Physics Flashcards: Compare Gravitational And Electric Forces

Study Compare Gravitational And Electric Forces in Physics with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

Physics

Compare Gravitational And Electric Forces

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QUESTION
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If m1m_1 doubles (all else constant), by what factor does FgF_g change?

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ANSWER

FgF_g doubles. Force is directly proportional to each mass in the numerator.

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Flashcard 1: If m1m_1 doubles (all else constant), by what factor does FgF_g change?

Answer: FgF_g doubles. Force is directly proportional to each mass in the numerator.

Flashcard 2: If both charges change sign (q1q1q_1\to -q_1, q2q2q_2\to -q_2), what happens to the electric force direction?

Answer: Direction is unchanged (still attractive or still repulsive). Product q1q2q_1q_2 stays same sign when both flip.

Flashcard 3: What is the formula for the magnitude of the gravitational force between two point masses?

Answer: Fg=Gm1m2r2F_g=G\frac{m_1m_2}{r^2}. Newton's law of universal gravitation with inverse square dependence on distance.

Flashcard 4: What is the direction rule for the electric force on q1q_1 due to q2q_2?

Answer: Along the line joining them; toward unlike, away from like. Electric forces act along the line between charges with direction based on sign.

Flashcard 5: What is the quantitative ratio FeFg\frac{F_e}{F_g} for two particles separated by the same rr?

Answer: FeFg=kq1q2Gm1m2\frac{F_e}{F_g}=\frac{k|q_1q_2|}{Gm_1m_2}. Divide Coulomb's law by Newton's law to compare force magnitudes directly.

Flashcard 6: If only one charge changes sign (q1q1q_1\to -q_1), what happens to the electric force direction?

Answer: Direction reverses (attractive becomes repulsive or vice versa). Product q1q2q_1q_2 changes sign when only one flips.

Flashcard 7: What is the correct sign behavior: can gravitational forces be repulsive, attractive, or both?

Answer: Gravitational force is always attractive. Masses always attract; no negative mass exists.

Flashcard 8: Identify the distance dependence shared by FgF_g and FeF_e for point particles.

Answer: Both follow an inverse-square law: F1r2F\propto \frac{1}{r^2}. Force decreases with square of distance for both interactions.

Flashcard 9: If the separation doubles, by what factor does each of FgF_g and FeF_e change?

Answer: Each becomes 14\frac{1}{4} of its original value. Both forces have 1r2\frac{1}{r^2} dependence, so doubling rr gives 122=14\frac{1}{2^2}=\frac{1}{4}.

Flashcard 10: If separation doubles, by what factor do both FgF_g and FeF_e change for point particles?

Answer: They become 14\frac{1}{4} as large. Inverse-square law: doubling rr gives F1(2r)2=14r2F\propto\frac{1}{(2r)^2}=\frac{1}{4r^2}.

Flashcard 11: If q1q_1 changes from +q+q to q-q (same magnitude), what happens to Fe|F_e|?

Answer: Fe|F_e| is unchanged. Magnitude depends on q1q2|q_1q_2|, which is same for +q+q or q-q.

Flashcard 12: Identify the units of Coulomb's constant kk in Fe=kq1q2r2F_e=k\frac{|q_1q_2|}{r^2}.

Answer: Nm2/C2\mathrm{N\,m^2/C^2}. Similar to GG but with charge (coulombs) instead of mass (kg).

Flashcard 13: For an electron and a proton, what is the ratio FeFg\frac{F_e}{F_g} (order of magnitude)?

Answer: FeFg1039\frac{F_e}{F_g}\approx10^{39}. Even larger ratio for electron-proton due to electron's tiny mass.

Flashcard 14: What is the correct sign behavior: can electric forces be attractive, repulsive, or both?

Answer: Electric force can be attractive or repulsive. Like charges repel, opposite charges attract.

Flashcard 15: Which force can be attractive or repulsive depending on the interacting objects: gravity or electric?

Answer: Electric can attract or repel; gravity is always attractive. Opposite charges attract, like charges repel; masses always attract.

Flashcard 16: For fixed m1,m2,q1,q2m_1,m_2,q_1,q_2, does changing rr change the ratio FeFg\frac{F_e}{F_g}?

Answer: No; FeFg\frac{F_e}{F_g} is independent of rr. Both forces have same r2r^2 dependence, which cancels in ratio.

Flashcard 17: If separation triples, by what factor do both FgF_g and FeF_e change for point particles?

Answer: They become 19\frac{1}{9} as large. Inverse-square law: tripling rr gives F1(3r)2=19r2F\propto\frac{1}{(3r)^2}=\frac{1}{9r^2}.

Flashcard 18: If the separation triples, by what factor does each of FgF_g and FeF_e change?

Answer: Each becomes 19\frac{1}{9} of its original value. Tripling distance gives 132=19\frac{1}{3^2}=\frac{1}{9} due to inverse square law.

Flashcard 19: What is the formula for the electric force magnitude between two point charges (Coulomb's law)?

Answer: Fe=kq1q2r2F_e = k\frac{|q_1 q_2|}{r^2}. Coulomb's law gives force between point charges.

