Distributive Property - ACT Math

This simply requires us to recall our rules from FOIL

First: X multiplied by X yields x2

Outer: X multplied by 2 yields 2x

Inner: 3 multiplied by x yields 3x

Lasts: 2 multiplied by 3 yields 6

Add it all together and we have x2 + 2x + 3x + 6

using FOIL:

First: f x f = f2

Outer: f x – 4 = –4f

Intter: 4 x f = 4f

Lasts: 4 x – 4 = –16

Adding it all up:

f2 – 4f +4f – 16

We start by foiling out the original equation, giving us 36 – 9(i2). Next, substitute 36 – 9(–1). This equals 36 + 9 = 45.

To solve this problem, you should FOIL: (4_x_ – 3)(4_x_ – 3) = 16_x_2 – 12_x –_ 12_x_ + 9 = 16_x_2 – 24_x_ + 9.

To solve this equation, first distribute on the right side of the equation.

Then, subtract from both sides.

Then divide both sides by .

Another method for solving this problem is to plug in the answer choices and solve.

The length is equal to W – 3

The area of a rectangle is length x width.

So W * (W – 3) = W2 – 3W

Here we use FOIL:

Firsts: B * B = B2

Outer: B * 4 = 4B

Inner: –2 * B = –2B

Lasts: –2 * 4 = –8

All together this yields

B2 + 2B – 8

x2 + 5x – 6 = 0 factors to (x+6)(x**–**1) = 0.

Therefore, the two real solutions are x = **–**6 and x = 1. Their product is simply **–**6.

Use FOIL: (2g – 3h)(2g – 3h) = 4g2 – 6gh – 6gh + 9h2 = 4g2 – 12gh + 9h2

By FOIL (First Outer Inner Last), we obtain –8_x_2 – 8_x_ – 6_x_ – 6.

Simplify: –8_x_2 – 14_x_ – 6

We FOIL the equation to obtain 30 – 10_i_ + 18_i_ – 6_i_2, combining like terms and substituting i_2 = –1, we obtain 36 + 8_i.

FOIL and we get:

Then multiply it by and get:

FOIL (First, Outside, Inside, Last): (x + 1)(x – 1) which is (x2 – 1) then multiply it by x, which is (x3 – x)

To solve you must use FOIL (first outer inner last)

Multiply 4_x_ and 2_x_ to get 8x²

Multiply 4_x_ and 4 to get 16_x_

Multiply 3 and 2_x_ to get 6_x_

Multiply 3 and 4 to get 12

Add the common terms and the awnser is 8_x_² + 22_x_ + 12

Expanding out gives .

We know that so when we substitute that in we get .

This is essentially a multi-part question that at first may seem confusing, until it's realized that the question only involves basic algebra, or more specifically, using FOIL and greatest common factor concepts.

First, we must use FOIL (first, outside, inside, last), to evaluate the given expression: ⋅

First:

Outside:

Inside:

Last:

Now add all of the terms together:

Which simplifies to:

Now, we must see what is greatest common factor shared between each of these two terms. They are both divisible by as well as .

Therefore, is the greatest common factor.

Use the FOIL method to find the product. The answer must be in standard form.

Step 1: Use the FOIL method

First:

Outside:

Inside:

Last:

Add these to find the product:

Step 2: Write the product in standard form

Standard form means the terms are written from highest degree to lowest degree. You find the degree of a term by adding the exponents in the term.

Therefore:

Simplify:

Expand the equation and use the FOIL method:

First:

Outside:

Inside:

Last:

Sum the terms:

Step One: Expand

Step 2: Use the FOIL method

First:

Outside:

Inside:

Last:

Sum the products:

In order to get the form, we must FOIL out .

FOIL is technique for distributing two binomials. The letters stand for First, Outer, Inner, and Last.

"First" stands for multiply the terms which occur first in each binomial.

"Outer" stands for multiply the outermost terms in the product.

"Inner" stands for multiply the innermost two terms.

"Last" stands for multiply the terms which occur last in each binomial.

Then, we must simplify the like terms, as shown below:

.

Here, , , while , so .