AP Statistics Flashcards: Mean And Standard Deviation

Study Mean And Standard Deviation in AP Statistics with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Statistics

Mean And Standard Deviation

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QUESTION
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Identify the standard deviation of a Poisson random variable with rate lambda\text{lambda}.

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ANSWER

Standard deviation is sqrt(lambda)\text{sqrt(lambda)}. Poisson standard deviation is square root of rate parameter.

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Flashcard 1: Identify the standard deviation of a Poisson random variable with rate lambda\text{lambda}.

Answer: Standard deviation is sqrt(lambda)\text{sqrt(lambda)}. Poisson standard deviation is square root of rate parameter.

Flashcard 2: What is the variance of the difference of two independent random variables XX and YY?

Answer: Var(XY)=Var(X)+Var(Y)Var(X-Y) = Var(X) + Var(Y). Variances still add even when subtracting variables.

Flashcard 3: What is the formula for the variance of a linear transformation Y=a+bXY = a + bX?

Answer: Var(Y)=b2Var(X)Var(Y) = b^2 Var(X). Variance multiplied by b2b^2; constant aa has no effect.

Flashcard 4: If XX is a random variable with variance 25, what is Var(2X+3)Var(2X + 3)?

Answer: Var(2X+3)=100Var(2X + 3) = 100. Constant doesn't affect variance: Var(2X+3)=4(25)Var(2X + 3) = 4(25).

Flashcard 5: Calculate the variance for P(X=1)=0.4P(X=1)=0.4, P(X=2)=0.6P(X=2)=0.6. Mean is 1.61.6.

Answer: Variance is 0.240.24. Sum (xi1.6)2×pi(x_i - 1.6)^2 \times p_i for each value.

Flashcard 6: Find the variance of a random variable XX with Var(X)=9Var(X)=9 after Y=2X3Y=2X-3.

Answer: Var(Y)=36Var(Y) = 36. Apply variance rule: Var(Y)=22×9=36Var(Y) = 2^2 \times 9 = 36.

Flashcard 7: What is the variance of a Poisson random variable with rate lambda\text{lambda}?

Answer: Var(X)=lambdaVar(X) = \text{lambda}. For Poisson distribution, variance equals the rate parameter.

Flashcard 8: What is the variance of XX if XX follows a normal distribution with variance sigma2\text{sigma}^2?

Answer: Var(X)=sigma2Var(X) = \text{sigma}^2. Normal distribution variance is σ2\sigma^2 by definition.

Flashcard 9: What is the mean of the sum of two independent random variables XX and YY?

Answer: E(X+Y)=E(X)+E(Y)E(X+Y) = E(X) + E(Y). Expected values always add for independent variables.

Flashcard 10: What is the mean of a Poisson random variable with rate lambda\text{lambda}?

Answer: E(X)=lambdaE(X) = \text{lambda}. For Poisson distribution, mean equals the rate parameter.

Flashcard 11: For XX uniform from 2 to 8, calculate the variance.

Answer: Variance is 33. Uniform variance: (82)212=3612=3\frac{(8-2)^2}{12} = \frac{36}{12} = 3.

Flashcard 12: Calculate the mean of a random variable XX with E(X)=5E(X) = 5 after transformation Y=3X+2Y = 3X + 2.

Answer: E(Y)=17E(Y) = 17. Apply linear transformation: E(Y)=3(5)+2=17E(Y) = 3(5) + 2 = 17.

Flashcard 13: State the formula for the variance of a discrete random variable XX.

Answer: Var(X)=sum of [(xixˉ)2×pi]Var(X) = \text{sum of } [(x_i - \bar{x})^2 \times p_i]. Each squared deviation from mean times its probability, then sum.

Flashcard 14: Calculate the variance of XX with Var(X)=16Var(X)=16 after Y=XY=-X.

Answer: Var(Y)=16Var(Y) = 16. Multiplying by 1-1 doesn't change variance: (1)2=1(-1)^2 = 1.

