Study Graphing Functions in PSAT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: What does the vertical line test determine for a graph in the coordinate plane? Answer: Whether the graph represents a function. Functions have at most one y-value per x-value.
Flashcard 2: Identify the domain of the rational function y = 1 x − a y=\frac{1}{x-a} y = x − a 1 for constant a a a . Answer: All real x x x except x ≠ a x\ne a x = a . Division by zero is undefined, excluding x = a x=a x = a from the domain.
Flashcard 3: What is the range of a function f f f as shown on its graph? Answer: All y y y -values of points on the graph. The vertical extent of the graph shows all possible outputs.
Flashcard 4: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with − f ( x ) -f(x) − f ( x ) ? Answer: Reflect across the x x x -axis. Negating outputs flips all y y y -values to opposite signs.
Flashcard 5: Identify the slope and y y y -intercept of y = − 3 x + 5 y=-3x+5 y = − 3 x + 5 . Answer: Slope − 3 -3 − 3 ; y y y -intercept ( 0 , 5 ) (0,5) ( 0 , 5 ) . Read directly from y = m x + b y=mx+b y = m x + b form: m = − 3 m=-3 m = − 3 , b = 5 b=5 b = 5 .
Flashcard 6: Identify the transformation: y = f ( − x ) y=f(-x) y = f ( − x ) compared to y = f ( x ) y=f(x) y = f ( x ) . Answer: Reflection across the y y y -axis. Negative input flips all points horizontally across the y y y -axis.
Flashcard 7: What is the y y y -intercept of the line y = − 2 x + 7 y=-2x+7 y = − 2 x + 7 ? Answer: ( 0 , 7 ) (0,7) ( 0 , 7 ) . Substitute x = 0 x=0 x = 0 : y = − 2 ( 0 ) + 7 = 7 y=-2(0)+7=7 y = − 2 ( 0 ) + 7 = 7 .
Flashcard 8: Identify the transformation: y = a f ( x ) y=af(x) y = a f ( x ) for a > 1 a>1 a > 1 compared to y = f ( x ) y=f(x) y = f ( x ) . Answer: Vertical stretch by factor a a a . Multiplying output by a > 1 a>1 a > 1 stretches graph vertically.
Flashcard 9: What is the definition of the y y y -intercept of a graph of y = f ( x ) y=f(x) y = f ( x ) ? Answer: The point where x = 0 x=0 x = 0 , so y = f ( 0 ) y=f(0) y = f ( 0 ) . The y y y -intercept occurs where the graph crosses the y y y -axis.
Flashcard 10: Identify the domain and range of the parent function y = x y=\sqrt{x} y = x . Answer: Domain: x ≥ 0 x\ge 0 x ≥ 0 ; Range: y ≥ 0 y\ge 0 y ≥ 0 . Square root requires non-negative input and produces non-negative output.
Flashcard 11: What is the vertical line test used to determine when a graph represents y y y as a function of x x x ? Answer: No vertical line intersects the graph more than once. Functions have only one y y y -value per x x x -value.
Flashcard 12: What transformation occurs to y = f ( x ) y=f(x) y = f ( x ) when graphing y = f ( x ) + k y=f(x)+k y = f ( x ) + k for constant k k k ? Answer: Vertical shift by k k k units (up if k > 0 k>0 k > 0 , down if k < 0 k<0 k < 0 ). Adding k k k to outputs shifts the entire graph vertically.
Flashcard 13: What transformation does y = − f ( x ) y=-f(x) y = − f ( x ) represent on the graph of y = f ( x ) y=f(x) y = f ( x ) ? Answer: Reflection across the x x x -axis. Negating the output flips all y y y -values across the x x x -axis.
Flashcard 14: What transformation occurs to y = f ( x ) y=f(x) y = f ( x ) when graphing y = f ( x − h ) y=f(x-h) y = f ( x − h ) for constant h h h ? Answer: Horizontal shift by h h h units (right if h > 0 h>0 h > 0 , left if h < 0 h<0 h < 0 ). Subtracting h h h from inputs shifts the graph horizontally.
Flashcard 15: What is the axis of symmetry of y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k ? Answer: The vertical line x = h x=h x = h . Parabolas are symmetric about the vertical line through the vertex.
