ACT Math Flashcards: Circles

Study Circles in ACT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

ACT Math

Circles

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QUESTION
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If the circumference is 31.4, estimate the radius.

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ANSWER

Radius 5\approx 5. Using C=2πrC = 2\pi r, solve for rr.

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What this deck covers

This deck focuses on Circles, giving you a quick way to review the definitions, rules, and examples that matter most for ACT Math.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

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Flashcard 1: If the circumference is 31.4, estimate the radius.

Answer: Radius 5\approx 5. Using C=2πrC = 2\pi r, solve for rr.

Flashcard 2: State the radius of a circle with equation x2+y2=81x^2 + y^2 = 81.

Answer: Radius = 9. Radius is square root of constant term.

Flashcard 3: What is the relationship between radius rr and diameter dd of a circle?

Answer: d=2rd=2r. Diameter is twice the radius.

Flashcard 4: State the conversion from degrees to radians for an angle of θ\theta^\circ.

Answer: θπ180\theta\cdot\frac{\pi}{180}. Multiply by π180\frac{\pi}{180} to convert degrees.

Flashcard 5: What is the relationship between a radius and a tangent line at the point of tangency?

Answer: They are perpendicular. Forms a 90°90° angle at point of contact.

Flashcard 6: Identify the distance between the center and any point on the circle.

Answer: The radius. Definition of radius in a circle.

Flashcard 7: Find the diameter of a circle with circumference 18π18\pi.

Answer: 1818. From C=πdC=\pi d, solve for dd.

Flashcard 8: What is the center of the circle (x+1)2+(y1)2=9(x+1)^2 + (y-1)^2 = 9?

Answer: (1,1)(-1, 1). Center is ((1),(1))=(1,1)(-(-1), -(-1)) = (-1, 1).

Flashcard 9: What is the measure of an inscribed angle that intercepts a semicircle?

Answer: 9090^\circ. Inscribed angle in semicircle is always right.

Flashcard 10: Find the area of a circle with radius 12\frac{1}{2} in terms of π\pi.

Answer: π4\frac{\pi}{4}. Use A=πr2A=\pi r^2 with r=12r=\frac{1}{2}.

Flashcard 11: What is the arc length of a circle with radius 44 cm and angle 9090^\circ?

Answer: 2π2\pi cm. Using L=90360×2π(4)=2πL = \frac{90}{360} \times 2\pi(4) = 2\pi.

Flashcard 12: Identify the center and radius of (x1)2+(y+2)2=16(x-1)^2 + (y+2)^2 = 16.

Answer: Center: (1,2)(1, -2), Radius: 4. Read values from standard form equation.

Flashcard 13: Identify the term for a section of a circle bounded by two radii.

Answer: A sector. A sector is a pie-slice shaped region.

Flashcard 14: Find the area of a circle with diameter 1010 in terms of π\pi.

Answer: 25π25\pi. Use A=πr2A=\pi r^2 where r=5r=5 (half of diameter).

Flashcard 15: What is the circumference of a circle with diameter 1414?

Answer: 14π14\pi. Using C=πdC = \pi d with d=14d = 14.

Flashcard 16: Find the arc length when r=4r=4 and θ=π3\theta=\frac{\pi}{3} (radians).

Answer: 4π3\frac{4\pi}{3}. Apply s=rθs=r\theta with given values.

Flashcard 17: Identify the definition of a chord in a circle.

Answer: A segment with endpoints on the circle. A line segment inside the circle.

Flashcard 18: State the equation of a circle centered at the origin with radius rr.

Answer: x2+y2=r2x^2+y^2=r^2. Special case where center is at (0,0)(0,0).

Flashcard 19: What is the length of a radius if the circle's diameter is 1010?

Answer: 55. Radius is half the diameter.

Flashcard 20: State the circumference formula for a circle with radius rr.

Answer: C=2πrC=2\pi r. Perimeter of a circle using radius.

Flashcard 21: Find the radius of a circle with area 49π49\pi.

Answer: 77. From A=πr2A=\pi r^2, solve for rr.

Flashcard 22: Identify the center of a circle with equation (x3)2+(y+2)2=25(x-3)^2 + (y+2)^2 = 25.

Answer: Center: (3,2)(3, -2). Center is (h,k)(h, k) from standard form.

