Physics Flashcards: Evaluate Collision Design Solutions

Study Evaluate Collision Design Solutions in Physics with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

Physics

Evaluate Collision Design Solutions

0 mastered0 still learning

0% Complete

QUESTION
1/ 37

Which evaluation tool best organizes criteria, constraints, and scores across designs?

Tap card or press Space to flip

ANSWER

A decision matrix (scoring table). Systematically compares designs against all criteria and constraints.

How well did you know it?

Card 1 / 37

What this deck covers

This deck focuses on Evaluate Collision Design Solutions, giving you a quick way to review the definitions, rules, and examples that matter most for Physics.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

All flashcards

Flashcard 1: Which evaluation tool best organizes criteria, constraints, and scores across designs?

Answer: A decision matrix (scoring table). Systematically compares designs against all criteria and constraints.

Flashcard 2: Which collision is more elastic based on ee: Option A e=0.30e=0.30 or Option B e=0.80e=0.80?

Answer: Option B (e=0.80e=0.80). Higher ee means more elastic (closer to 1).

Flashcard 3: What decision rule selects the best design when multiple criteria have weights?

Answer: Choose the highest weighted total score. Sum weighted scores for each design; pick the highest.

Flashcard 4: What formula defines linear momentum used to compare collision design options?

Answer: p=mvp=mv. Momentum equals mass times velocity.

Flashcard 5: What is the work–energy relation used to evaluate stopping distance designs?

Answer: W=ΔKW=\Delta K. Work done equals change in kinetic energy for stopping analysis.

Flashcard 6: If two designs have the same Δp\Delta p, which has lower FavgF_{avg}: Δt=0.10s\Delta t=0.10\,\text{s} or 0.20s0.20\,\text{s}?

Answer: Δt=0.20s\Delta t=0.20\,\text{s}. Doubling time halves average force per Favg=ΔpΔtF_{avg}=\frac{\Delta p}{\Delta t}.

Flashcard 7: What kinetic energy formula is used when comparing energy absorption in crashes?

Answer: K=12mv2K=\frac{1}{2}mv^2. Standard kinetic energy formula for calculating crash energies.

Flashcard 8: If speed doubles, by what factor does kinetic energy increase in K=12mv2K=\frac{1}{2}mv^2?

Answer: Increases by a factor of 44. Kinetic energy depends on v2v^2, so doubling vv quadruples KK.

Flashcard 9: What equation links average impact force to stopping time for fixed momentum change?

Answer: Favg=ΔpΔtF_{avg}=\frac{\Delta p}{\Delta t}. Rearranging impulse-momentum theorem to isolate average force.

Flashcard 10: What coefficient indicates a perfectly inelastic collision when evaluating design outcomes?

Answer: e=0e=0. Objects stick together with no relative velocity after impact.

Flashcard 11: What is the momentum formula used to compare collision outcomes?

Answer: p=mvp=mv. Linear momentum equals mass times velocity for collision analysis.

Flashcard 12: Which collision type maximizes kinetic energy after impact: elastic or perfectly inelastic?

Answer: Elastic collision. Elastic collisions conserve kinetic energy; inelastic ones lose it.

Flashcard 13: What physics quantity is conserved in an isolated collision and is used as a key criterion?

Answer: Total momentum, ptotalp_{total}, is conserved. In isolated systems, momentum before equals momentum after collision.

Flashcard 14: Identify the better safety design if Δp\Delta p is fixed: Design A Δt=0.20s\Delta t=0.20\,s or B Δt=0.10s\Delta t=0.10\,s.

Answer: Design A (Δt=0.20s\Delta t=0.20\,s). Twice the time means half the average force.

Flashcard 15: Which design better meets a 'limit peak force' constraint: A Fpeak=900NF_{peak}=900\,N or B Fpeak=1200NF_{peak}=1200\,N if limit is 1000N1000\,N?

Answer: Design A (B violates the 1000N1000\,N constraint). B exceeds the maximum allowed force.

Flashcard 16: Which design satisfies a mass constraint of m2.0kgm\le 2.0\,kg: Design A 1.8kg1.8\,kg or Design B 2.3kg2.3\,kg?

Answer: Design A (Design B violates m2.0kgm\le 2.0\,kg). B exceeds the maximum allowed mass.

Flashcard 17: What is the impulse–momentum relation used to compare collision designs?

Answer: J=Δp=FavgΔtJ=\Delta p=F_{avg}\Delta t. Impulse equals momentum change and average force times time interval.

