GED Math Quiz: Functions

What this quiz covers

This quiz focuses on Functions, giving you a quick way to practice the rules, question types, and explanations that matter most for GED Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

Question 1

1. $a > 0$ and $c > 0$
2. $a < 0$ and $c > 0$ (correct answer)
3. $a < 0$ and $c < 0$
4. $a > 0$ and $c < 0$

Explanation: The parabola opens downward, so $a < 0$. The y-intercept is $c = f(0)$, and the graph crosses the y-axis above the x-axis, so $c > 0$. Choice A confuses direction of opening. Choice C gets both signs wrong on the y-intercept. Choice D reverses the opening direction.

Question 2

1. $f(x) = -(x+1)(x-3)$ (correct answer)
2. $f(x) = -(x-1)(x+3)$
3. $f(x) = (x+1)(x-3)$
4. $f(x) = -2(x+1)(x-3)$

Explanation: The x-intercepts are at $x = -1$ and $x = 3$, giving factors $(x+1)$ and $(x-3)$. The parabola opens downward, so leading coefficient is negative. The y-intercept from the graph is $3$: check $f(0) = -(1)(-3) = 3$ ✓. So $f(x) = -(x+1)(x-3)$. Choice B swaps the x-intercept signs. Choice C has wrong opening direction. Choice D gives y-intercept of 6, not 3.

Question 3

1. $6$
2. $-2$
3. $10$ (correct answer)
4. $2$

Explanation: Note that $f(-1) = a(-1)^2 + b(-1) + c = a - b + c$. From the table, $f(-1) = 10$. Therefore $a - b + c = 10$. Choice A is $f(1) = a + b + c$. Choice B is $f(0)$-adjacent error. Choice D is simple sign confusion. This clever question tests understanding that $f(-1)$ directly gives $a-b+c$.

Question 4

1. $22
2. $33
3. $44 (correct answer)
4. $55

Explanation: When $x = 4$ items, the price per item is $p(4) = 2(4) + 3 = 11$ dollars. Revenue equals price per item times number of items: Revenue $= 11 \times 4 = 44$ dollars. Choice A likely confuses the setup and uses $p(4) \times q(11) = 11 \times 2 = 22$. Choice B might result from $p(4) + p(4) + p(4) = 11 + 11 + 11 = 33$ (adding price three times instead of multiplying by 4). Choice D could come from misunderstanding the problem setup entirely.

Question 5

1. 3
2. 5
3. 7 (correct answer)
4. 9

Explanation: Using the given conditions: $f(3) = 9 + 3b + c = 4$ and $f(-1) = 1 - b + c = 12$. From the first equation: $3b + c = -5$. From the second equation: $-b + c = 11$. Subtracting the second from the first: $4b = -16$, so $b = -4$. Substituting back into the second equation: $c = 11 + b = 11 + (-4) = 7$. Therefore $f(x) = x^2 - 4x + 7$, and $f(0) = 0 - 0 + 7 = 7$. We can verify: $f(3) = 9 - 12 + 7 = 4$ ✓ and $f(-1) = 1 + 4 + 7 = 12$ ✓.

Question 6

1. Maximum profit of $8,000 when producing 400 units (correct answer)
2. Maximum profit of $8,000 when producing 800 units
3. Maximum profit of $4,000 when producing 400 units
4. Maximum profit of $4,000 when producing 800 units

Explanation: For $P(x) = -2x^2 + 16x - 24$, the vertex occurs at $x = -\frac{b}{2a} = -\frac{16}{2(-2)} = 4$. The maximum profit is $P(4) = -2(16) + 16(4) - 24 = -32 + 64 - 24 = 8$. Since $x$ is in hundreds of units, this means 400 units, and since $P(x)$ is in thousands of dollars, the maximum profit is $8,000. Choice B uses the correct profit but wrong production level (800 vs 400). Choices C and D use incorrect profit calculations, likely from arithmetic errors in evaluating $$P(4)$ $.

