All questions
Question 1
A researcher compares signaling from two receptors in the same immune cell. Receptor M is activated by a membrane-impermeant cytokine and leads to phosphorylation of STAT proteins that dimerize and enter the nucleus. Receptor N is activated by a steroid hormone that diffuses across the membrane and binds an intracellular receptor. In an experiment, a selective blocker prevents ligand binding to receptor M only.
Which outcome would be expected if receptor M is blocked?
- Reduced STAT phosphorylation and reduced nuclear accumulation of STAT dimers after cytokine exposure (correct answer)
- Increased transcriptional effects of the steroid hormone due to compensatory activation of receptor N
- Unchanged cytokine response because cytokines primarily signal through intracellular receptors
- Increased cAMP production as the default downstream pathway of cytokine receptors
Explanation: This question tests understanding of cytokine receptor signaling via the JAK-STAT pathway versus steroid hormone nuclear receptor signaling. The principle involves recognizing that cytokine receptors typically lack intrinsic kinase activity but recruit JAK kinases that phosphorylate STAT proteins, which then dimerize and translocate to the nucleus. The passage describes receptor M as a cytokine receptor that leads to STAT phosphorylation and nuclear entry, while receptor N is activated by a steroid hormone with an intracellular receptor. Blocking receptor M prevents cytokine binding, which means no JAK activation, no STAT phosphorylation, and no STAT nuclear translocation. The correct answer A accurately predicts reduced STAT phosphorylation and nuclear accumulation. Choice B incorrectly suggests compensatory activation between unrelated pathways, choice C wrongly claims cytokines use intracellular receptors (they use membrane receptors), and choice D incorrectly identifies cAMP as the primary cytokine signaling mechanism (JAK-STAT is more common). When distinguishing immune signaling pathways, remember that most cytokines use JAK-STAT, while inflammatory mediators might use NF-κB, and some growth factors use MAPK cascades.
Question 2
In a cell line expressing a GPCR for hormone M, investigators measure second messengers after acute M exposure. M increases cAMP but does not change IP3. A point mutation is introduced into the receptor's cytosolic region that prevents coupling to heterotrimeric G proteins while leaving ligand binding intact. After mutation, M still binds the receptor at the cell surface, but cAMP no longer increases.
Which outcome would be expected if the receptor is blocked (or uncoupled) as described?
- cAMP increases normally because adenylyl cyclase is activated directly by M binding to the extracellular receptor domain
- cAMP does not increase because G protein coupling is required to transmit the signal from receptor binding to adenylyl cyclase (correct answer)
- IP3 increases because loss of G protein coupling shifts signaling toward PLC activation
- Gene transcription increases immediately because the receptor becomes a nuclear transcription factor when uncoupled
Explanation: This question tests understanding of the essential role of G protein coupling in GPCR signal transduction, demonstrating that receptor-G protein interaction is required for transmitting the binding signal to downstream effectors. Signal transduction through GPCRs requires functional coupling between the receptor and heterotrimeric G proteins; ligand binding causes conformational changes that activate G proteins, which then modulate effector enzymes like adenylyl cyclase. The mutation that prevents G protein coupling while preserving ligand binding creates a non-functional receptor - hormone M can still bind but cannot activate G proteins to stimulate adenylyl cyclase, so cAMP doesn't increase (option B is correct). This elegantly demonstrates that ligand binding alone is insufficient; the receptor must couple to G proteins to transduce the signal. The distractor A incorrectly suggests direct receptor-adenylyl cyclase interaction bypassing G proteins, while C wrongly proposes a compensatory switch to PLC signaling. When analyzing GPCR mutations, remember that the signaling cascade is sequential and obligate - disrupting any step (binding, G protein coupling, effector activation) blocks all downstream events without creating alternative pathways.
