Precalculus Quiz: Subtract And Represent Vectors Graphically
20 questions · exam conditions
0:00
Subtract And Represent Vectors GraphicallyQuestion 1 of 20

Vector u=5,2\vec{u} = \langle 5, -2 \rangle and vector v=3,4\vec{v} = \langle -3, 4 \rangle. If the resultant vector w=uv\vec{w} = \vec{u} - \vec{v} is represented graphically starting from the origin, what are the coordinates of its terminal point?

8,6\langle 8, -6 \rangle
2,2\langle 2, 2 \rangle
8,6\langle -8, 6 \rangle
2,2\langle -2, -2 \rangle
← Back to quizzes

Precalculus Quiz

Precalculus Quiz: Subtract And Represent Vectors Graphically

Practice Subtract And Represent Vectors Graphically in Precalculus with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Subtract And Represent Vectors Graphically, giving you a quick way to practice the rules, question types, and explanations that matter most for Precalculus.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Vector u=5,2\vec{u} = \langle 5, -2 \rangle and vector v=3,4\vec{v} = \langle -3, 4 \rangle. If the resultant vector w=uv\vec{w} = \vec{u} - \vec{v} is represented graphically starting from the origin, what are the coordinates of its terminal point?

  1. 8,6\langle 8, -6 \rangle (correct answer)
  2. 2,2\langle 2, 2 \rangle
  3. 8,6\langle -8, 6 \rangle
  4. 2,2\langle -2, -2 \rangle
Explanation: Vector subtraction is performed component-wise: uv=5,23,4=5(3),24=8,6\vec{u} - \vec{v} = \langle 5, -2 \rangle - \langle -3, 4 \rangle = \langle 5-(-3), -2-4 \rangle = \langle 8, -6 \rangle. Choice B results from adding the vectors instead of subtracting. Choice C results from computing vu\vec{v} - \vec{u} instead of uv\vec{u} - \vec{v}. Choice D results from both reversing the order and making sign errors.

Question 2

If p=7,1\vec{p} = \langle 7, -1 \rangle and q=2,5\vec{q} = \langle 2, 5 \rangle, what is the magnitude of pq\vec{p} - \vec{q}?

  1. 61\sqrt{61} (correct answer)
  2. 45\sqrt{45}
  3. 85\sqrt{85}
  4. 29\sqrt{29}
Explanation: First compute pq=7,12,5=5,6\vec{p} - \vec{q} = \langle 7, -1 \rangle - \langle 2, 5 \rangle = \langle 5, -6 \rangle. Then find the magnitude: pq=52+(6)2=25+36=61|\vec{p} - \vec{q}| = \sqrt{5^2 + (-6)^2} = \sqrt{25 + 36} = \sqrt{61}. Choice B results from computing 32+62\sqrt{3^2 + 6^2} (wrong x-component). Choice C results from computing p+q|\vec{p} + \vec{q}| instead. Choice D results from computing qp|\vec{q} - \vec{p}| with a calculation error.

Question 3

For vectors v=5,3\vec v=\langle 5,3\rangle and w=2,1\vec w=\langle 2,1\rangle, what are the components of vw\vec v-\vec w? (Recall: vector subtraction means adding the opposite, vw=v+(w)\vec v-\vec w=\vec v+(-\vec w).)

  1. 7,4\langle 7,4\rangle
  2. 3,2\langle 3,2\rangle (correct answer)
  3. 3,2\langle -3,-2\rangle
  4. 10,3\langle 10,3\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it algebraically using components. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. For v = ⟨5, 3⟩ and w = ⟨2, 1⟩, we compute v - w = ⟨5 - 2, 3 - 1⟩ = ⟨3, 2⟩. Choice B is correct because it applies the component subtraction formula correctly, giving ⟨3, 2⟩. Choice A adds the vectors instead of subtracting them, calculating v + w = ⟨5 + 2, 3 + 1⟩ = ⟨7, 4⟩ when we need v - w. Key to vector subtraction: remember that v - w = v + (-w), so you can either subtract components directly (⟨v₁ - w₁, v₂ - w₂⟩) or add the opposite vector (-w), both methods give the same result. To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 4

If w=4,3\vec w=\langle -4, 3 \rangle, what is the opposite vector w-\vec w (the vector with the same magnitude but opposite direction), which is used when rewriting vw\vec v-\vec w as v+(w)\vec v+(-\vec w)?

