GMAT Data Insights Quiz: Determine Sufficiency
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Determine SufficiencyQuestion 1 of 5

In triangle ABCABC, what is the length of side BCBC?

(1) The area of triangle ABCABC is 24, and the altitude from AA to side BCBC has length 6 (2) AB=10AB = 10, AC=8AC = 8, and angle A=60°A = 60°

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
EACH statement ALONE is sufficient to answer the question.
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GMAT Data Insights Quiz

GMAT Data Insights Quiz: Determine Sufficiency

Practice Determine Sufficiency in GMAT Data Insights with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Determine Sufficiency, giving you a quick way to practice the rules, question types, and explanations that matter most for GMAT Data Insights.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

In triangle ABCABC, what is the length of side BCBC?

(1) The area of triangle ABCABC is 24, and the altitude from AA to side BCBC has length 6 (2) AB=10AB = 10, AC=8AC = 8, and angle A=60°A = 60°

  1. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
  2. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
  3. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
  4. EACH statement ALONE is sufficient to answer the question. (correct answer)

Explanation: Statement (1): Using the formula for area, Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}. Here, 24=12×BC×624 = \frac{1}{2} \times BC \times 6, which gives us BC=8BC = 8. Statement (1) is sufficient. Statement (2): We can use the Law of Cosines: BC2=AB2+AC22(AB)(AC)cosA=102+822(10)(8)cos(60°)=100+64160×12=16480=84BC^2 = AB^2 + AC^2 - 2(AB)(AC)\cos A = 10^2 + 8^2 - 2(10)(8)\cos(60°) = 100 + 64 - 160 \times \frac{1}{2} = 164 - 80 = 84. Therefore, BC=84=221BC = \sqrt{84} = 2\sqrt{21}. Statement (2) is sufficient. Each statement alone is sufficient.

Question 2

What is the value of x2+y2x^2 + y^2?

(1) x+y=5x + y = 5 and xy=6xy = 6 (2) (xy)2=1(x - y)^2 = 1

  1. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. (correct answer)
  2. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
  3. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
  4. EACH statement ALONE is sufficient to answer the question.

Explanation: We need to find x2+y2x^2 + y^2. Statement (1): Given x+y=5x + y = 5 and xy=6xy = 6. We can use the identity (x+y)2=x2+2xy+y2(x + y)^2 = x^2 + 2xy + y^2, which gives us 25=x2+12+y225 = x^2 + 12 + y^2. Therefore, x2+y2=13x^2 + y^2 = 13. Statement (1) is sufficient. Statement (2): (xy)2=1(x - y)^2 = 1 means x22xy+y2=1x^2 - 2xy + y^2 = 1, so x2+y2=1+2xyx^2 + y^2 = 1 + 2xy. However, we don't know the value of xyxy, so we cannot determine x2+y2x^2 + y^2. Statement (2) alone is not sufficient.

Question 3

If xx and yy are integers, is xyxy even?

(1) x+yx + y is odd (2) x2+y2x^2 + y^2 is even

  1. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
  2. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. (correct answer)
  3. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
  4. EACH statement ALONE is sufficient to answer the question.

Explanation: This data sufficiency question tests your understanding of even/odd properties and how they interact through different operations. The key insight is recognizing what each statement tells you about the parity (even/odd nature) of xx and yy. For xyxy to be even, at least one of xx or yy must be even. If both are odd, their product is odd. Statement (1) tells us x+yx + y is odd. This happens only when one number is even and the other is odd (since even + even = even, and odd + odd = even). If exactly one of xx or yy is even, then their product xyxy must be even. Statement (1) alone is sufficient. Statement (2) tells us x2+y2x^2 + y^2 is even. Since squaring preserves parity (even² = even, odd² = odd), this means we have either even² + even² = even or odd² + odd² = even. Both scenarios give an even sum, so we can't determine whether xx and yy have the same parity or different parities. For example, if x=1,y=3x = 1, y = 3, then x2+y2=10x^2 + y^2 = 10 (even) but xy=3xy = 3 (odd). If x=1,y=2x = 1, y = 2, then x2+y2=5x^2 + y^2 = 5 (odd), contradicting our statement. Actually, if x=2,y=4x = 2, y = 4, then x2+y2=20x^2 + y^2 = 20 (even) and xy=8xy = 8 (even). Statement (2) alone is insufficient. Answer choice B is correct because statement (1) alone is sufficient while statement (2) alone is not. Choices A and D incorrectly assess statement (2) as sufficient. Choice C incorrectly claims both statements are needed. Strategy tip: For even/odd questions, systematically test what each parity combination produces, and remember that addition and multiplication have different parity rules.

