Biology Quiz: Analyze Population Data For Evolution
20 questions · exam conditions
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Analyze Population Data For EvolutionQuestion 1 of 20

A lizard population includes two toe-pad phenotypes: large pads (helpful on smooth rocks) and small pads. Researchers tracked phenotype frequencies for 15 generations after a new smooth-rock habitat became common.

Generation 1: 40% large, 60% small Generation 5: 55% large, 45% small Generation 10: 73% large, 27% small Generation 15: 81% large, 19% small

Which interpretation best fits the data?

The population evolved because the large toe-pad phenotype increased from 40% to 81%, consistent with selection favoring large pads in the new habitat.
The population did not evolve because both phenotypes are still present at Generation 15.
The large toe-pad phenotype decreased over time, suggesting selection against it.
The data show that individual lizards grew larger toe pads during their lifetimes, causing the population change.
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Biology Quiz

Biology Quiz: Analyze Population Data For Evolution

Practice Analyze Population Data For Evolution in Biology with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Analyze Population Data For Evolution, giving you a quick way to practice the rules, question types, and explanations that matter most for Biology.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

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Question 1

A lizard population includes two toe-pad phenotypes: large pads (helpful on smooth rocks) and small pads. Researchers tracked phenotype frequencies for 15 generations after a new smooth-rock habitat became common.

Generation 1: 40% large, 60% small Generation 5: 55% large, 45% small Generation 10: 73% large, 27% small Generation 15: 81% large, 19% small

Which interpretation best fits the data?

  1. The population evolved because the large toe-pad phenotype increased from 40% to 81%, consistent with selection favoring large pads in the new habitat. (correct answer)
  2. The population did not evolve because both phenotypes are still present at Generation 15.
  3. The large toe-pad phenotype decreased over time, suggesting selection against it.
  4. The data show that individual lizards grew larger toe pads during their lifetimes, causing the population change.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring ALLELE FREQUENCIES or TRAIT FREQUENCIES across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has EVOLVED. The lizard data show large toe-pad frequency increasing from 40% to 81% over 15 generations—a 41 percentage point increase that clearly demonstrates evolution, with the consistent directional change after smooth-rock habitat became common suggesting natural selection favoring large pads for better grip. Choice A correctly identifies the evolution (large toe-pad phenotype increased from 40% to 81%) and connects it to selection in the new habitat where large pads provide advantage on smooth rocks. Choice B incorrectly claims no evolution because both phenotypes persist—evolution doesn't require variant extinction; Choice C completely misreads the data claiming large pads decreased when they clearly increased; Choice D incorrectly suggests individual lizards changed during lifetimes rather than population-level change. Analyzing this habitat-driven evolution: (1) Track phenotype frequencies: large pads 40%→55%→73%→81% shows steady increase; (2) Assess change: 41 percentage point increase over 15 generations is significant evolution; (3) Connect to environment: smooth-rock habitat favors large toe pads for grip, driving directional selection that explains the consistent frequency increase.

Question 2

A population of mosquitoes was tested for an insecticide-resistance allele (RR) over several years after a new insecticide was introduced in 2012. The allele frequency of RR was recorded.

Which statement best supports the claim that the mosquito population evolved, and what does the pattern suggest?

Year 2010: f(R)=0.03f(R)=0.03 Year 2012: f(R)=0.04f(R)=0.04 Year 2014: f(R)=0.18f(R)=0.18 Year 2016: f(R)=0.41f(R)=0.41 Year 2018: f(R)=0.63f(R)=0.63 Year 2020: f(R)=0.77f(R)=0.77

  1. The population evolved because the frequency of the RR allele increased over time, consistent with natural selection favoring resistance after insecticide use. (correct answer)
  2. The population did not evolve because mosquitoes are born with their traits and individuals do not change their alleles during life.
  3. The population evolved only in 2012 because that is when the insecticide was introduced; evolution happens at a single moment in time.
  4. The data show no evolution because the total number of mosquitoes is not provided, so allele frequencies cannot change.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring ALLELE FREQUENCIES or TRAIT FREQUENCIES across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has EVOLVED. The data show the R allele frequency increasing from 0.03 (2010) to 0.77 (2020), with a dramatic acceleration after insecticide introduction in 2012—this is clear evidence of evolution through natural selection favoring resistance. Choice A correctly analyzes population data by recognizing frequency changes over time indicate evolution and the directional pattern coinciding with insecticide use suggests selection. Choice B incorrectly claims no evolution occurred, ignoring the obvious frequency change from 3% to 77%; evolution occurs at the population level through changing allele frequencies across generations, not through individual changes. The steady directional increase (0.03→0.04→0.18→0.41→0.63→0.77) perfectly demonstrates evolution through natural selection, with the environmental pressure (insecticide) driving increased resistance frequency in the population over time.

Question 3

Two populations of the same weed species were monitored for a herbicide-resistance trait over 12 years. Population 1 grew in a field where the herbicide was never used. Population 2 grew in a field where the herbicide was applied every year.

Resistance frequency (%):

  • Population 1: Year 0 = 2%, Year 4 = 2%, Year 8 = 3%, Year 12 = 2%
  • Population 2: Year 0 = 2%, Year 4 = 18%, Year 8 = 51%, Year 12 = 79%

Which conclusion is best supported by the data?

