Informally Assess the Degree of Visual Overlap in Data: CCSS.Math.Content.7.SP.B.3 - 7th Grade Math

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what are the visual overlaps?

Answer

The visual overlaps are heights that both dot graphs have in common. In this case, there are both swimmers and basketball players that are $66\textup{ in}$ , $69\textup{ in}$ , and $71\textup{ in}$ ; thus, all the answer choices are correct.

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the mean height of the basketball players, rounded to the nearest tenth?

Answer

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

$\frac{66+69+70+70+71+72+72+72+73+73+74+75+75+65}{14}=71.9\textup{ in}$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the difference between the mean heights of basketball players and swimmers, rounded to the nearest tenth?

Answer

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

Basketball players:

$\frac{66+69+70+70+71+72+72+72+73+73+74+75+75+65}{14}=71.9\textup{ in}$

Swimmers:

$\frac{63+63+63+64+65+65+66+66+68+68+68+69+69+71}{14}=66.3\textup{ in}$

To find the different, we subtract our two means:

$\frac{\begin{array}[b]{r}71.9\ -\ 66.3\end{array}}{ \ \ \ \ \ \space 5.6}$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the mean absolute deviation of the height of basketball players, rounded to the nearest tenth?

Answer

The mean absolute deviation is the average distance between each data point and the mean. So the first step to solving for the mean absolute deviation is to solve for the mean.

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

$\frac{66+69+70+70+71+72+72+72+73+73+74+75+75+65}{14}=71.9\textup{ in}$

Next, we subtract to find the distance between each data point and , which is shown in the following table:

Now that we have all of the distances from the mean, we find the average of those differences to find the mean absolute deviation:

$\frac{5.9+2.9+1.9+1.9+0.9+0.1+0.1+0.1+1.1+1.1+2.1+3.1+3.1+3.1}{14}=2.0$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided. Using the dot plots provided, what is the mean absolute deviation of the height of swimmers, rounded to the nearest tenth?

Answer

The mean absolute deviation is the average distance between each data point and the mean. So the first step to solving for the mean absolute deviation is to solve for the mean.

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

$\frac{63+63+63+64+65+65+66+66+68+68+68+69+69+71}{14}=66.3\textup{ in}$

Next, we subtract to find the distance between each data point and , which is shown in the following table:

Now that we have all of the distances from the mean, we find the average of those differences to find the mean absolute deviation:

$\frac{3.3+3.3+3.3+2.3+1.3+1.3+0.3+0.3+1.7+1.7+1.7+2.7+2.7+4.7}{14}=2.2$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the difference between mean absolute deviation of the height of the basketball players and swimmer, rounded to the nearest tenth?

Answer

The mean absolute deviation is the average distance between each data point and the mean. So the first step to solving for the mean absolute deviation is to solve for the mean.

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

Basketball players:

$\frac{66+69+70+70+71+72+72+72+73+73+74+75+75+65}{14}=71.9\textup{ in}$

Next, we subtract to find the distance between each data point and , which is shown in the following table:

Now that we have all of the distances from the mean, we find the average of those differences to find the mean absolute deviation:

$\frac{5.9+2.9+1.9+1.9+0.9+0.1+0.1+0.1+1.1+1.1+2.1+3.1+3.1+3.1}{14}=2.0$

Swimmers:

$\frac{63+63+63+64+65+65+66+66+68+68+68+69+69+71}{14}=66.3\textup{ in}$

Next, we subtract to find the distance between each data point and , which is shown in the following table:

Now that we have all of the distances from the mean, we find the average of those differences to find the mean absolute deviation:

$\frac{3.3+3.3+3.3+2.3+1.3+1.3+0.3+0.3+1.7+1.7+1.7+2.7+2.7+4.7}{14}=2.2$

Now that we have each of the mean absolute deviations we can subtract to find the difference:

$\frac{\begin{array}[b]{r}2.2\ -\ 2.0\end{array}}{ \ \ \ \space 0.2}$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the median height of the swimmers?