Flashcard 15: What is the effect on the mean if XX is shifted by cc, i.e., Y=X+cY = X + c?

Answer: Mean increases by cc, E(Y)=E(X)+cE(Y) = E(X) + c. Adding constant shifts mean but doesn't change spread.

Flashcard 16: What is the effect on the variance if XX is shifted by cc, i.e., Y=X+cY = X + c?

Answer: Variance remains unchanged, Var(Y)=Var(X)Var(Y) = Var(X). Adding constant doesn't affect variability measures.

Flashcard 17: Calculate the variance for P(X=1)=0.4P(X=1)=0.4, P(X=2)=0.6P(X=2)=0.6. Mean is 1.61.6.

Answer: Variance is 0.240.24. Sum (xi1.6)2×pi(x_i - 1.6)^2 \times p_i for each value.

Flashcard 18: How do you calculate the standard deviation from variance?

Answer: Take the square root of the variance, SD(X)=sqrt(Var(X))\text{SD}(X) = \text{sqrt}(Var(X)). Standard deviation is always the positive square root of variance.

Flashcard 19: What is the mean of XX if XX follows a normal distribution with mean mu\text{mu}?

Answer: E(X)=muE(X) = \text{mu}. Normal distribution mean is the location parameter μ\mu.

Flashcard 20: Identify the standard deviation of XX if XX follows a normal distribution with variance sigma2\text{sigma}^2.

Answer: Standard deviation is sigma\text{sigma}. Standard deviation is square root of variance: σ2=σ\sqrt{\sigma^2} = \sigma.

Flashcard 21: What is the mean of the difference of two independent random variables XX and YY?

Answer: E(XY)=E(X)E(Y)E(X-Y) = E(X) - E(Y). Expected values subtract when finding difference.

Flashcard 22: Calculate the mean of a random variable XX with E(X)=5E(X) = 5 after transformation Y=3X+2Y = 3X + 2.

Answer: E(Y)=17E(Y) = 17. Apply linear transformation: E(Y)=3(5)+2=17E(Y) = 3(5) + 2 = 17.

Flashcard 23: Calculate the variance for XX with Var(X)=4Var(X) = 4 after transformation Y=3X+2Y = 3X + 2.

Answer: Var(Y)=36Var(Y) = 36. Apply variance rule: Var(Y)=32×4=36Var(Y) = 3^2 \times 4 = 36.

Flashcard 24: What is the formula for the variance of a linear transformation Y=a+bXY = a + bX?

Answer: Var(Y)=b2Var(X)Var(Y) = b^2 Var(X). Variance multiplied by b2b^2; constant aa has no effect.

Flashcard 25: What is the variance of a Poisson random variable with rate lambda\text{lambda}?

Answer: Var(X)=lambdaVar(X) = \text{lambda}. For Poisson distribution, variance equals the rate parameter.

Flashcard 26: Identify the mean of a uniformly distributed random variable XX over aa to bb.

Answer: E(X)=a+b2E(X) = \frac{a+b}{2}. Uniform mean is the midpoint of the interval.

Flashcard 27: What is the mean of a binomial random variable XX with nn trials and probability pp?

Answer: E(X)=n×pE(X) = n \times p. Binomial mean equals number of trials times success probability.

Flashcard 28: State the formula for the mean of a linear transformation Y=a+bXY = a + bX.

Answer: E(Y)=a+bE(X)E(Y) = a + bE(X). Linear transformation: add constant aa, multiply by bb.

Flashcard 29: What is the variance of the difference of two independent random variables XX and YY?

Answer: Var(XY)=Var(X)+Var(Y)Var(X-Y) = Var(X) + Var(Y). Variances still add even when subtracting variables.

Flashcard 30: What is the variance of XX if XX follows a normal distribution with variance sigma2\text{sigma}^2?

