Physics Flashcards: Design Momentum Conservation Experiments

Study Design Momentum Conservation Experiments in Physics with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

Physics

Design Momentum Conservation Experiments

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QUESTION
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Find the total initial momentum if m1=0.50kgm_1=0.50\,\text{kg} at +0.80m/s+0.80\,\text{m/s} and m2=0.50kgm_2=0.50\,\text{kg} at 0.20m/s-0.20\,\text{m/s}.

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ANSWER

pi=0.30kgm/sp_i=0.30\,\text{kg}\cdot\text{m/s}. pi=(0.50)(0.80)+(0.50)(0.20)=0.400.10=0.30p_i=(0.50)(0.80)+(0.50)(-0.20)=0.40-0.10=0.30

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Flashcard 1: Find the total initial momentum if m1=0.50kgm_1=0.50\,\text{kg} at +0.80m/s+0.80\,\text{m/s} and m2=0.50kgm_2=0.50\,\text{kg} at 0.20m/s-0.20\,\text{m/s}.

Answer: pi=0.30kgm/sp_i=0.30\,\text{kg}\cdot\text{m/s}. pi=(0.50)(0.80)+(0.50)(0.20)=0.400.10=0.30p_i=(0.50)(0.80)+(0.50)(-0.20)=0.40-0.10=0.30

Flashcard 2: What formula should you use to compute the system momentum before collision in 1D1\text{D}?

Answer: pi=m1v1i+m2v2ip_i=m_1v_{1i}+m_2v_{2i}. Sum individual momenta algebraically with proper signs.

Flashcard 3: What is the correct sign convention to specify before collecting momentum data in 1D1\text{D}?

Answer: Choose one direction as positive; opposite direction is negative. Sign convention prevents errors when velocities oppose each other.

Flashcard 4: Which collision type is easiest to test for momentum conservation using carts that stick together?

Answer: Perfectly inelastic collision (carts stick; share one final velocity). Single final velocity simplifies analysis.

Flashcard 5: What should be defined as the system when testing momentum conservation in a cart collision?

Answer: Both carts (and any attached masses) treated as one system. System boundary must include all interacting objects for conservation to apply.

Flashcard 6: Find pfp_f if m1=0.40kgm_1=0.40\,\text{kg} at +0.25m/s+0.25\,\text{m/s} and m2=0.60kgm_2=0.60\,\text{kg} at +0.10m/s+0.10\,\text{m/s} after collision.

Answer: pf=0.16kgm/sp_f=0.16\,\text{kg}\cdot\text{m/s}. pf=(0.40)(0.25)+(0.60)(0.10)=0.10+0.06=0.16p_f=(0.40)(0.25)+(0.60)(0.10)=0.10+0.06=0.16

Flashcard 7: What is the best operational check that a track is level before momentum trials?

Answer: A cart at rest remains at rest (no drift) on the track. No drift indicates zero net force along track direction.

Flashcard 8: Which design change best reduces external impulse in a cart collision: add a fan, add magnets, or level the track?

Answer: Level the track (minimizes external force component along motion). Eliminates gravity component along track, unlike fans or magnets which add forces.

Flashcard 9: What quantities must you measure to compute total momentum before and after a collision?

Answer: Each cart mass mm and velocity vv before and after the interaction. Need all masses and velocities to calculate p=mvp=mv for each object.

Flashcard 10: Which variable should be controlled to reduce external forces in a cart collision test?

Answer: Track level and friction (use low-friction track, level it). Minimizing friction and gravity components ensures negligible external forces.

Flashcard 11: Which diagram best represents a 1D two-cart collision experiment used to test momentum conservation?

Answer: Two carts on a straight track with labeled m1,m2m_1,m_2 and v1i,v2i,v1f,v2fv_{1i},v_{2i},v_{1f},v_{2f}. Shows all needed quantities for momentum calculations.

Flashcard 12: Find pfp_f for m1=0.50kgm_1=0.50\,\text{kg}, v1f=0.20m/sv_{1f}=0.20\,\text{m/s}, m2=0.30kgm_2=0.30\,\text{kg}, v2f=1.00m/sv_{2f}=1.00\,\text{m/s}.

Answer: pf=0.40kgm/sp_f=0.40\,\text{kg}\cdot\text{m/s}. pf=(0.50)(0.20)+(0.30)(1.00)=0.10+0.30=0.40kgm/sp_f = (0.50)(0.20) + (0.30)(1.00) = 0.10 + 0.30 = 0.40\,\text{kg}\cdot\text{m/s}

Flashcard 13: Which measurement tool directly provides cart velocity for momentum tests on a track?

Answer: Photogate(s) with a flag of known length (or motion sensor). Time through flag gives velocity; motion sensors measure directly.

Flashcard 14: What is the independent variable in a design where you change cart masses and test conservation?

Answer: Cart mass configuration (values of m1m_1 and/or m2m_2). You manipulate mass to see its effect on conservation.

Flashcard 15: Choose the correct conclusion: if pi=0.60p_i=0.60 and pf=0.58kgm/sp_f=0.58\,\text{kg}\cdot\text{m/s} with small uncertainty, is momentum conserved?

Answer: Yes, within experimental uncertainty (pfpip_f\approx p_i). 3.3%3.3\% difference is within typical experimental error.

Flashcard 16: Which collision type is most suitable for testing momentum conservation with minimal ambiguity?

Answer: One-dimensional head-on collision along a straight track. Simplifies vector analysis to scalar math with sign convention.

Flashcard 17: Which track setup best reduces external forces when testing cart momentum conservation?

