sin ( a + b ) = sin a cos b + cos a sin b . Used to find sine of sum of two angles.
Flashcard 70: What is the cotangent of an angle in terms of tangent? Answer: Cotangent = 1 tan θ \frac{1}{\tan \theta} t a n θ 1 . Reciprocal function of tangent.