Precalculus Quiz: Using 2x2 Matrices For Plane Transformations
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Using 2x2 Matrices For Plane TransformationsQuestion 1 of 20

For the transformation matrix R=(0110)R=\begin{pmatrix}0&-1\\1&0\end{pmatrix}, which represents a rotation of the coordinate plane, what is the image of the point (3,4)(3,4) under T(v)=RvT(\mathbf{v})=R\mathbf{v}? (This transformation has det(R)=1\det(R)=1, so areas are preserved.)

(4,3)(4,-3)
(4,3)(-4,3)
(3,4)(3,-4)
(3,4)(-3,4)
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Precalculus Quiz: Using 2x2 Matrices For Plane Transformations

Practice Using 2x2 Matrices For Plane Transformations in Precalculus with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Using 2x2 Matrices For Plane Transformations, giving you a quick way to practice the rules, question types, and explanations that matter most for Precalculus.

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Question 1

For the transformation matrix R=(0110)R=\begin{pmatrix}0&-1\\1&0\end{pmatrix}, which represents a rotation of the coordinate plane, what is the image of the point (3,4)(3,4) under T(v)=RvT(\mathbf{v})=R\mathbf{v}? (This transformation has det(R)=1\det(R)=1, so areas are preserved.)

  1. (4,3)(4,-3)
  2. (4,3)(-4,3) (correct answer)
  3. (3,4)(3,-4)
  4. (3,4)(-3,4)
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane and how the determinant relates to area scaling. Common 2×2 transformations include rotations (like [0 -1; 1 0] for 90° counterclockwise), reflections (like [1 0; 0 -1] for reflection across the x-axis), and scalings (like [k 0; 0 k] for uniform scaling by factor k). To transform point (3, 4) by matrix R = [0 -1; 1 0], we compute [0 -1; 1 0][3; 4] = [03 + (-1)4; 13 + 04] = [-4; 3], giving the image point (-4, 3). Choice B is correct because it accurately computes the matrix-vector product. Choice A makes an error in the matrix-vector multiplication, calculating perhaps the clockwise rotation or sign error, getting (4, -3) instead of (-4, 3). Key to plane transformations: apply the matrix to a vector [x; y] by computing [ax+by; cx+dy], and remember that the determinant det(A) = ad - bc tells you about area scaling (|det| is the factor) and orientation (sign indicates preserved or reversed). Common transformations to recognize: [0 -1; 1 0] rotates 90° counterclockwise, [1 0; 0 -1] reflects across x-axis, [-1 0; 0 1] reflects across y-axis, [0 1; 1 0] reflects across y = x, and [k 0; 0 k] scales uniformly by k.

Question 2

A triangle with vertices at A(2,1)A(2, 1), B(4,1)B(4, 1), and C(2,3)C(2, 3) is transformed by the matrix $$ \begin{pmatrix} 1 & -1 \ 2 & 0 \end{pmatrix}

  1. 12\frac{1}{2}
  2. 11
  3. 22 (correct answer)
  4. 44
Explanation: The ratio of areas under a linear transformation equals the absolute value of the determinant of the transformation matrix. The determinant is (1)(0)(1)(2)=0+2=2(1)(0) - (-1)(2) = 0 + 2 = 2. Therefore, the ratio is 2=2|2| = 2. Choice A results from incorrectly taking the reciprocal. Choice B assumes the determinant is 1. Choice D results from squaring the determinant instead of taking absolute value.

Question 3

Consider the composition of two transformations: first a reflection across the line y=xy = x represented by matrix R=(0110)R = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} , followed by a scaling transformation S=(3002)S = \begin{pmatrix} 3 & 0 \\ 0 & 2 \end{pmatrix} . A circle with area π\pi square units undergoes this composition. What is the area of the final image?

  1. 2π2\pi square units
  2. 3π3\pi square units
  3. 5π5\pi square units
  4. 6π6\pi square units (correct answer)
Explanation: The composition is SR=(3002)(0110)=(0320)SR = \begin{pmatrix} 3 & 0 \\ 0 & 2 \end{pmatrix}\begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} = \begin{pmatrix} 0 & 3 \\ 2 & 0 \end{pmatrix} . The determinant is 0(0)3(2)=60(0) - 3(2) = -6, so the area scaling factor is 6=6|-6| = 6. The final area is π×6=6π\pi \times 6 = 6\pi. Choice A uses only det(S)/3|\det(S)|/3. Choice B uses only det(S)/2|\det(S)|/2. Choice C adds the individual determinants instead of computing the composition.