Flashcard 16: What is the axis of symmetry for y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k ? Answer: x = h x=h x = h . Vertical line through vertex where parabola folds.
Flashcard 17: What is the vertical line test for deciding whether a graph represents a function? Answer: A graph is a function if every vertical line hits it at most once. Functions have only one y y y -value per x x x -value.
Flashcard 18: For y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k , what is the axis of symmetry? Answer: Axis of symmetry is x = h x=h x = h . The parabola is symmetric about the vertical line through vertex.
Flashcard 19: What transformation occurs to y = f ( x ) y=f(x) y = f ( x ) when graphing y = f ( − x ) y=f(-x) y = f ( − x ) ? Answer: Reflection across the y y y -axis. Negating inputs flips the graph left-to-right.
Flashcard 20: What is the slope between points ( x 1 , y 1 ) (x_1,y_1) ( x 1 , y 1 ) and ( x 2 , y 2 ) (x_2,y_2) ( x 2 , y 2 ) on a graph? Answer: rac{y_2-y_1}{x_2-x_1} . Slope equals rise over run: change in y y y divided by change in x x x .
Flashcard 21: What are the vertical and horizontal asymptotes of y = 1 x − a y=\frac{1}{x-a} y = x − a 1 ? Answer: Vertical: x = a x=a x = a ; Horizontal: y = 0 y=0 y = 0 . The function approaches these lines but never reaches them.
Flashcard 22: What is the y y y -intercept of the line given by y = m x + b y=mx+b y = m x + b ? Answer: The point ( 0 , b ) (0,b) ( 0 , b ) . When x = 0 x=0 x = 0 , y = m ( 0 ) + b = b y=m(0)+b=b y = m ( 0 ) + b = b , giving the point ( 0 , b ) (0,b) ( 0 , b ) .
Flashcard 23: What is the definition of an x x x -intercept of a function y = f ( x ) y=f(x) y = f ( x ) on its graph? Answer: A point where y = 0 y=0 y = 0 , so it satisfies f ( x ) = 0 f(x)=0 f ( x ) = 0 . The x x x -intercept occurs where the graph crosses the x x x -axis.
Flashcard 24: What does it mean on a graph if ( a , b ) (a,b) ( a , b ) lies on y = f ( x ) y=f(x) y = f ( x ) ? Answer: f ( a ) = b f(a)=b f ( a ) = b . The point satisfies the function equation.
Flashcard 25: Find the y y y -intercept of f ( x ) = 2 x 2 − 3 x + 4 f(x)=2x^2-3x+4 f ( x ) = 2 x 2 − 3 x + 4 . Answer: ( 0 , 4 ) (0,4) ( 0 , 4 ) . Substitute x = 0 x=0 x = 0 : f ( 0 ) = 2 ( 0 ) 2 − 3 ( 0 ) + 4 = 4 f(0)=2(0)^2-3(0)+4=4 f ( 0 ) = 2 ( 0 ) 2 − 3 ( 0 ) + 4 = 4 .
Flashcard 26: What is the definition of an x x x -intercept (zero) of y = f ( x ) y=f(x) y = f ( x ) ? Answer: Any x x x where f ( x ) = 0 f(x)=0 f ( x ) = 0 , giving a point ( x , 0 ) (x,0) ( x , 0 ) . Zeros occur where the graph crosses the x x x -axis.
Flashcard 27: What is the axis of symmetry of the parabola y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k ? Answer: The vertical line x = h x=h x = h . Parabolas are symmetric about the vertical line through vertex.
Flashcard 28: Identify the end behavior of y = x 2 y=x^2 y = x 2 as x → ± ∞ x\to\pm\infty x → ± ∞ . Answer: y → ∞ y\to\infty y → ∞ as x → ∞ x\to\infty x → ∞ and as x → − ∞ x\to-\infty x → − ∞ . The parabola opens upward, so both ends go to infinity.
Flashcard 29: What is the range of a function given its graph? Answer: All y y y -values attained by points on the graph. The range includes all y y y -coordinates that appear on the graph.