Flashcard 23: Determine the area of a circle with radius 33.

Answer: 9π9\pi. Using A=πr2A = \pi r^2 with r=3r = 3.

Flashcard 24: If the radius is 77, what is the area of the circle?

Answer: 49π49\pi. Using A=πr2A = \pi r^2 with r=7r = 7.

Flashcard 25: Define a sector of a circle.

Answer: Sector: A region bounded by two radii and an arc. Part of circle enclosed by two radii.

Flashcard 26: Find the circumference of a circle with diameter 1414 in terms of π\pi.

Answer: 14π14\pi. Use C=πdC=\pi d with d=14d=14.

Flashcard 27: What is the formula for the area of a sector?

Answer: Area = 12r2θ\frac{1}{2}r^2\theta (in radians). Half radius squared times central angle.

Flashcard 28: State the sector area formula for radius rr and central angle θ\theta in radians.

Answer: A=12r2θA=\frac{1}{2}r^2\theta. Half of radius squared times angle.

Flashcard 29: What is the meaning of 'tangent' in relation to circles?

Answer: A line touching the circle at exactly one point. A tangent line intersects the circle at one point.

Flashcard 30: What is the formula for the area of a circle segment?

Answer: Area = 12r2(θsinθ)\frac{1}{2}r^2(\theta - \sin\theta) (in radians). Area between chord and arc.

Flashcard 31: Define the term 'radius' in the context of a circle.

Answer: Distance from the center to any point on the circle. The radius is a fundamental measure of a circle's size.

Flashcard 32: What is the distance between parallel tangents to a circle if diameter is 10?

Answer: Distance = 10. Distance between parallel tangents equals diameter.

Flashcard 33: Identify the definition of a diameter in a circle.

Answer: A chord passing through the center. The longest chord in a circle.

Flashcard 34: Find the diameter of a circle with radius 99 cm.

Answer: 1818 cm. Diameter is twice the radius.

Flashcard 35: Find the diameter of a circle with radius 99 cm.

Answer: 1818 cm. Diameter is twice the radius.

Flashcard 36: What is the relationship between radius and circumference?

Answer: Circumference = 2πr2\pi r. Circumference is proportional to radius.

Flashcard 37: Find the diameter of a circle with circumference 18π18\pi.

Answer: 1818. From C=πdC=\pi d, solve for dd.

Flashcard 38: How do you calculate the chord length in a circle?

Answer: Chord Length =2rsin(θ2)= 2r\sin(\frac{\theta}{2}). Uses central angle and radius.

Flashcard 39: Find the sector area when r=3r=3 and θ=120\theta=120^\circ in terms of π\pi.

Answer: 3π3\pi. Use degrees formula: 120360π9\frac{120}{360}\cdot \pi\cdot 9.

Flashcard 40: What is the formula for the length of an arc?

Answer: L=θ360×2πrL = \frac{\theta}{360} \times 2\pi r. Proportion of the full circumference based on angle.

Flashcard 41: Find the circumference of a circle with radius 55 cm.

Answer: 10π10\pi cm. Using C=2πrC = 2\pi r with r=5r = 5.

Flashcard 42: What is the standard form equation of a circle?

Answer: (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2. General equation with center (h,k)(h, k).

Flashcard 43: If a circle's equation is (x2)2+(y3)2=16(x-2)^2 + (y-3)^2 = 16, what is the center?

Answer: (2,3)(2, 3). Center is (h,k)=(2,3)(h,k) = (2,3) from the equation.

Flashcard 44: Calculate the radius of a circle with circumference 12π12\pi.

Answer: 66. From C=2πrC = 2\pi r, solve for rr.

Flashcard 45: Find the area of a circle with diameter 1010 cm.

Answer: 25π25\pi cm2^2. Using A=πr2A = \pi r^2 with r=5r = 5 (since d=10d = 10).

Flashcard 46: State the area formula for a circle with radius rr.

Answer: A=πr2A=\pi r^2. Interior space enclosed by a circle.

Flashcard 47: What is the arc length of a circle with radius 44 cm and angle 9090^\circ?

Answer: 2π2\pi cm. Using L=90360×2π(4)=2πL = \frac{90}{360} \times 2\pi(4) = 2\pi.