Question 4

For the transformation matrix A=(1111),A=\begin{pmatrix}1&1\\1&1\end{pmatrix}, the determinant indicates whether the transformation collapses area. What is det(A)\det(A), and what does it imply about the area scaling factor det(A)|\det(A)|?​

  1. det(A)=2\det(A)=2; areas scale by factor 22
  2. det(A)=0\det(A)=0; areas scale by factor 00 (collapse to a line) (correct answer)
  3. det(A)=2\det(A)=-2; areas scale by factor 2-2
  4. det(A)=1\det(A)=-1; areas scale by factor 11 with orientation preserved
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane and how the determinant relates to area scaling. The determinant of a 2×2 transformation matrix A represents the area scaling factor: if det(A) = k, then the transformation scales all areas by a factor of |k| (the absolute value), with positive determinant preserving orientation and negative determinant reversing it (indicating a reflection). For matrix A = [1 1; 1 1], we calculate det(A) = 11 - 11 = 1 - 1 = 0. This means the transformation scales all areas by a factor of |0| = 0, so regions collapse to zero area (like projecting onto a line). Choice B is correct because it correctly calculates the determinant. Choice A confuses the determinant formula, computing ad + bc=2 instead of ad - bc. For area scaling, always use the absolute value: |det(A)| gives the area magnification factor, so if det(A) = -2, areas are scaled by 2 (the absolute value), and the negative sign indicates orientation reversal (a reflection component).

Question 5

Given the transformation matrix A=(1001)A=\begin{pmatrix}-1&0\\0&1\end{pmatrix} applied to the coordinate plane by T(v)=AvT(\mathbf{v})=A\mathbf{v}, what geometric transformation does AA represent? (Here det(A)=1\det(A)=-1, so orientation is reversed while area is preserved.)

  1. Reflection across the xx-axis
  2. Reflection across the yy-axis (correct answer)
  3. Rotation 180180^\circ about the origin
  4. Uniform scaling by factor 1-1
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane and how the determinant relates to area scaling. Common 2×2 transformations include rotations (like [0 -1; 1 0] for 90° counterclockwise), reflections (like [1 0; 0 -1] for reflection across the x-axis), and scalings (like [k 0; 0 k] for uniform scaling by factor k). The matrix [-1 0; 0 1] has the form of a reflection because the first column [-1; 0] flips the x-basis, and second column [0; 1] keeps y, reflecting across the y-axis. Choice B is correct because it properly describes the geometric transformation. Choice A incorrectly identifies the transformation as reflection across x-axis, but the matrix [-1 0; 0 1] actually represents reflection across y-axis because it negates x while keeping y. To identify a transformation geometrically, see what it does to the standard basis vectors: [1; 0] maps to the first column of A, and [0; 1] maps to the second column, which reveals the transformation's nature (rotation, reflection, scaling, etc.). Common transformations to recognize: [0 -1; 1 0] rotates 90° counterclockwise, [1 0; 0 -1] reflects across x-axis, [-1 0; 0 1] reflects across y-axis, [0 1; 1 0] reflects across y = x, and [k 0; 0 k] scales uniformly by k.

Question 6

Given the transformation matrix A=(1001)A = \begin{pmatrix} -1 & 0 \\ 0 & 1 \end{pmatrix} , which acts on points in the plane by (xy)=A(xy)\begin{pmatrix} x' \\ y' \end{pmatrix} = A \begin{pmatrix} x \\ y \end{pmatrix}, what is the image of (4,3)(4,-3)?