  1. 4,3\langle 4, -3 \rangle (correct answer)
  2. 4,3\langle -4, -3 \rangle
  3. 4,3\langle 4, 3 \rangle
  4. 3,4\langle -3, 4 \rangle
Explanation: This question tests understanding of vector subtraction and how to represent it as addition of the opposite. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. If w = ⟨-4, 3⟩, then -w = ⟨-(-4), -3⟩ = ⟨4, -3⟩, which means we negate both components; this gives a vector with the same length but pointing in the exact opposite direction. Choice A is correct because it correctly negates both components for -w. Choice B only negates one component when finding -w, but the opposite of a vector requires negating both components. When finding the opposite of a vector, -w = ⟨-w₁, -w₂⟩, negate every component; this creates a vector with identical magnitude but pointing in the exactly opposite direction (180° rotation). To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 5

An object's displacement over two steps is represented by vectors v=6,0\vec v=\langle 6,0\rangle and w=1,0\vec w=\langle 1,0\rangle drawn from the same starting point. The difference vw\vec v-\vec w can be found as v+(w)\vec v+(-\vec w). What are the components of vw\vec v-\vec w?

  1. 7,0\langle 7,0\rangle
  2. 5,0\langle 5,0\rangle (correct answer)
  3. 5,0\langle -5,0\rangle
  4. 6,1\langle 6,1\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it algebraically using components. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. For v = ⟨6, 0⟩ and w = ⟨1, 0⟩, we compute v - w = ⟨6 - 1, 0 - 0⟩ = ⟨5, 0⟩. Choice B is correct because it applies the component subtraction formula correctly. Choice C reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped. Key to vector subtraction: remember that v - w = v + (-w), so you can either subtract components directly (⟨v₁ - w₁, v₂ - w₂⟩) or add the opposite vector (-w), both methods give the same result. To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 6

For vectors v=5,3\vec v=\langle 5,3\rangle and w=2,1\vec w=\langle 2,1\rangle, use component-wise subtraction (equivalently, vw=v+(w)\vec v-\vec w=\vec v+(-\vec w)) to find the components of vw\vec v-\vec w in a,b\langle a,b\rangle form.

  1. 7,4\langle 7,4\rangle
  2. 3,2\langle 3,2\rangle (correct answer)
  3. 3,2\langle -3,-2\rangle
  4. 10,3\langle 10,3\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it algebraically using components. To subtract vectors component-wise, subtract the corresponding components: if v = ⟨v₁, v₂⟩ and w = ⟨w₁, w₂⟩, then v - w = ⟨v₁ - w₁, v₂ - w₂⟩. For v = ⟨5, 3⟩ and w = ⟨2, 1⟩, we compute v - w = ⟨5 - 2, 3 - 1⟩ = ⟨3, 2⟩. Choice B is correct because it applies the component subtraction formula correctly. Choice A adds the vectors instead of subtracting them, calculating v + w = ⟨5 + 2, 3 + 1⟩ = ⟨7, 4⟩ when we need v - w. Key to vector subtraction: remember that v - w = v + (-w), so you can either subtract components directly (⟨v₁ - w₁, v₂ - w₂⟩) or add the opposite vector (-w), both methods give the same result. To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 7

Vector m\vec{m} has initial point (3,2)(3, -2) and terminal point (8,5)(8, -5). Vector n\vec{n} has initial point (1,4)(-1, 4) and terminal point (2,6)(2, 6). What is mn\vec{m} - \vec{n} expressed in component form?

