Both teams average 6.2 runs per game, but Team A's smaller MAD (2.1 vs 3.8) indicates their individual game scores cluster closer to the mean. Team A shows more consistent scoring with fewer extreme deviations, while Team B's larger MAD suggests more games with unusually high or low run totals. Choice B reverses which team is more consistent. Choice C ignores that equal means don't guarantee equal variability. Choice D incorrectly states Team A has more variability.

This question tests calculating measures of center like the median and variability like the range, while describing the overall pattern in words and noting striking deviations such as outliers. Measures of center include the median, which is the middle value of ordered data (for even counts, average the two middle values), summarizing a typical value, and variability like range is max minus min, showing total spread. For example, in data 50,52,53,54,55,80, the median is (53+54)/2=53.5, range=80-50=30, pattern: most values cluster tightly between 50-55, striking deviation: outlier at 80 far above the rest. For this data ordered as 12,12,13,14,15,15,16,30, the median is (14+15)/2=14.5, range=30-12=18, pattern: values mostly cluster between 12 and 16 pages, striking deviation: 30 is much higher than the others. Common errors include misordering the data leading to wrong median, calculating range incorrectly, describing pattern only with numbers instead of words like 'most values 12–16', or missing the outlier at 30. To calculate median: (1) order the data, (2) for even n=8, average the 4th and 5th values. For range: (1) find max and min, (2) subtract; describe pattern in words like 'clustered low with one high value', and scan for deviations like values far from the cluster.

Original: 9 scores, sum = 9×78 = 702, median = 80 (5th value when ordered). After removing 65: 8 scores, sum = 702-65 = 637, new mean = 637÷8 = 79.625 (increase of 1.625). The new median will be the average of the 4th and 5th values, which will be slightly higher than 80 but the increase will be smaller than the mean's increase. Choice B incorrectly states median increases more. Choice C incorrectly assumes equal changes. Choice D incorrectly states mean decreases.

Mean absolute deviation measures spread around the mean. A smaller MAD indicates values are clustered closer to the mean. Data Set Q (MAD=3) has less variability than Data Set P (MAD=8), meaning Q's values are more consistent and closer to 45. The value 65 in Set P is 20 units from the mean, confirming greater spread. Choice A reverses which set is more consistent. Choice B incorrectly states Q has more variability. Choice D ignores that equal means don't imply equal variability.

This question tests calculating measures of center like mean, variability like MAD, describing the overall pattern in words, and noting striking deviations such as outliers, gaps, or clusters. Measures include mean (sum/count: 139/7≈19.857≈19.9) and MAD (average of absolute deviations from mean, e.g., deviations sum to ≈7, /7≈1.0). The overall pattern should be in words, like 'heights cluster around 20 cm with small spread.' Striking deviations: none here, as data are close. For this data of 18,19,19,20,20,21,22, correct are mean≈19.9, MAD≈1.0, pattern: cluster around 20 with small spread, no deviations. Common errors: wrong mean, MAD not averaging deviations, pattern not in words, falsely calling extremes outliers. To calculate: sum for mean, find |value-mean| and average for MAD; describe pattern narratively, check for deviations visually or with rules.

This question tests calculating mean and MAD (mean absolute deviation), which measures typical variation from the mean. First, find mean: sum = 10+11+12+12+13+14+15 = 87, so mean = 87/7 ≈ 12.43 messages. For MAD: find each deviation from mean |value - 12.43|: |10-12.43|=2.43, |11-12.43|=1.43, |12-12.43|=0.43, |12-12.43|=0.43, |13-12.43|=0.57, |14-12.43|=1.57, |15-12.43|=2.57. Average these deviations: (2.43+1.43+0.43+0.43+0.57+1.57+2.57)/7 = 10.29/7 ≈ 1.47. The pattern shows values increase steadily from 10 to 15, clustering near 12-13 with no gaps or outliers—15 is only 2.57 units from the mean, well within normal variation. Choice A correctly calculates mean ≈ 12.43 and MAD ≈ 1.47, accurately describing the tight cluster with no striking deviations. Choice B has wrong MAD, C has wrong mean, and D has impossibly small MAD.

This question tests calculating measures of center like median and mean, variability like range, describing the overall pattern in words, and noting striking deviations such as outliers, gaps, or clusters. Measures of center include median (middle value for odd count: 16 here) and mean (sum/count: 163/9≈18.11); variability includes range (40-12=28). The overall pattern should be described in words, like 'most values are in the mid-to-high teens, clustered tightly.' Striking deviations include outliers like 40, far from the rest. For this data of 12,14,15,15,16,16,17,18,40, correct measures are median=16, mean≈18.1, range=28, pattern: most in mid-to-high teens, deviation: 40 is an outlier. Common errors include wrong median by miscounting position, mean arithmetic errors, ignoring outlier in pattern description, or not noting deviations. To calculate: order data, find middle for median, sum and divide for mean, max-min for range; describe pattern in words, scan for outliers or gaps.

This question tests calculating measures of center like median and mean, variability like IQR, describing the overall pattern in words, and noting striking deviations such as outliers, gaps, or clusters. Measures include median (middle for even: average 2 and 2=2), mean (22/10=2.2), IQR (Q3-Q1=3-1=2). The overall pattern: 'most games between 1 and 3 goals, clustered low.' Striking deviation: 7 is an outlier. For this data 0,1,1,1,2,2,2,3,3,7, correct: median=2, mean=2.2, IQR=2, pattern: most 1-3, deviation: 7 outlier. Common errors: wrong IQR calculation, missing outlier, pattern only numbers. To calculate: order, find middles for median, sum/divide mean, quartiles for IQR; describe in words, identify outliers.

This question tests finding the median and range for an even number of values, plus identifying patterns and outliers in running times. First, the data is already ordered: 7, 7, 8, 8, 8, 9, 9, 14. For median with 8 values (even), we average the middle two values (4th and 5th positions): the 4th value is 8 and the 5th value is 8, so median = (8+8)/2 = 8. The range = max - min = 14 - 7 = 7 minutes, showing total spread. Looking at the pattern: seven of the eight times cluster tightly between 7-9 minutes (just a 2-minute span), while one time of 14 minutes is 5 minutes slower than the next slowest time, making it a clear outlier. Choice A correctly identifies median = 8 and range = 7, and accurately describes the pattern with 14 as a striking deviation. Choice B incorrectly calculates median as 8.5 (wrong middle values), C misses the outlier entirely, and D reverses the pattern description.

This question tests calculating measures of center like mean and median, variability like range, describing the overall pattern in words, and noting striking deviations. Measures: mean (15/6=2.5), median ((2+3)/2=2.5), range (4-1=3). Pattern: 'values clustered between 2 and 3, fairly balanced.' Deviations: none. For data 1,2,2,3,3,4, correct: mean=2.5, median=2.5, range=3, pattern: clustered 2-3 balanced, no deviations. Common errors: swapping mean/median, wrong range, falsely identifying outlier. To calculate: sum/divide mean, average middles median, max-min range; describe in words.