AP Statistics Flashcards: Combining Random Variables

Study Combining Random Variables in AP Statistics with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Statistics

Combining Random Variables

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QUESTION
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What is the variance of 2Y2Y given Var(Y)=4\text{Var}(Y) = 4?

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ANSWER

Var(2Y)=16\text{Var}(2Y) = 16. Apply variance scaling: 22(4)=4(4)=162^2(4) = 4(4) = 16.

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This deck focuses on Combining Random Variables, giving you a quick way to review the definitions, rules, and examples that matter most for AP Statistics.

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Flashcard 1: What is the variance of 2Y2Y given Var(Y)=4\text{Var}(Y) = 4?

Answer: Var(2Y)=16\text{Var}(2Y) = 16. Apply variance scaling: 22(4)=4(4)=162^2(4) = 4(4) = 16.

Flashcard 2: What is the formula for the variance of a random variable aXaX?

Answer: Var(aX)=a2Var(X)\text{Var}(aX) = a^2\text{Var}(X). Variance scales by the square of the constant multiplier.

Flashcard 3: What is the formula for the mean of the sum of two random variables XX and YY?

Answer: E(X+Y)=E(X)+E(Y)\text{E}(X + Y) = \text{E}(X) + \text{E}(Y). Expected value is linear, so sums distribute across expectations.

Flashcard 4: What is the mean of 2X+3Y2X + 3Y given E(X)=4\text{E}(X) = 4 and E(Y)=6\text{E}(Y) = 6?

Answer: E(2X+3Y)=26\text{E}(2X + 3Y) = 26. Apply linear combination: 2(4)+3(6)=8+18=262(4) + 3(6) = 8 + 18 = 26.

Flashcard 5: What is the standard deviation of 2Y2Y given SD(Y)=3\text{SD}(Y) = 3?

Answer: SD(2Y)=6\text{SD}(2Y) = 6. Apply standard deviation scaling: 2(3)=62(3) = 6.

Flashcard 6: What is the formula for the standard deviation of aXaX?

Answer: SD(aX)=aSD(X)\text{SD}(aX) = |a|\text{SD}(X). Standard deviation scales by absolute value of the constant.

Flashcard 7: What is the formula for the variance of a random variable aXaX?

Answer: Var(aX)=a2Var(X)\text{Var}(aX) = a^2\text{Var}(X). Variance scales by the square of the constant multiplier.

Flashcard 8: What is the variance of X+Y+ZX + Y + Z given Var(X)=1\text{Var}(X) = 1, Var(Y)=2\text{Var}(Y) = 2, and Var(Z)=3\text{Var}(Z) = 3, assuming independence?

Answer: Var(X+Y+Z)=6\text{Var}(X + Y + Z) = 6. Sum all variances: 1+2+3=61 + 2 + 3 = 6.

Flashcard 9: What is the formula for the variance of the sum of two independent random variables XX and YY?

Answer: Var(X+Y)=Var(X)+Var(Y)\text{Var}(X + Y) = \text{Var}(X) + \text{Var}(Y). For independent variables, variances add when combining random variables.

Flashcard 10: What is the mean of 2Y2Y given E(Y)=6\text{E}(Y) = 6?

Answer: E(2Y)=12\text{E}(2Y) = 12. Apply scaling: 2(6)=122(6) = 12.

Flashcard 11: What is the variance of X+Y+ZX + Y + Z given Var(X)=1\text{Var}(X) = 1, Var(Y)=2\text{Var}(Y) = 2, Var(Z)=3\text{Var}(Z) = 3, assuming independence?

Answer: Var(X+Y+Z)=6\text{Var}(X + Y + Z) = 6. Sum all variances: 1+2+3=61 + 2 + 3 = 6.

Flashcard 12: What is the formula for the variance of the sum of two independent random variables XX and YY?

Answer: Var(X+Y)=Var(X)+Var(Y)\text{Var}(X + Y) = \text{Var}(X) + \text{Var}(Y). For independent variables, variances add when combining random variables.

Flashcard 13: What is the formula for the mean of the sum of two random variables XX and YY?

Answer: E(X+Y)=E(X)+E(Y)\text{E}(X + Y) = \text{E}(X) + \text{E}(Y). Expected value is linear, so sums distribute across expectations.

Flashcard 14: What is the formula for the mean of a random variable aXaX?

Answer: E(aX)=aE(X)\text{E}(aX) = a\text{E}(X). Expected value scales linearly with multiplication by constants.