Answer: Var(X)=sigma2Var(X) = \text{sigma}^2. Normal distribution variance is σ2\sigma^2 by definition.

Flashcard 31: What is the variance of XX if XX follows an exponential distribution with rate lambda\text{lambda}?

Answer: Var(X)=1lambda2Var(X) = \frac{1}{\text{lambda}^2}. Exponential variance is reciprocal of rate squared.

Flashcard 32: For a random variable XX, what happens to the standard deviation if XX is multiplied by bb?

Answer: Standard deviation is multiplied by b|b|. Multiplying by bb scales standard deviation by b|b|.

Flashcard 33: What is the variance of XX if XX is a geometric random variable with probability pp?

Answer: Var(X)=1pp2Var(X) = \frac{1-p}{p^2}. Geometric variance uses (1p)(1-p) in numerator, p2p^2 in denominator.

Flashcard 34: What is the effect on the mean if XX is shifted by cc, i.e., Y=X+cY = X + c?

Answer: Mean increases by cc, E(Y)=E(X)+cE(Y) = E(X) + c. Adding constant shifts mean but doesn't change spread.

Flashcard 35: State the formula for the variance of a discrete random variable XX.

Answer: Var(X)=sum of [(xixˉ)2×pi]Var(X) = \text{sum of } [(x_i - \bar{x})^2 \times p_i]. Each squared deviation from mean times its probability, then sum.

Flashcard 36: Calculate the variance of XX with Var(X)=16Var(X)=16 after Y=XY=-X.

Answer: Var(Y)=16Var(Y) = 16. Multiplying by 1-1 doesn't change variance: (1)2=1(-1)^2 = 1.

Flashcard 37: For a random variable XX, what happens to the standard deviation if XX is multiplied by bb?

Answer: Standard deviation is multiplied by b|b|. Multiplying by bb scales standard deviation by b|b|.

Flashcard 38: Calculate the mean of XX if XX is uniform from 1 to 5.

Answer: E(X)=3E(X) = 3. Uniform from 1 to 5: mean = (1+5)/2=3(1+5)/2 = 3.

Flashcard 39: Find the mean of a random variable XX with E(X)=4E(X)=4 after Y=2X3Y=2X-3.

Answer: E(Y)=5E(Y) = 5. Apply transformation: E(Y)=2(4)3=5E(Y) = 2(4) - 3 = 5.

Flashcard 40: Identify the mean of a uniformly distributed random variable XX over aa to bb.

Answer: E(X)=a+b2E(X) = \frac{a+b}{2}. Uniform mean is the midpoint of the interval.

Flashcard 41: For XX uniform from 2 to 8, calculate the variance.

Answer: Variance is 33. Uniform variance: (82)212=3612=3\frac{(8-2)^2}{12} = \frac{36}{12} = 3.

Flashcard 42: Find the mean of a random variable XX given P(X=1)=0.2P(X=1)=0.2, P(X=2)=0.5P(X=2)=0.5, P(X=3)=0.3P(X=3)=0.3.

Answer: E(X)=2.1E(X) = 2.1. Sum each value times its probability: 1(0.2)+2(0.5)+3(0.3)1(0.2) + 2(0.5) + 3(0.3).

Flashcard 43: What is the formula for the expected value of a discrete random variable XX?

Answer: E(X)=sum of (xi×pi)E(X) = \text{sum of } (x_i \times p_i). Each value times its probability, then sum all products.

Flashcard 44: Find the mean of a random variable XX given P(X=1)=0.2P(X=1)=0.2, P(X=2)=0.5P(X=2)=0.5, P(X=3)=0.3P(X=3)=0.3.

Answer: E(X)=2.1E(X) = 2.1. Sum each value times its probability: 1(0.2)+2(0.5)+3(0.3)1(0.2) + 2(0.5) + 3(0.3).

Flashcard 45: State the formula for the mean of a linear transformation Y=a+bXY = a + bX.