Flashcard 30: What is the definition of the x x x -intercept of a graph of y = f ( x ) y=f(x) y = f ( x ) ? Answer: A point where y = 0 y=0 y = 0 , so f ( x ) = 0 f(x)=0 f ( x ) = 0 . The x x x -intercept occurs where the graph crosses the x x x -axis.
Flashcard 31: Identify the vertex of y = ( x − 4 ) 2 − 7 y=(x-4)^2-7 y = ( x − 4 ) 2 − 7 . Answer: ( 4 , − 7 ) (4,-7) ( 4 , − 7 ) . In vertex form y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k , vertex is ( h , k ) (h,k) ( h , k ) .
Flashcard 32: What does it mean for a relation to be a function in terms of x x x -values and outputs? Answer: Each x x x -value corresponds to exactly one output y y y . This is the definition of a function - no two outputs for one input.
Flashcard 33: What is the y y y -intercept of y = f ( x ) y=f(x) y = f ( x ) in terms of f f f ? Answer: The point ( 0 , f ( 0 ) ) (0, f(0)) ( 0 , f ( 0 )) . Occurs where the graph crosses the y y y -axis, when x = 0 x=0 x = 0 .
Flashcard 34: What is the definition of the y y y -intercept of a function y = f ( x ) y=f(x) y = f ( x ) on its graph? Answer: The point where x = 0 x=0 x = 0 , so the intercept is ( 0 , f ( 0 ) ) (0,f(0)) ( 0 , f ( 0 )) . The y y y -intercept occurs where the graph crosses the y y y -axis.
Flashcard 35: What is the slope-intercept form of a linear function and what does each parameter represent? Answer: y = m x + b y=mx+b y = m x + b ; slope m m m , y y y -intercept b b b . Linear graphs have constant slope m m m and cross y y y -axis at ( 0 , b ) (0,b) ( 0 , b ) .
Flashcard 36: What is the x x x -intercept of y = x − 7 y=x-7 y = x − 7 ? Answer: ( 7 , 0 ) (7,0) ( 7 , 0 ) . Set y = 0 y=0 y = 0 : 0 = x − 7 0=x-7 0 = x − 7 gives x = 7 x=7 x = 7 , so the intercept is ( 7 , 0 ) (7,0) ( 7 , 0 ) .
Flashcard 37: Identify the vertical asymptote of f(x)=rac{3}{x+5} . Answer: x = − 5 x=-5 x = − 5 . The function approaches infinity when the denominator x + 5 = 0 x+5=0 x + 5 = 0 .
Flashcard 38: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with a f ( x ) a f(x) a f ( x ) for a > 1 a>1 a > 1 ? Answer: Vertical stretch by factor a a a . Multiplying outputs by a > 1 a>1 a > 1 stretches graph away from x x x -axis.
Flashcard 39: Identify the axis of symmetry of y = − 2 ( x + 3 ) 2 + 1 y=-2(x+3)^2+1 y = − 2 ( x + 3 ) 2 + 1 . Answer: x = − 3 x=-3 x = − 3 . Axis passes through vertex; here h = − 3 h=-3 h = − 3 gives x = − 3 x=-3 x = − 3 .
Flashcard 40: What is the definition of the y y y -intercept of a function's graph? Answer: The point where x = 0 x=0 x = 0 , so y = f ( 0 ) y=f(0) y = f ( 0 ) . The y y y -intercept occurs where the graph crosses the y y y -axis.
Flashcard 41: Identify the transformation: y = f ( x − k ) y=f(x-k) y = f ( x − k ) compared to y = f ( x ) y=f(x) y = f ( x ) . Answer: Horizontal shift right k k k units. Subtracting k k k from input shifts graph right (opposite direction).
Flashcard 42: What is the effect on the graph of y = − f ( x ) y=-f(x) y = − f ( x ) ? Answer: Reflection across the x x x -axis. Negating outputs flips the graph over the x x x -axis.
Flashcard 43: What is the effect on the graph of y = f ( x ) + k y=f(x)+k y = f ( x ) + k for a constant k k k ? Answer: Vertical shift up k k k units. Adding k k k to outputs moves the graph up k k k units.