Question 3
In thyroid follicular cells, investigators track transport of two hormones: TSH (a glycoprotein peptide) and T3 (a thyroid hormone). In serum-like medium containing albumin, T3 is mostly protein-bound, whereas TSH remains largely unbound. Cells are exposed to equal total concentrations of TSH and T3. TSH produces a rapid increase in intracellular cAMP, while T3 produces no immediate change in cAMP but increases transcription of a metabolic gene after several hours.
Which statement best accounts for these observations?
- TSH requires intracellular binding proteins to cross the membrane, delaying its effect relative to T3
- T3 acts primarily through a cell-surface GPCR to stimulate cAMP, but albumin binding blocks receptor access
- TSH signals through a membrane receptor coupled to cAMP, whereas T3 enters cells and alters gene transcription via an intracellular receptor (correct answer)
- Both hormones act through receptor tyrosine kinases, but only TSH activates phospholipase C to generate IP3
Explanation: This question tests understanding of peptide versus steroid hormone transport, receptor localization, and distinct signal transduction mechanisms. Signal transduction pathways fundamentally differ based on hormone hydrophobicity: hydrophilic peptides like TSH cannot cross membranes and must bind cell-surface receptors, while lipophilic hormones like T3 diffuse across membranes to bind intracellular receptors. The experimental observations - TSH causing rapid cAMP increase and T3 causing delayed transcriptional changes - perfectly match option C's explanation of TSH using membrane receptor-cAMP signaling while T3 enters cells for genomic effects. The albumin binding detail is a distractor element, as it affects free hormone concentration but doesn't change the fundamental signaling mechanisms. Common mistakes include option B suggesting T3 uses a GPCR (contradicted by no cAMP response) or option D proposing both use RTKs (inconsistent with the cAMP data). When analyzing hormone comparisons, use the response timing (seconds/minutes vs. hours) and second messenger involvement (cAMP presence/absence) to distinguish between membrane receptor signaling and genomic pathways.
Question 4
In cardiomyocytes, a hormone (E) increases contractility within seconds. E binds a cell-surface receptor; downstream, intracellular Ca2+ rises and phosphorylation of L-type calcium channels increases. When cells are pretreated with a Gs inhibitor, E no longer increases channel phosphorylation. When cells are pretreated with an inhibitor of phospholipase C (PLC), E still increases channel phosphorylation.
Which cellular response is most consistent with the signal transduction pathway described?
- Increased phosphorylation of membrane proteins by PKA due to Gs-dependent cAMP production (correct answer)
- Decreased cAMP due to Gi activation, leading to reduced Ca2+ influx through L-type channels
- Increased IP3 formation and ER Ca2+ release as the primary driver of channel phosphorylation
- Direct phosphorylation of L-type calcium channels by the receptor's intrinsic tyrosine kinase domain
Explanation: This question tests understanding of G protein-coupled receptor signal transduction, specifically distinguishing between Gs-mediated cAMP/PKA pathways and Gq-mediated PLC/IP3 pathways in hormone signaling. Signal transduction through GPCRs involves specific G protein subtypes: Gs stimulates adenylyl cyclase to produce cAMP and activate PKA, while Gq activates PLC to generate IP3 and DAG. The experimental evidence shows hormone E requires Gs (blocked by Gs inhibitor) but not PLC (still works with PLC inhibitor) for channel phosphorylation, indicating option A is correct - E signals through Gs to produce cAMP and activate PKA. The rapid timeframe (seconds) and phosphorylation outcome are consistent with PKA-mediated effects on ion channels. Common distractors like option C incorrectly emphasize the IP3 pathway despite the PLC inhibitor having no effect, while option D suggests RTK signaling inconsistent with GPCR/G protein involvement. When analyzing GPCR questions, use specific inhibitor effects to map the pathway: Gs inhibition blocking the response indicates cAMP/PKA involvement, while PLC inhibition having no effect rules out the IP3/Ca2+ branch.