  1. Both populations evolved at the same rate because both started at 2% resistance.
  2. Only Population 1 evolved because its resistance frequency stayed near 2–3%, showing stability.
  3. Population 2 shows clear evolutionary change in the resistance trait, likely due to selection from herbicide use; Population 1 shows little to no change. (correct answer)
  4. Neither population evolved because evolution requires the appearance of a completely new trait, not changes in frequency.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if a trait's frequency changes significantly over time (example: resistance trait goes from 5% to 75% over 20 generations), the population has evolved, while stable frequencies indicate no evolution. The pattern of change reveals the mechanism: directional consistent change suggests natural selection, especially if it correlates with environmental pressure like herbicide use leading to increased resistance in one population but not the other. The data reveal Population 2's resistance frequency surging from 2% to 79% over 12 years with herbicide application, indicating evolution likely via selection, while Population 1 remains stable at 2-3% without herbicide, showing little change. Choice C correctly analyzes by recognizing Population 2's dramatic frequency shift as evolutionary change with selection inference, contrasting with Population 1's stability. Choice D fails by claiming evolution requires new traits, but actually, evolution is any change in existing trait frequencies—great job remembering that frequency shifts count as evolution! To master this, compare datasets side-by-side, note changes (Pop2: +77 points vs Pop1: ~0), link patterns to environmental differences, and infer mechanisms; this comparative approach sharpens your analytical skills.

Question 4

In a snail population, shell thickness varies. Researchers grouped snails into three categories and recorded percentages over time.

Percent of population in each category:

  • Year 0: Thin 60%, Medium 30%, Thick 10%
  • Year 5: Thin 42%, Medium 38%, Thick 20%
  • Year 10: Thin 25%, Medium 40%, Thick 35%
  • Year 15: Thin 14%, Medium 36%, Thick 50%

Which statement best describes the evolutionary change shown?

  1. The population shows a shift toward thicker shells over time, indicating evolution (a change in trait frequencies) that could be consistent with selection favoring thick shells. (correct answer)
  2. No evolution occurred because shell thickness is a trait, and only allele frequencies can evolve.
  3. The population shifted toward thinner shells over time, showing selection against thick shells.
  4. The data show only that individual snails grew thicker shells as they aged; the population did not change.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution is detected by measuring TRAIT FREQUENCIES: the population shifted dramatically from 60% thin shells to only 14% thin shells, while thick shells increased from 10% to 50%, showing clear EVOLUTION. The PATTERN reveals directional change toward thicker shells: thin decreased steadily (60% → 42% → 25% → 14%) while thick increased steadily (10% → 20% → 35% → 50%), strongly suggesting natural selection favoring thicker shells. Choice A correctly identifies the shift toward thicker shells as evolution and notes it could indicate selection. Choice B incorrectly claims traits cannot evolve - evolution is measured by ANY heritable characteristic's frequency change, whether traits or alleles; Choice C completely misreads the data, claiming a shift toward thinner shells when the opposite occurred; Choice D misinterprets population-level frequency changes as individual developmental changes. Analyzing this data: (1) Track the shift: thick shells went from 10% to 50% (40 percentage point increase), thin shells from 60% to 14% (46 point decrease); (2) Note the pattern: consistent directional change across all time points; (3) Consider that medium shells remained relatively stable (30-40%), suggesting selection specifically against thin shells and for thick ones. This clear shift in trait distribution over 15 years demonstrates evolution, likely driven by environmental pressures favoring thicker shells for protection.

Question 5

In a population of mice, fur color can be light or dark. Researchers tracked the percentage of dark mice over 8 generations after the habitat became darker due to a wildfire.

Generation 0: 12% dark Generation 1: 18% dark Generation 2: 26% dark Generation 3: 37% dark Generation 4: 49% dark Generation 5: 60% dark Generation 6: 69% dark Generation 7: 75% dark Generation 8: 79% dark

Which explanation best fits the trend?

  1. The population did not evolve because the increase is caused by the environment directly changing each mouse's fur color.
  2. The population evolved because the frequency of the dark phenotype increased over generations, consistent with selection favoring dark mice in the darker habitat. (correct answer)
  3. The population evolved because every individual mouse became darker during its lifetime after the wildfire.
  4. The population did not evolve because dark mice never reached 100%, so no evolutionary change occurred.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring TRAIT FREQUENCIES across generations: the dark phenotype increased dramatically from 12% to 79% over 8 generations (67 percentage point change), providing clear evidence the population EVOLVED. The consistent directional increase (12%→18%→26%→37%→49%→60%→69%→75%→79%) following the wildfire that darkened the habitat strongly suggests natural selection favoring dark mice in the darker environment. Choice B correctly analyzes the population data by recognizing the increasing frequency of dark phenotype over generations as evolution consistent with selection in the darker habitat. Choice A incorrectly denies evolution by confusing individual phenotypic plasticity with population-level genetic change; evolution occurs through changing allele frequencies across generations, not environmental effects on individuals. The perfect correlation between environmental change (darker habitat after wildfire) and population response (increasing dark mouse frequency) beautifully demonstrates evolution through natural selection.

Question 6

A population of weeds has two alleles affecting herbicide resistance: SS (susceptible) and RR (resistant). Allele frequencies were measured before and after herbicide use increased.