Flashcard 15: What is the variance of X+YX + Y given Var(X)=1\text{Var}(X) = 1 and Var(Y)=4\text{Var}(Y) = 4, assuming independence?

Answer: Var(X+Y)=5\text{Var}(X + Y) = 5. For independent variables: 1+4=51 + 4 = 5.

Flashcard 16: What is the formula for the mean of X+Y+ZX + Y + Z?

Answer: E(X+Y+Z)=E(X)+E(Y)+E(Z)\text{E}(X + Y + Z) = \text{E}(X) + \text{E}(Y) + \text{E}(Z). Expected value is linear for any number of variables.

Flashcard 17: What is the variance of 2Y2Y given Var(Y)=4\text{Var}(Y) = 4?

Answer: Var(2Y)=16\text{Var}(2Y) = 16. Apply variance scaling: 22(4)=4(4)=162^2(4) = 4(4) = 16.

Flashcard 18: What is the variance of XYX - Y given Var(X)=3\text{Var}(X) = 3 and Var(Y)=2\text{Var}(Y) = 2, assuming independence?

Answer: Var(XY)=5\text{Var}(X - Y) = 5. For independent variables: 3+2=53 + 2 = 5.

Flashcard 19: What is the formula for the variance of a linear combination aX+bYaX + bY when XX and YY are independent?

Answer: Var(aX+bY)=a2Var(X)+b2Var(Y)\text{Var}(aX + bY) = a^2\text{Var}(X) + b^2\text{Var}(Y). Coefficients are squared when calculating variance of linear combinations.

Flashcard 20: What is the mean of the sum X+Y+ZX + Y + Z given E(X)=3\text{E}(X) = 3, E(Y)=4\text{E}(Y) = 4, and E(Z)=5\text{E}(Z) = 5?

Answer: E(X+Y+Z)=12\text{E}(X + Y + Z) = 12. Sum all expected values: 3+4+5=123 + 4 + 5 = 12.

Flashcard 21: Find the mean of 3X2Y3X - 2Y given E(X)=5\text{E}(X) = 5 and E(Y)=3\text{E}(Y) = 3.

Answer: E(3X2Y)=9\text{E}(3X - 2Y) = 9. Apply linear combination formula: 3(5)2(3)=156=93(5) - 2(3) = 15 - 6 = 9.

Flashcard 22: Find the variance of X+YX + Y given Var(X)=4\text{Var}(X) = 4 and Var(Y)=9\text{Var}(Y) = 9, assuming XX and YY are independent.

Answer: Var(X+Y)=13\text{Var}(X + Y) = 13. For independent variables: 4+9=134 + 9 = 13.

Flashcard 23: What is the mean of 4XY4X - Y given E(X)=5\text{E}(X) = 5 and E(Y)=3\text{E}(Y) = 3?

Answer: E(4XY)=17\text{E}(4X - Y) = 17. Apply linear combination: 4(5)1(3)=203=174(5) - 1(3) = 20 - 3 = 17.

Flashcard 24: What is the formula for the mean of a linear combination aX+bYaX + bY?

Answer: E(aX+bY)=aE(X)+bE(Y)\text{E}(aX + bY) = a\text{E}(X) + b\text{E}(Y). Linearity of expectation applies to any linear combination.

Flashcard 25: What is the mean of the sum X+Y+ZX + Y + Z given E(X)=3\text{E}(X) = 3, E(Y)=4\text{E}(Y) = 4, and E(Z)=5\text{E}(Z) = 5?

Answer: E(X+Y+Z)=12\text{E}(X + Y + Z) = 12. Sum all expected values: 3+4+5=123 + 4 + 5 = 12.

Flashcard 26: Identify the formula for the variance of the difference of two independent random variables XX and YY.

Answer: Var(XY)=Var(X)+Var(Y)\text{Var}(X - Y) = \text{Var}(X) + \text{Var}(Y). Variance of difference equals sum of variances for independent variables.

Flashcard 27: What is the formula for the variance of X+Y+ZX + Y + Z assuming independence?

Answer: Var(X+Y+Z)=Var(X)+Var(Y)+Var(Z)\text{Var}(X + Y + Z) = \text{Var}(X) + \text{Var}(Y) + \text{Var}(Z). Variances add for independent variables regardless of quantity.

Flashcard 28: What is the formula for the mean of a linear combination aX+bYaX + bY?

Answer: E(aX+bY)=aE(X)+bE(Y)\text{E}(aX + bY) = a\text{E}(X) + b\text{E}(Y). Linearity of expectation applies to any linear combination.

