GED MATHEMATICAL REASONING • ALGEBRAIC PROBLEM SOLVING

Solve quadratic equations.

Master three powerful methods to find unknown values in equations with squared terms.

Historical Context & Motivation

People have been solving quadratic equations for thousands of years, long before anyone called them "quadratic." Ancient civilizations needed to calculate areas of land, design buildings, and predict the paths of projectiles. Whenever the quantity you are looking for is squared—multiplied by itself—you are dealing with a quadratic equation. Understanding where these equations come from helps you see why they appear so often on the GED and in everyday life.

~2000 BCE
Babylonian Clay Tablets
Babylonian scribes solved area problems that we would now write as quadratic equations, using a method similar to completing the square—all without modern notation.
~300 BCE
Greek Geometric Algebra
Euclid's Elements showed how to solve quadratic problems by constructing geometric shapes, connecting algebra to visual reasoning.
~820 CE
Al-Khwarizmi's Algebra
The Persian mathematician al-Khwarizmi published systematic rules for solving quadratics. The word "algebra" itself comes from the title of his book.
1637
Descartes & Modern Notation
René Descartes introduced the notation we use today—letters like x for unknowns and superscripts for exponents—making quadratic equations easier to write and solve.

Today, quadratic equations show up in contexts ranging from calculating the trajectory of a basketball to figuring out profit in a business plan. On the GED, roughly 55 percent of the test focuses on algebraic problem solving, and quadratics are a core part of that. The good news: there are clear, step-by-step methods you can learn to solve every quadratic equation you will encounter.

Core Principles & Definitions

A quadratic equation is any equation that can be written in the form ax² + bx + c = 0, where a, b, and c are numbers and a is not zero. The highest power of the variable x is 2, which is why the graph of a quadratic makes a U-shaped curve called a parabola. Before you can solve a quadratic, you need to understand a few foundational ideas.

1

Standard Form

Always rearrange the equation so it reads ax² + bx + c = 0. Everything on one side, zero on the other. This is your starting point for every method.
2

Two Solutions (Usually)

Because the variable is squared, a quadratic equation can have two solutions, one solution, or no real solutions. The GED focuses on equations with one or two real solutions.
3

Three Solving Methods

You can solve by factoring, by using the quadratic formula, or (less commonly on the GED) by completing the square. Choosing the right method saves time.
4

Check Your Work

Plug each solution back into the original equation. If both sides are equal, your answer is correct. This verification step catches sign errors and arithmetic mistakes.
KEY TAKEAWAY
Think of a quadratic equation like asking, "At what two times does a ball thrown in the air reach a height of 20 feet?" The ball passes through that height once on the way up and once on the way down—that is why quadratics usually have two solutions.

Visual Explanation — The Parabola and Its Solutions

The graph of a quadratic equation is a parabola. The solutions (also called roots or x-intercepts) are the x-values where the parabola crosses the horizontal axis. The diagram below shows the parabola for y = x² − 2x − 3, which factors into (x − 3)(x + 1) = 0. Notice the curve crosses the x-axis at x = −1 and x = 3.

The parabola for y = x² − 2x − 3 crosses the x-axis at the two solutions: x = −1 and x = 3. The vertex at (1, −4) is the lowest point of the curve.

When you solve a quadratic equation, you are finding those x-intercept values—the places where the parabola touches or crosses the x-axis. If the parabola just touches the axis at one point, the equation has one solution. If the parabola floats above or below the axis without crossing, there are no real solutions. On the GED, you will almost always work with equations that have one or two real solutions.

Mathematical Framework — Three Solving Methods

There are three main methods for solving quadratic equations. Each one works, but some are faster depending on the equation. The GED formula sheet provides the quadratic formula, so you never need to memorize it—but you do need to know how to use it. Let's look at each method.

Method 1: Factoring

Factoring works when you can rewrite the quadratic as a product of two binomials. You rely on the zero product property: if A × B = 0, then either A = 0 or B = 0. So once you factor, set each factor equal to zero and solve.

FACTORING PATTERN
ax² + bx + c = 0 → (x + p)(x + q) = 0 → x = −p or x = −q
Find two numbers p and q that multiply to c and add to b (when a = 1). Set each factor to zero to find the solutions.

