Operations - 7th Grade Math

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Question

Andrew spends every Saturday at the gym working out. He can complete $\frac{1}{12}$ of his workout in $\frac{1}{6}$ of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

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Answer

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of his workout, $\frac{1}{12}$ , divided by hours, $\frac{1}{6}$ :

$$\frac{\ \frac{1}{12}$\ \textup{of a workout}}{\ $\frac{1}{6}$\ \textup{hours}}$

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.

$\frac{1}{6}\rightarrow $\frac{6}{1}$

Therefore:

$\frac{1}{12}$\times$\frac{6}{1}$=\frac{6}{12}$=\frac{1}{2}$

Andrew can complete $\frac{1}{2}$ of his workout per hour.

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Question

Solve:

Tap to reveal answer

Answer

In order to solve this problem, we need to start at on the number line.

Next, we have which means we need to move places to the right on the number line. When we have an addition sign we move to the right because that is towards the positive side of the number line. When we have a subtraction sign we move to the left because that is towards the negative side of the number line.

The orange arrow moved places to the right, and ended at ; thus,

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Question

Solve:

$-35\div-5$

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Answer

We know the following information:

$35\div5=7$

In this particular case, do the negative numbers change our answer? . There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.

A negative number divided by a negative number will always equal a positive number

Thus,

$-35\div-5=7$

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Question

Andrew spends every Saturday at the gym working out. He can complete $\frac{1}{12}$ of his workout in $\frac{1}{6}$ of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Tap to reveal answer

Answer

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of his workout, $\frac{1}{12}$ , divided by hours, $\frac{1}{6}$ :

$$\frac{\ \frac{1}{12}$\ \textup{of a workout}}{\ $\frac{1}{6}$\ \textup{hours}}$

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.

$\frac{1}{6}\rightarrow $\frac{6}{1}$

Therefore:

$\frac{1}{12}$\times$\frac{6}{1}$=\frac{6}{12}$=\frac{1}{2}$

Andrew can complete $\frac{1}{2}$ of his workout per hour.

← Didn't Know|Knew It →

Question

Solve:

Tap to reveal answer

Answer

In order to solve this problem, we need to start at on the number line.

Next, we have which means we need to move places to the right on the number line. When we have an addition sign we move to the right because that is towards the positive side of the number line. When we have a subtraction sign we move to the left because that is towards the negative side of the number line.

The orange arrow moved places to the right, and ended at ; thus,

← Didn't Know|Knew It →

Question

Solve:

$-35\div-5$

Tap to reveal answer

Answer

We know the following information:

$35\div5=7$

In this particular case, do the negative numbers change our answer? . There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.

A negative number divided by a negative number will always equal a positive number

Thus,

$-35\div-5=7$

← Didn't Know|Knew It →

Question

Andrew spends every Saturday at the gym working out. He can complete $\frac{1}{12}$ of his workout in $\frac{1}{6}$ of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Tap to reveal answer

Answer

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of his workout, $\frac{1}{12}$ , divided by hours, $\frac{1}{6}$ :

$$\frac{\ \frac{1}{12}$\ \textup{of a workout}}{\ $\frac{1}{6}$\ \textup{hours}}$

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.

$\frac{1}{6}\rightarrow $\frac{6}{1}$

Therefore:

$\frac{1}{12}$\times$\frac{6}{1}$=\frac{6}{12}$=\frac{1}{2}$

Andrew can complete $\frac{1}{2}$ of his workout per hour.

← Didn't Know|Knew It →

Question

Solve:

Tap to reveal answer

Answer

In order to solve this problem, we need to start at on the number line.

Next, we have which means we need to move places to the right on the number line. When we have an addition sign we move to the right because that is towards the positive side of the number line. When we have a subtraction sign we move to the left because that is towards the negative side of the number line.

The orange arrow moved places to the right, and ended at ; thus,

← Didn't Know|Knew It →

Question

Solve:

$-35\div-5$

Tap to reveal answer

Answer

We know the following information:

$35\div5=7$

In this particular case, do the negative numbers change our answer? . There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.

A negative number divided by a negative number will always equal a positive number

Thus,

$-35\div-5=7$

← Didn't Know|Knew It →

Question

Andrew spends every Saturday at the gym working out. He can complete $\frac{1}{12}$ of his workout in $\frac{1}{6}$ of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Tap to reveal answer

Answer

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of his workout, $\frac{1}{12}$ , divided by hours, $\frac{1}{6}$ :

$$\frac{\ \frac{1}{12}$\ \textup{of a workout}}{\ $\frac{1}{6}$\ \textup{hours}}$

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve.

$\frac{1}{6}\rightarrow $\frac{6}{1}$

Therefore:

$\frac{1}{12}$\times$\frac{6}{1}$=\frac{6}{12}$=\frac{1}{2}$

Andrew can complete $\frac{1}{2}$ of his workout per hour.

← Didn't Know|Knew It →

Question

Solve:

Tap to reveal answer

Answer

In order to solve this problem, we need to start at on the number line.

Next, we have which means we need to move places to the right on the number line. When we have an addition sign we move to the right because that is towards the positive side of the number line. When we have a subtraction sign we move to the left because that is towards the negative side of the number line.

The orange arrow moved places to the right, and ended at ; thus,

← Didn't Know|Knew It →

Question

Solve:

$-35\div-5$

Tap to reveal answer

Answer

We know the following information:

$35\div5=7$

In this particular case, do the negative numbers change our answer? . There are a couple of rules that we need to remember when multiplying with negative numbers:

A negative number divided by a positive number will always equal a negative number, and a positive number divided by a negative number will always equal a negative number.

A negative number divided by a negative number will always equal a positive number

Thus,

$-35\div-5=7$

← Didn't Know|Knew It →

Knew It

Operations - 7th Grade Math

Andrew spends every Saturday at the gym working out. He can complete of his workout in of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Solve:

Solve:

Andrew spends every Saturday at the gym working out. He can complete of his workout in of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Solve:

Solve:

Andrew spends every Saturday at the gym working out. He can complete of his workout in of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Solve:

Solve:

Andrew spends every Saturday at the gym working out. He can complete of his workout in of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Solve:

Solve:

Andrew spends every Saturday at the gym working out. He can complete $\frac{1}{12}$ of his workout in $\frac{1}{6}$ of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Solve:

$-35\div-5$

Andrew spends every Saturday at the gym working out. He can complete $\frac{1}{12}$ of his workout in $\frac{1}{6}$ of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Solve:

$-35\div-5$

Andrew spends every Saturday at the gym working out. He can complete $\frac{1}{12}$ of his workout in $\frac{1}{6}$ of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Solve:

$-35\div-5$

Andrew spends every Saturday at the gym working out. He can complete $\frac{1}{12}$ of his workout in $\frac{1}{6}$ of an hour. If he continues at this rate, how much of his workout does Andrew complete per hour?

Solve:

$-35\div-5$