Flashcard 44: Identify the vertex of the parabola y = ( x − 3 ) 2 − 5 y=(x-3)^2-5 y = ( x − 3 ) 2 − 5 . Answer: ( 3 , − 5 ) (3,-5) ( 3 , − 5 ) . In vertex form, ( h , k ) = ( 3 , − 5 ) (h,k)=(3,-5) ( h , k ) = ( 3 , − 5 ) directly.
Flashcard 45: Identify the transformation: y = − f ( x ) y=-f(x) y = − f ( x ) compared to y = f ( x ) y=f(x) y = f ( x ) . Answer: Reflection across the x x x -axis. Negative sign flips all y y y -values across the x x x -axis.
Flashcard 46: Find the x x x -intercept of y = 2 x − 8 y=2x-8 y = 2 x − 8 as a point on the coordinate plane. Answer: ( 4 , 0 ) (4,0) ( 4 , 0 ) . Set y = 0 y=0 y = 0 : 0 = 2 x − 8 0=2x-8 0 = 2 x − 8 , so x = 4 x=4 x = 4 .
Flashcard 47: What transformation does y = a f ( x ) y=af(x) y = a f ( x ) represent for a > 1 a>1 a > 1 compared to y = f ( x ) y=f(x) y = f ( x ) ? Answer: Vertical stretch by factor a a a . Multiplying output by a > 1 a>1 a > 1 stretches the graph vertically.
Flashcard 48: What is the meaning of the range of a function y = f ( x ) y=f(x) y = f ( x ) from its graph? Answer: All y y y -values attained by points on the graph. Range is the set of possible output values.
Flashcard 49: What does the vertical line test determine for a graph in the x y xy x y -plane? Answer: Whether the graph represents a function of x x x . If any vertical line crosses more than once, it's not a function.
Flashcard 50: What is the vertical line test used to determine about a graph? Answer: Whether the graph represents a function of x x x . A function has at most one y y y -value for each x x x -value.
Flashcard 51: What is the location of the vertex of y = ( x − 3 ) 2 − 5 y=(x-3)^2-5 y = ( x − 3 ) 2 − 5 ? Answer: ( 3 , − 5 ) (3,-5) ( 3 , − 5 ) . In vertex form ( x − h ) 2 + k (x-h)^2+k ( x − h ) 2 + k , the vertex is at ( h , k ) (h,k) ( h , k ) .
Flashcard 52: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with f ( x ) + k f(x)+k f ( x ) + k ? Answer: Shift up k k k units. Adding k k k to outputs increases all y y y -values by k k k .
Flashcard 53: What are the x x x -intercepts of y = f ( x ) y=f(x) y = f ( x ) in terms of an equation involving f f f ? Answer: Solutions to f ( x ) = 0 f(x)=0 f ( x ) = 0 , written as points ( x , 0 ) (x,0) ( x , 0 ) . These are where the graph crosses the x x x -axis.
Flashcard 54: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with f ( x − h ) f(x-h) f ( x − h ) ? Answer: Shift right h h h units. Replacing x x x with x − h x-h x − h delays the function by h h h units.
Flashcard 55: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with f ( a x ) f(ax) f ( a x ) for a > 1 a>1 a > 1 ? Answer: Horizontal compression by factor a a a . Multiplying inputs by a > 1 a>1 a > 1 squeezes horizontally.
Flashcard 56: What is the vertex of y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k ? Answer: Vertex is ( h , k ) (h,k) ( h , k ) . The parabola's turning point is at these coordinates.
Flashcard 57: What is the slope of a line passing through ( x 1 , y 1 ) (x_1,y_1) ( x 1 , y 1 ) and ( x 2 , y 2 ) (x_2,y_2) ( x 2 , y 2 ) ? Answer: m=rac{y_2-y_1}{x_2-x_1} . This formula gives the rate of change between two points.
Flashcard 58: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with a f ( x ) af(x) a f ( x ) for a > 1 a>1 a > 1 ? Answer: Vertical stretch by factor a a a . Multiplying outputs by a > 1 a>1 a > 1 stretches vertically.
Flashcard 59: What is the effect on the graph of y = f ( x ) y=f(x) y = f ( x ) when graphing y = f ( − x ) y=f(-x) y = f ( − x ) ? Answer: Reflect across the y y y -axis. Replacing x x x with − x -x − x flips all points horizontally.