Answer

The median is the middle number of a set of data points.

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle.

$63, 63, 63, 64, 65, 65, {\color{DarkRed} 66, 66,} 68, 68, 68, 69, 69, 71$

There are two numbers in the middle, so we take the average of the two numbers:

$\frac{66+66}{2}=66$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the median height of the basketball players?

Answer

The median is the middle number of a set of data points.

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle.

$66, 69, 70, 70, 71, 72, {\color{DarkRed} 72, 72,} 73, 73, 74, 75, 75, 75$

There are two numbers in the middle, so we take the average of the two numbers:

$\frac{72+72}{2}=72$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the difference in median heights of the basketball players and swimmers?

Answer

The median is the middle number of a set of data points.

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle.

Swimmers:

$63, 63, 63, 64, 65, 65, {\color{DarkRed} 66, 66,} 68, 68, 68, 69, 69, 71$

There are two numbers in the middle, so we take the average of the two numbers:

$\frac{66+66}{2}=66$

Basketball players:

$66, 69, 70, 70, 71, 72, {\color{DarkRed} 72, 72,} 73, 73, 74, 75, 75, 75$

There are two numbers in the middle, so we take the average of the two numbers:

$\frac{72+72}{2}=72$

Finally, we subtract to find the difference:

$\frac{\begin{array}[b]{r}72\ -\ 66\end{array}}{ \ \ \ \ \ \space 6}$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, is there an outlier in the plot for basketball players? If yes, what is the outlier?

Answer

An outlier is a value in a data set that lies outside of the rang of the other data points. In this case, is three inches away from any other height, and there are no other gaps like this in the set; thus, is our outlier.

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plot for women swimmers, select the answer choice that provides the outlier for the set.

Answer

An outlier is a value in a data set that lies outside of the rang of the other data points. In this case all of the data points are together, and there are no big gaps between the heights. There is only $1\textup{ inch}$ between some of the points, which isn't enough to create an outlier.

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what are the visual overlaps?

Answer

The visual overlaps are heights that both dot graphs have in common. In this case, there are both swimmers and basketball players that are $66\textup{ in}$ , $69\textup{ in}$ , and $71\textup{ in}$ ; thus, all the answer choices are correct.

Compare your answer with the correct one above

Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the mean height of the basketball players, rounded to the nearest tenth?

Answer

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

$\frac{66+69+70+70+71+72+72+72+73+73+74+75+75+65}{14}=71.9\textup{ in}$

Compare your answer with the correct one above

Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the difference between the mean heights of basketball players and swimmers, rounded to the nearest tenth?

Answer

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

Basketball players:

$\frac{66+69+70+70+71+72+72+72+73+73+74+75+75+65}{14}=71.9\textup{ in}$

Swimmers:

$\frac{63+63+63+64+65+65+66+66+68+68+68+69+69+71}{14}=66.3\textup{ in}$

To find the different, we subtract our two means:

$\frac{\begin{array}[b]{r}71.9\ -\ 66.3\end{array}}{ \ \ \ \ \ \space 5.6}$

Compare your answer with the correct one above

Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the mean absolute deviation of the height of basketball players, rounded to the nearest tenth?

Answer

The mean absolute deviation is the average distance between each data point and the mean. So the first step to solving for the mean absolute deviation is to solve for the mean.

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

$\frac{66+69+70+70+71+72+72+72+73+73+74+75+75+65}{14}=71.9\textup{ in}$

Next, we subtract to find the distance between each data point and , which is shown in the following table:

Now that we have all of the distances from the mean, we find the average of those differences to find the mean absolute deviation:

$\frac{5.9+2.9+1.9+1.9+0.9+0.1+0.1+0.1+1.1+1.1+2.1+3.1+3.1+3.1}{14}=2.0$

Compare your answer with the correct one above

Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided. Using the dot plots provided, what is the mean absolute deviation of the height of swimmers, rounded to the nearest tenth?

