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This deck focuses on Evaluate Evidence For Population Change, giving you a quick way to review the definitions, rules, and examples that matter most for Biology.
Study Evaluate Evidence For Population Change in Biology with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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In Hardy–Weinberg terms, what does q represent?
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Frequency of the recessive allele. Conventionally represents the less common or recessive allele frequency.
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This deck focuses on Evaluate Evidence For Population Change, giving you a quick way to review the definitions, rules, and examples that matter most for Biology.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Frequency of the recessive allele. Conventionally represents the less common or recessive allele frequency.
Answer: Directional selection. Population mean moves toward one end of the trait distribution.
Answer: Stabilizing selection. Selection against extremes increases frequency of intermediate phenotypes.
Answer: q=0.1. Allele frequencies must sum to 1, so q=1−0.9.
Answer: Homologous structures. Same underlying structure from common ancestor, modified for different functions.
Answer: Genetic drift. Population bottlenecks reduce size, increasing random sampling effects.
Answer: Directional selection. One extreme has higher fitness, shifting the population mean.
Answer: Frequency of the dominant allele. Conventionally represents the more common or dominant allele frequency.
Answer: No selection, no mutation, no migration, random mating, very large N. These conditions prevent allele frequency changes, maintaining equilibrium.
Answer: Stabilizing selection. Average trait values are preserved while extremes are eliminated.
Answer: Relative reproductive success of a genotype or phenotype. Measured by survival and reproductive output compared to other genotypes.
Answer: Genetic drift. Random sampling effects are strongest when population size is limited.
Answer: Trait-associated alleles increase in frequency over time. Higher survival leads to increased reproduction and allele transmission.
Answer: Frequency of the recessive allele. Conventionally represents the less common or recessive allele frequency.
Answer: q2=0.36. If p=0.4, then q=0.6, so q2=0.36.
Answer: p2=0.36. Square the dominant allele frequency: 0.62.
Answer: Gene flow (migration). Movement of individuals carries alleles between separate populations.
Answer: Trait-associated alleles increase in frequency over time. Higher survival leads to increased reproduction and allele transmission.
Answer: Gene flow. Immigration introduces new alleles and increases genetic mixing.
Answer: Disruptive selection. Intermediates have lower fitness than either extreme phenotype.
Answer: Comparative embryology. Early developmental similarities reveal shared ancestry despite adult differences.
Answer: 2pq=0.32. If q2=0.04, then q=0.2, p=0.8, so 2pq=0.32.
Answer: Observed genotype frequencies differ from expected frequencies. Deviations from Hardy-Weinberg predictions indicate evolutionary forces acting.
Answer: Random allele frequency shifts, strongest in small populations. Random changes are more pronounced in smaller population sizes.
Answer: Groups that interbreed and produce fertile offspring. Reproductive compatibility determines species boundaries in this concept.
Answer: p2. Probability of getting dominant allele from both parents equals p×p.
Answer: q2=0.01. Square the recessive allele frequency: 0.12.
Answer: Interbreeding members of the same species in one area. Geographic boundaries define the scope of genetic exchange.
Answer: p=0.7. If q2=0.09, then q=0.3 and p=1−0.3=0.7.
Answer: q2. Probability of getting recessive allele from both parents equals q×q.
Answer: p2. Probability of getting dominant allele from both parents equals p×p.
Answer: High DNA sequence similarity (molecular homology). Genetic similarity indicates recent divergence from common ancestor.
Answer: q=0.1. Allele frequencies must sum to 1, so q=1−0.9.
Answer: Natural selection can increase the trait's allele frequency. Heritable traits under selection will increase in frequency over generations.
Answer: 2pq=0.5. When allele frequencies are equal, heterozygotes reach maximum frequency.
Answer: Analogous structures. Similar function without shared ancestry indicates independent evolution.
Answer: Disruptive selection. Intermediates have lower fitness than either extreme phenotype.
Answer: Random allele frequency shifts, strongest in small populations. Random changes are more pronounced in smaller population sizes.
Answer: Homologous structures. Same bone pattern across species indicates common ancestral structure.
Answer: Mutation. DNA errors during replication create novel alleles in populations.
Answer: 2pq=0.42. Multiply 2×0.7×0.3 to get heterozygote frequency.
Answer: 2pq=0.32. If q2=0.04, then q=0.2, p=0.8, so 2pq=0.32.
Answer: Homologous structures. Same bone pattern across species indicates common ancestral structure.
Answer: Analogous structures (convergent evolution). Similar functions evolved independently due to similar environmental pressures.
Answer: Change in allele frequencies over time. Evolution occurs when allele proportions shift between generations.
Answer: q=0.6. Take the square root of the recessive phenotype frequency.
Answer: Stabilizing selection. Average trait values are preserved while extremes are eliminated.
Answer: Proportion of all gene copies that are a specific allele. Calculated by dividing copies of one allele by total gene copies in the population.
Answer: Descent with modification from ancestors. Reduced or nonfunctional structures inherited from functional ancestors.
Answer: q2=0.01. Square the recessive allele frequency: 0.12.
Answer: No evidence of evolution for that gene in that population. Matching Hardy-Weinberg expectations indicates no evolutionary forces acting.
Answer: p=0.7. If q2=0.09, then q=0.3 and p=1−0.3=0.7.
Answer: Heterozygote advantage (balancing selection). Heterozygotes outperform both homozygotes, preserving both alleles.
Answer: p2+2pq+q2=1. Expansion of (p+q)2 gives genotype frequencies for diploid organisms.
Answer: q2. Probability of getting recessive allele from both parents equals q×q.
Answer: Whether a population is evolving (deviating from equilibrium). Compares observed frequencies to equilibrium expectations to detect evolution.
Answer: Mutation. DNA errors during replication create novel alleles in populations.
Answer: 2pq. Two ways to get heterozygotes: dominant-recessive or recessive-dominant.
Answer: Molecular homology. DNA and protein similarities reflect shared evolutionary history.
Answer: q2=0.36. If p=0.4, then q=0.6, so q2=0.36.
Answer: p+q=1. For a two-allele system, frequencies must sum to one.
Answer: No evidence of evolution for that gene in that population. Matching Hardy-Weinberg expectations indicates no evolutionary forces acting.
Answer: Fossil record. Chronological sequence of fossils reveals morphological changes over time.
Answer: Mutation. DNA replication errors create entirely new genetic variants.
Answer: A measurable increase in resistance allele frequency over generations. Direct measurement of evolutionary change through allele frequency shifts.
Answer: Increased migration accompanied by reduced allele frequency differences. Migration homogenizes allele frequencies between previously distinct populations.
Answer: Gene flow. Immigration introduces new alleles and increases genetic mixing.
Answer: Disruptive selection. Selection against intermediates can lead to population splitting.
Answer: Analogous structures. Similar function without shared ancestry indicates independent evolution.
Answer: 2pq=0.5. When allele frequencies are equal, heterozygotes reach maximum frequency.
Answer: Microevolution. Evolution within a population, as opposed to macroevolution between species.
Answer: p=0.8. Since p+q=1, subtract q from 1.
Answer: Fossil record. Chronological sequence of fossils reveals morphological changes over time.