  1. 6,1\langle 6, 1 \rangle
  2. 8,3\langle 8, -3 \rangle
  3. 2,5\langle -2, 5 \rangle
  4. 2,5\langle 2, -5 \rangle (correct answer)
Explanation: When working with vectors defined by initial and terminal points, you need to find the component form of each vector before performing any operations. The component form of a vector is found by subtracting the coordinates of the initial point from the coordinates of the terminal point. For vector m\vec{m} with initial point (3,2)(3, -2) and terminal point (8,5)(8, -5): m=83,5(2)=5,3\vec{m} = \langle 8-3, -5-(-2) \rangle = \langle 5, -3 \rangle For vector n\vec{n} with initial point (1,4)(-1, 4) and terminal point (2,6)(2, 6): n=2(1),64=3,2\vec{n} = \langle 2-(-1), 6-4 \rangle = \langle 3, 2 \rangle Now you can find mn\vec{m} - \vec{n} by subtracting corresponding components: mn=5,33,2=53,32=2,5\vec{m} - \vec{n} = \langle 5, -3 \rangle - \langle 3, 2 \rangle = \langle 5-3, -3-2 \rangle = \langle 2, -5 \rangle This confirms answer choice D is correct. Looking at the wrong answers: Choice A, 6,1\langle 6, 1 \rangle, likely comes from adding the vectors instead of subtracting. Choice B, 8,3\langle 8, -3 \rangle, appears to use just the terminal point of m\vec{m} without proper vector subtraction. Choice C, 2,5\langle -2, 5 \rangle, results from calculating nm\vec{n} - \vec{m} instead of mn\vec{m} - \vec{n}. Remember: always convert position vectors to component form first (terminal minus initial), then perform the vector operations component-wise. Vector subtraction is not commutative, so order matters.

Question 8

Using the vectors given, v=0,4\vec v=\langle 0, -4 \rangle and w=3,2\vec w=\langle -3, 2 \rangle, what are the components of vw\vec v-\vec w? (Remember: subtracting w\vec w is the same as adding the opposite vector w-\vec w.)

  1. 3,2\langle -3, -2 \rangle
  2. 3,6\langle 3, -6 \rangle (correct answer)
  3. 3,6\langle -3, -6 \rangle
  4. 3,6\langle 3, 6 \rangle
Explanation: This question tests understanding of vector subtraction and how to represent it algebraically using components. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. For v = ⟨0, -4⟩ and w = ⟨-3, 2⟩, we compute v - w = ⟨0 - (-3), -4 - 2⟩ = ⟨3, -6⟩. Choice B is correct because it applies the component subtraction formula correctly. Choice A reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped. Key to vector subtraction: remember that v - w = v + (-w), so you can either subtract components directly (⟨v₁ - w₁, v₂ - w₂⟩) or add the opposite vector (-w), both methods give the same result. To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 9

For vectors v=2,6\vec v=\langle -2,6\rangle and w=3,1\vec w=\langle 3,-1\rangle, rewrite vw\vec v-\vec w as v+(w)\vec v+(-\vec w) and find the components of vw\vec v-\vec w.

  1. 1,5\langle 1,5\rangle
  2. 5,7\langle -5,7\rangle (correct answer)
  3. 5,7\langle 5,-7\rangle
  4. 6,6\langle -6,-6\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it algebraically using components. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. For v = ⟨-2, 6⟩ and w = ⟨3, -1⟩, we compute v - w = ⟨-2 - 3, 6 - (-1)⟩ = ⟨-5, 7⟩. Choice B is correct because it applies the component subtraction formula correctly. Choice C reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped. Key to vector subtraction: remember that v - w = v + (-w), so you can either subtract components directly (⟨v₁ - w₁, v₂ - w₂⟩) or add the opposite vector (-w), both methods give the same result. To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 10

For vectors v\vec v and w\vec w drawn tail-to-tail from the same point, which statement correctly describes the graphical representation of vw\vec v-\vec w using the tip-to-tip method (and the idea vw=v+(w)\vec v-\vec w=\vec v+(-\vec w))?

  1. vw\vec v-\vec w is the vector from the tip of v\vec v to the tip of w\vec w.
  2. vw\vec v-\vec w is the vector from the tail of v\vec v to the tail of w\vec w.
  3. vw\vec v-\vec w is the vector from the tip of w\vec w to the tip of v\vec v. (correct answer)
  4. vw\vec v-\vec w is the same as wv\vec w-\vec v because subtraction is commutative.
Explanation: This question tests understanding of vector subtraction and how to represent it graphically using the tip-to-tip method. Graphically, when vectors v and w are drawn from the same initial point (tail-to-tail), the vector v - w is represented by the vector from the tip of w to the tip of v, forming a triangle. When v and w are drawn with their tails at the same point, visualize walking from the tip of w to the tip of v—that path represents v - w. This is equivalent to the triangle rule: v, w, and v - w form a closed triangle. Choice C is correct because it properly describes the tip-to-tip method. Choice A describes the graphical vector going from the tip of v to the tip of w, but v - w goes from the tip of w to the tip of v (the opposite direction). For the tip-to-tip graphical method, place both vectors tail-to-tail and draw the difference vector from the tip of what you're subtracting (w) to the tip of what you're subtracting from (v). Remember that vector subtraction is not commutative: v - w and w - v are different vectors pointing in opposite directions, so order matters in subtraction unlike addition.

