AP Statistics Flashcards: Introduction To The Binomial Distribution

Study Introduction To The Binomial Distribution in AP Statistics with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Statistics

Introduction To The Binomial Distribution

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What is P(X=n)P(X=n) for XBin(n,p)X \sim \text{Bin}(n,p)?

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ANSWER

pnp^n. All trials succeed when each has probability pp.

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What this deck covers

This deck focuses on Introduction To The Binomial Distribution, giving you a quick way to review the definitions, rules, and examples that matter most for AP Statistics.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

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Flashcard 1: What is P(X=n)P(X=n) for XBin(n,p)X \sim \text{Bin}(n,p)?

Answer: pnp^n. All trials succeed when each has probability pp.

Flashcard 2: Which option correctly interprets P(X=0)P(X=0) for XBin(n,p)X\sim\text{Bin}(n,p)?

Answer: No successes in nn trials: P(X=0)=(1p)nP(X=0)=(1-p)^n. All failures occur with probability (1p)n(1-p)^n.

Flashcard 3: What is the formula for the binomial coefficient (nk)\binom{n}{k}?

Answer: (nk)=n!k!(nk)!\binom{n}{k}=\frac{n!}{k!(n-k)!}. Counts ways to choose kk items from nn.

Flashcard 4: Find μ\mu and σ\sigma for XBin(25,0.4)X\sim\text{Bin}(25,0.4).

Answer: μ=10, σ=6\mu=10,\ \sigma=\sqrt{6}. Use μ=np=25(0.4)\mu=np=25(0.4) and σ=25(0.4)(0.6)\sigma=\sqrt{25(0.4)(0.6)}.

Flashcard 5: Find P(X1)P(X\ge 1) for XBin(6,p)X\sim\text{Bin}(6,p) in terms of pp.

Answer: 1(1p)61-(1-p)^6. Use complement: P(X1)=1P(X=0)P(X\ge 1)=1-P(X=0).

Flashcard 6: What is the mean of a binomial random variable XBin(n,p)X\sim\text{Bin}(n,p)?

Answer: μ=np\mu=np. Expected number of successes in nn trials.

Flashcard 7: Identify whether this is binomial: sample 5 cards without replacement, XX = number of aces.

Answer: No; trials are not independent (without replacement). Removing cards changes probabilities between draws.

Flashcard 8: Which option lists the four binomial conditions as BINSBINS?

Answer: BINSBINS: Binary outcomes, Independent trials, fixed Number of trials, Same pp. Mnemonic for Binary, Independent, Number fixed, Same probability.

Flashcard 9: What four conditions must hold for a setting to be binomial (BINS)?

Answer: Binary outcomes, Independent trials, fixed Number nn, Same pp each trial. These ensure each trial has two outcomes with constant probability.

Flashcard 10: Find P(X1)P(X\le 1) for XBin(4,0.3)X \sim \text{Bin}(4,0.3) as a sum of exact probabilities.

Answer: (40)(0.3)0(0.7)4+(41)(0.3)1(0.7)3\binom{4}{0}(0.3)^0(0.7)^4+\binom{4}{1}(0.3)^1(0.7)^3. Sum probabilities for X=0X=0 and X=1X=1.

Flashcard 11: Identify whether this is binomial: 10 coin flips, let XX be number of heads.

Answer: Yes; XBin(10,0.5)X \sim \text{Bin}(10,0.5). Fixed trials, constant p=0.5p=0.5, independent flips.

Flashcard 12: Identify whether this is binomial: sample 2020 students without replacement from a class of 2020 and count left-handed.

Answer: No; trials are not independent (without replacement from the entire class). Sampling entire population changes probabilities.

Flashcard 13: Identify the missing binomial condition: outcomes are success or failure, nn fixed, pp constant, and  .

Answer: Trials are independent. Independence ensures constant pp across all trials.

Flashcard 14: State the probability formula for exactly kk successes when XBin(n,p)X\sim\text{Bin}(n,p).

Answer: P(X=k)=(nk)pk(1p)nkP(X=k)=\binom{n}{k}p^k(1-p)^{n-k}. Combines choosing positions with probability of outcomes.

Flashcard 15: What is the standard deviation of XBin(n,p)X\sim\text{Bin}(n,p)?

Answer: σ=np(1p)\sigma=\sqrt{np(1-p)}. Measures typical deviation from the mean.

Flashcard 16: Which option describes the key difference between geometric and binomial settings?

Answer: Binomial: fixed nn; geometric: trials continue until first success. Binomial has predetermined trials; geometric stops at success.

Flashcard 17: Find P(X2)P(X\ge 2) for XBin(6,0.1)X \sim \text{Bin}(6,0.1) using a complement.

Answer: 1[P(X=0)+P(X=1)]1-[P(X=0)+P(X=1)]. Use complement: P(X2)=1P(X1)P(X≥2)=1-P(X≤1).

Flashcard 18: What does the parameter pp represent in a binomial model XBin(n,p)X\sim\text{Bin}(n,p)?

Answer: The probability of success on each trial. Remains constant across all trials in the experiment.

Flashcard 19: Which option gives the range of possible values for XBin(n,p)X \sim \text{Bin}(n,p)?

