Draw Inferences From Random Samples
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7th Grade Math › Draw Inferences From Random Samples
A school nurse wants to estimate the average amount of sleep students get per night. She randomly surveys 20 students four different times, getting these average results: 7.2 hours, 6.8 hours, 7.5 hours, and 6.9 hours. A teacher suggests the nurse should survey 100 students just once instead. Which approach is better for making inferences?
The teacher's approach, because larger samples always provide more accurate estimates of population parameters
The nurse's approach, because multiple samples reveal how much estimates can vary and improve reliability
Both approaches are equally good since they survey the same total number of students overall
The teacher's approach, because it eliminates the confusion caused by getting different results from multiple samples
Explanation
When you encounter questions about sampling methods and statistical inference, focus on what makes estimates more reliable and informative rather than just looking at sample size alone.
The nurse's approach of taking multiple samples of 20 students each is superior because it reveals the natural variability in estimates and provides more reliable results. When you take multiple samples, you can see how much your estimates typically vary (7.2, 6.8, 7.5, and 6.9 hours), which helps you understand the precision of your measurement. You can also average these results (7.1 hours) for a more stable estimate than any single sample would provide.
Let's examine why the other options miss the mark. Choice A incorrectly assumes larger samples are always better, but a single large sample can't show you how much estimates vary from sample to sample. Choice B misunderstands that getting "different results" isn't confusion—it's valuable information about variability that helps assess reliability. Choice C seems logical since both approaches survey 80 students total, but it ignores that the sampling structure matters more than just the total count.
The correct answer is D because multiple samples reveal estimation variability and improve reliability through repeated measurement. This approach follows sound statistical principles used in real research.
Study tip: When comparing sampling methods, remember that multiple smaller samples often beat one large sample because they show you the consistency of your results and reduce the risk of getting misled by one unusual sample.
A student council wants to predict the winner of a school election between candidates Martinez and Chen. They conduct three random surveys of 40 students each. Survey 1 shows Martinez leading 24-16, Survey 2 shows Chen leading 23-17, and Survey 3 shows Martinez leading 22-18. What conclusion is most appropriate?
The election is too close to call reliably, given the variation and small margins in the sample data
Martinez will definitely win because she led in two out of three surveys conducted
Chen will likely win because Survey 2 showed the largest margin of victory for any candidate
Martinez will probably win because her average support across all surveys exceeds 50% of responses
Explanation
The correct answer is B. The surveys show conflicting results with small margins (60% vs 40%, 57.5% vs 42.5%, 55% vs 45%), indicating high uncertainty. Multiple samples showing different winners suggests the race is too close to predict reliably. A is wrong because survey frequency doesn't guarantee electoral victory. C is wrong because one survey's margin doesn't override contradictory evidence. D is wrong because averaging across conflicting samples doesn't provide reliable prediction when variation is high.
A sports analyst randomly samples game statistics to predict a basketball player's average points per game for the season. Five samples of 8 games each yield averages of 14.3, 16.1, 13.8, 15.7, and 14.9 points. The player has 82 games total in the season. Which prediction strategy is most appropriate?
Predict 16.1 points per game since this was the highest average observed in the samples
Predict the season average will fall between 13.5 and 16.5 points per game based on sample variation
Predict between 14.0 and 15.5 points per game using only the three most consistent sample results
Predict exactly 14.96 points per game by averaging all sample means and multiplying by appropriate factors
Explanation
When you're making predictions from sample data, you need to understand that samples give you estimates, not exact values. The key insight here is recognizing the natural variation in sample results and accounting for uncertainty in your prediction.
The correct approach is D because it acknowledges the range of variation observed in the samples (13.8 to 16.1) and provides a reasonable prediction interval. Since all five sample means fall between these values, it's logical to expect the true season average will likely fall within a similar range. Adding some buffer (13.5 to 16.5) accounts for the fact that samples don't capture every possible outcome.
A is wrong because it suggests you can calculate an exact prediction by "multiplying by appropriate factors." Real statistical prediction doesn't work this way—you can't eliminate uncertainty through mathematical manipulation of sample means.
B is flawed because it arbitrarily throws out data by selecting only "three most consistent" results. In statistics, you should use all available data unless there's a valid reason to exclude outliers, which don't exist here.
C makes the error of cherry-picking the highest value. Using only the best sample result ignores the natural variation in the data and would likely lead to an overestimate.