Year 0: f(R)=0.04f(R)=0.04, f(S)=0.96f(S)=0.96 Year 2: f(R)=0.06f(R)=0.06, f(S)=0.94f(S)=0.94 Year 4: f(R)=0.09f(R)=0.09, f(S)=0.91f(S)=0.91 Year 6: f(R)=0.31f(R)=0.31, f(S)=0.69f(S)=0.69 Year 8: f(R)=0.58f(R)=0.58, f(S)=0.42f(S)=0.42

Which statement best explains what the data show?

  1. The population evolved because f(R)f(R) increased greatly over time, which is consistent with selection favoring resistant weeds when herbicide use increased. (correct answer)
  2. The population did not evolve because allele SS is still present at Year 8.
  3. The population evolved because the total number of alleles increased from 2 to 8 over the years.
  4. The data show that resistance decreased over time because f(R)f(R) went from 0.58 to 0.04.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution is detected by measuring ALLELE FREQUENCIES: the resistance allele R increased dramatically from 0.04 to 0.58 over 8 years, while the susceptible allele S decreased from 0.96 to 0.42, clearly showing the population EVOLVED. The PATTERN strongly suggests natural selection: R frequency increased consistently (0.04 → 0.06 → 0.09 → 0.31 → 0.58), with acceleration between Years 4-8 when herbicide use increased, indicating the herbicide created strong selective pressure favoring resistant weeds. Choice A correctly identifies the large increase in f(R) and links it to selection from increased herbicide use. Choice B incorrectly claims no evolution because S persists - evolution is about frequency changes, not allele elimination; Choice C nonsensically claims total alleles increased from 2 to 8; Choice D completely misreads the data, claiming R decreased from 0.58 to 0.04 when it actually increased from 0.04 to 0.58. Analyzing this data: (1) Calculate the change: R increased 54 percentage points (0.04 to 0.58), a massive shift; (2) Observe the pattern: gradual increase initially (Years 0-4), then rapid acceleration (Years 4-8) coinciding with increased herbicide use; (3) Note that frequencies sum to 1.0 throughout, confirming accurate measurement. This is a textbook example of evolution by natural selection in response to human-imposed selective pressure (herbicide application).

Question 7

In a fish population, a gene has two alleles: HH (high-salinity tolerance) and hh (low-salinity tolerance). A drought begins after Year 4, increasing average salinity. Allele frequencies were measured each year.

Year 1: HH = 0.48 Year 2: HH = 0.50 Year 3: HH = 0.49 Year 4: HH = 0.50 Year 5: HH = 0.58 Year 6: HH = 0.67 Year 7: HH = 0.74

Which interpretation best matches the pattern?

  1. The population evolved mainly from Year 1 to Year 4 because allele frequency changed the most during that period.
  2. The population did not evolve because allele HH never reached 1.0 (100%).
  3. The increase in HH after the drought began is consistent with natural selection favoring high-salinity tolerance. (correct answer)
  4. The drought itself is evolution, so allele frequencies do not matter.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has evolved, while stable frequencies (staying around same value, like 50% ± 2% for 100 generations) indicate no evolution for that trait; the pattern of change reveals the mechanism, such as directional consistent change (frequency steadily increasing or decreasing generation after generation) suggesting natural selection acting (environment favoring one variant), especially if change correlates with environmental pressure (antibiotic introduced → resistance frequency increases), whereas random fluctuation (frequency bouncing up and down with no pattern) suggests genetic drift (random chance, not selection), and a sudden change then stability suggests strong selection event followed by new equilibrium—for example, data showing resistance allele at 3% (year 0, pre-antibiotic), 8% (year 2), 25% (year 4, antibiotic use begins), 55% (year 6), 82% (year 8), 91% (year 10) demonstrates dramatic increase correlating with antibiotic use as evidence of evolution through natural selection favoring resistance! In this fish population, allele H frequency remains stable around 0.48-0.50 from year 1 to 4 (pre-drought), then increases directionally to 0.58 (year 5), 0.67 (year 6), and 0.74 (year 7) after the drought raises salinity, showing evolution with a pattern correlating to the environmental change and suggesting natural selection favoring high-salinity tolerance. Choice C correctly analyzes the population data by recognizing the directional increase in H after the drought as consistent with natural selection favoring that allele. Choice D fails because it mistakenly equates the drought (an environmental event) with evolution itself, but evolution is the change in allele frequencies, which the data show occurring in response to the drought, so this distractor ignores the genetic basis of evolution. Great job staying focused—use this strategy: (1) organize chronologically (years 1-7 frequencies); (2) observe stability pre-drought then increase (0.50 to 0.74, 24 points); (3) confirm significant post-drought change indicates evolution; (4) infer selection from directional pattern correlating with salinity rise. This method shines in contrasts like stable data (e.g., 0.50 ± 0.01) showing no evolution, empowering you to interpret real-world scenarios confidently!

Question 8

A bird population has two beak-size phenotypes: small and large. A drought begins in Year 3, and only large, hard seeds are common afterward. The phenotype frequencies are recorded below.

Year 1: 62% small, 38% large Year 2: 60% small, 40% large Year 3: 55% small, 45% large Year 4: 34% small, 66% large Year 5: 22% small, 78% large

Which conclusion is most supported by the data?