Answer

The mean absolute deviation is the average distance between each data point and the mean. So the first step to solving for the mean absolute deviation is to solve for the mean.

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

$\frac{63+63+63+64+65+65+66+66+68+68+68+69+69+71}{14}=66.3\textup{ in}$

Next, we subtract to find the distance between each data point and , which is shown in the following table:

Now that we have all of the distances from the mean, we find the average of those differences to find the mean absolute deviation:

$\frac{3.3+3.3+3.3+2.3+1.3+1.3+0.3+0.3+1.7+1.7+1.7+2.7+2.7+4.7}{14}=2.2$

Compare your answer with the correct one above

Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the difference between mean absolute deviation of the height of the basketball players and swimmer, rounded to the nearest tenth?

Answer

The mean absolute deviation is the average distance between each data point and the mean. So the first step to solving for the mean absolute deviation is to solve for the mean.

The mean is the average of a data set. In order to solve for the mean, we add all of our heights together, and divide by the number of people in our data set.

Basketball players:

$\frac{66+69+70+70+71+72+72+72+73+73+74+75+75+65}{14}=71.9\textup{ in}$

Next, we subtract to find the distance between each data point and , which is shown in the following table:

Now that we have all of the distances from the mean, we find the average of those differences to find the mean absolute deviation:

$\frac{5.9+2.9+1.9+1.9+0.9+0.1+0.1+0.1+1.1+1.1+2.1+3.1+3.1+3.1}{14}=2.0$

Swimmers:

$\frac{63+63+63+64+65+65+66+66+68+68+68+69+69+71}{14}=66.3\textup{ in}$

Next, we subtract to find the distance between each data point and , which is shown in the following table:

Now that we have all of the distances from the mean, we find the average of those differences to find the mean absolute deviation:

$\frac{3.3+3.3+3.3+2.3+1.3+1.3+0.3+0.3+1.7+1.7+1.7+2.7+2.7+4.7}{14}=2.2$

Now that we have each of the mean absolute deviations we can subtract to find the difference:

$\frac{\begin{array}[b]{r}2.2\ -\ 2.0\end{array}}{ \ \ \ \space 0.2}$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the median height of the swimmers?

Answer

The median is the middle number of a set of data points.

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle.

$63, 63, 63, 64, 65, 65, {\color{DarkRed} 66, 66,} 68, 68, 68, 69, 69, 71$

There are two numbers in the middle, so we take the average of the two numbers:

$\frac{66+66}{2}=66$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the median height of the basketball players?

Answer

The median is the middle number of a set of data points.

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle.

$66, 69, 70, 70, 71, 72, {\color{DarkRed} 72, 72,} 73, 73, 74, 75, 75, 75$

There are two numbers in the middle, so we take the average of the two numbers:

$\frac{72+72}{2}=72$

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Question

A university wanted to compare the heights of women on the basketball team and women on the swim team. The data is in the dot plots provided.

Using the dot plots provided, what is the difference in median heights of the basketball players and swimmers?

Answer

The median is the middle number of a set of data points.

To solve for the median, we list our data points in order from least to greatest, and then find the number in the middle.

Swimmers:

$63, 63, 63, 64, 65, 65, {\color{DarkRed} 66, 66,} 68, 68, 68, 69, 69, 71$

There are two numbers in the middle, so we take the average of the two numbers:

$\frac{66+66}{2}=66$

Basketball players:

$66, 69, 70, 70, 71, 72, {\color{DarkRed} 72, 72,} 73, 73, 74, 75, 75, 75$

There are two numbers in the middle, so we take the average of the two numbers:

$\frac{72+72}{2}=72$

Finally, we subtract to find the difference:

$\frac{\begin{array}[b]{r}72\ -\ 66\end{array}}{ \ \ \ \ \ \space 6}$

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