  1. (4,3)(4,3)
  2. (4,3)(-4,3)
  3. (4,3)(-4,-3) (correct answer)
  4. (4,3)(4,-3)
Explanation: This question tests understanding of how 2×22 \times 2 matrices act as transformations of the coordinate plane. A 2×22 \times 2 matrix A represents a transformation of the plane: when applied to a point or vector (xy)\begin{pmatrix} x \\ y \end{pmatrix}, it produces a new point/vector (xy)=A(xy)=(ax+bycx+dy)\begin{pmatrix} x' \\ y' \end{pmatrix} = A \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} ax + by \\ cx + dy \end{pmatrix}, effectively moving, rotating, reflecting, or scaling points according to the matrix entries. To transform point (4, -3) by matrix A = (1001)\begin{pmatrix} -1 & 0 \\ 0 & 1 \end{pmatrix}, we compute [1×4+0×(3);0×4+1×(3)]=[4+0;03]=[4;3][-1 \times 4 + 0 \times (-3); 0 \times 4 + 1 \times (-3)] = [-4 + 0; 0 - 3] = [-4; -3], giving the image point (-4, -3). Choice C is correct because it accurately computes the matrix-vector product. Choice A makes an error in the matrix-vector multiplication, calculating as if the matrix negated y instead of x. Key to plane transformations: apply the matrix to a vector (xy)\begin{pmatrix} x \\ y \end{pmatrix} by computing (ax+bycx+dy)\begin{pmatrix} ax + by \\ cx + dy \end{pmatrix}, and remember that the determinant det(A) = ad - bc tells you about area scaling (|det| is the factor) and orientation (sign indicates preserved or reversed). Common transformations to recognize: (0110)\begin{pmatrix} 0 & -1 \\ 1 & 0 \end{pmatrix} rotates 90° counterclockwise, (1001)\begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix} reflects across x-axis, (1001)\begin{pmatrix} -1 & 0 \\ 0 & 1 \end{pmatrix} reflects across y-axis, (0110)\begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} reflects across y = x, and (k00k)\begin{pmatrix} k & 0 \\ 0 & k \end{pmatrix} scales uniformly by k.

Question 7

First rotate the plane by 9090^\circ counterclockwise using R=(0110),R=\begin{pmatrix}0&-1\\1&0\end{pmatrix}, then reflect across the xx-axis using F=(1001).F=\begin{pmatrix}1&0\\0&-1\end{pmatrix}. What is the combined transformation matrix (apply RR first, then FF)?

  1. (0110)\begin{pmatrix}0&-1\\-1&0\end{pmatrix} (correct answer)
  2. (0110)\begin{pmatrix}0&1\\1&0\end{pmatrix}
  3. (0110)\begin{pmatrix}0&-1\\1&0\end{pmatrix}
  4. (0110)\begin{pmatrix}0&1\\-1&0\end{pmatrix}
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane. Common 2×2 transformations include rotations (like [0 -1; 1 0] for 90° counterclockwise), reflections (like [1 0; 0 -1] for reflection across the x-axis), and scalings (like [k 0; 0 k] for uniform scaling by factor k). The combined matrix for applying R first then F is F R = [[1 0]; [0 -1]] times [[0 -1]; [1 0]] = [[0 -1]; [-1 0]], as computed by matrix multiplication. Choice A is correct because it accurately computes the matrix product for the composition. Choice C uses the wrong order for composition, computing R F instead of F R. For composition of transformations, remember the order: 'apply A then B' is written B(Av) = (BA)v, with the matrix applied first written on the right—this is backward from reading left to right. To identify a transformation geometrically, see what it does to the standard basis vectors: [1; 0] maps to the first column of A, and [0; 1] maps to the second column, which reveals the transformation's nature (rotation, reflection, scaling, etc.).

Question 8

A shear transformation is represented by the matrix (1k01)\begin{pmatrix} 1 & k \\ 0 & 1 \end{pmatrix} where kk is a real number. A student observes that when k=5k = 5, a rectangle with area 8 square units is transformed to a parallelogram with area 8 square units. What can be concluded about the value of k=3k = -3?

  1. A rectangle with area 8 will transform to have area 24 square units
  2. A rectangle with area 8 will transform to have area 83\frac{8}{3} square units
  3. A rectangle with area 8 will transform to have area 8 square units (correct answer)
  4. A rectangle with area 8 will transform to have area 3 square units
Explanation: For any shear matrix (1k01)\begin{pmatrix} 1 & k \\ 0 & 1 \end{pmatrix}, the determinant is 1(1)k(0)=11(1) - k(0) = 1, regardless of the value of kk. Since det=1|\det| = 1 for any kk, area is always preserved under shear transformations. The area remains 8 square units. Choice A incorrectly multiplies by kk. Choice B incorrectly divides by k|k|. Choice D incorrectly uses k|k| as a scaling factor.

Question 9

The transformation matrix T=(0110)T = \begin{pmatrix} 0 & 1 \\ -1 & 0 \end{pmatrix} is applied to a rectangle with area 12 square units. After applying transformation TT twice in succession, what is the area of the resulting figure?