Flashcard 60: Identify the y y y -intercept of f ( x ) = 3 x − 5 f(x)=3x-5 f ( x ) = 3 x − 5 . Answer: ( 0 , − 5 ) (0,-5) ( 0 , − 5 ) . Substitute x = 0 x=0 x = 0 : f ( 0 ) = 3 ( 0 ) − 5 = − 5 f(0)=3(0)-5=-5 f ( 0 ) = 3 ( 0 ) − 5 = − 5 .
Flashcard 61: What transformation does y = f ( − x ) y=f(-x) y = f ( − x ) represent on the graph of y = f ( x ) y=f(x) y = f ( x ) ? Answer: Reflection across the y y y -axis. Negating the input flips all x x x -values across the y y y -axis.
Flashcard 62: Identify the vertex form of a quadratic and state its vertex in terms of h h h and k k k . Answer: y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k ; vertex is ( h , k ) (h,k) ( h , k ) . This form directly shows the parabola's turning point.
Flashcard 63: What is the meaning of a a a in y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k for the parabola's opening? Answer: a > 0 a>0 a > 0 opens up; a < 0 a<0 a < 0 opens down. Sign of a a a determines if parabola opens upward or downward.
Flashcard 64: What transformation does y = f ( x ) + k y=f(x)+k y = f ( x ) + k represent on the graph of y = f ( x ) y=f(x) y = f ( x ) ? Answer: A vertical shift up k k k units (down if k < 0 k<0 k < 0 ). Adding k k k to the output shifts every point up by k k k units.
Flashcard 65: Identify the transformation in y = − f ( x ) y=-f(x) y = − f ( x ) relative to y = f ( x ) y=f(x) y = f ( x ) . Answer: Reflection across the x x x -axis. Negative sign flips all y-values across the x-axis.
Flashcard 66: What are the x x x -intercepts of y = ( x − 1 ) ( x + 4 ) y=(x-1)(x+4) y = ( x − 1 ) ( x + 4 ) ? Answer: ( − 4 , 0 ) (-4,0) ( − 4 , 0 ) and ( 1 , 0 ) (1,0) ( 1 , 0 ) . Set y = 0 y=0 y = 0 and solve: ( x − 1 ) ( x + 4 ) = 0 (x-1)(x+4)=0 ( x − 1 ) ( x + 4 ) = 0 gives x = 1 x=1 x = 1 or x = − 4 x=-4 x = − 4 .
Flashcard 67: What does it mean for a function to be increasing on an interval? Answer: As x x x increases, f ( x ) f(x) f ( x ) increases on that interval. The graph rises from left to right.
Flashcard 68: Identify the axis of symmetry of y = − 2 ( x + 1 ) 2 + 7 y=-2(x+1)^2+7 y = − 2 ( x + 1 ) 2 + 7 . Answer: Axis of symmetry is x = − 1 x=-1 x = − 1 . In vertex form, h = − 1 h=-1 h = − 1 so axis of symmetry is x = − 1 x=-1 x = − 1 .
Flashcard 69: Identify the y y y -intercept of y = 3 x − 4 y=3x-4 y = 3 x − 4 . Answer: y y y -intercept is ( 0 , − 4 ) (0,-4) ( 0 , − 4 ) . Substitute x = 0 x=0 x = 0 : y = 3 ( 0 ) − 4 = − 4 y=3(0)-4=-4 y = 3 ( 0 ) − 4 = − 4 .
Flashcard 70: Identify the vertex of y = ( x − 4 ) 2 + 7 y=(x-4)^2+7 y = ( x − 4 ) 2 + 7 . Answer: ( 4 , 7 ) (4,7) ( 4 , 7 ) . In vertex form ( x − h ) 2 + k (x-h)^2+k ( x − h ) 2 + k , vertex is ( h , k ) (h,k) ( h , k ) .