Question 5
In an endocrine pharmacology experiment, a lipophilic hormone (Z) is administered intravenously. Plasma measurements show high total Z concentration but low free Z concentration when binding proteins are elevated. In target cells, the biological response correlates with free Z rather than total Z. Z is known to cross the plasma membrane and bind an intracellular receptor.
Based on the scenario, which step is most likely to be influenced by external factors (binding protein levels) to change Z signaling?
- The rate of Z receptor endocytosis after ligand binding at the plasma membrane
- The availability of Z to enter cells, determined by the free (unbound) fraction in plasma (correct answer)
- The opening probability of ligand-gated Cl− channels in response to Z binding
- The conversion of phosphatidylinositol 4,5-bisphosphate to diacylglycerol by phospholipase C
Explanation: This question tests understanding of steroid hormone transport and bioavailability, specifically how plasma protein binding affects hormone signaling. The principle is that lipophilic hormones like steroids circulate bound to plasma proteins, but only the free (unbound) fraction can cross cell membranes to activate intracellular receptors. The passage establishes that hormone Z is lipophilic, crosses membranes, binds intracellular receptors, and its biological activity correlates with free rather than total concentration. When binding protein levels increase, more hormone becomes sequestered in the bound form, reducing the free fraction available for cellular uptake. The correct answer B identifies this critical step - the availability of Z to enter cells depends on the free fraction, which is directly influenced by binding protein levels. Choice A incorrectly focuses on receptor endocytosis (relevant for membrane receptors, not intracellular ones), choice C describes ligand-gated channels (unrelated to the steroid signaling described), and choice D describes PLC signaling (not mentioned for hormone Z). Understanding the free hormone hypothesis is crucial for interpreting endocrine function tests and drug interactions affecting binding proteins.
Question 6
In a study of hepatocytes, investigators perfused cells with a peptide hormone (H) that does not cross the plasma membrane. Within 60 seconds, intracellular cAMP increased ~6-fold and phosphorylation of a cytosolic enzyme increased. When cells were pretreated with a competitive antagonist to the H receptor, both the cAMP rise and enzyme phosphorylation were abolished. The investigators note that H circulates largely unbound in plasma and has a short half-life.
Which outcome would be expected if the receptor is blocked, as in the antagonist condition?
- Increased transcription of H-responsive genes via direct binding of the H–receptor complex to nuclear DNA
- Reduced activation of protein kinase A and reduced phosphorylation of downstream cytosolic targets (correct answer)
- Increased intracellular Ca2+ release from the endoplasmic reticulum via IP3 receptors
- Increased receptor tyrosine kinase autophosphorylation and recruitment of SH2-domain proteins
Explanation: This question tests understanding of GPCR signal transduction, specifically how blocking a receptor affects downstream signaling through the cAMP pathway. In GPCR signaling, hormone binding activates the receptor, which then activates a G protein that stimulates adenylyl cyclase to produce cAMP, which in turn activates protein kinase A (PKA) to phosphorylate target proteins. The passage describes a peptide hormone that increases cAMP and enzyme phosphorylation, classic hallmarks of Gs-coupled GPCR signaling. When the receptor is blocked by an antagonist, the entire cascade is prevented: no receptor activation means no G protein activation, no adenylyl cyclase stimulation, no cAMP production, and therefore no PKA activation. The correct answer B accurately describes this outcome - reduced PKA activation and reduced phosphorylation of downstream targets. Choice A incorrectly describes nuclear receptor signaling (which requires membrane-permeable hormones), while choices C and D describe different signaling pathways (Gq/PLC/IP3 and receptor tyrosine kinase pathways, respectively) that are not consistent with the cAMP response described.
Question 7
A lab compared signaling from two hormones in the same cell type. Hormone X is lipid-soluble and circulates largely bound to a plasma carrier protein; hormone Y is water-soluble and circulates mostly free. In cells, X produced changes in mRNA abundance after 2 hours, while Y produced increased phosphorylation of a cytosolic protein within 1 minute. Which statement best distinguishes the receptor location and initial signaling mechanism for X versus Y?