Flashcard 48: Find the measure of an inscribed angle intercepting an arc of 110110^\circ.

Answer: 5555^\circ. Inscribed angle is half the intercepted arc.

Flashcard 49: What is the relationship between radius and circumference?

Answer: Circumference = 2πr2\pi r. Circumference is proportional to radius.

Flashcard 50: What is the formula for the area of a circle?

Answer: Area = πr2\pi r^2. Standard formula for circular area.

Flashcard 51: Find the circumference of a circle with radius 66 in terms of π\pi.

Answer: 12π12\pi. Use C=2πrC=2\pi r with r=6r=6.

Flashcard 52: What is the measure of an inscribed angle for a semicircle?

Answer: Inscribed Angle = 90 degrees. Inscribed angle in semicircle is always 90°.

Flashcard 53: Define the term 'diameter' in a circle.

Answer: Distance across the circle through the center, 2r2r. The diameter is the longest chord in a circle.

Flashcard 54: What is the relationship between diameter and circumference?

Answer: Circumference = π\pi times Diameter. Circumference equals π\pi times diameter.

Flashcard 55: What is the angle measure of a full circle in degrees?

Answer: 360360^\circ. Complete rotation around a circle.

Flashcard 56: Determine the area of a circle with radius 33.

Answer: 9π9\pi. Using A=πr2A = \pi r^2 with r=3r = 3.

Flashcard 57: Determine the diameter of a circle with area 16π16\pi.

Answer: 88. From A=πr2A = \pi r^2, find r=4r = 4, so d=8d = 8.

Flashcard 58: Identify the definition of a diameter in a circle.

Answer: A chord passing through the center. The longest chord in a circle.

Flashcard 59: What is the circumference of a circle with diameter 1414?

Answer: 14π14\pi. Using C=πdC = \pi d with d=14d = 14.

Flashcard 60: What is the arc length of a 6060^\circ sector in a circle with radius 55?

Answer: 5π3\frac{5\pi}{3}. Using L=60360×2π(5)=5π3L = \frac{60}{360} \times 2\pi(5) = \frac{5\pi}{3}.

Flashcard 61: State the sector area formula for radius rr and central angle θ\theta in radians.

Answer: A=12r2θA=\frac{1}{2}r^2\theta. Half of radius squared times angle.

Flashcard 62: State the standard equation of a circle with center (h,k)(h,k) and radius rr.

Answer: (xh)2+(yk)2=r2(x-h)^2+(y-k)^2=r^2. Standard form with center (h,k)(h,k) and radius rr.

Flashcard 63: What is the length of chord ABAB if it is a diameter in a circle of radius 99?

Answer: 1818. Diameter equals twice the radius.

Flashcard 64: State the radius of a circle with equation x2+y2=81x^2 + y^2 = 81.

Answer: Radius=9\text{Radius} = 9. Radius is square root of constant term.

Flashcard 65: Identify the center and radius of (x1)2+(y+2)2=16(x-1)^2 + (y+2)^2 = 16.

Answer: Center: (1,2)(1, -2), Radius: 4. Read values from standard form equation.

Flashcard 66: Find the radius of a circle with area 49π49\pi.

Answer: 77. From A=πr2A=\pi r^2, solve for rr.

Flashcard 67: Identify the center and radius of x2+y26x+8y+9=0x^2+y^2-6x+8y+9=0.

Answer: Center (3,4)(3,-4), radius 44. Complete the square to find center and radius.

Flashcard 68: What is the formula for the circumference of a circle?

Answer: C=2πrC = 2\pi r. Standard formula where rr is the radius.

Flashcard 69: Find the area of a circle segment with radius 6 and angle 90 degrees.

Answer: Area 9π18\approx 9\pi - 18. Apply segment area formula.

Flashcard 70: Find the sector area when r=6r=6 and θ=π2\theta=\frac{\pi}{2} (radians).

Answer: 9π9\pi. Apply A=12r2θA=\frac{1}{2}r^2\theta with given values.

Flashcard 71: Find the measure of an arc intercepted by a central angle of 140140^\circ.

Answer: 140140^\circ. Central angle equals its intercepted arc measure.

Flashcard 72: Identify the length of a chord if radius is 5 and angle is 60 degrees.

Answer: Chord Length 5\approx 5. Apply chord formula with given values.