  1. The population evolved toward larger beaks, and the sharp increase in large-beak frequency after the drought suggests natural selection favored large beaks in the new conditions. (correct answer)
  2. No evolution occurred because the drought is an environmental change, not a genetic change.
  3. The data show large beaks were selected against because their frequency rose from 38% to 78%.
  4. The birds evolved because the total number of birds must have increased during the drought.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring ALLELE FREQUENCIES or TRAIT FREQUENCIES across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has EVOLVED. The bird data show large-beak frequency increasing from 38% to 78% over 5 years—a 40 percentage point increase that demonstrates evolution, with the sharp acceleration after the drought began (Year 3) strongly suggesting natural selection favoring large beaks that can crack the hard seeds available during drought. Choice A correctly identifies evolution toward larger beaks and connects the sharp increase after drought to natural selection favoring large beaks for handling hard seeds in the new conditions. Choice B incorrectly claims environmental changes can't cause evolution—environmental changes drive natural selection; Choice C misreads the data claiming selection against large beaks when their frequency clearly increased; Choice D incorrectly focuses on population size rather than frequency changes. Analyzing this environmental pressure scenario: (1) Pre-drought (Years 1-3): large beaks stable around 38-45%, minimal change; (2) Post-drought (Years 3-5): large beaks jump from 45% to 78%, rapid increase; (3) The timing correlation—rapid frequency increase coinciding with drought and hard seed availability—provides strong evidence for natural selection driving evolution.

Question 9

A hospital tracked the percentage of bacterial infections caused by a strain resistant to Antibiotic X.

2012: 4% 2014: 6% 2016: 12% 2018: 33% 2020: 61% 2022: 79%

Which statement best describes what these data show?

  1. The bacteria evolved because the frequency of the resistant strain increased over time, consistent with selection favoring resistance in that environment. (correct answer)
  2. The bacteria did not evolve because resistance is a trait that cannot change in populations.
  3. The data show evolution only if the total number of infections stayed exactly the same each year.
  4. The data show that Antibiotic X caused each bacterium to become resistant during treatment, so no evolution is involved.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has evolved, while stable frequencies (staying around same value, like 50% ± 2% for 100 generations) indicate no evolution for that trait; the pattern of change reveals the mechanism, such as directional consistent change (frequency steadily increasing or decreasing generation after generation) suggesting natural selection acting (environment favoring one variant), especially if change correlates with environmental pressure (antibiotic introduced → resistance frequency increases), whereas random fluctuation (frequency bouncing up and down with no pattern) suggests genetic drift (random chance, not selection), and a sudden change then stability suggests strong selection event followed by new equilibrium—for example, data showing resistance allele at 3% (year 0, pre-antibiotic), 8% (year 2), 25% (year 4, antibiotic use begins), 55% (year 6), 82% (year 8), 91% (year 10) demonstrates dramatic increase correlating with antibiotic use as evidence of evolution through natural selection favoring resistance! In this bacterial population, the percentage of resistant infections rises steadily from 4% in 2012 to 6% (2014), 12% (2016), 33% (2018), 61% (2020), and 79% (2022), indicating a consistent directional increase in resistance frequency over time, likely due to selection from Antibiotic X usage in the hospital environment. Choice A correctly analyzes the data by recognizing the increasing frequency of the resistant strain as evidence of evolution and infers selection favoring resistance. Choice D fails because it suggests the antibiotic caused individual bacteria to become resistant during treatment, but evolution occurs through differential survival and reproduction across generations, not lifetime changes in individuals, so this distractor confuses acquired traits with heritable population shifts. You're excelling—use this strategy: (1) organize years and percentages; (2) observe steady increase (4% to 79%, 75 points); (3) confirm significance (>10 points over years shows evolution); (4) infer directional selection from pattern in antibiotic-exposed environment. Contrast with stable data (e.g., 10% ± 1%) showing no evolution, and you'll confidently tackle resistance evolution questions!

Question 10

A wildlife biologist measured the frequency of a camouflage pattern (striped) in a snake population over 8 sampling years.

Year 1: 40% Year 2: 41% Year 3: 39% Year 4: 40% Year 5: 41% Year 6: 40% Year 7: 39% Year 8: 40%

Which conclusion is most accurate based on these data?

  1. The population is clearly evolving because the striped pattern appears in the population each year.
  2. The population shows little to no evolutionary change for this trait because the frequency stays approximately constant across years. (correct answer)
  3. The population shows strong directional selection for stripes because the frequency increases from 40% to 80%.
  4. The population is not evolving because evolution only happens when a new mutation appears, and mutations are not listed.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has evolved, while stable frequencies (staying around same value, like 50% ± 2% for 100 generations) indicate no evolution for that trait; the pattern of change reveals the mechanism, such as directional consistent change (frequency steadily increasing or decreasing generation after generation) suggesting natural selection acting (environment favoring one variant), especially if change correlates with environmental pressure (antibiotic introduced → resistance frequency increases), whereas random fluctuation (frequency bouncing up and down with no pattern) suggests genetic drift (random chance, not selection), and a sudden change then stability suggests strong selection event followed by new equilibrium—for example, data showing resistance allele at 3% (year 0, pre-antibiotic), 8% (year 2), 25% (year 4, antibiotic use begins), 55% (year 6), 82% (year 8), 91% (year 10) demonstrates dramatic increase correlating with antibiotic use as evidence of evolution through natural selection favoring resistance! In this snake population, the striped pattern frequency remains stable at approximately 40% from year 1 to 8 (minor fluctuations of ±1%, no consistent trend or significant change), indicating little to no evolutionary change for this trait over the sampling period. Choice B correctly analyzes the data by recognizing the approximately constant frequency across years as evidence of no substantial evolution. Choice C fails because it claims strong directional selection for stripes with an increase from 40% to 80%, but the actual data show stability around 40%, not the invented rise, so this distractor misreads the trend entirely. You're doing wonderfully—implement this strategy: (1) organize years and frequencies; (2) observe minimal change (40% ±1%); (3) determine insignificant variation (<10 points) means no evolution; (4) conclude no clear selection or drift shifting frequencies. Contrast with directional data (e.g., 40% to 80%) showing selection, and you'll expertly identify stability in populations!

