Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games


Sign up

Log in

Opening subject page...

Loading your content

Practice

  • All Subjects
  • Algebra Flashcards
  • SAT Math Practice Tests
  • Math Question of the Day
  • Live Classes
  • On-Demand Courses

Varsity Tutors

  • Find a Tutor
  • Test Prep
  • Online Classes
  • K-12 Learning
  • College Search
  • VarsityTutors.com

© 2026 Varsity Tutors. All rights reserved.

← Back to quizzes

College Algebra Quiz

College Algebra Quiz: Real Numbers Operations And Properties

Practice Real Numbers Operations And Properties in College Algebra with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

Question 1 / 16

0 of 16 answered

How does commutativity affect 2+92 + 92+9?

Select an answer to continue

What this quiz covers

This quiz focuses on Real Numbers Operations And Properties, giving you a quick way to practice the rules, question types, and explanations that matter most for College Algebra.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

How does commutativity affect 2+92 + 92+9?

  1. It allows 2+9=9+22 + 9 = 9 + 22+9=9+2 (correct answer)
  2. It allows 2+9=2−92 + 9 = 2 - 92+9=2−9
  3. It allows 2+9=2⋅92 + 9 = 2 \cdot 92+9=2⋅9
  4. It allows 2+9=2÷92 + 9 = 2 \div 92+9=2÷9

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, commutativity allows switching the order of addition. The correct answer notes it allows 2 + 9 = 9 + 2. A common distractor might incorrectly apply it to other operations like subtraction. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 2

Solve 24÷6⋅224 \div 6 \cdot 224÷6⋅2 using order of operations.

  1. 222
  2. 888 (correct answer)
  3. 444
  4. 121212

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, division and multiplication are performed left to right. The correct answer computes 24 ÷ 6 * 2 = 8. A common distractor might incorrectly group the multiplication first. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 3

Identify the error: 16÷2⋅4=16÷(2⋅4)=216 \div 2 \cdot 4 = 16 \div (2 \cdot 4) = 216÷2⋅4=16÷(2⋅4)=2.

  1. Multiplication and division go left-to-right (correct answer)
  2. Division must always be done last
  3. You must add before multiplying
  4. Parentheses are optional here

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, the error is not performing division and multiplication left to right. The correct answer states that multiplication and division go left to right. A common distractor might suggest division is done last. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 4

Which property justifies x+0=xx + 0 = xx+0=x?

  1. Additive inverse
  2. Additive identity (correct answer)
  3. Multiplicative identity
  4. Associative property of addition

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, the additive identity property justifies adding zero without change. The correct answer selects the additive identity. A common distractor might confuse it with the additive inverse. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 5

Which property justifies a+b+c=a+(b+c)a + b + c = a + (b + c)a+b+c=a+(b+c)?

  1. Commutative property of addition
  2. Associative property of addition (correct answer)
  3. Additive identity
  4. Distributive property

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, the associative property justifies grouping terms differently. The correct answer identifies the associative property of addition. A common distractor might choose the commutative property. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 6

Which step is incorrect: 2(3+4)=6+42(3 + 4) = 6 + 42(3+4)=6+4?

  1. The 222 must multiply both 333 and 444 (correct answer)
  2. Distribution changes +++ to ×\times×
  3. The 222 should be added to 333 first
  4. Parentheses mean divide by 222

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, the error is in improperly applying the distributive property by not multiplying both terms. The correct answer notes that 2 must multiply both 3 and 4. A common distractor might confuse distribution with other operations. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 7

If xxx and yyy are nonzero real numbers, and 1x+1y=12\frac{1}{x} + \frac{1}{y} = \frac{1}{2}x1​+y1​=21​, which property justifies the step y+xxy=12\frac{y + x}{xy} = \frac{1}{2}xyy+x​=21​?

  1. The distributive property of multiplication over addition combined with properties of fractions
  2. The commutative property of addition combined with finding a common denominator (correct answer)
  3. The associative property of addition combined with the multiplicative inverse property
  4. The additive inverse property combined with the closure property of real numbers

Explanation: To get from 1x+1y\frac{1}{x} + \frac{1}{y}x1​+y1​ to y+xxy\frac{y + x}{xy}xyy+x​, we find a common denominator: 1x+1y=yxy+xxy=y+xxy\frac{1}{x} + \frac{1}{y} = \frac{y}{xy} + \frac{x}{xy} = \frac{y + x}{xy}x1​+y1​=xyy​+xyx​=xyy+x​. The numerator y+xy + xy+x shows the commutative property since x+y=y+xx + y = y + xx+y=y+x. Choice A incorrectly identifies the distributive property. Choice C mentions properties that don't apply to this fraction addition. Choice D incorrectly identifies additive inverse, which isn't used here.