Question 7

1. $x = 1$
2. $x = 2$
3. $x = 3$ (correct answer)
4. $x = 4$

Explanation: From the graph, $f(x) = -\frac{1}{2}x + \frac{9}{2}$ (passes through $(1,4)$ and $(5,2)$). Setting $f(x) = x$: $-\frac{1}{2}x + \frac{9}{2} = x$, so $\frac{9}{2} = \frac{3}{2}x$, giving $x = 3$. Check: $f(3) = -1.5 + 4.5 = 3$. ✓ Distractors correspond to misreading the slope or y-intercept from the graph.

Question 8

1. $-9$ (correct answer)
2. $-8$
3. $-1$
4. $0$

Explanation: The function values are symmetric: $f(-1)=0$ and $f(5)=0$, so the axis of symmetry is $x=2$. The vertex is at $x=2$. Using finite differences or the pattern, $f(2)$ can be computed: from $f(0)=-5$ and $f(4)=-5$, with $f(1)=-8$ and $f(3)=-8$, the vertex at $x=2$ gives $f(2)=-9$. Choice B picks the lowest value shown. Choice C picks the average of zeros incorrectly. Choice D picks a zero of the function.

Question 9

1. $2$
2. $3$
3. $4$ (correct answer)
4. $5$

Explanation: From the graph, f(x) = x + 2 and g(x) = x² - 2. They intersect where x + 2 = x² - 2, giving x² - x - 4 = 0, so x ≈ -1.56 and x ≈ 2.56. Between these intersection points, the linear function is above the parabola. Checking integer values in [-3, 4]: at x = -1: f(-1) = 1, g(-1) = -1, so f > g ✓. At x = 0: f(0) = 2, g(0) = -2, so f > g ✓. At x = 1: f(1) = 3, g(1) = -1, so f > g ✓. At x = 2: f(2) = 4, g(2) = 2, so f > g ✓. Therefore, 4 integer values satisfy f(x) > g(x).

Question 10

1. $(-1, 1)$
2. $(3, 1)$
3. $(-1, 7)$
4. $(3, 7)$ (correct answer)

Explanation: The vertex of $f(x)$ is at $(1, 4)$. The transformation $g(x) = f(x-2) + 3$ shifts the graph right 2 and up 3. New vertex: $(1+2, 4+3) = (3, 7)$. Choice A shifts left and down (reverses both). Choice B shifts right but subtracts 3. Choice C shifts left but adds 3.

Question 11

1. 13 (correct answer)
2. 3
3. -3
4. -13

Explanation: When you encounter a function notation problem like $f(x) = 5 - 2x$, you're being asked to substitute a specific value for the variable and calculate the result. Function notation $f(-4)$ means "find the output when the input is -4." To solve this, replace every $x$ in the function with -4: $f(-4) = 5 - 2(-4)$ Following order of operations, multiply first: $2(-4) = -8$ Then subtract: $f(-4) = 5 - (-8) = 5 + 8 = 13$ Looking at the wrong answers reveals common mistakes. Choice B (3) results from incorrectly calculating $5 - 2(-4)$ as $5 - 2 + 4 = 7$, then making an arithmetic error. Choice C (-3) comes from treating the negative input incorrectly, perhaps calculating $5 - 2(4) = -3$ by dropping the negative sign. Choice D (-13) occurs when you forget that subtracting a negative number means addition, calculating $5 - 8 = -13$ instead of recognizing that $5 - (-8) = 5 + 8$. The correct answer is A (13). Remember this key strategy for function problems: substitute carefully and watch your signs. When you see a negative input like -4, pay extra attention to how it interacts with operations in the function. The most common error is mishandling the arithmetic when negative numbers are involved, so double-check your work by verifying each step of the calculation.

Question 12

1. 2
2. 4
3. 6 (correct answer)
4. 18

Explanation: This question tests function evaluation and solving linear equations. When you see $g(x) = 11$, you're being asked to find which input value makes the function output equal to 11. To solve this, substitute 11 for $g(x)$ in the equation: $11 = 3x - 7$. Now solve for $x$ by adding 7 to both sides: $18 = 3x$. Finally, divide both sides by 3: $x = 6$. You can verify this by substituting back: $g(6) = 3(6) - 7 = 18 - 7 = 11$ ✓ Looking at the wrong answers: Choice A gives us $g(2) = 3(2) - 7 = -1$, not 11. Choice B gives us $g(4) = 3(4) - 7 = 5$, still not 11. Choice D gives us $g(18) = 3(18) - 7 = 47$, which is far too large. These incorrect answers likely come from common algebraic mistakes like forgetting to add 7 to both sides, or confusing the input with the output. Remember that function notation like $g(x) = 11$ means "what input gives me an output of 11?" Don't let the notation intimidate you—it's just asking you to solve a regular equation. Always check your answer by plugging it back into the original function to make sure you get the desired output.