Flashcard 71: Identify the x x x -intercept of y = 2 x + 6 y=2x+6 y = 2 x + 6 . Answer: x x x -intercept is ( − 3 , 0 ) (-3,0) ( − 3 , 0 ) . Set y = 0 y=0 y = 0 and solve: 0 = 2 x + 6 0=2x+6 0 = 2 x + 6 , so x = − 3 x=-3 x = − 3 .
Flashcard 72: Identify the domain of f(x)=rac{1}{x-2} . Answer: All real x x x with x ≠ 2 x\ne 2 x = 2 . The function is undefined when the denominator equals zero at x = 2 x=2 x = 2 .
Flashcard 73: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with f ( x + h ) f(x+h) f ( x + h ) ? Answer: Shift left h h h units. Replacing x x x with x + h x+h x + h advances the function by h h h units.
Flashcard 74: Identify the y y y -intercept of the line y = − 3 x + 7 y=-3x+7 y = − 3 x + 7 as an ordered pair. Answer: ( 0 , 7 ) (0,7) ( 0 , 7 ) . When x = 0 x=0 x = 0 , y = − 3 ( 0 ) + 7 = 7 y=-3(0)+7=7 y = − 3 ( 0 ) + 7 = 7 .
Flashcard 75: For y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k , what are the vertex coordinates? Answer: Vertex is ( h , k ) (h,k) ( h , k ) . The parabola's turning point is shifted to ( h , k ) (h,k) ( h , k ) from origin.
Flashcard 76: Find the slope of the line passing through ( 2 , 5 ) (2,5) ( 2 , 5 ) and ( 6 , 1 ) (6,1) ( 6 , 1 ) . Answer: m = − 1 m=-1 m = − 1 . Using slope formula: rac{1-5}{6-2}=rac{-4}{4}=-1 .
Flashcard 77: What is the domain of a function f f f as shown on its graph? Answer: All x x x -values of points on the graph. The horizontal extent of the graph shows all possible inputs.
Flashcard 78: What is the domain of f ( x ) = x − 5 f(x)=\sqrt{x-5} f ( x ) = x − 5 ? Answer: x ≥ 5 x\ge 5 x ≥ 5 . Square roots require non-negative inputs: x − 5 ≥ 0 x-5\ge 0 x − 5 ≥ 0 .
Flashcard 79: What transformation does y = f ( a x ) y=f(ax) y = f ( a x ) represent for a > 1 a>1 a > 1 compared to y = f ( x ) y=f(x) y = f ( x ) ? Answer: Horizontal compression by factor a a a (scale factor rac{1}{a} ). Multiplying input by a > 1 a>1 a > 1 compresses the graph horizontally.
Flashcard 80: What is the domain of a function given its graph? Answer: All x x x -values for which the graph has at least one point. The domain includes all x x x -coordinates that appear on the graph.
Flashcard 81: What is the effect on the graph of y = f ( x ) y=f(x) y = f ( x ) when graphing y = f ( x ) + k y=f(x)+k y = f ( x ) + k ? Answer: Shift up k k k units (down if k < 0 k<0 k < 0 ). Adding k k k to the output shifts the entire graph vertically.
Flashcard 82: What is the slope of the line given by y = m x + b y=mx+b y = m x + b ? Answer: Slope is m m m . In slope-intercept form, the coefficient of x x x is the slope.
Flashcard 83: What is the domain of a function in a graphing context? Answer: All x x x -values for which f ( x ) f(x) f ( x ) is defined. The horizontal extent of the graph.
Flashcard 84: What is the definition of the y y y -intercept of a function y = f ( x ) y=f(x) y = f ( x ) on its graph? Answer: The point where x = 0 x=0 x = 0 , which is ( 0 , f ( 0 ) ) (0,f(0)) ( 0 , f ( 0 )) . The y-intercept occurs when the input variable equals zero.
Flashcard 85: What is the effect on the graph of y = f ( x ) y=f(x) y = f ( x ) when graphing y = a f ( x ) y=af(x) y = a f ( x ) for a > 1 a>1 a > 1 ? Answer: Vertical stretch by factor a a a . Multiplying output by a > 1 a>1 a > 1 stretches graph away from x x x -axis.
Flashcard 86: What is the effect on the graph of y = f ( x − k ) y=f(x-k) y = f ( x − k ) for a constant k k k ? Answer: Horizontal shift right k k k units. Subtracting k k k from inputs shifts right k k k units.
