Place Value and Properties of Operations to Add and Subtract - 1st Grade Math

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Question

Add:

$\frac{\begin{array}[b]{r}51\ +\ 12\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}5{\color{Red} 1}\ +\ 1{\color{Red} 2}\end{array}}{ \ \ \ \ \ \space3}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 5}1\ +\ {\color{Red} 1}2\end{array}}{ \ \ \ \ \space63}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}22\ +\ 34\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}2{\color{Red} 2}\ +\ 3{\color{Red} 4}\end{array}}{ \ \ \ \ \ \space6}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 2}2\ +\ {\color{Red} 3}4\end{array}}{ \ \ \ \space56}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}37\ +\ 31\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}3{\color{Red} 7}\ +\ 3{\color{Red} 1}\end{array}}{ \ \ \ \ \ \space8}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 3}7\ +\ {\color{Red} 3}1\end{array}}{ \ \ \ \space68}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}43\ +\ 15\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}4{\color{Red} 3}\ +\ 1{\color{Red} 5}\end{array}}{ \ \ \ \ \ \space8}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 4}3\ +\ {\color{Red} 1}5\end{array}}{ \ \ \ \space58}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}13\ +\ 76\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}1{\color{Red} 3}\ +\ 7{\color{Red} 6}\end{array}}{ \ \ \ \ \ \space9}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 1}3\ +\ {\color{Red} 7}6\end{array}}{ \ \ \ \space89}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}19\ +\ 30\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}1{\color{Red} 9}\ +\ 3{\color{Red} 0}\end{array}}{ \ \ \ \ \ \space9}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 1}9\ +\ {\color{Red} 3}0\end{array}}{ \ \ \ \space49}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}27\ +\ 62\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}2{\color{Red} 7}\ +\ 6{\color{Red} 2}\end{array}}{ \ \ \ \ \ \space9}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 2}7\ +\ {\color{Red} 6}2\end{array}}{ \ \ \ \space89}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}42\ +\ 36\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}4{\color{Red} 2}\ +\ 3{\color{Red} 6}\end{array}}{ \ \ \ \ \ \space8}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 3}7\ +\ {\color{Red} 3}1\end{array}}{ \ \ \ \space78}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}11\ +\ 46\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}1{\color{Red} 1}\ +\ 4{\color{Red} 6}\end{array}}{ \ \ \ \ \ \space7}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 1}1\ +\ {\color{Red} 4}6\end{array}}{ \ \ \ \space57}$

The final answer is

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Question

Solve the following:

$\frac{\begin{array}[b]{r}18\ +\ 51\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}1{\color{Red} 8}\ +\ 5{\color{Red} 1}\end{array}}{ \ \ \ \ \ \space9}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 1}8\ +\ {\color{Red} 5}1\end{array}}{ \ \ \ \space69}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}22\ +\ 13\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}2{\color{Red} 2}\ +\ 1{\color{Red} 3}\end{array}}{ \ \ \ \ \ \space5}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 2}2\ +\ {\color{Red} 1}3\end{array}}{ \ \ \ \space35}$

The final answer is

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Question

Add:

$\frac{\begin{array}[b]{r}36\ +\ 11\end{array}}{ \ \ \space}$

Answer

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}3{\color{Red} 6}\ +\ 1{\color{Red} 1}\end{array}}{ \ \ \ \ \ \space7}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 3}6\ +\ {\color{Red} 1}1\end{array}}{ \ \ \ \space47}$

The final answer is

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Question

$\frac{\begin{array}[b]{r}15\ +\ 10\end{array}}{ \ \ \space}$

Answer

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}15\ +\ 10\end{array}}{ \ \ \ \ \space25}$

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Question

$\frac{\begin{array}[b]{r}10\ +\ 10\end{array}}{ \ \ \space}$

Answer

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}10\ +\ 10\end{array}}{ \ \ \ \space20}$

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Question

$\frac{\begin{array}[b]{r}20\ +\ 10\end{array}}{ \ \ \space}$

Answer

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}20\ +\ 10\end{array}}{ \ \ \ \space30}$

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Question

$\frac{\begin{array}[b]{r}25\ +\ 10\end{array}}{ \ \ \space}$

Answer

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}25\ +\ 10\end{array}}{ \ \ \ \space35}$

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Question

$\frac{\begin{array}[b]{r}30\ +\ 10\end{array}}{ \ \ \space}$

Answer

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}20\ +\ 10\end{array}}{ \ \ \ \space40}$

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Question

$\frac{\begin{array}[b]{r}35\ +\ 10\end{array}}{ \ \ \space}$

Answer

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}35\ +\ 10\end{array}}{ \ \ \ \space45}$

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Question

$\frac{\begin{array}[b]{r}40\ +\ 10\end{array}}{ \ \ \space}$

Answer

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}40\ +\ 10\end{array}}{ \ \ \ \space50}$

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Question

$\frac{\begin{array}[b]{r}45\ +\ 10\end{array}}{ \ \ \space}$

Answer

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}45\ +\ 10\end{array}}{ \ \ \ \space55}$

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