Answer: X{0,1,2,,n}X \in \{0,1,2,\dots,n\}. Can have 0 to nn successes in nn trials.

Flashcard 20: What is P(X=0)P(X=0) for XBin(n,p)X \sim \text{Bin}(n,p)?

Answer: (1p)n(1-p)^n. All trials fail when each has probability (1p)(1-p).

Flashcard 21: What is the support (possible values) of XX when XBin(n,p)X\sim\text{Bin}(n,p)?

Answer: Integers 0,1,2,,n0,1,2,\dots,n. Can have anywhere from zero to all successes.

Flashcard 22: Identify the distribution of the number of failures Y=nXY=n-X when XBin(n,p)X\sim\text{Bin}(n,p).

Answer: YBin(n,1p)Y\sim\text{Bin}(n,1-p). Failures have probability 1p1-p each.

Flashcard 23: Find P(X=3)P(X=3) for XBin(5,0.2)X\sim\text{Bin}(5,0.2).

Answer: (53)(0.2)3(0.8)2\binom{5}{3}(0.2)^3(0.8)^2. Apply formula with n=5n=5, k=3k=3, p=0.2p=0.2.

Flashcard 24: What is the mean of XBin(n,p)X \sim \text{Bin}(n,p)?

Answer: μ=np\mu=np. Expected successes equals trials times success probability.

Flashcard 25: What is the variance of XBin(n,p)X \sim \text{Bin}(n,p)?

Answer: Var(X)=np(1p)\text{Var}(X)=np(1-p). Product of mean npnp and failure probability (1p)(1-p).

Flashcard 26: What does the parameter nn represent in a binomial model XBin(n,p)X\sim\text{Bin}(n,p)?

Answer: The fixed number of trials. How many times the experiment is repeated.

Flashcard 27: What is the variance of XBin(n,p)X\sim\text{Bin}(n,p)?

Answer: Var(X)=np(1p)\text{Var}(X)=np(1-p). Square of standard deviation; measures spread.

Flashcard 28: Find μ\mu and σ\sigma for XBin(20,0.4)X \sim \text{Bin}(20,0.4).

Answer: μ=8, σ=4.8\mu=8,\ \sigma=\sqrt{4.8}. μ=20(0.4)=8\mu=20(0.4)=8; σ=20(0.4)(0.6)=4.8\sigma=\sqrt{20(0.4)(0.6)}=\sqrt{4.8}.

Flashcard 29: State the probability formula for exactly kk successes: P(X=k)P(X=k) for XBin(n,p)X \sim \text{Bin}(n,p).

Answer: P(X=k)=(nk)pk(1p)nkP(X=k)=\binom{n}{k}p^k(1-p)^{n-k}. Combines choosing kk spots with probability of exact outcome.

Flashcard 30: State the formula for combinations (nk)\binom{n}{k} using factorials.

Answer: (nk)=n!k!(nk)!\binom{n}{k}=\frac{n!}{k!(n-k)!}. Counts arrangements divided by duplicate orderings.

Flashcard 31: Find P(X1)P(X\le 1) for XBin(4,0.3)X\sim\text{Bin}(4,0.3) using binomial probabilities.

Answer: (40)(0.7)4+(41)(0.3)(0.7)3\binom{4}{0}(0.7)^4+\binom{4}{1}(0.3)(0.7)^3. Sum probabilities for X=0X=0 and X=1X=1.

Flashcard 32: What is the binomial distribution used to model in AP Statistics?

Answer: The number of successes XX in nn independent trials with constant pp. Counts how many times an event occurs in repeated independent trials.

Flashcard 33: Identify whether this is binomial: flip a fair coin 1010 times and count heads.

Answer: Yes; XBin(10,0.5)X\sim\text{Bin}(10,0.5). Each flip is independent with p=0.5p=0.5.

Flashcard 34: What is the standard deviation of XBin(n,p)X \sim \text{Bin}(n,p)?

Answer: σ=np(1p)\sigma=\sqrt{np(1-p)}. Square root of variance np(1p)np(1-p).

Flashcard 35: Identify the complement event to "at least kk successes" for a binomial XX.

Answer: "At most k1k-1 successes," i.e., Xk1X\le k-1. "At least kk" means XkX\ge k; complement is X<kX<k.

Flashcard 36: Identify the distribution of the indicator variable II for one trial with success probability pp.

Answer: IBernoulli(p)I \sim \text{Bernoulli}(p). Single trial with two outcomes is Bernoulli.

Flashcard 37: What is the meaning of the notation (nk)\binom{n}{k} in the binomial probability formula?

Answer: The number of ways to choose kk successes from nn trials. Also called "n choose k" or combinations.

Flashcard 38: What is the notation and meaning of XBin(n,p)X \sim \text{Bin}(n,p)?

Answer: XX counts successes in nn trials with success probability pp. Standard notation for binomial random variable.

Flashcard 39: Find P(X=3)P(X=3) for XBin(5,0.2)X \sim \text{Bin}(5,0.2).

Answer: (53)(0.2)3(0.8)2\binom{5}{3}(0.2)^3(0.8)^2. Apply formula with n=5n=5, k=3k=3, p=0.2p=0.2.