Question 11

For vectors drawn tail-to-tail at the origin, v=4,0\vec v = \langle 4, 0\rangle and w=1,0\vec w = \langle 1, 0\rangle. Using vw=v+(w)\vec v-\vec w=\vec v+(-\vec w), what are the components of vw\vec v-\vec w?

  1. 3,0\langle 3, 0\rangle (correct answer)
  2. 5,0\langle 5, 0\rangle
  3. 3,0\langle -3, 0\rangle
  4. 4,1\langle 4, 1\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it as addition of the opposite. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. For v = ⟨4, 0⟩ and w = ⟨1, 0⟩, we compute v - w = ⟨4 - 1, 0 - 0⟩ = ⟨3, 0⟩. Choice A is correct because it applies the component subtraction formula correctly, giving ⟨3, 0⟩. Choice B adds the vectors instead of subtracting them, calculating v + w = ⟨5, 0⟩ when we need v - w. To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v: ⟨1, 0⟩ + ⟨3, 0⟩ = ⟨4, 0⟩ ✓.

Question 12

Two vectors a=4,3\vec{a} = \langle 4, -3 \rangle and b=1,5\vec{b} = \langle -1, 5 \rangle are given. A student claims that ab\vec{a} - \vec{b} has the same magnitude as ba\vec{b} - \vec{a}. Which statement best evaluates this claim?

  1. The claim is correct because subtraction of vectors is commutative under magnitude calculations
  2. The claim is correct because ab\vec{a} - \vec{b} and ba\vec{b} - \vec{a} are additive inverses with equal magnitudes (correct answer)
  3. The claim is incorrect because vector subtraction reverses both direction and magnitude relationships
  4. The claim is incorrect because the components have different signs in each subtraction operation
Explanation: Computing both: ab=5,8\vec{a} - \vec{b} = \langle 5, -8 \rangle and ba=5,8\vec{b} - \vec{a} = \langle -5, 8 \rangle. These are additive inverses (opposite vectors) and therefore have the same magnitude: 25+64=89\sqrt{25 + 64} = \sqrt{89}. The claim is correct. Choice A incorrectly describes subtraction as commutative. Choice C incorrectly states that magnitude is affected by direction. Choice D focuses on signs rather than the magnitude relationship.

Question 13

For vectors v=3,2\vec v = \langle 3, 2\rangle and w=1,5\vec w = \langle -1, 5\rangle, what are the components of wv\vec w-\vec v? (Recall that vector subtraction is not commutative, and wv=w+(v)\vec w-\vec v=\vec w+(-\vec v).)

  1. 4,3\langle 4, 3\rangle
  2. 4,3\langle -4, -3\rangle (correct answer)
  3. 2,7\langle 2, 7\rangle
  4. 2,7\langle -2, -7\rangle
Explanation: This question tests understanding of vector subtraction and the non-commutative nature of this operation. To subtract vectors component-wise, subtract the corresponding components: if v = ⟨v₁, v₂⟩ and w = ⟨w₁, w₂⟩, then w - v = ⟨w₁ - v₁, w₂ - v₂⟩. For v = ⟨3, 2⟩ and w = ⟨-1, 5⟩, we compute w - v = ⟨-1 - 3, 5 - 2⟩ = ⟨-4, 3⟩. Choice B is correct because it applies the component subtraction formula correctly, giving ⟨-4, 3⟩. Choice A computes v - w instead of w - v, which gives ⟨4, -3⟩, the opposite vector with all signs flipped. Remember that vector subtraction is not commutative: v - w and w - v are different vectors pointing in opposite directions, so order matters in subtraction unlike addition.