  1. 3 square units
  2. 6 square units
  3. 12 square units (correct answer)
  4. 24 square units
Explanation: Applying transformation TT twice means computing T2=(0110)2=(1001)T^2 = \begin{pmatrix} 0 & 1 \\ -1 & 0 \end{pmatrix}^2 = \begin{pmatrix} -1 & 0 \\ 0 & -1 \end{pmatrix} . The determinant of T2T^2 is (1)(1)(0)(0)=1(-1)(-1) - (0)(0) = 1, so the area scaling factor is 1=1|1| = 1. The area remains 12 square units. Choice A results from dividing by the square of det(T)|\det(T)|. Choice B results from dividing by det(T)|\det(T)|. Choice D results from multiplying by det(T)|\det(T)|.

Question 10

First rotate points 9090^\circ counterclockwise using R=(0110),R=\begin{pmatrix}0&-1\\1&0\end{pmatrix}, then reflect across the xx-axis using F=(1001).F=\begin{pmatrix}1&0\\0&-1\end{pmatrix}. What is the combined transformation matrix (apply RR first, then FF)?

  1. (0110)\begin{pmatrix}0&-1\\-1&0\end{pmatrix} (correct answer)
  2. (0110)\begin{pmatrix}0&1\\1&0\end{pmatrix}
  3. (0110)\begin{pmatrix}0&-1\\1&0\end{pmatrix}
  4. (0110)\begin{pmatrix}0&1\\-1&0\end{pmatrix}
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane. Common 2×2 transformations include rotations (like [0 -1; 1 0] for 90° counterclockwise), reflections (like [1 0; 0 -1] for reflection across the x-axis), and scalings (like [k 0; 0 k] for uniform scaling by factor k). For composition, applying R first then F gives the matrix FR = [1 0; 0 -1] [0 -1; 1 0] = [0 -1; -1 0], as calculated by matrix multiplication. Choice A is correct because it accurately computes the matrix product in the correct order. Choice C uses the wrong order for composition, computing RF when the correct order is FR. For composition of transformations, remember the order: 'apply A then B' is written B(Av) = (BA)v, with the matrix applied first written on the right—this is backward from reading left to right. Key to plane transformations: apply the matrix to a vector [x; y] by computing [ax+by; cx+dy], and remember that the determinant det(A) = ad - bc tells you about area scaling (|det| is the factor) and orientation (sign indicates preserved or reversed).

Question 11

The transformation matrix (cosθsinθsinθcosθ)\begin{pmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{pmatrix} represents a rotation by angle θ\theta. A student claims that applying this transformation to a triangle will always preserve its area. Which statement best explains why this claim is correct?

  1. The matrix is symmetric, so all eigenvalues equal 1, preserving area through spectral properties
  2. The determinant equals cos2θ+sin2θ=1\cos^2\theta + \sin^2\theta = 1, so the area scaling factor is 1 (correct answer)
  3. Rotation matrices have trace equal to 2cosθ2\cos\theta, which maintains geometric area invariants
  4. The matrix entries sum to zero when θ=π2\theta = \frac{\pi}{2}, indicating area preservation
Explanation: The determinant of the rotation matrix is cosθcosθ(sinθ)sinθ=cos2θ+sin2θ=1\cos\theta \cdot \cos\theta - (-\sin\theta) \cdot \sin\theta = \cos^2\theta + \sin^2\theta = 1. Since the absolute value of the determinant equals 1, the area scaling factor is 1, preserving area. Choice A incorrectly focuses on eigenvalues and symmetry. Choice C confuses trace with determinant for area scaling. Choice D incorrectly relates matrix entry sums to area preservation.

Question 12

For the transformation matrix A=(0110)A=\begin{pmatrix}0&1\\1&0\end{pmatrix} applied to points by T(v)=AvT(\mathbf{v})=A\mathbf{v}, what geometric transformation does AA represent? (Hint: det(A)=1\det(A)=-1 indicates orientation reversal.)