Study tip: When working with sample data, remember that your goal is to estimate a range where the true value likely falls, not to calculate a precise number. Look for answer choices that acknowledge uncertainty and variation rather than those claiming false precision.
A botanist wants to estimate the average height of oak trees in a forest. She measures random samples of 10 trees each, obtaining these average heights: 18.2 ft, 16.8 ft, 19.5 ft, and 17.3 ft. Before concluding her study, she takes one final sample that yields an average of 21.1 ft. How should this last result affect her inference?
She should expand her estimated range to account for this additional variation in the data
She should repeat the final sample because 21.1 ft is probably a measurement error
She should discard the 21.1 ft result because it differs too much from the other samples
She should conclude that oak trees are getting taller, since the final sample showed the highest average
Explanation
The correct answer is B. The new sample of 21.1 ft extends the range of observed sample means from 16.8-19.5 ft to 16.8-21.1 ft, indicating greater population variability than initially estimated. A responsible inference should expand the estimated range accordingly. A is wrong because all random samples are valid. C is wrong because samples don't show temporal trends. D is wrong because higher values aren't necessarily errors.
A researcher wants to estimate the average number of books read per year by students at Lincoln Middle School. She randomly selects 30 students and finds their average is 8.2 books per year. To check the reliability of this estimate, she takes four more random samples of 30 students each, obtaining averages of 7.8, 9.1, 8.5, and 7.6 books per year. Based on all five samples, what is the most reasonable prediction for the population mean?
Between 7.5 and 9.2 books per year, since this range captures the variation observed across multiple samples
Exactly 8.2 books per year, since this was the result from the original and most important sample
Between 7.6 and 9.1 books per year, since these are the minimum and maximum values from all samples
Between 8.0 and 8.5 books per year, since this represents the middle half of all sample means obtained
Explanation
The correct answer is A. When using multiple samples to gauge variation, we should consider a reasonable range that accounts for sampling variability. The range 7.5-9.2 provides a buffer around the observed values (7.6-9.1) that reflects realistic uncertainty. B is wrong because no single sample gives the exact population mean. C is wrong because it arbitrarily uses only the middle values. D is wrong because using just the extreme values doesn't account for sampling uncertainty.
A city planner estimates daily park usage by counting visitors during random hour-long periods and extrapolating to full days. Over several weeks, she conducts this sampling five times, estimating 240, 180, 290, 210, and 260 daily visitors. City council asks for a single definitive number for budget planning. What should she report?
A range of 200-270 daily visitors, accounting for sampling uncertainty while avoiding extreme values
236 daily visitors, calculated as the precise average of all five estimates obtained through sampling
260 daily visitors, using the most recent estimate since it reflects current park usage patterns
A range of 180-290 daily visitors, since these represent the minimum and maximum from her samples
Explanation
When you encounter questions about sampling and data reporting, you need to balance accuracy with the inherent uncertainty that comes from sampling rather than counting every visitor.
Choice A is correct because it acknowledges sampling uncertainty while providing useful guidance. The city planner didn't count every visitor—she extrapolated from small samples, which introduces variability. By reporting 200-270, she excludes the extreme values (180 and 290) that are more likely to be sampling errors, while giving the council a realistic range that accounts for this uncertainty. The average of her five estimates is 236, and this range reasonably encompasses that central value.
Choice B fails because it simply reports the minimum and maximum values (180-290) without any statistical judgment. This range is too wide to be useful for budget planning and doesn't account for the fact that extreme values in small samples are often outliers.
Choice C presents 236 as a "precise" number, but this false precision ignores the reality of sampling variability. Reporting a single number from sample data misleads the council into thinking this estimate is more certain than it actually is.
Choice D assumes the most recent estimate (260) is automatically the best, but there's no evidence that park usage changed over time or that recent samples are more accurate than earlier ones.
Study tip: When dealing with sampling data, remember that reporting ranges often provides more honest and useful information than false precision from single numbers, especially when sample sizes are small.
A restaurant owner surveys random customers to estimate average satisfaction ratings for the entire month. Three samples of 15 customers each yield average ratings of 3.8, 4.2, and 3.5 on a 5-point scale. If she takes two more samples and gets averages of 4.1 and 3.9, how should she interpret these results?