Question 14

Vector v\vec v points 2 units east and 1 unit north, so v=2,1\vec v = \langle 2, 1\rangle. Vector w\vec w points 5 units east and 3 units north, so w=5,3\vec w = \langle 5, 3\rangle. Using component-wise subtraction (equivalently vw=v+(w)\vec v-\vec w=\vec v+(-\vec w)), what is vw\vec v-\vec w?

  1. 7,4\langle 7, 4\rangle
  2. 3,2\langle 3, 2\rangle
  3. 3,2\langle -3, -2\rangle (correct answer)
  4. 7,4\langle -7, -4\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it using component-wise subtraction. To subtract vectors component-wise, subtract the corresponding components: if v = ⟨v₁, v₂⟩ and w = ⟨w₁, w₂⟩, then v - w = ⟨v₁ - w₁, v₂ - w₂⟩. For v = ⟨2, 1⟩ and w = ⟨5, 3⟩, we compute v - w = ⟨2 - 5, 1 - 3⟩ = ⟨-3, -2⟩. Choice C is correct because it applies the component subtraction formula correctly, giving ⟨-3, -2⟩. Choice B reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped: ⟨3, 2⟩. Remember that vector subtraction is not commutative: v - w and w - v are different vectors pointing in opposite directions, so order matters in subtraction unlike addition.

Question 15

Vectors v\vec v and w\vec w are drawn tail-to-tail from the same initial point. How is vw\vec v-\vec w represented graphically using the tip-to-tip method (consistent with vw=v+(w)\vec v-\vec w=\vec v+(-\vec w))?

  1. The vector from the tip of v\vec v to the tip of w\vec w.
  2. The vector from the tail of v\vec v to the tip of w\vec w.
  3. The vector from the tip of w\vec w to the tip of v\vec v. (correct answer)
  4. The vector from the tail of w\vec w to the tail of v\vec v.
Explanation: This question tests understanding of vector subtraction and how to represent it graphically using the tip-to-tip method. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. Graphically, when vectors v and w are drawn from the same initial point (tail-to-tail), the vector v - w is represented by the vector from the tip of w to the tip of v, forming a triangle. Choice C is correct because it properly describes the tip-to-tip method. Choice A describes the graphical vector going from the tip of v to the tip of w, but v - w goes from the tip of w to the tip of v (the opposite direction). For the tip-to-tip graphical method, place both vectors tail-to-tail and draw the difference vector from the tip of what you're subtracting (w) to the tip of what you're subtracting from (v). To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 16

Vectors v\vec v and w\vec w are drawn tail-to-tail from the origin on a coordinate plane. If v=4,1\vec v=\langle 4, -1 \rangle and w=1,2\vec w=\langle 1, 2 \rangle, what are the components of vw\vec v-\vec w? (Recall vw=v+(w)\vec v-\vec w=\vec v+(-\vec w).)

  1. 3,3\langle 3, -3 \rangle (correct answer)
  2. 5,1\langle 5, 1 \rangle
  3. 3,3\langle -3, 3 \rangle
  4. 4,2\langle 4, -2 \rangle
Explanation: This question tests understanding of vector subtraction and how to represent it algebraically using components. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. For v = ⟨4, -1⟩ and w = ⟨1, 2⟩, we compute v - w = ⟨4 - 1, -1 - 2⟩ = ⟨3, -3⟩. Choice A is correct because it applies the component subtraction formula correctly. Choice C reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped. Key to vector subtraction: remember that v - w = v + (-w), so you can either subtract components directly (⟨v₁ - w₁, v₂ - w₂⟩) or add the opposite vector (-w), both methods give the same result. To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 17

Let v=3,4\vec v=\langle 3,-4\rangle and w=2,5\vec w=\langle -2,5\rangle. Using component-wise subtraction (vw=v1w1,v2w2\vec v-\vec w=\langle v_1-w_1,\,v_2-w_2\rangle) and the fact that vw=v+(w)\vec v-\vec w=\vec v+(-\vec w), what is vw\vec v-\vec w?