- X binds a cell-surface receptor coupled to G proteins; Y binds an intracellular receptor that directly binds DNA
- X binds an intracellular receptor that regulates transcription; Y binds a cell-surface receptor that initiates second messengers (correct answer)
- X and Y both bind receptor tyrosine kinases but differ only in carrier protein binding
- X and Y both diffuse into the nucleus to activate phosphorylation cascades directly
Explanation: This question probes hormone transport, receptors, and signal transduction, contrasting lipid- and water-soluble hormone mechanisms. Signal transduction differs by receptor location: intracellular for lipid-soluble, surface for water-soluble, leading to transcriptional or rapid phosphorylation changes. Hormone X, lipid-soluble and carrier-bound, acts via intracellular receptors for slow mRNA effects, while Y uses surface receptors for quick phosphorylation. Choice B correctly distinguishes these, with X regulating transcription and Y initiating second messengers. Choice A reverses the mechanisms, a common mix-up flaw. For parallels, note solubility and timing to infer receptor type. Evaluate carrier protein roles in transport equilibrium.
Question 8
Two hormones, A and B, each increase glycogen breakdown in hepatocytes but via different receptors. Hormone A binds a GPCR coupled to Gs and increases cAMP, activating PKA. Hormone B binds a receptor tyrosine kinase (RTK), leading to autophosphorylation and recruitment of cytosolic adaptor proteins that activate a kinase cascade. Inhibiting adenylyl cyclase prevents A-induced glycogen breakdown but does not affect B-induced glycogen breakdown.
Which outcome would be expected if the RTK for hormone B is blocked while hormone A signaling remains intact?
- No change in either response because both pathways converge only at gene transcription
- Loss of A-induced glycogen breakdown because RTKs are required to activate Gs
- Enhanced B-induced glycogen breakdown due to increased cAMP from RTK blockade
- Loss of B-induced glycogen breakdown with preserved A-induced glycogen breakdown (correct answer)
Explanation: This question tests understanding of distinct signal transduction pathways - GPCR-cAMP versus RTK cascades - and their independence in mediating hormone responses like glycogen breakdown. Hormone A uses a GPCR-Gs-cAMP-PKA pathway while hormone B uses an RTK-kinase cascade pathway, representing two major but separate signaling mechanisms that can achieve similar cellular outcomes through different molecular intermediates. In this scenario, blocking the RTK for hormone B would specifically prevent B-induced glycogen breakdown by disrupting its unique signaling cascade, while leaving the A pathway intact since it operates through entirely different molecular components. The correct answer D accurately predicts loss of B-induced glycogen breakdown with preserved A-induced glycogen breakdown, reflecting the independence of these two pathways. A common distractor (B) incorrectly suggests that RTKs are required for GPCR signaling, when in fact these are completely separate receptor systems with distinct downstream effectors. When analyzing questions involving multiple hormone pathways, identify whether they use the same or different receptor types and signaling cascades to predict how selective inhibition will affect each response independently.
Question 9
A steroid hormone (S) circulates mostly bound to a specific carrier protein. Target cells express an intracellular receptor (R) that, upon binding S, dimerizes and binds a DNA response element to alter transcription. In an experiment, carrier protein concentration in plasma-like medium is doubled while total S (free + bound) is held constant. Cells are exposed to this medium for 1 hour, and transcriptional activation of an S-responsive gene is measured.
Which outcome would be expected from doubling the carrier protein concentration at constant total S?