Answer: Level, low-friction track (or air track) with minimal contact friction. Minimizes external forces that would violate conservation.

Flashcard 18: Identify the independent variable in a basic momentum-conservation collision experiment design.

Answer: Initial conditions (for example v1iv_{1i} or mass distribution). The experimenter controls what collides and how fast.

Flashcard 19: State the momentum conservation equation for two objects in one dimension.

Answer: m1v1i+m2v2i=m1v1f+m2v2fm_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}. Total momentum before equals total momentum after in isolated systems.

Flashcard 20: What equation defines linear momentum for a single object?

Answer: p=mv\vec{p}=m\vec{v}. Momentum equals mass times velocity vector.

Flashcard 21: Identify the sign of pp for a cart moving left if right is defined as positive in 1D1\text{D}.

Answer: Negative momentum: p<0p<0. Velocity opposite to positive direction has negative sign.

Flashcard 22: Find pip_i for m1=0.50kgm_1=0.50\,\text{kg}, v1i=0.80m/sv_{1i}=0.80\,\text{m/s}, m2=0.30kgm_2=0.30\,\text{kg}, v2i=0v_{2i}=0.

Answer: pi=0.40kgm/sp_i=0.40\,\text{kg}\cdot\text{m/s}. pi=(0.50)(0.80)+(0.30)(0)=0.40kgm/sp_i = (0.50)(0.80) + (0.30)(0) = 0.40\,\text{kg}\cdot\text{m/s}

Flashcard 23: Identify the dependent variable used to evaluate momentum conservation in the experiment.

Answer: Change in system momentum: Δp=pfpi\Delta p=p_f-p_i (or percent difference). Measures how well momentum is conserved in the collision.

Flashcard 24: What procedural step improves reliability when testing whether pipfp_i\approx p_f?

Answer: Repeat trials and average results (report spread/uncertainty). Multiple trials reduce random errors and reveal consistency.

Flashcard 25: Which measurement tools are most appropriate to obtain cart velocities in a momentum lab?

Answer: Photogates or motion sensor (or video analysis with scale). These tools measure velocity precisely without disturbing the motion.

Flashcard 26: Identify the best control to check for external impulse before running collisions.

Answer: Verify constant velocity for a single cart: Δv0\Delta v\approx 0 over time. No velocity change confirms negligible external forces.

Flashcard 27: What conservation equation should you test for a two-cart interaction in 1D?

Answer: m1v1i+m2v2i=m1v1f+m2v2fm_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}. Total momentum before equals total momentum after for two objects.

Flashcard 28: What formula should you use to compute the system momentum after collision in 1D1\text{D}?

Answer: pf=m1v1f+m2v2fp_f=m_1v_{1f}+m_2v_{2f}. Sum final momenta to compare with initial total momentum.

Flashcard 29: What calculation gives the percent difference used to judge momentum conservation?

Answer: %diff=pfpipi×100%\%\text{diff}=\frac{|p_f-p_i|}{|p_i|}\times 100\%. Normalizes difference by initial value for comparison.

Flashcard 30: What graph would best show whether pfp_f matches pip_i across many trials of different masses?

Answer: Scatter plot of pfp_f vs pip_i; ideal trend is pf=pip_f=p_i (slope 11). Perfect conservation shows as 45° line through origin.

Flashcard 31: What condition must be met for a collision experiment to test momentum conservation in a system?

Answer: Net external impulse is negligible: FextΔt0\sum \vec{F}_{ext}\Delta t \approx 0. External forces must be minimal during collision time for momentum to be conserved.

Flashcard 32: What is the dependent variable when testing whether total momentum is conserved?

Answer: Difference between totals: Δp=pfpi\Delta p=p_f-p_i (or percent difference). Measures how well momentum is conserved.

Flashcard 33: Which variable should you keep constant to isolate the effect of mass on momentum conservation results?

Answer: Track conditions (levelness and friction) and the collision mechanism. Controls ensure only mass variation affects results.

Flashcard 34: Identify the missing step: you used photogates but did not know cart speed; what must be measured?

Answer: Flag length LL to compute v=LΔtv=\frac{L}{\Delta t}. Photogate timing gives Δt\Delta t; need LL for velocity.

Flashcard 35: Which option best reduces the effect of a small constant friction force during the collision interval?

Answer: Use a short collision time and measure velocities immediately before and after. Minimizes impulse from friction during collision.

Flashcard 36: What condition must be met for momentum to be conserved in an experiment?

Answer: Net external impulse is zero, Jext=0\sum J_{ext}=0 (isolated system). No external forces means no external impulse to change total momentum.

Flashcard 37: What is the vector definition of linear momentum for an object used in conservation tests?

Answer: p=mv\vec{p}=m\vec{v}. Momentum is mass times velocity, both magnitude and direction matter.

Flashcard 38: Which sign convention should you state when measuring 1D velocities for momentum calculations?

Answer: Choose + direction along the track; opposite motion has negative vv. Ensures consistent velocity signs for momentum calculations.

Flashcard 39: Compute %diff\%\text{diff} if pi=0.50p_i=0.50 and pf=0.47p_f=0.47 in kgm/s\text{kg}\cdot\text{m/s}.

Answer: 6%6\%. %diff=0.470.500.50×100%=6%\%\text{diff}=\frac{|0.47-0.50|}{0.50}\times 100\%=6\%

Flashcard 40: Which quantitative comparison best tests conservation: absolute difference or percent difference?

Answer: Percent difference: pfpipf+pi2×100%\frac{|p_f-p_i|}{\frac{|p_f|+|p_i|}{2}}\times 100\%. Percent difference accounts for measurement scale and uncertainty.