Question 8

Solve 10−(2+3)⋅210 - (2 + 3) \cdot 210−(2+3)⋅2 using order of operations.

  1. 000 (correct answer)
  2. 101010
  3. −5-5−5
  4. −2-2−2

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, parentheses are evaluated first, then multiplication, followed by subtraction. The correct answer computes 10 - 5 * 2 = 0. A common distractor might forget to multiply after parentheses. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 9

Identify the error: 8−3−2=8−(3−2)=78 - 3 - 2 = 8 - (3 - 2) = 78−3−2=8−(3−2)=7.

  1. Subtraction is not associative (correct answer)
  2. Addition must be done before subtraction
  3. You must distribute the minus sign only to 333
  4. Subtraction is commutative

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, the error is assuming subtraction is associative, which it is not. The correct answer identifies that subtraction is not associative. A common distractor might incorrectly apply commutativity to subtraction. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 10

Solve 2(7+1)−322(7 + 1) - 3^22(7+1)−32 using order of operations.

  1. 777 (correct answer)
  2. 555
  3. 161616
  4. 999

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, parentheses are evaluated first, followed by exponents and then subtraction. The correct answer follows the rules by computing 2(8) - 9 = 7. A common distractor might neglect parentheses and compute incorrectly. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 11

Which of the following correctly identifies the property that allows us to conclude that if x+5=12x + 5 = 12x+5=12, then x+5+(−5)=12+(−5)x + 5 + (-5) = 12 + (-5)x+5+(−5)=12+(−5)?

  1. The addition property of equality combined with the existence of additive inverses (correct answer)
  2. The substitution property combined with the commutative property of addition
  3. The transitive property of equality combined with the associative property of addition
  4. The reflexive property of equality combined with the additive identity property

Explanation: The addition property of equality states that if a=ba = ba=b, then a+c=b+ca + c = b + ca+c=b+c for any real number ccc. Here we're adding (−5)(-5)(−5) to both sides of x+5=12x + 5 = 12x+5=12. The fact that we can add (−5)(-5)(−5) (the additive inverse of 555) relies on the existence of additive inverses in the real number system. Choice B incorrectly identifies substitution and commutativity. Choice C incorrectly identifies transitivity and associativity. Choice D incorrectly identifies reflexive property and additive identity.

Question 12

Solve −32+4-3^2 + 4−32+4 using order of operations.

  1. 131313
  2. −5-5−5 (correct answer)
  3. 111
  4. −13-13−13

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, the exponent is applied first, then addition, with the negative sign meaning negation of the square. The correct answer computes -9 + 4 = -5. A common distractor might interpret it as (-3)^2 = 9 + 4 = 13. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 13

Which property justifies 6(x+2)=6x+126(x + 2) = 6x + 126(x+2)=6x+12?

  1. Commutative property of addition
  2. Associative property of multiplication
  3. Distributive property (correct answer)
  4. Additive inverse

Explanation: This question tests knowledge of the order of operations and the properties of real numbers. The order of operations (PEMDAS) dictates the order in which operations are performed in an expression: parentheses, exponents, multiplication and division, addition and subtraction. In this specific problem, the distributive property justifies expanding the expression. The correct answer selects the distributive property. A common distractor might choose the commutative property instead. Teaching strategies include reinforcing order of operations through practice problems and emphasizing differences between properties using varied examples. Encourage students to verbalize each step to enhance understanding and retention.

Question 14

Which statement correctly explains why (−3)2=3\sqrt{(-3)^2} = 3(−3)2​=3 but (−3)2≠−3\sqrt{(-3)^2} \neq -3(−3)2​=−3?

  1. The distributive property shows that (−3)2=(−1⋅3)2=(−1)2⋅32=1⋅9=9(-3)^2 = (-1 \cdot 3)^2 = (-1)^2 \cdot 3^2 = 1 \cdot 9 = 9(−3)2=(−1⋅3)2=(−1)2⋅32=1⋅9=9, giving a positive result
  2. The order of operations requires us to evaluate the exponent first, giving us a positive result under the radical
  3. The commutative property of multiplication ensures that (−3)2=(−3)⋅(−3)=9(-3)^2 = (-3) \cdot (-3) = 9(−3)2=(−3)⋅(−3)=9, which has a positive square root
  4. The principal square root is always positive, and (−3)2=9(-3)^2 = 9(−3)2=9, so 9=3\sqrt{9} = 39​=3 by definition (correct answer)