Flashcard 18: What is the defining velocity condition for a perfectly inelastic collision?

Answer: Objects share a final velocity: v1f=v2fv_{1f}=v_{2f}. Objects stick together, moving with same final velocity.

Flashcard 19: What coefficient indicates a perfectly elastic collision when evaluating design outcomes?

Answer: e=1e=1. Objects bounce apart with no kinetic energy loss.

Flashcard 20: Which design better meets 'maximize energy absorption' if Ki=10JK_i=10\,J: A Kf=2JK_f=2\,J or B Kf=7JK_f=7\,J?

Answer: Design A (ΔK=8J\Delta K=8\,J absorbed). More energy absorbed: 102=8J10-2=8\,J vs 107=3J10-7=3\,J.

Flashcard 21: Which option best meets the safety criterion if both designs have the same Δp\Delta p: larger or smaller Δt\Delta t?

Answer: Larger Δt\Delta t. Reduces average force via Favg=ΔpΔtF_{avg}=\frac{\Delta p}{\Delta t}.

Flashcard 22: In an isolated collision, what equation expresses momentum conservation for two objects?

Answer: m1v1i+m2v2i=m1v1f+m2v2fm_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}. Initial total momentum equals final total momentum.

Flashcard 23: Which metric best indicates occupant safety in a crash: maximize FmaxF_{max} or minimize FmaxF_{max}?

Answer: Minimize FmaxF_{max}. Lower peak forces reduce injury risk to occupants.

Flashcard 24: Which equation defines the coefficient of restitution used to compare bounce performance?

Answer: e=v2fv1fv1iv2ie=\frac{|v_{2f}-v_{1f}|}{|v_{1i}-v_{2i}|}. Ratio of relative separation to approach velocities.

Flashcard 25: Which design yields smaller average force if both have the same impulse JJ: larger or smaller Δt\Delta t?

Answer: Larger Δt\Delta t gives smaller FavgF_{avg}. From Favg=JΔtF_{avg}=\frac{J}{\Delta t}, larger time gives smaller force.

Flashcard 26: What is the difference between a design criterion and a design constraint?

Answer: Criterion: desired performance; constraint: nonnegotiable limit. Criteria are goals to optimize; constraints are absolute requirements.

Flashcard 27: What formula defines kinetic energy, often used to judge energy loss in collisions?

Answer: K=12mv2K=\frac{1}{2}mv^2. Kinetic energy equals half mass times velocity squared.

Flashcard 28: What coefficient of restitution value corresponds to a perfectly elastic collision?

Answer: e=1e=1. Unity restitution means perfect bounce with no energy loss.

Flashcard 29: What formula gives impulse, a common criterion for evaluating collision safety designs?

Answer: J=FΔt=ΔpJ=F\Delta t=\Delta p. Impulse equals force times time, which equals change in momentum.

Flashcard 30: Which option is a constraint: "minimize peak force" or "mass must be 2.0kg\le 2.0\,\text{kg}"?

Answer: "Mass must be 2.0kg\le 2.0\,\text{kg}". Mass limit is a hard requirement (constraint), not a goal.

Flashcard 31: What conservation law is typically applied to an isolated collision system?

Answer: Total momentum is conserved. No external forces means system momentum stays constant.

Flashcard 32: What coefficient of restitution value corresponds to a perfectly inelastic collision?

Answer: e=0e=0. Zero restitution means no relative separation after impact.

Flashcard 33: Which option better meets a 'minimize rebound' criterion: Design A e=0.10e=0.10 or Design B e=0.60e=0.60?

Answer: Design A (e=0.10e=0.10). Lower ee means less bounce-back velocity.

Flashcard 34: What relationship shows why increasing collision time reduces average impact force?

Answer: Favg=ΔpΔtF_{avg}=\frac{\Delta p}{\Delta t}. Longer collision time reduces force for same momentum change.

Flashcard 35: What is the momentum conservation equation for a 1D two-object collision?

Answer: m1v1i+m2v2i=m1v1f+m2v2fm_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}. Total momentum before equals total momentum after.

Flashcard 36: Which design change reduces peak force most directly when Δp\Delta p is fixed: increase or decrease Δt\Delta t?

Answer: Increase Δt\Delta t. Longer collision time spreads force over more time, reducing peak.

Flashcard 37: If a design violates any constraint, how should it be treated in evaluation?

Answer: Reject or redesign it; it is not acceptable. Constraint violations disqualify designs immediately.