Flashcard 29: Find the mean of X+YX + Y given E(X)=5\text{E}(X) = 5 and E(Y)=3\text{E}(Y) = 3.

Answer: E(X+Y)=8\text{E}(X + Y) = 8. Apply linearity: 5+3=85 + 3 = 8.

Flashcard 30: What is the formula for the variance of X+Y+ZX + Y + Z assuming independence?

Answer: Var(X+Y+Z)=Var(X)+Var(Y)+Var(Z)\text{Var}(X + Y + Z) = \text{Var}(X) + \text{Var}(Y) + \text{Var}(Z). Variances add for independent variables regardless of quantity.

Flashcard 31: What is the mean of 2X+3Y+4Z2X + 3Y + 4Z given E(X)=1\text{E}(X) = 1, E(Y)=2\text{E}(Y) = 2, E(Z)=3\text{E}(Z) = 3?

Answer: E(2X+3Y+4Z)=20\text{E}(2X + 3Y + 4Z) = 20. Apply linear combination: 2(1)+3(2)+4(3)=2+6+12=202(1) + 3(2) + 4(3) = 2 + 6 + 12 = 20.

Flashcard 32: What is the formula for the variance of a random variable bYbY?

Answer: Var(bY)=b2Var(Y)\text{Var}(bY) = b^2\text{Var}(Y). Variance scales by the square of the constant multiplier.

Flashcard 33: What is the mean of 5X2Y5X - 2Y given E(X)=2\text{E}(X) = 2 and E(Y)=3\text{E}(Y) = 3?

Answer: E(5X2Y)=4\text{E}(5X - 2Y) = 4. Apply linear combination: 5(2)2(3)=106=45(2) - 2(3) = 10 - 6 = 4.

Flashcard 34: What is the mean of the difference XYX - Y given E(X)=7\text{E}(X) = 7 and E(Y)=2\text{E}(Y) = 2?

Answer: E(XY)=5\text{E}(X - Y) = 5. Apply difference formula: 72=57 - 2 = 5.

Flashcard 35: What is the mean of 5X2Y5X - 2Y given E(X)=2\text{E}(X) = 2 and E(Y)=3\text{E}(Y) = 3?

Answer: E(5X2Y)=4\text{E}(5X - 2Y) = 4. Apply linear combination: 5(2)2(3)=106=45(2) - 2(3) = 10 - 6 = 4.

Flashcard 36: What is the variance of 4XY4X - Y given Var(X)=2\text{Var}(X) = 2 and Var(Y)=1\text{Var}(Y) = 1, assuming independence?

Answer: Var(4XY)=33\text{Var}(4X - Y) = 33. Calculate: 42(2)+12(1)=32+1=334^2(2) + 1^2(1) = 32 + 1 = 33.

Flashcard 37: What is the mean of 4XY4X - Y given E(X)=5\text{E}(X) = 5 and E(Y)=3\text{E}(Y) = 3?

Answer: E(4XY)=17\text{E}(4X - Y) = 17. Apply linear combination: 4(5)1(3)=203=174(5) - 1(3) = 20 - 3 = 17.

Flashcard 38: What is the formula for the mean of a random variable bYbY?

Answer: E(bY)=bE(Y)\text{E}(bY) = b\text{E}(Y). Expected value scales linearly with multiplication by constants.

Flashcard 39: State the formula for the mean of the difference of two random variables XX and YY.

Answer: E(XY)=E(X)E(Y)\text{E}(X - Y) = \text{E}(X) - \text{E}(Y). Expected value is linear, so differences distribute across expectations.

Flashcard 40: What is the formula for the standard deviation of aXaX?

Answer: SD(aX)=aSD(X)\text{SD}(aX) = |a|\text{SD}(X). Standard deviation scales by absolute value of the constant.

Flashcard 41: What is the variance of X+Y+ZX + Y + Z given Var(X)=1\text{Var}(X) = 1, Var(Y)=2\text{Var}(Y) = 2, Var(Z)=3\text{Var}(Z) = 3, assuming independence?

Answer: Var(X+Y+Z)=6\text{Var}(X + Y + Z) = 6. Sum all variances: 1+2+3=61 + 2 + 3 = 6.

Flashcard 42: What is the mean of the difference XYX - Y given E(X)=7\text{E}(X) = 7 and E(Y)=2\text{E}(Y) = 2?