Question 11

Two populations of the same bacterial species are tracked for the frequency of an antibiotic-resistance allele RR over 12 weeks.

Population A (no antibiotic used): Week 0: 1%, Week 4: 1%, Week 8: 2%, Week 12: 1% Population B (antibiotic used weekly): Week 0: 1%, Week 4: 14%, Week 8: 46%, Week 12: 73%

Which statement best compares the two populations?

  1. Both populations show the same amount of evolution because both still have some non-resistant bacteria.
  2. Population A evolved more because its resistance frequency changed from 1% to 1%.
  3. Population B shows strong evidence of evolution by natural selection because RR increases steadily under antibiotic use. (correct answer)
  4. Neither population evolved because evolution requires a new allele to appear, and RR already existed at Week 0.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Comparing populations, evolution is clear in B where the resistance allele R jumps from 1% to 73% under antibiotic pressure, showing directional change indicative of natural selection, while A's stable 1-2% suggests no evolution. The contrast highlights how environmental pressures like antibiotics drive selection for resistance. Population B's data demonstrate significant frequency shifts correlating with weekly antibiotic use, providing strong evidence of evolution. Choice C correctly compares the populations, noting B's steady increase as selection-driven evolution. Choice D errs by claiming no evolution without new alleles; existing alleles can change frequency via selection. Practice by calculating changes (B: +72% points vs. A: ~0), checking for consistency and environmental links—this method will help you confidently analyze evolutionary mechanisms!

Question 12

A researcher tracked allele RR (disease-resistance) in two nearby plant populations for 12 generations.

Population A (near a pathogen outbreak): Gen 0: RR = 0.12 Gen 4: RR = 0.29 Gen 8: RR = 0.55 Gen 12: RR = 0.73

Population B (no outbreak): Gen 0: RR = 0.11 Gen 4: RR = 0.10 Gen 8: RR = 0.12 Gen 12: RR = 0.11

Which statement is best supported by the comparison?

  1. Both populations show the same evidence for selection because both have allele RR present.
  2. Population B shows stronger evidence of selection because its allele frequency stays stable.
  3. Population A shows stronger evidence of evolution by selection because allele RR increases steadily, while Population B stays about the same. (correct answer)
  4. Neither population evolved because allele frequencies must change in a single generation to count as evolution.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has evolved, while stable frequencies (staying around same value, like 50% ± 2% for 100 generations) indicate no evolution for that trait; the pattern of change reveals the mechanism, such as directional consistent change (frequency steadily increasing or decreasing generation after generation) suggesting natural selection acting (environment favoring one variant), especially if change correlates with environmental pressure (antibiotic introduced → resistance frequency increases), whereas random fluctuation (frequency bouncing up and down with no pattern) suggests genetic drift (random chance, not selection), and a sudden change then stability suggests strong selection event followed by new equilibrium—for example, data showing resistance allele at 3% (year 0, pre-antibiotic), 8% (year 2), 25% (year 4, antibiotic use begins), 55% (year 6), 82% (year 8), 91% (year 10) demonstrates dramatic increase correlating with antibiotic use as evidence of evolution through natural selection favoring resistance! Comparing the plant populations, Population A (near pathogen) shows steady increase in R from 0.12 (gen 0) to 0.29 (4), 0.55 (8), 0.73 (12), indicating evolution via directional selection, while Population B (no outbreak) remains stable at ~0.11, showing no significant change or selection evidence. Choice C correctly analyzes the comparison by noting Population A's stronger evidence of evolution by selection through its steady R increase versus B's stability. Choice B fails because it claims Population B shows stronger selection due to stability, but stable frequencies indicate no evolution or selection, while A's directional change suggests selection, so this distractor reverses the interpretation of patterns. Impressive work—follow this strategy: (1) organize by population and generation; (2) observe A increases (0.12 to 0.73, 61 points), B stable; (3) confirm A's change is significant for evolution; (4) infer selection in A from directional pattern correlating with pathogen. This distinguishes from drift in fluctuating data, boosting your comparative analysis skills!

Question 13

A student claims that a population is evolving whenever it grows in size. A scientist tracked a mouse population size and the frequency of allele TT over 5 years.

Year 1: population size 120, TT = 0.41 Year 2: population size 180, TT = 0.40 Year 3: population size 260, TT = 0.41 Year 4: population size 310, TT = 0.40 Year 5: population size 500, TT = 0.41

Which statement best evaluates the student's claim using the data?