- Increased transcription due to greater total S available for receptor binding
- Decreased transcription due to reduced free S available to enter cells (correct answer)
- No change in transcription because carrier proteins prevent S degradation inside cells
- Increased transcription due to carrier-mediated endocytosis of S into the cytosol
Explanation: This question tests understanding of steroid hormone transport and the relationship between carrier protein binding and free hormone availability for intracellular receptor activation. Steroid hormones circulate bound to carrier proteins, but only the free (unbound) fraction can diffuse across cell membranes to bind intracellular receptors and activate transcription. In this scenario, doubling the carrier protein concentration while keeping total steroid S constant would shift the equilibrium toward more bound hormone, reducing the free fraction available to enter cells. The correct answer B accurately predicts decreased transcription due to reduced free S, as the increased carrier protein sequesters more hormone in the bound form. A common distractor (A) incorrectly assumes that total hormone concentration determines activity, ignoring the critical role of the free fraction in steroid hormone action. When analyzing steroid hormone signaling, always consider the equilibrium between bound and free hormone, remembering that only free hormone can cross membranes and activate intracellular receptors to alter gene transcription.
Question 10
Two ligands, X and Y, were tested on the same cell type. X causes receptor autophosphorylation on tyrosine residues and recruitment of adaptor proteins, followed by increased ERK phosphorylation. Y causes a rapid increase in cAMP without detectable receptor phosphorylation. Both ligands increase cell proliferation after 24 hours.
Which cellular response is most consistent with the signal transduction pathway described for ligand X (but not Y)?
- Activation of a receptor tyrosine kinase leading to a kinase cascade that includes ERK phosphorylation (correct answer)
- Activation of a ligand-gated ion channel causing direct Na+ influx as the initiating event
- Direct activation of adenylyl cyclase by Gαs to increase cAMP as the initiating event
- Ligand diffusion into the cell followed by binding to a nuclear receptor to regulate transcription
Explanation: This question tests the ability to distinguish between receptor tyrosine kinase (RTK) and GPCR signaling pathways based on their characteristic features. The principle involves recognizing that RTKs undergo autophosphorylation on tyrosine residues upon ligand binding, creating docking sites for adaptor proteins that initiate cascades like the MAPK/ERK pathway. The passage describes ligand X causing receptor tyrosine autophosphorylation, adaptor protein recruitment, and ERK phosphorylation - all hallmarks of RTK signaling. In contrast, ligand Y increases cAMP without receptor phosphorylation, indicating GPCR/Gs signaling. The correct answer A accurately identifies RTK activation leading to ERK phosphorylation as the pathway for ligand X. Choice B describes ligand-gated ion channels (not mentioned), choice C describes the cAMP pathway characteristic of ligand Y not X, and choice D describes nuclear receptor signaling (incompatible with the membrane receptor phosphorylation described). When comparing signaling mechanisms, focus on distinguishing features: RTKs show intrinsic kinase activity and tyrosine phosphorylation, while GPCRs typically activate second messenger systems without receptor phosphorylation.
Question 11
A researcher studies vasopressin signaling in kidney collecting duct cells. Vasopressin binding increases cAMP and is followed by rapid insertion of aquaporin-2 (AQP2) channels into the apical membrane. In cells treated with a competitive vasopressin receptor blocker, vasopressin fails to increase cAMP.
Which outcome would be expected if the receptor is blocked?
- Decreased AQP2 insertion into the apical membrane and decreased water reabsorption (correct answer)
- Increased AQP2 insertion due to constitutive activation of the receptor by the blocker
- Increased intracellular Ca2+ via IP3-mediated endoplasmic reticulum release as the primary response
- Immediate transcriptional activation by a receptor that must enter the nucleus to function
Explanation: This question tests understanding of GPCR-mediated signal transduction in physiological contexts, specifically vasopressin signaling in kidney water reabsorption. The principle involves recognizing that vasopressin acts through a Gs-coupled receptor to increase cAMP, which triggers PKA-mediated phosphorylation events leading to aquaporin-2 (AQP2) trafficking to the apical membrane. The passage clearly establishes that vasopressin increases cAMP and causes AQP2 insertion, while receptor blockade prevents the cAMP increase. Without receptor activation, the entire signaling cascade is blocked: no cAMP production means no PKA activation, no AQP2 phosphorylation, and therefore no AQP2 insertion into the membrane. The correct answer A accurately predicts decreased AQP2 insertion and consequently decreased water reabsorption. Choice B incorrectly suggests the blocker would activate the receptor, choice C describes a different signaling pathway (Gq/PLC/IP3/Ca2+), and choice D describes nuclear receptor signaling incompatible with the rapid membrane trafficking response. This question demonstrates how molecular signaling mechanisms directly translate to physiological outcomes in specific tissues.
