What this quiz covers
This quiz focuses on Determine Sufficiency, giving you a quick way to practice the rules, question types, and explanations that matter most for GMAT.
In triangle ABC, what is the length of side BC?
(1) The area of triangle ABC is 24, and the altitude from A to side BC has length 6 (2) AB=10, AC=8, and angle A=60°
GMAT Quiz
Practice Determine Sufficiency in GMAT with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.
This quiz focuses on Determine Sufficiency, giving you a quick way to practice the rules, question types, and explanations that matter most for GMAT.
Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.
In triangle ABC, what is the length of side BC?
(1) The area of triangle ABC is 24, and the altitude from A to side BC has length 6 (2) AB=10, AC=8, and angle A=60°
Explanation: Statement (1): Using the formula for area, Area=21×base×height. Here, 24=21×BC×6, which gives us BC=8. Statement (1) is sufficient. Statement (2): We can use the Law of Cosines: BC2=AB2+AC2−2(AB)(AC)cosA=102+82−2(10)(8)cos(60°)=100+64−160×21=164−80=84. Therefore, BC=84=221. Statement (2) is sufficient. Each statement alone is sufficient.
What is the value of x2+y2?
(1) x+y=5 and xy=6 (2) (x−y)2=1
Explanation: We need to find x2+y2. Statement (1): Given x+y=5 and xy=6. We can use the identity (x+y)2=x2+2xy+y2, which gives us 25=x2+12+y2. Therefore, x2+y2=13. Statement (1) is sufficient. Statement (2): (x−y)2=1 means x2−2xy+y2=1, so x2+y2=1+2xy. However, we don't know the value of xy, so we cannot determine x2+y2. Statement (2) alone is not sufficient.
If x and y are integers, is xy even?
(1) x+y is odd (2) x2+y2 is even
Explanation: This data sufficiency question tests your understanding of even/odd properties and how they interact through different operations. The key insight is recognizing what each statement tells you about the parity (even/odd nature) of x and y. For xy to be even, at least one of x or y must be even. If both are odd, their product is odd. Statement (1) tells us x+y is odd. This happens only when one number is even and the other is odd (since even + even = even, and odd + odd = even). If exactly one of x or y is even, then their product xy must be even. Statement (1) alone is sufficient. Statement (2) tells us x2+y2 is even. Since squaring preserves parity (even² = even, odd² = odd), this means we have either even² + even² = even or odd² + odd² = even. Both scenarios give an even sum, so we can't determine whether x and y have the same parity or different parities. For example, if x=1,y=3, then x2+y2=10 (even) but xy=3 (odd). If x=1,y=2, then x2+y2=5 (odd), contradicting our statement. Actually, if x=2,y=4, then x2+y2=20 (even) and xy=8 (even). Statement (2) alone is insufficient. Answer choice B is correct because statement (1) alone is sufficient while statement (2) alone is not. Choices A and D incorrectly assess statement (2) as sufficient. Choice C incorrectly claims both statements are needed. Strategy tip: For even/odd questions, systematically test what each parity combination produces, and remember that addition and multiplication have different parity rules.
What is the remainder when the positive integer n is divided by 8?
(1) When n is divided by 4, the remainder is 3 (2) When n is divided by 6, the remainder is 5
Explanation: Statement (1): If n≡3(mod4), then n=4k+3 for some integer k. When we divide by 8, we need to consider k even or odd. If k=2m, then n=8m+3, so remainder is 3. If k=2m+1, then n=8m+7, so remainder is 7. Statement (1) alone is not sufficient. Statement (2): If n≡5(mod6), then n=6j+5 for some integer j. We need to find nmod8. Since gcd(6,8)=2, the possible remainders when n=6j+5 is divided by 8 depend on jmod4. Testing: j=0:n=5, remainder = 5. j=1:n=11, remainder = 3. j=2:n=17, remainder = 1. j=3:n=23, remainder = 7. Statement (2) alone is not sufficient. Combined: We need n≡3(mod4) and n≡5(mod6). Using the Chinese Remainder Theorem, since gcd(4,6)=2 and 3≡5≡1(mod2) (the system is consistent), there exists a unique solution modulo lcm(4,6)=12. Solving: n=4k+3=6j+5. From the first equation, k=4n−3. Substituting into n≡5(mod6): we need 4k+3≡5(mod6), so 4k≡2(mod6), which gives 2k≡1(mod3). Since 2×2≡1(mod3), we have k≡2(mod3). So k=3m+2, giving n=4(3m+2)+3=12m+11. Therefore, n≡11≡3(mod8). Both statements together are sufficient.
Is the average of a, b, and c equal to b?
(1) a+c=2b (2) b is the median of a, b, and c
Explanation: We want to determine if 3a+b+c=b, which is equivalent to asking if a+b+c=3b, or a+c=2b. Statement (1): This directly gives us a+c=2b, which means a+b+c=3b, so the average equals b. Statement (1) is sufficient. Statement (2): If b is the median of a, b, and c, then when the three numbers are arranged in order, b is in the middle. However, this doesn't guarantee that a+c=2b. For example, if a=1, b=2, c=10, then b is the median, but a+c=11=4=2b. The average would be 313=2. Statement (2) alone is not sufficient.