Study Integer Properties Divisibility in GRE Quantitative with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Flashcard 1: What is the basic divisibility test for 3 in base 10?
Answer: Divisible by 3 iff the sum of digits is divisible by 3. This rule works because 10≡1(mod3), so the number modulo 3 equals the digit sum modulo 3.
Flashcard 2: What is the remainder when 210 is divided by 3?
Answer: 1. 210=1024, and 1024÷3=341 with remainder 1.
Flashcard 3: What is the basic divisibility test for 6 in base 10?
Answer: Divisible by 6 iff divisible by 2 and by 3. Since 6=2*3 and they are coprime, divisibility requires both conditions.
Flashcard 4: What is the basic divisibility test for 9 in base 10?
Answer: Divisible by 9 iff the sum of digits is divisible by 9. This follows since 10≡1(mod9), equating the number to its digit sum modulo 9.
Flashcard 5: What is the value of gcd(a,b) when a and b are relatively prime?
Answer: gcd(a,b)=1. Relatively prime integers share no common divisors other than 1.
Flashcard 6: What is the definition of the greatest common divisor gcd(a,b) for integers a and b not both 0?
Answer: The greatest positive integer dividing both a and b. It identifies the largest positive integer that divides both without remainder.
Flashcard 7: What is the definition of the least common multiple lcm(a,b) for nonzero integers a and b?
Answer: The least positive integer that is a multiple of both a and b. It specifies the smallest positive integer divisible by both a and b.
Flashcard 8: What is the remainder when 1050+3 is divided by 10?
Answer: 3. 1050 is divisible by 10, so adding 3 gives remainder 3.
Flashcard 9: Identify the result: If a∣b and a∣c, what must be true about a∣(b−c)?
Answer: a∣(b−c). Divisibility holds for differences of multiples.
Flashcard 10: What is lcm(a,0) for a nonzero integer a?
Answer: lcm(a,0)=0. Using the gcd-lcm relation, it evaluates to 0 for nonzero a.
Flashcard 11: What is the basic divisibility test for 10 in base 10?
Answer: Divisible by 10 iff the last digit is 0. In base 10, ending in 0 means it's a multiple of 10.
Flashcard 12: What is the basic divisibility test for 5 in base 10?
Answer: Divisible by 5 iff the last digit is 0 or 5. In base 10, these endings make the number a multiple of 5.
Flashcard 13: What is the relationship between gcd(a,b) and lcm(a,b) for nonzero integers a and b?
Answer: gcd(a,b)lcm(a,b)=∣ab∣. This formula relates gcd and lcm through the absolute product of the integers.
Flashcard 14: What is gcd(a,0) for a nonzero integer a?
Answer: gcd(a,0)=∣a∣. Every integer divides 0, so the gcd is the absolute value of a.
Flashcard 15: What is the remainder when 7100 is divided by 7?
Answer: 0. Any positive power of 7 is divisible by 7, leaving no remainder.
Flashcard 16: Identify the result: If a∣b, what must be true about a∣(bk) for any integer k?
Answer: a∣(bk) for every integer k. Scaling a multiple by any integer k retains divisibility by a.
Flashcard 17: Identify whether 357 is divisible by 3.
Answer: Yes, 357 is divisible by 3. Digit sum 3+5+7=15 is divisible by 3, confirming divisibility.
Flashcard 18: What is the basic divisibility test for 4 in base 10?
Answer: Divisible by 4 iff the last two digits form a multiple of 4. The last two digits represent the number modulo 100, and divisibility by 4 checks modulo 4.
Flashcard 19: What does it mean to say that a is divisible by b (with b=0) in the integers?
Answer: b∣a means a=bk for some integer k. This defines divisibility where a is an integer multiple of b.
Flashcard 20: What is the basic divisibility test for 2 in base 10?
Answer: An integer is divisible by 2 iff its last digit is even. In base 10, even last digits ensure the number is even.
Flashcard 21: What is the basic divisibility test for 12 in base 10?
Answer: Divisible by 12 iff divisible by 3 and by 4. 12=3*4 with coprime factors, so both divisibility tests must hold.
Flashcard 22: What is the basic divisibility test for 8 in base 10?
Answer: Divisible by 8 iff the last three digits form a multiple of 8. The last three digits form the number modulo 1000, sufficient for divisibility by 8.
Flashcard 23: Identify the result: If a∣b and a∣c, what must be true about a∣(b+c)?
Answer: a∣(b+c). Divisibility preserves under addition of multiples.