Question 13

1. 16
2. 23 (correct answer)
3. 26
4. 35

Explanation: First, find $a$ and $b$. From $g(a) = 2$: $3a - 7 = 2$, so $3a = 9$ and $a = 3$. From $g(b) = 14$: $3b - 7 = 14$, so $3b = 21$ and $b = 7$. Therefore $a + b = 3 + 7 = 10$. Finally, $g(a + b) = g(10) = 3(10) - 7 = 23$. Choice A incorrectly adds $g(a) + g(b) = 2 + 14 = 16$. Choice C likely results from calculation errors. Choice D uses $3(a + b) + 7$ instead of $3(a + b) - 7$.

Question 14

1. $\frac{1}{2}$
2. $1$
3. $3$
4. $2$ (correct answer)

Explanation: When you encounter a quadratic function problem with given zeros and a minimum/maximum value, you're working with the vertex form and factored form together. The zeros tell you where the parabola crosses the x-axis, while the minimum value gives you information about the vertex. Since the zeros are at $x = -1$ and $x = 5$, you can write the function in factored form: $y = a(x + 1)(x - 5)$. The vertex occurs at the midpoint between the zeros, so $x = \frac{-1 + 5}{2} = 2$. Since $a$ will be positive (the function has a minimum, not maximum), the vertex is at $(2, -18)$. To find $a$, substitute the vertex coordinates into your factored form: $-18 = a(2 + 1)(2 - 5) = a(3)(-3) = -9a$. Solving for $a$: $a = \frac{-18}{-9} = 2$. Let's check why the other answers don't work. Choice A ($a = \frac{1}{2}$) would give a minimum value of $-9$, not $-18$. Choice B ($a = 1$) would produce a minimum of $-9$ as well. Choice C ($a = 3$) would create a minimum of $-27$, which is too low. Remember this key strategy: when you have zeros and a vertex value, use the factored form $y = a(x - r_1)(x - r_2)$ where $r_1$ and $r_2$ are the zeros. The vertex x-coordinate is always the average of the zeros, and you can substitute the vertex point to solve for $a$.

Question 15

1. $t = 1$ second and $t = 4$ seconds only
2. $t = 2$ seconds and $t = 3$ seconds only
3. $t = 2$ seconds only, at the maximum height
4. $t = 1$ second and $t = 3$ seconds only (correct answer)

Explanation: This question tests your ability to solve quadratic equations in a real-world context. When you see a quadratic function modeling height over time, you're typically looking for specific values of time when the object reaches a particular height. To find when the object is at 128 feet, you need to set the height function equal to 128 and solve for $t$: $-16t^2 + 64t + 80 = 128$ Subtract 128 from both sides: $-16t^2 + 64t - 48 = 0$ Divide everything by -16 to simplify: $t^2 - 4t + 3 = 0$ This factors as $(t - 1)(t - 3) = 0$, giving you $t = 1$ and $t = 3$ seconds. Let's examine why the other answers are wrong. Choice A includes $t = 4$ seconds, but substituting this into the original equation gives $h(4) = -16(16) + 64(4) + 80 = 80$ feet, not 128. Choice B gives $t = 2$ and $t = 3$ seconds. While $t = 3$ is correct, $t = 2$ yields $h(2) = -16(4) + 64(2) + 80 = 144$ feet. Choice C suggests only $t = 2$ at maximum height, but as we calculated, the height at $t = 2$ is 144 feet, and the maximum occurs at the vertex, not necessarily when height equals 128. When solving quadratic equations in context, always check your solutions by substituting back into the original equation. This catches calculation errors and ensures your answers make sense within the problem's constraints.