Differential Equations Quiz: Frobenius Method

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Frobenius MethodQuestion 1 of 6

The differential equation $xy'' + 2y' + xy = 0$ has a regular singular point at $x = 0$ . After applying the Frobenius method and finding that one root of the indicial equation is $r_1 = 0$ , which of the following statements about the second linearly independent solution is correct?

The second solution has the form

y_2 = y_1 \ln x + x^{-1}\sum_{n=0}^{\infty} b_n x^n

where

y_1

is the first solution

The second solution has the form

y_2 = x^{-1}\sum_{n=0}^{\infty} b_n x^n

and can be found directly using the second root

r_2 = -1

The second solution requires the method of reduction of order and has the form

y_2 = y_1 \ln x + \sum_{n=1}^{\infty} b_n x^n

The second solution cannot be determined by the Frobenius method alone due to the integer difference in roots and requires alternative techniques

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Differential Equations Quiz

Differential Equations Quiz: Frobenius Method

Practice Frobenius Method in Differential Equations with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Frobenius Method, giving you a quick way to practice the rules, question types, and explanations that matter most for Differential Equations.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

The second solution has the form $y_2 = y_1 \ln x + x^{-1}\sum_{n=0}^{\infty} b_n x^n$ where $y_1$ is the first solution
The second solution has the form $y_2 = x^{-1}\sum_{n=0}^{\infty} b_n x^n$ and can be found directly using the second root $r_2 = -1$
The second solution requires the method of reduction of order and has the form $y_2 = y_1 \ln x + \sum_{n=1}^{\infty} b_n x^n$ (correct answer)
The second solution cannot be determined by the Frobenius method alone due to the integer difference in roots and requires alternative techniques

Explanation: The correct answer is C. The indicial equation for this equation gives roots

r_1 = 0

and

r_2 = -1

, with difference 1 (an integer). When the roots differ by an integer, the second solution typically has the form

y_2 = cy_1 \ln x + x^{r_2}\sum_{n=0}^{\infty} b_n x^n

where

c

may be zero. For this specific equation, the second solution is

y_2 = y_1 \ln x + \sum_{n=1}^{\infty} b_n x^n

(starting from

n=1

due to the specific structure). Choice A has incorrect powers of

x

. Choice B ignores the logarithmic term that's needed. Choice D is incorrect because Frobenius method can handle this case, though it requires the generalized form with logarithmic terms.

Question 2

Consider the modified Bessel equation $x^2y'' + xy' - (x^2 + ν^2)y = 0$ . When $ν = \frac{1}{2}$ , what distinguishes the behavior of the Frobenius series solutions from those of the standard Bessel equation $x^2y'' + xy' + (x^2 - ν^2)y = 0$ ?

The modified equation yields exponentially growing and decaying solutions rather than oscillatory Bessel functions, but both maintain the same $x^{±1/2}$ behavior near $x = 0$ (correct answer)
The modified equation requires logarithmic terms in both solutions due to the negative coefficient, while the standard equation has pure power series solutions
Both equations yield identical solutions since the sign change only affects higher-order terms in the series expansion
The modified equation produces polynomial solutions when $ν = 1/2$ , while the standard equation yields infinite series solutions

Explanation: The correct answer is A. The key difference is the sign of the

x^2

term. Both equations have the same indicial equation giving roots

r = ±1/2

, so both have the same

x^{±1/2}

behavior near

x = 0

. However, the modified Bessel equation leads to modified Bessel functions

I_{1/2}(x)

and

K_{1/2}(x)

, which have exponential rather than oscillatory character for large

x

. The recurrence relations differ due to the sign change, leading to fundamentally different asymptotic behavior. Choice B is wrong because logarithmic terms don't automatically appear due to sign changes. Choice C is incorrect because the sign change fundamentally alters the solution character. Choice D is wrong because neither equation produces polynomial solutions for

ν = 1/2

Question 3

For the equation $x^2y'' + x(x-1)y' + (x^2 + 1)y = 0$ , suppose the indicial equation has roots $r_1 = \frac{1}{2}$ and $r_2 = -\frac{3}{2}$ . If the series solution corresponding to $r_1$ is $y_1 = x^{1/2}(1 + a_1x + a_2x^2 + \cdots)$ , what constraint must be satisfied for the existence of a second linearly independent solution of standard Frobenius form?