Question 4

What is the remainder when the positive integer nn is divided by 8?

(1) When nn is divided by 4, the remainder is 3 (2) When nn is divided by 6, the remainder is 5

  1. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
  2. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
  3. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. (correct answer)
  4. EACH statement ALONE is sufficient to answer the question.

Explanation: Statement (1): If n3(mod4)n \equiv 3 \pmod{4}, then n=4k+3n = 4k + 3 for some integer kk. When we divide by 8, we need to consider kk even or odd. If k=2mk = 2m, then n=8m+3n = 8m + 3, so remainder is 3. If k=2m+1k = 2m + 1, then n=8m+7n = 8m + 7, so remainder is 7. Statement (1) alone is not sufficient. Statement (2): If n5(mod6)n \equiv 5 \pmod{6}, then n=6j+5n = 6j + 5 for some integer jj. We need to find nmod8n \bmod 8. Since gcd(6,8)=2\gcd(6,8) = 2, the possible remainders when n=6j+5n = 6j + 5 is divided by 8 depend on jmod4j \bmod 4. Testing: j=0:n=5j = 0: n = 5, remainder = 5. j=1:n=11j = 1: n = 11, remainder = 3. j=2:n=17j = 2: n = 17, remainder = 1. j=3:n=23j = 3: n = 23, remainder = 7. Statement (2) alone is not sufficient. Combined: We need n3(mod4)n \equiv 3 \pmod{4} and n5(mod6)n \equiv 5 \pmod{6}. Using the Chinese Remainder Theorem, since gcd(4,6)=2\gcd(4,6) = 2 and 351(mod2)3 \equiv 5 \equiv 1 \pmod{2} (the system is consistent), there exists a unique solution modulo lcm(4,6)=12\text{lcm}(4,6) = 12. Solving: n=4k+3=6j+5n = 4k + 3 = 6j + 5. From the first equation, k=n34k = \frac{n-3}{4}. Substituting into n5(mod6)n \equiv 5 \pmod{6}: we need 4k+35(mod6)4k + 3 \equiv 5 \pmod{6}, so 4k2(mod6)4k \equiv 2 \pmod{6}, which gives 2k1(mod3)2k \equiv 1 \pmod{3}. Since 2×21(mod3)2 \times 2 \equiv 1 \pmod{3}, we have k2(mod3)k \equiv 2 \pmod{3}. So k=3m+2k = 3m + 2, giving n=4(3m+2)+3=12m+11n = 4(3m + 2) + 3 = 12m + 11. Therefore, n113(mod8)n \equiv 11 \equiv 3 \pmod{8}. Both statements together are sufficient.

Question 5

Is the average of aa, bb, and cc equal to bb?

(1) a+c=2ba + c = 2b (2) bb is the median of aa, bb, and cc

  1. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. (correct answer)
  2. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
  3. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
  4. EACH statement ALONE is sufficient to answer the question.

Explanation: We want to determine if a+b+c3=b\frac{a + b + c}{3} = b, which is equivalent to asking if a+b+c=3ba + b + c = 3b, or a+c=2ba + c = 2b. Statement (1): This directly gives us a+c=2ba + c = 2b, which means a+b+c=3ba + b + c = 3b, so the average equals bb. Statement (1) is sufficient. Statement (2): If bb is the median of aa, bb, and cc, then when the three numbers are arranged in order, bb is in the middle. However, this doesn't guarantee that a+c=2ba + c = 2b. For example, if a=1a = 1, b=2b = 2, c=10c = 10, then bb is the median, but a+c=114=2ba + c = 11 \neq 4 = 2b. The average would be 1332\frac{13}{3} \neq 2. Statement (2) alone is not sufficient.