Flashcard 87: What is the vertex form of a parabola, and what point is the vertex? Answer: y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k with vertex ( h , k ) (h,k) ( h , k ) . This form makes the vertex coordinates immediately visible.
Flashcard 88: What is the effect on the graph of y = f ( a x ) y=f(ax) y = f ( a x ) when a > 1 a>1 a > 1 ? Answer: Horizontal compression by factor a a a . Multiplying inputs by a > 1 a>1 a > 1 compresses horizontally.
Flashcard 89: What is the slope-intercept form of a line, and what do m m m and b b b represent? Answer: y = m x + b y=mx+b y = m x + b ; m m m is slope and b b b is the y y y -intercept. Standard form showing slope and where line crosses y y y -axis.
Flashcard 90: What is the slope-intercept form of a line, and what do its parameters represent? Answer: y = m x + b y=mx+b y = m x + b ; m m m is slope and b b b is the y y y -intercept. This form directly shows how the line rises and where it crosses the y y y -axis.
Flashcard 91: What is the slope of the line given by y = m x + b y=mx+b y = m x + b ? Answer: Slope is m m m . In slope-intercept form, the coefficient of x x x is the slope.
Flashcard 92: What is the effect on the graph of y = a f ( x ) y=af(x) y = a f ( x ) when a > 1 a>1 a > 1 ? Answer: Vertical stretch by factor a a a . Multiplying outputs by a > 1 a>1 a > 1 stretches vertically.
Flashcard 93: Identify the vertex of y = ( x − 3 ) 2 − 5 y=(x-3)^2-5 y = ( x − 3 ) 2 − 5 . Answer: Vertex is ( 3 , − 5 ) (3,-5) ( 3 , − 5 ) . Compare to y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k to identify h = 3 h=3 h = 3 and k = − 5 k=-5 k = − 5 .
Flashcard 94: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with f ( x ) − k f(x)-k f ( x ) − k ? Answer: Shift down k k k units. Subtracting k k k from outputs decreases all y y y -values by k k k .
Flashcard 95: Identify the transformation in y = f ( − x ) y=f(-x) y = f ( − x ) relative to y = f ( x ) y=f(x) y = f ( x ) . Answer: Reflection across the y y y -axis. Negating input flips all x-values across the y-axis.
Flashcard 96: Identify the vertex of y = ( x − 3 ) 2 + 5 y=(x-3)^2+5 y = ( x − 3 ) 2 + 5 . Answer: ( 3 , 5 ) (3,5) ( 3 , 5 ) . Vertex form y = ( x − h ) 2 + k y=(x-h)^2+k y = ( x − h ) 2 + k has vertex at ( h , k ) (h,k) ( h , k ) .
Flashcard 97: What is the y y y -intercept of y = f ( x ) y=f(x) y = f ( x ) in terms of function notation (when it exists)? Answer: The point ( 0 , f ( 0 ) ) (0,f(0)) ( 0 , f ( 0 )) . Found by substituting x = 0 x=0 x = 0 into the function.
Flashcard 98: What is the definition of the graph of a function y = f ( x ) y=f(x) y = f ( x ) in the coordinate plane? Answer: The set of all points ( x , f ( x ) ) (x,f(x)) ( x , f ( x )) for allowed x x x . Each input x x x maps to exactly one output point ( x , f ( x ) ) (x,f(x)) ( x , f ( x )) .
Flashcard 99: Find the slope of the line through ( 2 , 1 ) (2,1) ( 2 , 1 ) and ( 6 , 9 ) (6,9) ( 6 , 9 ) . Answer: m = 2 m=2 m = 2 . Using slope formula: m = 9 − 1 6 − 2 = 8 4 = 2 m=\frac{9-1}{6-2}=\frac{8}{4}=2 m = 6 − 2 9 − 1 = 4 8 = 2 .
Flashcard 100: What is the effect on the graph of replacing f ( x ) f(x) f ( x ) with f ( x − k ) f(x-k) f ( x − k ) ? Answer: Horizontal shift right k k k units. Subtracting k k k from inputs shifts the graph right.