No additional constraint is needed since the roots differ by 2, which ensures two independent power series solutions exist
The coefficient $a_2$ in the first solution must satisfy $a_2 = 0$ to prevent resonance in the second solution's recurrence relation
The second solution automatically requires logarithmic terms because the difference $r_1 - r_2 = 2$ is an even integer
We must verify that the recurrence relation for the second solution doesn't lead to division by zero at the critical step corresponding to the root difference (correct answer)

Explanation: The correct answer is D. When the roots of the indicial equation differ by an integer (here,

r_1 - r_2 = 2

), the second solution may or may not exist in standard Frobenius form. The critical issue is whether the recurrence relation for the second solution leads to division by zero at the step where

n = r_1 - r_2 = 2

. At this step, the coefficient of

a_2

in the recurrence becomes zero, potentially making

a_2

indeterminate or forcing logarithmic terms. We must check if the numerator is also zero at this step. Choice A is wrong because integer difference doesn't guarantee two standard solutions. Choice B incorrectly identifies which coefficient matters. Choice C is wrong because even integers don't automatically require logarithmic terms.

Question 4

Consider the equation $x^2y'' + xy' + (x^2 - ν^2)y = 0$ where $ν$ is not an integer. When $ν = \frac{3}{2}$ , the Frobenius method yields two solutions. What is the relationship between these solutions near $x = 0$ ?

Both solutions behave like $x^{3/2}$ and $x^{-3/2}$ respectively, with the second requiring logarithmic terms due to resonance
Both solutions behave like $x^{3/2}$ and $x^{-3/2}$ respectively, and both can be expressed as pure power series without logarithmic terms (correct answer)
One solution behaves like $x^{3/2}$ while the second behaves like $x^{-3/2} \ln x$ due to the half-integer difference in roots
Both solutions require logarithmic terms because $ν = \frac{3}{2}$ creates a resonance condition in the recurrence relations

Explanation: The correct answer is B. This is Bessel's equation with

ν = 3/2

. The indicial equation gives roots

r_1 = 3/2

and

r_2 = -3/2

, with difference 3 (an integer). However, since

ν = 3/2

is not an integer, both solutions

J_{3/2}(x)

and

J_{-3/2}(x)

exist as linearly independent power series solutions. The key insight is that logarithmic terms only appear when the parameter

ν

itself is an integer, not when the difference of roots is an integer. Choice A incorrectly mentions logarithmic terms. Choice C incorrectly assumes logarithmic behavior due to half-integer difference. Choice D incorrectly claims resonance occurs for non-integer

ν

Question 5

The Frobenius method is applied to $x^2y'' + xy' + (\alpha x^3 + \beta x^2 + \gamma)y = 0$ where $\alpha, \beta, \gamma$ are constants. If the indicial equation yields a double root $r = 0$ , and the first solution is found successfully, what determines whether the second linearly independent solution requires logarithmic terms?

Logarithmic terms are always required when the indicial equation has a double root, regardless of the equation parameters
The presence of logarithmic terms depends on whether $\gamma = 0$ , since this affects the lowest-order terms in the recurrence
The coefficient $\beta$ determines the need for logarithmic terms, as it controls the $x^2$ term that creates resonance with the double root
Whether logarithmic terms appear depends on the solvability condition in the recurrence relation at the step where the coefficient determinant vanishes (correct answer)

Explanation: The correct answer is D. When the indicial equation has a double root, the second solution may or may not require logarithmic terms depending on the specific equation. The determining factor is whether the recurrence relation for the second solution leads to a consistency condition (solvability condition) at the step where the coefficient determinant becomes zero. If this condition is satisfied, a second power series solution exists; if not, logarithmic terms are required. Choice A is incorrect because double roots don't automatically require logarithmic terms. Choice B oversimplifies the relationship to just one parameter. Choice C incorrectly identifies

\beta

as the sole determining factor. The actual determination requires careful analysis of the full recurrence system.

Question 6

Consider the equation $x(x-1)y'' + (3x-1)y' + y = 0$ . This equation has singular points at $x = 0$ and $x = 1$ . When analyzing the behavior near $x = 0$ using the Frobenius method, what complication arises that doesn't occur in equations with a single regular singular point?

The indicial equation becomes a quartic rather than quadratic, requiring numerical methods to find the roots
The radius of convergence of the Frobenius series is limited by the distance to the next singular point at $x = 1$ (correct answer)
Both singular points must be regular for the Frobenius method to work, requiring simultaneous analysis at both points
The recurrence relations become coupled due to interference from the second singular point, preventing closed-form solutions

Explanation: The correct answer is B. When applying the Frobenius method near

x = 0

, the presence of another singular point at

x = 1

limits the radius of convergence of the power series to at most the distance between singular points, which is 1. This is a fundamental limitation of series solutions - they can only converge in a neighborhood that doesn't contain other singular points. The indicial equation remains quadratic (choice A is wrong). The regularity of both points is important for global analysis but doesn't prevent local Frobenius analysis (choice C is wrong). The recurrence relations are determined locally and aren't directly coupled by distant singular points (choice D is wrong). This radius limitation is a crucial practical consideration when using Frobenius series.