Method 2: The Quadratic Formula

The quadratic formula works for every quadratic equation, whether or not it factors neatly. It is provided on the GED formula sheet, so your job is to identify a, b, and c from standard form, plug them in, and simplify carefully.

QUADRATIC FORMULA
x = (−b ± √(b² − 4ac)) / (2a)
a = coefficient of x², b = coefficient of x, c = constant term. The ± symbol means you compute two values: one with + and one with −.

The Discriminant — How Many Solutions?

DISCRIMINANT
D = b² − 4ac
If D > 0 → two real solutions. If D = 0 → one real solution. If D < 0 → no real solutions. The discriminant is the expression under the square root in the quadratic formula.

Method 3: Square Root Method

When the equation has no bx term (b = 0) or can be written as (x + k)² = d, you can solve by taking the square root of both sides. Remember to include both the positive and negative square root.

SQUARE ROOT METHOD
x² = d → x = ±√d
This method is the fastest when there is no middle term (bx). For example, x² = 25 gives x = 5 or x = −5.

Choosing the Right Method

Knowing which method to use is just as important as knowing how to use it. On the timed GED, picking the most efficient approach can save you valuable minutes. The decision tree below walks you through the process, and the comparison table summarizes when each method shines.

Start at the top and follow the arrows. If the bx term is missing, use the square root method. If the equation factors easily, use factoring. Otherwise, use the quadratic formula.
Comparison of quadratic solving methods
MethodBest When...Example
Square RootNo bx term; equation is x² = numberx² − 16 = 0 → x = ±4
FactoringCoefficients are small integers; factors are easy to spotx² + 5x + 6 = 0 → (x + 2)(x + 3) = 0
Quadratic FormulaFactoring is not obvious; messy coefficients; or you want a guaranteed approach2x² − 3x − 7 = 0 → use the formula

Worked Examples

Example A — Solving by Factoring

Solve x² + 2x − 15 = 0 by Factoring
1
Step 1 — Confirm Standard FormThe equation is already in the form ax² + bx + c = 0. Here, a = 1, b = 2, and c = −15.
2
Step 2 — Find Two Numbers That Multiply to c and Add to bWe need two numbers that multiply to −15 and add to 2. Try factor pairs of −15: (1, −15), (−1, 15), (3, −5), (−3, 5). The pair −3 and 5 works because −3 × 5 = −15 and −3 + 5 = 2.
Numbers: −3 and 5
3
Step 3 — Write in Factored Formx² + 2x − 15 = (x − 3)(x + 5) = 0
4
Step 4 — Apply the Zero Product PropertySet each factor equal to zero: x − 3 = 0 gives x = 3. x + 5 = 0 gives x = −5.
x = 3 or x = −5
5
Step 5 — Check Both SolutionsFor x = 3: (3)² + 2(3) − 15 = 9 + 6 − 15 = 0 ✓. For x = −5: (−5)² + 2(−5) − 15 = 25 − 10 − 15 = 0 ✓. Both solutions check out.

Example B — Solving with the Quadratic Formula

Solve 2x² − 5x − 3 = 0 Using the Quadratic Formula
1
Step 1 — Identify a, b, and cFrom 2x² − 5x − 3 = 0: a = 2, b = −5, c = −3. Be careful with signs—b is negative.
2
Step 2 — Calculate the DiscriminantD = b² − 4ac = (−5)² − 4(2)(−3) = 25 + 24 = 49. Since D > 0, there are two real solutions.
D = 49
3
Step 3 — Plug into the Formulax = (−b ± √D) / (2a) = (−(−5) ± √49) / (2 × 2) = (5 ± 7) / 4
4
Step 4 — Compute Both SolutionsUsing +: x = (5 + 7) / 4 = 12/4 = 3. Using −: x = (5 − 7) / 4 = −2/4 = −1/2.
x = 3 or x = −0.5
5
Step 5 — VerifyFor x = 3: 2(9) − 5(3) − 3 = 18 − 15 − 3 = 0 ✓. For x = −0.5: 2(0.25) − 5(−0.5) − 3 = 0.5 + 2.5 − 3 = 0 ✓.