Customer satisfaction improved over time, since the later samples had higher average ratings than earlier ones
Customer satisfaction likely ranges between 3.4 and 4.3, reflecting the uncertainty shown by sample variation
The sampling method is flawed because the results vary too much to provide useful information
The true average satisfaction is approximately 3.9, calculated as the mean of all five sample averages
Explanation
The correct answer is C. Multiple samples showing variation from 3.5 to 4.2 suggest the population mean likely falls in a range accounting for sampling uncertainty, such as 3.4-4.3. A is wrong because random samples don't show time trends. B is wrong because averaging sample means doesn't account for sampling variability. D is wrong because this amount of variation is normal and expected in sampling.
A quality control inspector randomly samples 25 light bulbs from a large shipment and finds that 3 are defective. She then takes three additional samples of 25 bulbs each, finding 1, 4, and 2 defective bulbs respectively. If the shipment contains 10,000 bulbs, which inference about the total number of defective bulbs is most justified?
Approximately 1,000 to 1,600 defective bulbs, based on the range of defect rates observed across samples
Approximately 800 to 1,200 defective bulbs, using only the most reliable middle samples to avoid extremes
Exactly 1,200 defective bulbs, calculated using the average defect rate of 12% across all samples
Between 400 and 1,600 defective bulbs, reflecting the minimum and maximum defect rates from individual samples
Explanation
The correct answer is C. The defect rates from the four samples are 12%, 4%, 16%, and 8%. Applied to 10,000 bulbs, this gives a range of 400 to 1,600 defective bulbs, which appropriately reflects the variation observed. A is wrong because it doesn't include the full range of observed rates. B is wrong because we cannot predict an exact number from sample data. D is wrong because it arbitrarily excludes valid sample results.
A librarian wants to estimate the average number of pages in all the mystery books in the school library (the population). She randomly selects 25 mystery books and finds the sample mean is 218 pages. Which is the best inference about the population mean number of pages?
The population mean is 25 pages because 25 books were sampled.
No inference can be made about the population mean from a random sample.
The population mean number of pages is approximately 218 pages, but it may not be exactly 218.
The population mean is exactly 218 pages because the sample mean is 218.
Explanation
This question tests drawing inferences about a population from random sample data, specifically estimating the mean number of pages in mystery books and understanding that sample means approximate but do not exactly equal population means due to sampling variability. Random sample data estimates population: the sample mean of 218 pages from 25 books approximates the population mean, not exactly but as a reasonable estimate; similarly, sample proportions would estimate population proportions. Multiple samples show variability: different random samples give different estimates, and the variation magnitude indicates uncertainty, such as a range of several pages suggesting the estimate might be off by that amount. For example, with the sample mean of 218 pages, we can infer the population mean is approximately 218 pages, acknowledging some uncertainty. The correct inference is that the population mean is approximately 218 pages but may not be exactly 218, as it recognizes the sample as an estimate with potential variability. A common error is claiming the population mean is exactly 218 pages, ignoring uncertainty, or stating no inference can be made, which defeats the purpose of sampling. Drawing inferences involves calculating the sample mean and using it to estimate the population mean approximately, while acknowledging variability; uses include efficiently estimating library book characteristics without checking all books, and mistakes include treating estimates as exact or linking the mean to sample size incorrectly.
To estimate the percentage of students who would vote for Team Blue in a spirit-week poll, three random samples were taken:
Sample 1 (n=80): 46 students vote Team Blue
Sample 2 (n=80): 50 students vote Team Blue
Sample 3 (n=80): 48 students vote Team Blue
Which is the most reasonable conclusion about the population percentage and the variability of these estimates?
The true population percentage is exactly 60% because the middle sample is 48/80.
No conclusion can be drawn unless every student in the school votes.
The estimates are 46/80, 50/80, and 48/80 (about 58%–63%), varying by about 5 percentage points, so the true value is likely around 60%.
The estimates vary by about 50 percentage points, so the sampling method failed.
Explanation
This question tests drawing inferences about a population from random sample data, estimating the percentage voting Team Blue and understanding sampling variability where multiple samples vary, gauging uncertainty. Random sample data estimates the population: proportions about 58%-63% vary by 5 points, suggesting true value around 60%. For example, three samples with 46/80, 50/80, 48/80 indicate variability of about 5 points and estimate near 60%. The most reasonable conclusion is the estimates are 46/80, 50/80, 48/80 (about 58%-63%), varying by 5 points, true around 60%, as in choice A. A common error is claiming exactness or that variability means failure. Assessing variability involves: (1) comparing proportions, (2) finding range, (3) estimating true value, (4) larger samples reduce variability. Uses include predicting polls efficiently; mistakes include requiring full population.