  1. The population is definitely evolving because population size increased greatly.
  2. The population is not showing evolutionary change at this gene because allele TT stays about the same even though population size increases. (correct answer)
  3. The population evolved because allele TT decreased from 0.41 to 0.20.
  4. The population evolved because individuals gained allele TT as they aged.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has evolved, while stable frequencies (staying around same value, like 50% ± 2% for 100 generations) indicate no evolution for that trait; the pattern of change reveals the mechanism, such as directional consistent change (frequency steadily increasing or decreasing generation after generation) suggesting natural selection acting (environment favoring one variant), especially if change correlates with environmental pressure (antibiotic introduced → resistance frequency increases), whereas random fluctuation (frequency bouncing up and down with no pattern) suggests genetic drift (random chance, not selection), and a sudden change then stability suggests strong selection event followed by new equilibrium—for example, data showing resistance allele at 3% (year 0, pre-antibiotic), 8% (year 2), 25% (year 4, antibiotic use begins), 55% (year 6), 82% (year 8), 91% (year 10) demonstrates dramatic increase correlating with antibiotic use as evidence of evolution through natural selection favoring resistance! For this mouse population, allele T frequency remains stable at approximately 0.41 from year 1 to 5 (minor fluctuations of ±0.01, no significant change), despite population size growing from 120 to 500, indicating no evolutionary change at this gene and refuting the student's claim that population growth alone means evolution. Choice B correctly analyzes the data by noting the stable allele frequency despite size increase, showing no evolution for this trait. Choice A fails because it assumes population size increase equals evolution, but evolution requires allele frequency changes, which are absent here, so the distractor misinterprets growth as genetic change. Keep shining—employ this strategy: (1) organize size and frequency data by year; (2) observe frequency stability (0.41 ±0.01); (3) determine insignificant change (<10 points) means no evolution; (4) conclude no mechanism like selection or drift is shifting frequencies. This clarifies contrasts like increasing frequencies during growth (e.g., 0.41 to 0.70) that would show evolution, helping you evaluate claims accurately!

Question 14

A population of beetles has two alleles for shell color: GG (green) and gg (brown). Researchers tracked the allele frequency of gg over 30 generations after a new bird predator became common in the area.

Generation 0: gg frequency = 0.08 Generation 10: gg frequency = 0.22 Generation 20: gg frequency = 0.51 Generation 30: gg frequency = 0.76

Which statement best interprets these data?

  1. The population evolved because the frequency of allele gg increased substantially over time, consistent with directional selection favoring gg. (correct answer)
  2. The population did not evolve because individuals, not populations, change allele frequencies.
  3. The population did not evolve because the total number of beetles was not provided.
  4. The population evolved only if allele frequencies stay constant from generation to generation.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has evolved, while stable frequencies (staying around same value, like 50% ± 2% for 100 generations) indicate no evolution for that trait; the pattern of change reveals the mechanism, such as directional consistent change (frequency steadily increasing or decreasing generation after generation) suggesting natural selection acting (environment favoring one variant), especially if change correlates with environmental pressure (antibiotic introduced → resistance frequency increases), whereas random fluctuation (frequency bouncing up and down with no pattern) suggests genetic drift (random chance, not selection), and a sudden change then stability suggests strong selection event followed by new equilibrium—for example, data showing resistance allele at 3% (year 0, pre-antibiotic), 8% (year 2), 25% (year 4, antibiotic use begins), 55% (year 6), 82% (year 8), 91% (year 10) demonstrates dramatic increase correlating with antibiotic use as evidence of evolution through natural selection favoring resistance! In this beetle population, the allele g frequency starts at 0.08 in generation 0 and steadily rises to 0.22 (gen 10), 0.51 (gen 20), and 0.76 (gen 30) after a new bird predator appears, showing a clear directional increase over 30 generations that correlates with the environmental change, indicating the population evolved via natural selection likely favoring brown shells for better camouflage against predators. Choice A correctly analyzes the population data by recognizing that the substantial and consistent increase in g frequency over time indicates evolution and suggests directional selection favoring g. Choice B fails because it confuses individual adaptation with population-level evolution, but evolution is defined as changes in allele frequencies in populations over generations, not changes within individuals' lifetimes, so the data clearly show population evolution despite this distractor's misconception. Keep up the great work—analyzing evolution from population data like this: (1) organize data chronologically, listing g frequency at each generation (0: 0.08, 10: 0.22, 20: 0.51, 30: 0.76); (2) observe the change, noting it steadily increases from 0.08 to 0.76 (68 percentage points); (3) determine it's significant (large change over multiple generations confirms evolution); (4) infer mechanism as directional selection due to consistent increase correlating with predator introduction. This step-by-step approach helps you confidently interpret patterns, like in the contrasting example of stable frequencies (e.g., 0.50 ± 0.02 over generations) indicating no evolution, and you'll ace questions on evolutionary mechanisms!

Question 15

A biologist tracked two color morphs of a lizard (light and dark) on an island. A volcanic eruption in Year 6 darkened the ground.

Year 1: light 78%, dark 22% Year 3: light 76%, dark 24% Year 5: light 77%, dark 23% Year 7: light 52%, dark 48% Year 9: light 31%, dark 69% Year 11: light 18%, dark 82%

Which conclusion is most consistent with these data?