Answer: E(Y)=a+bE(X)E(Y) = a + bE(X). Linear transformation: add constant aa, multiply by bb.

Flashcard 46: What is the variance of a uniformly distributed random variable XX over aa to bb?

Answer: Var(X)=(ba)212Var(X) = \frac{(b-a)^2}{12}. Uniform variance uses range squared divided by 12.

Flashcard 47: What is the standard deviation of a binomial random variable XX with nn trials and probability pp?

Answer: SD(X)=n×p×(1p)\text{SD}(X) = \sqrt{n \times p \times (1-p)}. Binomial standard deviation uses nn, pp, and (1p)(1-p) under square root.

Flashcard 48: How do you calculate the standard deviation from variance?

Answer: Take the square root of the variance, SD(X)=sqrt(Var(X))\text{SD}(X) = \text{sqrt}(Var(X)). Standard deviation is always the positive square root of variance.

Flashcard 49: Find the standard deviation for Var(X)=4Var(X)=4.

Answer: SD(X)=2\text{SD}(X) = 2. Standard deviation is the square root of variance.

Flashcard 50: What is the mean of XX if XX is a geometric random variable with probability pp?

Answer: E(X)=1pE(X) = \frac{1}{p}. Geometric mean is reciprocal of success probability.

Flashcard 51: Calculate the mean of XX if XX is uniform from 1 to 5.

Answer: E(X)=3E(X) = 3. Uniform from 1 to 5: mean = (1+5)/2=3(1+5)/2 = 3.

Flashcard 52: Calculate the mean of XX with E(X)=3E(X)=3 after Y=XY=-X.

Answer: E(Y)=3E(Y) = -3. Multiplying by 1-1 changes sign: E(X)=E(X)E(-X) = -E(X).

Flashcard 53: What is the mean of the difference of two independent random variables XX and YY?

Answer: E(XY)=E(X)E(Y)E(X-Y) = E(X) - E(Y). Expected values subtract when finding difference.

Flashcard 54: What is the mean of XX if XX is a geometric random variable with probability pp?

Answer: E(X)=1pE(X) = \frac{1}{p}. Geometric mean is reciprocal of success probability.

Flashcard 55: What is the mean of XX if XX follows a normal distribution with mean mu\text{mu}?

Answer: E(X)=muE(X) = \text{mu}. Normal distribution mean is the location parameter μ\mu.

Flashcard 56: What is the standard deviation of a binomial random variable XX with nn trials and probability pp?

Answer: SD(X)=sqrt(n×p×(1p))\text{SD}(X) = \text{sqrt}(n \times p \times (1-p)). Binomial standard deviation uses nn, pp, and (1p)(1-p) under square root.

Flashcard 57: What is the variance of XX if XX is a geometric random variable with probability pp?

Answer: Var(X)=1pp2Var(X) = \frac{1-p}{p^2}. Geometric variance uses (1p)(1-p) in numerator, p2p^2 in denominator.

Flashcard 58: Calculate the variance for XX with Var(X)=4Var(X) = 4 after transformation Y=3X+2Y = 3X + 2.

Answer: Var(Y)=36Var(Y) = 36. Apply variance rule: Var(Y)=32×4=36Var(Y) = 3^2 \times 4 = 36.

Flashcard 59: Calculate the mean of XX with E(X)=3E(X)=3 after Y=XY=-X.

Answer: E(Y)=3E(Y) = -3. Multiplying by 1-1 changes sign: E(X)=E(X)E(-X) = -E(X).

Flashcard 60: If XX is a random variable with variance 25, what is Var(2X+3)Var(2X + 3)?

Answer: Var(2X+3)=100Var(2X + 3) = 100. Constant doesn't affect variance: Var(2X+3)=4(25)Var(2X + 3) = 4(25).

Flashcard 61: Find the mean of a random variable XX with E(X)=4E(X)=4 after Y=2X3Y=2X-3.

