Use place value understanding and properties of operations to perform multi-digit arithmetic - 4th Grade Math

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Question

Solve $3{\overline{\smash{)}27}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$27\div3=9$

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Question

Solve $3{\overline{\smash{)}18}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$18\div3=6$

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Question

Solve $4{\overline{\smash{)}48}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$48\div4=12$

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Question

Solve $4{\overline{\smash{)}52}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$52\div4=13$

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Question

Solve $5{\overline{\smash{)}45}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$45\div5=9$

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Question

Solve $5{\overline{\smash{)}70}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$70\div5=14$

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Question

Solve $6{\overline{\smash{)}84}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$84\div6=14$

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Question

Solve $6{\overline{\smash{)}42}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$42\div6=7$

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Question

Solve:

$\frac{\begin{array}[b]{r}569\ +\ 221\end{array}}{\space }$

Answer

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

Because this sum is greater than , we write the from the ones place and carry the from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}5^{{\color{Red} 1}}6\ 9\ +\ 2\ 2\ 1\end{array}}{\ \ \ \ \ \ \ \ 0 }$

Add the numbers in the tens place, including the that was carried over:

Add the numbers in the hundreds place:

Your final answer should be

$\frac{\begin{array}[b]{r}569\ +\ 221\end{array}}{\ \ \ 790 }$

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Question

Solve $90\div6$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$90\div6=15$

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Question

Solve $9{\overline{\smash{)}63}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$63\div9=7$

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Question

Solve $9{\overline{\smash{)}99}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$99\div9=11$

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Question

Solve $9{\overline{\smash{)}117}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high.

$117\div9=13$

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Question

Solve $3{\overline{\smash{)}29}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high with squares left over, which is our remainder.

$29\div3=9\ R2$

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Question

Solve $3{\overline{\smash{)}19}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high with square left over, which is our remainder.

$19\div3=6\ R1$

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Question

Solve $4{\overline{\smash{)}50}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high with sqaures left over, which is our remainder.

$50\div4=12\ R2$

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Question

Solve $4{\overline{\smash{)}63}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high with squares left over, which is our remainder.

$63\div4=15\ R3$

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Question

Solve $5{\overline{\smash{)}49}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high with squares left over, which is our remainder.

$49\div5=9\ R4$

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Question

Solve $5{\overline{\smash{)}73}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high with squares left over, which is our remainder.

$73\div5=14\ R3$

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Question

Solve $6{\overline{\smash{)}89}}$ by making a rectangular array.

Answer

Using our problem to make a rectangular array, we know that we are going to use a total of squares, and one dimension of the rectangular array is going to have squares, we'll make that the width. Our answer will be how many squares high the rectangle array is, or the height.

We can start with squares and keep adding on top of the previous until we've used all squares. Our rectangular array is squares high with quares left over, which is our remainder.

$89\div6=14 R\5$

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