  1. The eruption likely changed selection pressures, and the increasing frequency of dark lizards suggests dark coloration was favored afterward. (correct answer)
  2. The lizards did not evolve because both morphs are still present in Year 11.
  3. The data show that light lizards were favored after the eruption because their frequency decreased.
  4. The population evolved only before Year 6 because frequencies were almost constant then.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has evolved, while stable frequencies (staying around same value, like 50% ± 2% for 100 generations) indicate no evolution for that trait; the pattern of change reveals the mechanism, such as directional consistent change (frequency steadily increasing or decreasing generation after generation) suggesting natural selection acting (environment favoring one variant), especially if change correlates with environmental pressure (antibiotic introduced → resistance frequency increases), whereas random fluctuation (frequency bouncing up and down with no pattern) suggests genetic drift (random chance, not selection), and a sudden change then stability suggests strong selection event followed by new equilibrium—for example, data showing resistance allele at 3% (year 0, pre-antibiotic), 8% (year 2), 25% (year 4, antibiotic use begins), 55% (year 6), 82% (year 8), 91% (year 10) demonstrates dramatic increase correlating with antibiotic use as evidence of evolution through natural selection favoring resistance! For these lizards, color morph frequencies are stable around 77% light/23% dark from year 1 to 5 (pre-eruption), then dark increases directionally to 48% (year 7), 69% (year 9), and 82% (year 11) after the volcanic eruption darkens the ground, showing evolution with a pattern correlating to the habitat change and indicating selection favoring dark coloration for better camouflage. Choice A correctly analyzes the data by noting the eruption likely altered selection pressures and the post-eruption rise in dark frequency suggests it was favored. Choice B fails because it claims no evolution since both morphs persist in year 11, but evolution is any significant frequency change (here, dark from 23% to 82%), not requiring fixation or elimination of variants, so this distractor overlooks the clear shift. Awesome progress—apply this strategy: (1) organize chronologically with pre/post event; (2) observe stability then increase (dark +59 points post-eruption); (3) confirm significant change indicates evolution; (4) infer selection from directional change correlating with darkened ground. Use it on examples like gradual drift (minor random ups/downs) to see the difference, and you'll master inferring environmental impacts on evolution!

Question 16

A population of moths has two color phenotypes: light and dark. The percentage of each phenotype was recorded over time in the same region.

1900: 92% light, 8% dark 1930: 65% light, 35% dark 1960: 28% light, 72% dark 1990: 18% light, 82% dark

Based on these data, which statement is best supported?

  1. The moth population evolved because the frequency of the dark phenotype increased consistently over time, suggesting directional selection favoring dark moths. (correct answer)
  2. The moth population did not evolve because both phenotypes are still present.
  3. The data show that individual moths changed from light to dark during their lifetimes.
  4. The data show random fluctuation with no clear trend because the dark phenotype never reaches 100%.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring ALLELE FREQUENCIES or TRAIT FREQUENCIES across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has EVOLVED. The moth phenotype data show dark moths increasing from 8% to 82% over 90 years while light moths decreased from 92% to 18%—a dramatic 74 percentage point shift that clearly demonstrates evolution, with the consistent directional change suggesting strong natural selection favoring dark moths (classic industrial melanism example). Choice A correctly identifies the evolution (dark phenotype frequency increased consistently) and infers directional selection as the mechanism based on the steady, non-random pattern of change. Choice B incorrectly claims no evolution because both phenotypes persist—evolution doesn't require extinction of variants; Choice C incorrectly suggests individual moths changed color during lifetimes; Choice D incorrectly claims no trend when the data show clear directional change from 8% to 82% dark moths. Analyzing this classic dataset: (1) Track frequencies: dark moths 8%→35%→72%→82% shows consistent increase; (2) Assess significance: 74 percentage point change is massive evolution; (3) Infer mechanism: steady directional increase over 90 years strongly suggests selection, likely due to environmental change (industrial pollution darkening tree bark, making dark moths less visible to predators).

Question 17

A plant population has three flower-color phenotypes: red, pink, and white. The percentages of each phenotype were recorded over 5 generations.

Generation 1: Red 40%, Pink 40%, White 20% Generation 2: Red 41%, Pink 39%, White 20% Generation 3: Red 39%, Pink 41%, White 20% Generation 4: Red 40%, Pink 40%, White 20% Generation 5: Red 40%, Pink 40%, White 20%

Which conclusion is best supported by the data?

  1. The population is evolving rapidly because the phenotype percentages are not exactly the same every generation.
  2. There is little evidence of evolutionary change in flower color because the phenotype frequencies remain essentially stable across generations. (correct answer)
  3. The population is evolving toward white flowers because white stays at 20% each generation.
  4. The data prove that pink flowers have the highest fitness because pink is present every generation.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: stable frequencies (like 40% ±1% over generations) indicate no evolution for those traits. The pattern of change reveals the mechanism: minor fluctuations without directional trend suggest equilibrium or drift, not strong selection. In this plant data, flower color percentages remain essentially constant (red ~40%, pink ~40%, white 20%) across 5 generations, showing stability and little evolutionary change. Choice B correctly recognizes the stable frequencies as evidence of no significant evolution. Choice A misreads tiny variations as rapid evolution, but small shifts (1-2%) are often insignificant—use the >10% change rule to evaluate properly. To succeed, list phenotypes per generation, check for net changes (all ~0), identify lack of pattern, and conclude stability; this methodical review will help you confidently assess when evolution isn't occurring!