Answer: E(XY)=5\text{E}(X - Y) = 5. Apply difference formula: 72=57 - 2 = 5.

Flashcard 43: What is the mean of 2X+3Y+4Z2X + 3Y + 4Z given E(X)=1\text{E}(X) = 1, E(Y)=2\text{E}(Y) = 2, E(Z)=3\text{E}(Z) = 3?

Answer: E(2X+3Y+4Z)=20\text{E}(2X + 3Y + 4Z) = 20. Apply linear combination: 2(1)+3(2)+4(3)=2+6+12=202(1) + 3(2) + 4(3) = 2 + 6 + 12 = 20.

Flashcard 44: What is the variance of XYX - Y given Var(X)=3\text{Var}(X) = 3 and Var(Y)=2\text{Var}(Y) = 2, assuming independence?

Answer: Var(XY)=5\text{Var}(X - Y) = 5. For independent variables: 3+2=53 + 2 = 5.

Flashcard 45: What is the variance of X+YX + Y given Var(X)=1\text{Var}(X) = 1 and Var(Y)=4\text{Var}(Y) = 4, assuming independence?

Answer: Var(X+Y)=5\text{Var}(X + Y) = 5. For independent variables: 1+4=51 + 4 = 5.

Flashcard 46: What is the variance of 3X3X given Var(X)=5\text{Var}(X) = 5?

Answer: Var(3X)=45\text{Var}(3X) = 45. Apply variance scaling: 32(5)=9(5)=453^2(5) = 9(5) = 45.

Flashcard 47: What is the variance of 4XY4X - Y given Var(X)=2\text{Var}(X) = 2 and Var(Y)=1\text{Var}(Y) = 1, assuming independence?

Answer: Var(4XY)=33\text{Var}(4X - Y) = 33. Calculate: 42(2)+12(1)=32+1=334^2(2) + 1^2(1) = 32 + 1 = 33.

Flashcard 48: What is the mean of 2Y2Y given E(Y)=6\text{E}(Y) = 6?

Answer: E(2Y)=12\text{E}(2Y) = 12. Apply scaling: 2(6)=122(6) = 12.

Flashcard 49: What is the variance of X+Y+ZX + Y + Z given Var(X)=1\text{Var}(X) = 1, Var(Y)=2\text{Var}(Y) = 2, and Var(Z)=3\text{Var}(Z) = 3, assuming independence?

Answer: Var(X+Y+Z)=6\text{Var}(X + Y + Z) = 6. Sum all variances: 1+2+3=61 + 2 + 3 = 6.

Flashcard 50: Find the mean of 3X2Y3X - 2Y given E(X)=5\text{E}(X) = 5 and E(Y)=3\text{E}(Y) = 3.

Answer: E(3X2Y)=9\text{E}(3X - 2Y) = 9. Apply linear combination formula: 3(5)2(3)=156=93(5) - 2(3) = 15 - 6 = 9.

Flashcard 51: What is the formula for the variance of a random variable bYbY?

Answer: Var(bY)=b2Var(Y)\text{Var}(bY) = b^2\text{Var}(Y). Variance scales by the square of the constant multiplier.

Flashcard 52: Find the mean of X+YX + Y given E(X)=5\text{E}(X) = 5 and E(Y)=3\text{E}(Y) = 3.

Answer: E(X+Y)=8\text{E}(X + Y) = 8. Apply linearity: 5+3=85 + 3 = 8.

Flashcard 53: State the formula for the mean of the difference of two random variables XX and YY.

Answer: E(XY)=E(X)E(Y)\text{E}(X - Y) = \text{E}(X) - \text{E}(Y). Expected value is linear, so differences distribute across expectations.

Flashcard 54: What is the standard deviation of 2Y2Y given SD(Y)=3\text{SD}(Y) = 3?

Answer: SD(2Y)=6\text{SD}(2Y) = 6. Apply standard deviation scaling: 2(3)=62(3) = 6.

Flashcard 55: What is the mean of 2X+3Y2X + 3Y given E(X)=4\text{E}(X) = 4 and E(Y)=6\text{E}(Y) = 6?

Answer: E(2X+3Y)=26\text{E}(2X + 3Y) = 26. Apply linear combination: 2(4)+3(6)=8+18=262(4) + 3(6) = 8 + 18 = 26.

Flashcard 56: What is the mean of 3X3X given E(X)=4\text{E}(X) = 4?

Answer: E(3X)=12\text{E}(3X) = 12. Apply scaling: 3(4)=123(4) = 12.