Question 12
A peptide hormone (P) binds a GPCR on smooth muscle cells and increases intracellular Ca2+. Inhibiting phospholipase C (PLC) prevents the Ca2+ rise. In a separate condition, blocking IP3 receptors on the endoplasmic reticulum also prevents the Ca2+ rise, despite normal PLC activity.
Which outcome would be expected if the receptor is blocked?
- Increased Ca2+ release from the endoplasmic reticulum due to accumulation of IP3
- Decreased IP3 generation and decreased Ca2+ release from intracellular stores (correct answer)
- Unchanged Ca2+ signaling because IP3 receptors are downstream and independent of receptor activation
- Increased transcription of target genes via direct DNA binding by the membrane receptor
Explanation: This question tests understanding of the Gq-PLC-IP3-Ca2+ signaling cascade and how blocking the initiating receptor affects downstream events. The principle involves recognizing that GPCR activation through Gq leads to PLC activation, which cleaves PIP2 to generate IP3, which then binds IP3 receptors on the ER to release Ca2+. The passage establishes that hormone P increases Ca2+ through a PLC- and IP3-dependent mechanism, confirming Gq/PLC/IP3 signaling. If the receptor is blocked, the entire cascade cannot initiate: no Gq activation means no PLC activation, no IP3 generation, and therefore no Ca2+ release from intracellular stores. The correct answer B accurately predicts decreased IP3 generation and decreased Ca2+ release. Choice A incorrectly suggests increased Ca2+ (opposite of blocking the pathway), choice C wrongly claims the pathway is independent of receptor activation, and choice D describes nuclear receptor signaling unrelated to the rapid Ca2+ response described. When analyzing cascade questions, trace the signal flow from receptor to final output to predict blockade effects at any step.
Question 13
In a neuronal cell line, a peptide ligand (L) caused a transient increase in intracellular Ca2+ measured by a fluorescent indicator. The response persisted when extracellular Ca2+ was chelated but was eliminated by an inhibitor of phospholipase C (PLC). Which cellular response is most consistent with the pathway described?
- Direct phosphorylation of PLC by L after L diffuses into the cytosol
- Ca2+ influx through voltage-gated channels triggered by steroid receptor activation
- Increased cGMP production by soluble guanylyl cyclase leading to Ca2+ sequestration
- Release of Ca2+ from intracellular stores via IP3-dependent channels (correct answer)
Explanation: This question evaluates hormone transport, receptors, and signal transduction, focusing on Ca²⁺ mobilization via PLC pathways. Signal transduction involves GPCR activation of PLC, generating IP₃ to release ER Ca²⁺ stores. Ligand L activates PLC, increasing Ca²⁺ independently of extracellular sources. Choice D follows, with IP₃-dependent Ca²⁺ release matching persistence without external Ca²⁺. Choice B distracts with voltage-gated channels, flawed without depolarization cues. For similar cases, use chelators to distinguish sources. Link inhibitors to pathway enzymes.
Question 14
A lab engineered a chimeric receptor with an extracellular domain that binds a peptide ligand and an intracellular domain derived from a receptor tyrosine kinase. Upon ligand addition, cells showed tyrosine phosphorylation and ERK activation, despite the ligand normally signaling through cAMP in wild-type cells. Which cellular response is most consistent with the signal transduction pathway in the chimeric receptor cells?