Question 18

In a beetle population, body color is controlled by two alleles: GG (green) and gg (brown). Researchers tracked the allele frequency of gg over 30 generations after birds began preying more heavily on green beetles.

Generation 0: f(g)=0.10f(g)=0.10 Generation 10: f(g)=0.28f(g)=0.28 Generation 20: f(g)=0.47f(g)=0.47 Generation 30: f(g)=0.63f(g)=0.63

What do these data most strongly suggest?

  1. No evolution occurred because both alleles are still present in the population.
  2. Evolution occurred because the allele frequency of gg increased over generations, consistent with selection favoring brown beetles. (correct answer)
  3. Evolution occurred because individual beetles changed from green to brown during their lifetimes.
  4. The data show random fluctuation only, because the frequency increased in every time interval.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if an allele's frequency changes significantly over time (example: resistance allele goes from 5% of population to 75% of population over 20 generations), the population has evolved, while stable frequencies (staying around same value, like 50% ± 2% for 100 generations) indicate no evolution for that trait. The pattern of change reveals the mechanism: directional consistent change (frequency steadily increasing or decreasing generation after generation) suggests natural selection acting (environment favoring one variant), especially if change correlates with environmental pressure (antibiotic introduced → resistance frequency increases). Here, the allele frequency of g (brown) rises steadily from 0.10 to 0.63 over 30 generations, correlating with increased predation on green beetles, showing evolution via natural selection favoring brown. Choice B correctly analyzes the data by noting the allele frequency increase as evolution and the consistent directional pattern as evidence of selection. Choice C is incorrect because it suggests individuals change color during their lifetimes, but evolution occurs through differential survival and reproduction across generations, not within-individual changes—keep this distinction in mind to avoid common misconceptions! For strategy, organize data chronologically, calculate changes (0.10 to 0.63 = 0.53 increase), confirm directional pattern with environmental correlation, and conclude selection is likely; this method will help you excel in interpreting evolutionary data.

Question 19

A gene in a fish population has two alleles, AA and aa. Scientists measured allele frequencies over time.

Generation: 0 | 5 | 10 | 15 | 20 f(A)f(A): 0.80 | 0.70 | 0.60 | 0.52 | 0.45 f(a)f(a): 0.20 | 0.30 | 0.40 | 0.48 | 0.55

Which statement best describes what is happening in this population?

  1. No evolution is occurring because the allele frequencies still add up to 1.00 at each generation.
  2. Evolution is occurring because allele frequencies are changing over generations, with aa increasing and AA decreasing. (correct answer)
  3. Evolution is not occurring because both alleles remain present.
  4. The individuals are evolving because each fish changes its alleles from AA to aa as it ages.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Evolution at the population level is detected by measuring allele frequencies or trait frequencies across generations and looking for changes: if frequencies shift significantly (example: allele from 0.20 to 0.55 over generations), evolution is occurring, regardless of both alleles persisting. The pattern of change reveals the mechanism: consistent directional shifts (one increasing, one decreasing) could suggest selection or drift, but the key is recognizing the change itself as evolution. Here, f(a) increases from 0.20 to 0.55 while f(A) decreases from 0.80 to 0.45 over 20 generations, clearly showing evolving allele frequencies. Choice B correctly identifies the changing frequencies as evidence of population-level evolution. Choice D errs by claiming individuals change alleles with age, but alleles are inherited and fixed in individuals—evolution is generational, so keep focusing on populations! To analyze, tabulate frequencies per generation, compute differences (f(a) +0.35 total), confirm ongoing directional change, and conclude evolution is happening; this step-by-step process will make you proficient in spotting evolutionary dynamics.

Question 20

A biologist tracks three traits in the same lizard population over 40 generations.

Trait X frequency: 50%, 49%, 51%, 50%, 50% (Gen 0, 10, 20, 30, 40) Trait Y frequency: 8%, 18%, 33%, 55%, 72% (Gen 0, 10, 20, 30, 40) Trait Z frequency: 30%, 12%, 41%, 19%, 33% (Gen 0, 10, 20, 30, 40)

Which trait shows the clearest evidence of directional natural selection?

  1. Trait X, because it stays near 50% across all generations.
  2. Trait Z, because it changes the most from one time point to the next.
  3. Trait Y, because it increases consistently from 8% to 72% over time. (correct answer)
  4. All three traits, because any variation in a population automatically means selection is occurring.

Explanation: This question tests your ability to analyze population data over time to identify evolution (changes in allele or trait frequencies) and to infer whether natural selection is occurring based on patterns of change. Among the traits, Y's steady increase from 8% to 72% over 40 generations shows directional evolution likely due to natural selection, while X is stable (no evolution) and Z fluctuates randomly (possible drift). Directional selection is inferred from consistent, non-random increases correlating with potential environmental favors. The data allow comparison of patterns to pinpoint which trait is under strong selective pressure. Choice C correctly identifies Trait Y for its consistent upward trend. Choice B fails because Z's fluctuations aren't directional; they're erratic. Use this strategy: graph each trait, assess change type (steady up for selection, bouncing for drift), and compare magnitudes—keep up the excellent work in discerning selection signals!