Answer: E(Y)=5E(Y) = 5. Apply transformation: E(Y)=2(4)3=5E(Y) = 2(4) - 3 = 5.

Flashcard 62: Find the variance of a random variable XX with Var(X)=9Var(X)=9 after Y=2X3Y=2X-3.

Answer: Var(Y)=36Var(Y) = 36. Apply variance rule: Var(Y)=22×9=36Var(Y) = 2^2 \times 9 = 36.

Flashcard 63: Identify the standard deviation of a Poisson random variable with rate λ\lambda.

Answer: Standard deviation is λ\sqrt{\lambda}. Poisson standard deviation is square root of rate parameter.

Flashcard 64: What is the mean of a Poisson random variable with rate lambda\text{lambda}?

Answer: E(X)=lambdaE(X) = \text{lambda}. For Poisson distribution, mean equals the rate parameter.

Flashcard 65: What is the mean of XX if XX follows an exponential distribution with rate lambda\text{lambda}?

Answer: E(X)=1lambdaE(X) = \frac{1}{\text{lambda}}. Exponential mean is reciprocal of rate parameter.

Flashcard 66: What is the variance of XX if XX follows an exponential distribution with rate lambda\text{lambda}?

Answer: Var(X)=1lambda2Var(X) = \frac{1}{\text{lambda}^2}. Exponential variance is reciprocal of rate squared.

Flashcard 67: What is the variance of the sum of two independent random variables XX and YY?

Answer: Var(X+Y)=Var(X)+Var(Y)Var(X+Y) = Var(X) + Var(Y). Variances add for independent variables (never subtract).

Flashcard 68: If XX is a random variable with mean 10, what is E(2X+3)E(2X + 3)?

Answer: E(2X+3)=23E(2X + 3) = 23. Apply linear transformation: E(2X+3)=2(10)+3E(2X + 3) = 2(10) + 3.

Flashcard 69: If XX is a random variable with mean 10, what is E(2X+3)E(2X + 3)?

Answer: E(2X+3)=23E(2X + 3) = 23. Apply linear transformation: E(2X+3)=2(10)+3E(2X + 3) = 2(10) + 3.

Flashcard 70: What is the variance of a uniformly distributed random variable XX over aa to bb?

Answer: Var(X)=(ba)212Var(X) = \frac{(b-a)^2}{12}. Uniform variance uses range squared divided by 12.

Flashcard 71: What is the variance of the sum of two independent random variables XX and YY?

Answer: Var(X+Y)=Var(X)+Var(Y)Var(X+Y) = Var(X) + Var(Y). Variances add for independent variables (never subtract).

Flashcard 72: Identify the standard deviation of XX if XX follows a normal distribution with variance sigma2\text{sigma}^2.

Answer: Standard deviation is sigma\text{sigma}. Standard deviation is square root of variance: σ2=σ\sqrt{\sigma^2} = \sigma.

Flashcard 73: What is the formula for the expected value of a discrete random variable XX?

Answer: E(X)=sum of (xi×pi)E(X) = \text{sum of } (x_i \times p_i). Each value times its probability, then sum all products.

Flashcard 74: What is the mean of a binomial random variable XX with nn trials and probability pp?

Answer: E(X)=n×pE(X) = n \times p. Binomial mean equals number of trials times success probability.

Flashcard 75: What is the mean of the sum of two independent random variables XX and YY?

Answer: E(X+Y)=E(X)+E(Y)E(X+Y) = E(X) + E(Y). Expected values always add for independent variables.

Flashcard 76: Find the standard deviation for Var(X)=4Var(X)=4.

Answer: SD(X)=2\text{SD}(X) = 2. Standard deviation is the square root of variance.

Flashcard 77: What is the mean of XX if XX follows an exponential distribution with rate lambda\text{lambda}?

Answer: E(X)=1lambdaE(X) = \frac{1}{\text{lambda}}. Exponential mean is reciprocal of rate parameter.