- Increased cAMP because receptor tyrosine kinases directly synthesize cAMP
- Activation of nuclear receptors leading to immediate transcription without phosphorylation
- Decreased ERK activity because tyrosine phosphorylation inhibits all kinase cascades
- Activation of MAPK signaling downstream of receptor autophosphorylation on tyrosines (correct answer)
Explanation: This question assesses hormone transport, receptors, and signal transduction, exploring chimeric receptor signaling. Signal transduction via RTKs includes autophosphorylation activating MAPK like ERK. The chimera uses RTK domain for tyrosine phosphorylation and ERK activation. Choice D aligns with MAPK downstream of autophosphorylation. Choice B distracts with nuclear receptors, ignoring kinase activity. For similar cases, identify domain functions in hybrids. Compare to wild-type pathways.
Question 15
A hormone (H) produced opposite effects in two tissues: increased glycogen breakdown in liver and decreased contractility in cardiac tissue. In both tissues, H increased cAMP. Based on the scenario, which explanation best accounts for tissue-specific responses?
- Different downstream effector proteins and gene expression programs interpret the same second messenger (correct answer)
- cAMP can only activate one pathway, so one tissue's observation must be experimental error
- H must bind nuclear receptors in heart but GPCRs in liver to generate cAMP
- Carrier protein binding changes cAMP specificity between tissues
Explanation: This question tests hormone transport, receptors, and signal transduction, addressing tissue-specific responses to shared messengers. Signal transduction allows cAMP to activate varied effectors for diverse outcomes across tissues. Hormone H increases cAMP but elicits opposite effects in liver and heart via different programs. Choice A explains this through downstream interpretation differences. Choice B dismisses observations as error, ignoring signaling complexity. In similar queries, recognize context-dependent messenger effects. Evaluate if pathways converge or diverge post-messenger.
Question 16
A researcher applied insulin to skeletal muscle cells and observed increased phosphorylation of a membrane-proximal adaptor protein followed by increased translocation of GLUT4 to the plasma membrane. A pharmacologic inhibitor prevented receptor autophosphorylation on tyrosine residues. Which outcome would be expected if the receptor is blocked?
- Increased nuclear transcription within seconds due to direct insulin entry into the nucleus
- Increased GLUT4 translocation because blocking the receptor prevents its dephosphorylation
- Unchanged GLUT4 translocation because insulin primarily signals through cGMP
- Decreased GLUT4 translocation due to reduced downstream signaling from the receptor (correct answer)
Explanation: This question assesses hormone transport, receptors, and signal transduction, highlighting insulin's RTK pathway in muscle. Signal transduction starts with autophosphorylation, activating adaptors for GLUT4 translocation. Insulin binds RTK, phosphorylating adaptors to mobilize GLUT4. Receptor blockade reduces signaling and translocation, per choice D. Choice B suggests increased activity from dephosphorylation loss, but blockade prevents initiation. For related queries, identify RTK by tyrosine motifs. Examine inhibitor effects on proximal events.
Question 17
In a cell-based assay, ligand L activated a GPCR and increased cAMP. After prolonged exposure to L, the cAMP response to a second L dose was diminished, but the response to a direct adenylyl cyclase activator was preserved. Which outcome would be expected if the receptor is blocked during the first L exposure?
- Greater desensitization because receptor blockade increases receptor phosphorylation
- Less desensitization because initial receptor activation and subsequent regulatory changes are reduced (correct answer)
- No effect on desensitization because desensitization occurs only at adenylyl cyclase
- Increased cAMP during first exposure because antagonist acts as a full agonist
Explanation: This question evaluates hormone transport, receptors, and signal transduction, exploring GPCR desensitization mechanisms. Signal transduction can lead to desensitization via prolonged activation altering receptor responsiveness. Prolonged L exposure desensitizes the GPCR, reducing subsequent cAMP responses. Blocking during first exposure reduces activation and desensitization, per choice B. Choice A suggests increased desensitization, flawed without signaling. In analogous problems, distinguish receptor versus effector desensitization. Use direct activators to isolate loci.