  1. 1,1\langle 1,1\rangle
  2. 5,9\langle 5,-9\rangle (correct answer)
  3. 5,9\langle -5,9\rangle
  4. 6,20\langle -6,-20\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it algebraically using components. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. For v = ⟨3, -4⟩ and w = ⟨-2, 5⟩, we compute v - w = ⟨3 - (-2), -4 - 5⟩ = ⟨5, -9⟩. Choice B is correct because it applies the component subtraction formula correctly. Choice C reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped. Key to vector subtraction: remember that v - w = v + (-w), so you can either subtract components directly (⟨v₁ - w₁, v₂ - w₂⟩) or add the opposite vector (-w), both methods give the same result. To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 18

Let v=2,1\vec v=\langle 2,1\rangle and w=5,3\vec w=\langle 5,3\rangle. Since vw=v+(w)\vec v-\vec w=\vec v+(-\vec w), what is vw\vec v-\vec w in component form?

  1. 3,2\langle 3,2\rangle
  2. 3,2\langle -3,-2\rangle (correct answer)
  3. 7,4\langle 7,4\rangle
  4. 7,4\langle -7,-4\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it algebraically using components. Vector subtraction is defined as adding the opposite: v - w = v + (-w), where -w is the vector with the same magnitude as w but pointing in the opposite direction, having components -w = ⟨-w₁, -w₂⟩. For v = ⟨2, 1⟩ and w = ⟨5, 3⟩, we compute v - w = ⟨2 - 5, 1 - 3⟩ = ⟨-3, -2⟩. Choice B is correct because it applies the component subtraction formula correctly. Choice A reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped. Key to vector subtraction: remember that v - w = v + (-w), so you can either subtract components directly (⟨v₁ - w₁, v₂ - w₂⟩) or add the opposite vector (-w), both methods give the same result. Remember that vector subtraction is not commutative: v - w and w - v are different vectors pointing in opposite directions, so order matters in subtraction unlike addition.

Question 19

On a coordinate plane, v\vec v and w\vec w are drawn tail-to-tail at the origin with tips at V(2,1)V(2,-1) and W(1,1)W(-1,1), respectively. Using the tip-to-tip method (vector from the tip of w\vec w to the tip of v\vec v), what is vw\vec v-\vec w in component form?

  1. 1,0\langle 1,0\rangle
  2. 3,2\langle -3,2\rangle
  3. 3,2\langle 3,-2\rangle (correct answer)
  4. 1,0\langle -1,0\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it graphically using the tip-to-tip method. Graphically, when vectors v and w are drawn from the same initial point (tail-to-tail), the vector v - w is represented by the vector from the tip of w to the tip of v, forming a triangle. When v and w are drawn with their tails at the same point, visualize walking from the tip of w to the tip of v—that path represents v - w. This is equivalent to the triangle rule: v, w, and v - w form a closed triangle. Choice C is correct because it properly describes the tip-to-tip method. Choice B reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped. For the tip-to-tip graphical method, place both vectors tail-to-tail and draw the difference vector from the tip of what you're subtracting (w) to the tip of what you're subtracting from (v). To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.

Question 20

Vectors v\vec v and w\vec w are drawn tail-to-tail from the origin on a coordinate plane, with v=4,1\vec v=\langle 4,1\rangle and w=1,3\vec w=\langle 1,3\rangle. Using the tip-to-tip method, what are the components of vw\vec v-\vec w?

  1. 3,2\langle 3,-2\rangle (correct answer)
  2. 5,4\langle 5,4\rangle
  3. 3,2\langle -3,2\rangle
  4. 4,9\langle 4,9\rangle
Explanation: This question tests understanding of vector subtraction and how to represent it graphically using the tip-to-tip method. Graphically, when vectors v and w are drawn from the same initial point (tail-to-tail), the vector v - w is represented by the vector from the tip of w to the tip of v, forming a triangle. When v and w are drawn with their tails at the same point, visualize walking from the tip of w to the tip of v—that path represents v - w. This is equivalent to the triangle rule: v, w, and v - w form a closed triangle. Choice A is correct because it properly describes the tip-to-tip method. Choice C reverses the subtraction order, computing w - v instead of v - w, which gives the opposite vector with all signs flipped. For the tip-to-tip graphical method, place both vectors tail-to-tail and draw the difference vector from the tip of what you're subtracting (w) to the tip of what you're subtracting from (v). To check your work, verify that v = w + (v - w) using vector addition—if you add w back to your result v - w, you should get v.