Explanation: This question tests your understanding of square roots and the distinction between squaring a negative number versus taking the square root of a positive result. Let's work through this step by step. When you evaluate (−3)2(-3)^2(−3)2, you're multiplying (−3)×(−3)=9(-3) \times (-3) = 9(−3)×(−3)=9. Since you're multiplying two negative numbers, the result is positive. Now you have 9\sqrt{9}9​, and here's the crucial concept: the square root symbol (x\sqrt{\phantom{x}}x​) always refers to the principal square root, which is defined as the non-negative value. Since 3×3=93 \times 3 = 93×3=9 and 3 is positive, 9=3\sqrt{9} = 39​=3 by definition. Choice D correctly identifies this reasoning. The principal square root is always positive (or zero), so 9=3\sqrt{9} = 39​=3, not −3-3−3. Choice A incorrectly applies the distributive property, which doesn't apply to exponents in this way. You can't distribute an exponent over multiplication like (−1⋅3)2=(−1)2⋅32(-1 \cdot 3)^2 = (-1)^2 \cdot 3^2(−1⋅3)2=(−1)2⋅32. Choice B mentions order of operations, which is relevant but misses the main point about principal square roots. The key isn't just that we get a positive number under the radical, but what the square root symbol means. Choice C correctly explains why (−3)2=9(-3)^2 = 9(−3)2=9 using multiplication properties, but it incorrectly refers to the "commutative property" when this is really just the rule for multiplying signed numbers. Study tip: Remember that x\sqrt{x}x​ always means the principal (non-negative) square root. If you need the negative square root, it must be written as −x-\sqrt{x}−x​.

Question 15

Which of the following expressions demonstrates the correct application of both the distributive property and the commutative property of multiplication?

  1. 3(2x+5y)=6x+15y=15y+6x3(2x + 5y) = 6x + 15y = 15y + 6x3(2x+5y)=6x+15y=15y+6x
  2. 3(2x+5y)=(2x+5y)⋅3=2x⋅3+5y⋅33(2x + 5y) = (2x + 5y) \cdot 3 = 2x \cdot 3 + 5y \cdot 33(2x+5y)=(2x+5y)⋅3=2x⋅3+5y⋅3
  3. 3(2x+5y)=3⋅2x+3⋅5y=2x⋅3+5y⋅33(2x + 5y) = 3 \cdot 2x + 3 \cdot 5y = 2x \cdot 3 + 5y \cdot 33(2x+5y)=3⋅2x+3⋅5y=2x⋅3+5y⋅3 (correct answer)
  4. 3(2x+5y)=3⋅2x+3⋅5y=6x+15y3(2x + 5y) = 3 \cdot 2x + 3 \cdot 5y = 6x + 15y3(2x+5y)=3⋅2x+3⋅5y=6x+15y

Explanation: Choice C correctly shows both properties: first the distributive property 3(2x+5y)=3⋅2x+3⋅5y3(2x + 5y) = 3 \cdot 2x + 3 \cdot 5y3(2x+5y)=3⋅2x+3⋅5y, then the commutative property of multiplication 3⋅2x=2x⋅33 \cdot 2x = 2x \cdot 33⋅2x=2x⋅3 and 3⋅5y=5y⋅33 \cdot 5y = 5y \cdot 33⋅5y=5y⋅3. Choice A shows distributive then commutative of addition, not multiplication. Choice B shows commutative of multiplication first, then distributive, but doesn't complete the demonstration. Choice D only shows the distributive property without demonstrating commutativity of multiplication.

Question 16

Given that aaa, bbb, and ccc are real numbers with a≠0a \neq 0a=0, which statement about the expression ab+aca\frac{ab + ac}{a}aab+ac​ is correct when applying the properties of real numbers?

  1. It simplifies to b+cb + cb+c using the distributive property and multiplicative inverse property
  2. It simplifies to a(b+c)a=b+c\frac{a(b + c)}{a} = b + caa(b+c)​=b+c using factoring and the multiplicative identity property (correct answer)
  3. It cannot be simplified further because division distributes over addition differently than multiplication
  4. It simplifies to ab+acab + acab+ac using the commutative property of multiplication and addition

Explanation: The numerator ab+acab + acab+ac can be factored using the distributive property: ab+ac=a(b+c)ab + ac = a(b + c)ab+ac=a(b+c). Then ab+aca=a(b+c)a\frac{ab + ac}{a} = \frac{a(b + c)}{a}aab+ac​=aa(b+c)​. Since a≠0a \neq 0a=0, we have a(b+c)a=aa⋅(b+c)=1⋅(b+c)=b+c\frac{a(b + c)}{a} = \frac{a}{a} \cdot (b + c) = 1 \cdot (b + c) = b + caa(b+c)​=aa​⋅(b+c)=1⋅(b+c)=b+c by the multiplicative identity property. Choice A mentions the correct result but incorrectly identifies the multiplicative inverse property instead of identity. Choice C is incorrect as the expression can be simplified. Choice D doesn't lead to simplification.