Common Mistakes & How to Avoid Them

Quadratic equations are not inherently difficult, but small errors in arithmetic or sign-handling can derail an entire problem. The table below summarizes the most frequent mistakes GED test-takers make and how to prevent them.

Five most common quadratic mistakes on the GED
Common MistakeWhy It HappensHow to Fix It
Forgetting the ± signStudents take only the positive square rootAlways write ± immediately when taking a square root
Wrong sign for bThe formula says −b, so if b is already negative, −(−b) = +bWrite down a, b, c with their signs first, then substitute
Not setting equation = 0Trying to factor while terms are on both sidesMove everything to one side before solving
Dividing by x instead of factoringThis loses the solution x = 0Factor out x instead: x(x + 3) = 0 gives x = 0 or x = −3
Arithmetic errors in b² − 4acSquaring negative numbers or multiplying signs incorrectlyCompute b² first, then 4ac separately, then subtract
📝 GED TEST TIP
On the GED, you can use the TI-30XS calculator for Part 2 to double-check your discriminant calculation. Compute b² first, store it, then compute 4ac, and subtract. This two-step approach catches sign errors. Remember: Part 1 has no calculator, so for those five questions, practice doing these calculations by hand with small, clean numbers.

Connections to Advanced Topics

The skills you build solving quadratic equations form the foundation for more advanced algebra and beyond. While the GED tests the basics, understanding where these concepts lead can motivate your study and prepare you for college-level math.

How GED quadratic skills connect to college math
GED LevelCollege Level
Solve ax² + bx + c = 0 for xSolve polynomial equations of degree 3, 4, or higher
Graph a parabola and find x-interceptsAnalyze families of curves, transformations, and conic sections
Use the discriminant to count solutionsWork with complex numbers when D < 0
Apply quadratics to area and projectile problemsUse calculus to optimize area, profit, and motion

If you score 165 or higher on the GED Mathematical Reasoning test, you earn the "College Ready" designation, which can help you place directly into credit-bearing college math courses. Mastering quadratics is one of the most important steps toward that goal because these equations appear in nearly every branch of higher mathematics and science.

Practice Problems

💡 Before You Begin
Problems 1–2 should be attempted without a calculator, just like Part 1 of the GED. For Problems 3–5, feel free to use the TI-30XS or any calculator. Remember: the quadratic formula is on the GED formula sheet.
1
A physics student is solving the equation x² − 9 = 0 as part of a projectile problem on a homework assignment. She recognizes that this equation has no middle term (no bx term). Which method is the most efficient way to solve this equation? Choose the best answer.
2
Solve by factoring: x² + 7x + 12 = 0 What are the solutions?
3
Use the quadratic formula to solve 3x² + 2x − 5 = 0. What are the two solutions?
4
A rectangular garden has a length that is 3 feet more than its width. The area of the garden is 70 square feet. If w represents the width in feet, the equation w² + 3w − 70 = 0 models this situation. What is the width of the garden?
PROBLEM 5CRITICAL THINKING
A ball is launched upward from a 6-foot-high platform. Its height in feet after t seconds is modeled by h = −16t² + 32t + 6. At what time does the ball hit the ground? Set h = 0 and solve using the quadratic formula. Round your answer to the nearest hundredth of a second. (Show your work.)

Summary — Solving Quadratic Equations

A quadratic equation takes the form ax² + bx + c = 0 and typically has two solutions. You can solve by three methods: the square root method (when there is no bx term), factoring (when two numbers multiply to c and add to b), or the quadratic formula (which works every time and is provided on your GED formula sheet). Always start by putting the equation in standard form and always check your answers by plugging them back in.

The discriminant (b² − 4ac) tells you how many real solutions to expect: positive means two, zero means one, and negative means none. On applied word problems, remember to reject solutions that don't make sense in context—you cannot have a negative length or a negative time. Practice choosing the right method quickly: if factoring isn't obvious within 30 seconds, switch to the quadratic formula. Confidence with quadratics puts you in a strong position for the 55% of the GED that covers algebraic problem solving.

Varsity Tutors • GED Mathematical Reasoning • Solve quadratic equations.