  1. Rotation 9090^\circ counterclockwise about the origin
  2. Reflection across the line y=xy=x (correct answer)
  3. Reflection across the xx-axis
  4. Uniform scaling by factor 22
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane and how the determinant relates to area scaling. Common 2×2 transformations include rotations (like [0 -1; 1 0] for 90° counterclockwise), reflections (like [1 0; 0 -1] for reflection across the x-axis), and scalings (like [k 0; 0 k] for uniform scaling by factor k). The matrix [0 1; 1 0] has the form of a reflection because the first column [0; 1] and second column [1; 0] swap the standard basis vectors, reflecting across y = x. Choice B is correct because it properly describes the geometric transformation. Choice A incorrectly identifies the transformation as rotation 90° counterclockwise, but the matrix [0 1; 1 0] actually represents reflection across y = x because it swaps coordinates, and det = -1 indicates reflection. To identify a transformation geometrically, see what it does to the standard basis vectors: [1; 0] maps to the first column of A, and [0; 1] maps to the second column, which reveals the transformation's nature (rotation, reflection, scaling, etc.). Common transformations to recognize: [0 -1; 1 0] rotates 90° counterclockwise, [1 0; 0 -1] reflects across x-axis, [-1 0; 0 1] reflects across y-axis, [0 1; 1 0] reflects across y = x, and [k 0; 0 k] scales uniformly by k.

Question 13

Given the transformation matrix F=(1001)F=\begin{pmatrix}1&0\\0&-1\end{pmatrix} applied to vectors by T(v)=FvT(\mathbf{v})=F\mathbf{v}, what is the result of applying FF to (25)\begin{pmatrix}2\\5\end{pmatrix}? (Here det(F)=1\det(F)=-1, so area is preserved but orientation is reversed.)

  1. (25)\begin{pmatrix}-2\\5\end{pmatrix}
  2. (25)\begin{pmatrix}2\\-5\end{pmatrix} (correct answer)
  3. (25)\begin{pmatrix}-2\\-5\end{pmatrix}
  4. (52)\begin{pmatrix}5\\2\end{pmatrix}
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane and how the determinant relates to area scaling. A 2×2 matrix A represents a transformation of the plane: when applied to a point or vector [x; y], it produces a new point/vector [x'; y'] = A[x; y] = [ax+by; cx+dy], effectively moving, rotating, reflecting, or scaling points according to the matrix entries. To transform vector [2; 5] by matrix F = [1 0; 0 -1], we compute [1 0; 0 -1][2; 5] = [12 + 05; 0*2 + (-1)*5] = [2; -5], giving the image [2; -5]. Choice B is correct because it accurately computes the matrix-vector product. Choice A makes an error in the matrix-vector multiplication, calculating perhaps a reflection across y-axis or sign error on both, getting [-2; 5] instead of [2; -5]. Key to plane transformations: apply the matrix to a vector [x; y] by computing [ax+by; cx+dy], and remember that the determinant det(A) = ad - bc tells you about area scaling (|det| is the factor) and orientation (sign indicates preserved or reversed). For area scaling, always use the absolute value: |det(A)| gives the area magnification factor, so if det(A) = -2, areas are scaled by 2 (the absolute value), and the negative sign indicates orientation reversal (a reflection component).

Question 14

A transformation matrix TT maps the parallelogram with vertices (0,0)(0,0), (3,0)(3,0), (1,2)(1,2), (4,2)(4,2) to a new parallelogram with vertices (0,0)(0,0), (6,3)(6,3), (2,4)(-2,4), (4,7)(4,7). What is the absolute value of the determinant of TT?

  1. 22
  2. 33
  3. 66
  4. 55 (correct answer)
Explanation: When you encounter transformation matrices mapping one parallelogram to another, remember that the determinant tells you how the transformation changes areas. The absolute value of the determinant gives the area scaling factor. To find the transformation matrix TT, you need to determine how the basis vectors change. The original parallelogram has sides formed by vectors (3,0)(3,0) and (1,2)(1,2) from the origin. The transformed parallelogram has corresponding sides (6,3)(6,3) and (2,4)(-2,4). Since TT maps (3,0)(6,3)(3,0) \to (6,3) and (1,2)(2,4)(1,2) \to (-2,4), you can find TT by solving what happens to the standard basis vectors. From (1,0)(2,1)(1,0) \mapsto (2,1) and (0,1)(2,4)(0,1) \mapsto (-2,4), the transformation matrix is: The determinant is (2)(4)(2)(1)=8+2=10(2)(4) - (-2)(1) = 8 + 2 = 10, so det(T)=10|\det(T)| = 10. Wait—let me recalculate more carefully. The area of the original parallelogram using vectors (3,0)(3,0) and (1,2)(1,2) is 3201=6|3 \cdot 2 - 0 \cdot 1| = 6. The area of the transformed parallelogram using vectors (6,3)(6,3) and (2,4)(-2,4) is 643(2)=24+6=30|6 \cdot 4 - 3 \cdot (-2)| = |24 + 6| = 30. The area scaling factor is 306=5\frac{30}{6} = 5, which equals det(T)|\det(T)|. Choice (A) 2 and (B) 3 are too small given the significant expansion. Choice (C) 6 incorrectly uses just the original area. Study tip: For transformation problems, you can often find det(T)|\det(T)| by comparing the areas of the original and transformed shapes using the cross product formula for parallelogram area.