Question 18
In cultured ovarian granulosa cells, follicle-stimulating hormone (FSH) increased aromatase expression over several hours. Early after stimulation, cAMP rose and a transcription factor became phosphorylated. If the FSH receptor is blocked, which outcome would be expected?
- Reduced cAMP signaling and reduced induction of aromatase expression (correct answer)
- Increased aromatase expression because receptor blockade prevents feedback inhibition
- Unchanged aromatase expression because FSH enters cells and binds DNA directly
- Reduced aromatase expression due to decreased cGMP production by soluble guanylyl cyclase
Explanation: This question tests hormone transport, receptors, and signal transduction, examining FSH's cAMP-mediated effects in ovarian cells. Signal transduction involves GPCR activation increasing cAMP for transcription factor phosphorylation and gene expression. FSH binds receptors, elevating cAMP to induce aromatase. Blockade reduces cAMP and expression, as in choice A. Choice B suggests feedback prevention, but blockade halts activation. In like questions, link messengers to transcriptional outcomes. Assess timing for second-messenger versus gene changes.
Question 19
A cultured thyroid follicular cell line was treated with thyroid-stimulating hormone (TSH). Within 2 minutes, intracellular cAMP increased; within 10 minutes, iodide uptake increased. A mutant receptor (R*) bound TSH normally but failed to increase cAMP. Which step is most likely impaired in cells expressing R*?
- Ligand binding to the extracellular domain of the receptor
- Activation of a heterotrimeric G protein that stimulates adenylyl cyclase (correct answer)
- Diffusion of TSH across the plasma membrane to an intracellular receptor
- Basal transcription of the sodium-iodide symporter gene in the nucleus
Explanation: This question assesses hormone transport, receptors, and signal transduction, particularly TSH signaling in thyroid cells via cAMP-mediated pathways. Signal transduction involves receptor-ligand interaction activating G proteins to stimulate adenylyl cyclase and elevate cAMP for downstream effects. In this case, TSH binds its GPCR, activating Gs to increase cAMP and enhance iodide uptake. The mutant receptor impairs G protein activation, preventing cAMP rise despite binding, as in choice B. A distractor such as choice C might confuse TSH with steroid mechanisms, but TSH does not diffuse intracellularly. For related questions, identify if the receptor is a GPCR by second-messenger involvement. Verify pathway steps by noting timing and mutant effects.
Question 20
In an ex vivo rat aortic ring assay, a peptide ligand (L) triggered rapid relaxation within 30 seconds. Endothelial cells showed increased cGMP, and the effect was eliminated by an inhibitor of soluble guanylyl cyclase but not by an inhibitor of adenylyl cyclase. L did not enter cells when fluorescently labeled. Which cellular response is most consistent with the signal transduction pathway described?
- Activation of protein kinase G leading to decreased intracellular Ca2+ in smooth muscle (correct answer)
- Activation of protein kinase A leading to increased myosin light-chain phosphorylation
- Translocation of an intracellular receptor to the nucleus to induce transcription over minutes
- Opening of ligand-gated Na+ channels causing membrane depolarization and contraction
Explanation: This question tests knowledge of hormone transport, receptors, and signal transduction, focusing on rapid vascular responses mediated by peptide ligands and second messengers. Signal transduction often entails receptor activation leading to production of messengers like cGMP, which activate kinases to alter cellular function. Here, the peptide L activates a receptor to stimulate soluble guanylyl cyclase, increasing cGMP and causing aortic relaxation. The response in choice A follows logically, as PKG activation by cGMP decreases Ca²⁺ in smooth muscle, promoting relaxation. A distractor like choice B might suggest PKA involvement, but this is incorrect since adenylyl cyclase inhibition had no effect. In analogous scenarios, distinguish between cAMP and cGMP pathways by inhibitor effects. Check if the timeline matches second-messenger kinetics versus transcriptional changes.