Flashcard 20: Which option gives the correct SI units: kk in Nm2/C2\text{N}\cdot\text{m}^2/\text{C}^2 or Nm2/kg2\text{N}\cdot\text{m}^2/\text{kg}^2?

Answer: k: Nm2/C2k:\ \text{N}\cdot\text{m}^2/\text{C}^2. Coulomb's constant has units of force×area per charge squared.

Flashcard 21: Which option best compares force strengths for elementary particles: FeF_e or FgF_g?

Answer: FeFgF_e\gg F_g (by about 103610^{36} to 103910^{39}). Electric forces dominate by many orders of magnitude at particle scale.

Flashcard 22: Which option gives the correct SI units: GG in Nm2/kg2\text{N}\cdot\text{m}^2/\text{kg}^2 or Nm2/C2\text{N}\cdot\text{m}^2/\text{C}^2?

Answer: G: Nm2/kg2G:\ \text{N}\cdot\text{m}^2/\text{kg}^2. Gravitational constant has units of force×area per mass squared.

Flashcard 23: Find the ratio FeFg\frac{F_e}{F_g} for two identical particles with charge qq and mass mm.

Answer: FeFg=kq2Gm2\frac{F_e}{F_g}=\frac{k q^2}{G m^2}. Simplifies since q1=q2=qq_1=q_2=q and m1=m2=mm_1=m_2=m.

Flashcard 24: What is the formula for the magnitude of the electric (Coulomb) force between two point charges?

Answer: Fe=kq1q2r2F_e=k\frac{|q_1q_2|}{r^2}. Coulomb's law shows electric force also follows inverse square law like gravity.

Flashcard 25: If m1,m2,q1,q2m_1,m_2,q_1,q_2 are all doubled (same rr), by what factor does FeFg\frac{F_e}{F_g} change?

Answer: No change; FeFg\frac{F_e}{F_g} stays the same. Ratio cancels the factor of 2 in both numerator and denominator.

Flashcard 26: If m1m_1 is doubled (others fixed), by what factor does FgF_g change?

Answer: FgF_g doubles. Force is directly proportional to each mass.

Flashcard 27: If q1q_1 is doubled (others fixed), by what factor does FeF_e change?

Answer: FeF_e doubles. Force is directly proportional to each charge magnitude.

Flashcard 28: For two protons, what is the ratio FeFg\frac{F_e}{F_g} (order of magnitude)?

Answer: FeFg1036\frac{F_e}{F_g}\approx10^{36}. Electric force dominates at atomic scale due to large charge-to-mass ratio.

Flashcard 29: If both charges reverse sign (q1q1q_1\to -q_1 and q2q2q_2\to -q_2), what happens to the force type?

Answer: It stays the same (attractive stays attractive, repulsive stays repulsive). Product q1q2q_1q_2 has same sign when both charges flip, preserving force type.

Flashcard 30: What is the ratio FeFg\frac{F_e}{F_g} for the same separation rr between particles?

Answer: FeFg=kq1q2Gm1m2\frac{F_e}{F_g}=\frac{k|q_1 q_2|}{G m_1 m_2}. Ratio cancels r2r^2 terms, leaving charge and mass factors.

Flashcard 31: Identify the units of the gravitational constant GG in Fg=Gm1m2r2F_g=G\frac{m_1m_2}{r^2}.

Answer: Nm2/kg2\mathrm{N\,m^2/kg^2}. Derived from F=Gm2r2F=G\frac{m^2}{r^2} where FF has units of newtons.

Flashcard 32: Which interaction is stronger between two electrons: electric or gravitational (quantitatively)?

Answer: Electric; FeFg1042\frac{F_e}{F_g}\approx 10^{42} for two electrons. Electric force vastly exceeds gravity for elementary particles.

Flashcard 33: Find FeFg\frac{F_e}{F_g} when q1=q2=qq_1=q_2=q and m1=m2=mm_1=m_2=m (same rr).

Answer: FeFg=kq2Gm2\frac{F_e}{F_g}=\frac{kq^2}{Gm^2}. Simplifies when charges and masses are equal, showing dependence on qm\frac{q}{m} ratio.

Flashcard 34: Which interaction is stronger between two protons: electric or gravitational (quantitatively)?

Answer: Electric; FeFg1036\frac{F_e}{F_g}\approx 10^{36} for two protons. Electromagnetic force dominates at atomic scales.

Flashcard 35: What is the formula for the gravitational force magnitude between two point masses?

Answer: Fg=Gm1m2r2F_g = G\frac{m_1 m_2}{r^2}. Newton's law of universal gravitation for point masses.

Flashcard 36: Identify the correct constants: G6.67×1011G\approx 6.67\times 10^{-11} and k8.99×109k\approx 8.99\times 10^9 (SI).

Answer: G6.67×1011G\approx 6.67\times 10^{-11}, k8.99×109k\approx 8.99\times 10^9. Values show kGk\gg G in SI units.

Flashcard 37: What is the direction rule for the gravitational force on m1m_1 due to m2m_2?

Answer: Along the line joining them, toward m2m_2. Gravity is always attractive, pulling masses together along their connecting line.