Question 15

Two transformation matrices A=(2103)A = \begin{pmatrix} 2 & 1 \\ 0 & 3 \end{pmatrix} and B=(1021)B = \begin{pmatrix} 1 & 0 \\ 2 & 1 \end{pmatrix} are applied to the same original figure. If the area of the figure after transformation AA is 30 square units, what is the area of the figure after transformation BB?

  1. 5 square units (correct answer)
  2. 10 square units
  3. 15 square units
  4. 30 square units
Explanation: det(A)=2(3)1(0)=6\det(A) = 2(3) - 1(0) = 6 and det(B)=1(1)0(2)=1\det(B) = 1(1) - 0(2) = 1. If the original area is SS, then 6S=306S = 30, so S=5S = 5. Under transformation BB, the area becomes 1×5=51 \times 5 = 5 square units. Choice B results from using det(B)=2\det(B) = 2. Choice C results from taking half the area under AA. Choice D incorrectly assumes equal scaling factors.

Question 16

A parallelogram in the coordinate plane has vertices that form vectors u=(31)\vec{u} = \begin{pmatrix} 3 \\ 1 \end{pmatrix} and v=(12)\vec{v} = \begin{pmatrix} 1 \\ 2 \end{pmatrix} as adjacent sides. If this parallelogram is transformed by matrix $$M = \begin{pmatrix} 2 & 1 \ 0 & 3 \end{pmatrix}

  1. 15 square units
  2. 30 square units (correct answer)
  3. 35 square units
  4. 42 square units
Explanation: The original parallelogram has area det(u,v)=3(2)1(1)=61=5|\det(\vec{u}, \vec{v})| = |3(2) - 1(1)| = |6 - 1| = 5. Under transformation MM, the area is scaled by det(M)=2(3)1(0)=6|\det(M)| = |2(3) - 1(0)| = 6. The transformed area is 5×6=305 \times 6 = 30. Choice A uses only the determinant of MM. Choice C adds the original area and scaling factor. Choice D results from incorrect matrix multiplication of the area calculation.

Question 17

First rotate points 9090^\circ counterclockwise using R=(0110),R=\begin{pmatrix}0&-1\\1&0\end{pmatrix}, then reflect across the xx-axis using F=(1001).F=\begin{pmatrix}1&0\\0&-1\end{pmatrix}. What is the combined transformation matrix (apply RR first, then FF)?​

  1. (0110)\begin{pmatrix}0&-1\\-1&0\end{pmatrix} (correct answer)
  2. (0110)\begin{pmatrix}0&1\\1&0\end{pmatrix}
  3. (0110)\begin{pmatrix}0&-1\\1&0\end{pmatrix}
  4. (0110)\begin{pmatrix}0&1\\-1&0\end{pmatrix}
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane. Common 2×2 transformations include rotations (like [0 -1; 1 0] for 90° counterclockwise), reflections (like [1 0; 0 -1] for reflection across the x-axis), and scalings (like [k 0; 0 k] for uniform scaling by factor k). For composition, applying R first then F gives the matrix FR = [1 0; 0 -1] [0 -1; 1 0] = [0 -1; -1 0], as calculated by matrix multiplication. Choice A is correct because it accurately computes the matrix product in the correct order. Choice C uses the wrong order for composition, computing RF when the correct order is FR. For composition of transformations, remember the order: 'apply A then B' is written B(Av) = (BA)v, with the matrix applied first written on the right—this is backward from reading left to right. Key to plane transformations: apply the matrix to a vector [x; y] by computing [ax+by; cx+dy], and remember that the determinant det(A) = ad - bc tells you about area scaling (|det| is the factor) and orientation (sign indicates preserved or reversed).

Question 18

A transformation matrix has the property that it maps the unit square (with vertices at (0,0)(0,0), (1,0)(1,0), (1,1)(1,1), (0,1)(0,1)) to a parallelogram with vertices at (0,0)(0,0), (2,1)(2,1), (1,4)(1,4), (1,3)(-1,3). What is the determinant of this transformation matrix?

  1. 77 (correct answer)
  2. 7-7
  3. 99
  4. 9-9
Explanation: The transformation matrix maps (1,0)(2,1)(1,0) \to (2,1) and (0,1)(1,3)(0,1) \to (-1,3), so the matrix is (2113)\begin{pmatrix} 2 & -1 \\ 1 & 3 \end{pmatrix}. The determinant is 2(3)(1)(1)=6+1=72(3) - (-1)(1) = 6 + 1 = 7. We can verify: the parallelogram has adjacent sides u=(2,1)\vec{u} = (2,1) and v=(1,3)\vec{v} = (-1,3), giving area 2(3)1(1)=7|2(3) - 1(-1)| = 7. Choice B has the wrong sign. Choices C and D result from incorrectly identifying the transformation vectors.

Question 19

For the transformation matrix A=(01\10)A=\begin{pmatrix}0&1\1&0\end{pmatrix} , which swaps coordinates of each point, what is the determinant det(A)\det(A) and what does its sign indicate about orientation?

  1. det(A)=1\det(A)=1, orientation preserved
  2. det(A)=1\det(A)=-1, orientation reversed (correct answer)
  3. det(A)=0\det(A)=0, collapses to a line
  4. det(A)=1\det(A)=-1, orientation preserved
Explanation: This question tests understanding of how 2×22 \times 2 matrices act as transformations of the coordinate plane and how the determinant relates to area scaling. The determinant of a 2×22 \times 2 transformation matrix AA represents the area scaling factor: if det(A)=k\det(A) = k, then the transformation scales all areas by a factor of k|k| (the absolute value), with positive determinant preserving orientation and negative determinant reversing it (indicating a reflection). For matrix A=(0110)A = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}, we calculate det(A)=0011=01=1\det(A) = 0*0 - 1*1 = 0 - 1 = -1. This means the transformation scales all areas by a factor of 1=1|-1| = 1, so a region with area 1 would transform to area 1. Since det(A)=1\det(A) = -1 is negative, the transformation reverses orientation: if you traverse a region counterclockwise before transformation, you traverse clockwise after, indicating a reflection is involved. Choice B is correct because it correctly calculates the determinant. Choice D claims the transformation preserves orientation when det(A)=1\det(A) = -1, but positive determinant means orientation preserved and negative means reversed.

Question 20

Given the transformation matrix S=(3001)S=\begin{pmatrix}3&0\\0&1\end{pmatrix} acting on the plane by T(v)=SvT(\mathbf{v})=S\mathbf{v}, how does this transformation affect areas? (Use det(S)|\det(S)| as the area scaling factor.)

  1. Areas are scaled by a factor of 11.
  2. Areas are scaled by a factor of 33. (correct answer)
  3. Areas are scaled by a factor of 3\sqrt{3}.
  4. Areas are scaled by a factor of 99.
Explanation: This question tests understanding of how 2×2 matrices act as transformations of the coordinate plane and how the determinant relates to area scaling. The determinant of a 2×2 transformation matrix A represents the area scaling factor: if det(A) = k, then the transformation scales all areas by a factor of |k| (the absolute value), with positive determinant preserving orientation and negative determinant reversing it (indicating a reflection). For matrix S = [3 0; 0 1], we calculate det(S) = 31 - 00 = 3. This means the transformation scales all areas by a factor of |det(S)| = |3| = 3, so a region with area 1 would transform to area 3. Choice B is correct because it correctly identifies |det(S)| as the area scaling factor. Choice A uses det(S) instead of |det(S)| for the area scaling factor, but area magnification is the absolute value of the determinant (areas can't be negative). For area scaling, always use the absolute value: |det(A)| gives the area magnification factor, so if det(A) = -2, areas are scaled by 2 (the absolute value), and the negative sign indicates orientation reversal (a reflection component). Common transformations to recognize: [0 -1; 1 0] rotates 90° counterclockwise, [1 0; 0 -1] reflects across x-axis, [-1 0; 0 1] reflects across y-axis, [0 1; 1 0] reflects across y = x, and [k 0; 0 k] scales uniformly by k.