Flashcard 73: What is the relationship between a radius and a tangent line at the point of tangency?

Answer: They are perpendicular. Forms a 90°90° angle at point of contact.

Flashcard 74: Find the circumference of a circle with radius 66 in terms of π\pi.

Answer: 12π12\pi. Use C=2πrC=2\pi r with r=6r=6.

Flashcard 75: What is the equation of a circle with center at origin and radius 4?

Answer: x2+y2=16x^2 + y^2 = 16. Standard form with center at origin.

Flashcard 76: What is the value of π\pi to two decimal places?

Answer: π3.14\pi \approx 3.14. Common approximation for pi.

Flashcard 77: State the equation of a circle centered at the origin with radius rr.

Answer: x2+y2=r2x^2+y^2=r^2. Special case where center is at (0,0)(0,0).

Flashcard 78: What is the relationship between diameter and circumference?

Answer: Circumference = π\pi times Diameter. Circumference equals π\pi times diameter.

Flashcard 79: Identify hh and kk in the circle equation (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2.

Answer: Coordinates of the circle's center. (h,k)(h,k) represents the center point of the circle.

Flashcard 80: Determine the circumference for a circle with radius 22.

Answer: 4π4\pi. Using C=2πrC = 2\pi r with r=2r = 2.

Flashcard 81: What is the term for a chord passing through the center of a circle?

Answer: A diameter. A chord through the center is the diameter.

Flashcard 82: Identify the length of a chord if radius is 5 and angle is 60 degrees.

Answer: Chord Length 5\approx 5. Apply chord formula with given values.

Flashcard 83: How do you calculate the diameter if given the circumference?

Answer: d=Cπd = \frac{C}{\pi}. Rearranging C=πdC = \pi d to solve for diameter.

Flashcard 84: What is the formula for the area of a circle?

Answer: Area = πr2\pi r^2. Standard formula for circular area.

Flashcard 85: If a circle's equation is (x3)2+(y+4)2=25(x-3)^2 + (y+4)^2 = 25, what is the radius?

Answer: 55. The radius is 25=5\sqrt{25} = 5.

Flashcard 86: State the circumference formula for a circle with diameter dd.

Answer: C=πdC=\pi d. Perimeter of a circle using diameter.

Flashcard 87: State the area formula for a circle with radius rr.

Answer: A=πr2A=\pi r^2. Interior space enclosed by a circle.

Flashcard 88: What is the radian measure of a full circle?

Answer: 2π2\pi. Complete rotation in radian measure.

Flashcard 89: Find the area of a semicircle with radius 44 in terms of π\pi.

Answer: 8π8\pi. Half the area: 12π16\frac{1}{2}\cdot \pi\cdot 16.

Flashcard 90: Find the arc length when r=5r=5 and θ=72\theta=72^\circ in terms of π\pi.

Answer: 2π2\pi. Use degrees formula: 723602π5\frac{72}{360}\cdot 2\pi\cdot 5.

Flashcard 91: Calculate the radius of a circle with circumference 12π12\pi.

Answer: 66. From C=2πrC = 2\pi r, solve for rr.

Flashcard 92: Identify the length of a semicircular arc with radius 88 in terms of π\pi.

Answer: 8π8\pi. Half the circumference: 122π8\frac{1}{2}\cdot 2\pi\cdot 8.

Flashcard 93: What is the meaning of 'tangent' in relation to circles?

Answer: A line touching the circle at exactly one point. A tangent line intersects the circle at one point.

Flashcard 94: State the standard equation of a circle with center (h,k)(h,k) and radius rr.

Answer: (xh)2+(yk)2=r2(x-h)^2+(y-k)^2=r^2. Standard form with center (h,k)(h,k) and radius rr.

Flashcard 95: State the arc length formula for radius rr and central angle θ\theta in radians.

Answer: s=rθs=r\theta. Arc length equals radius times angle.

Flashcard 96: Find the area of a sector with angle 120120^\circ in a circle of radius 66.

Answer: 12π12\pi. Using A=120360π(6)2=12πA = \frac{120}{360} \pi (6)^2 = 12\pi.

Flashcard 97: What term describes the set of all points equidistant from a center point?

Answer: A circle. This is the geometric definition of a circle.

Flashcard 98: Find the radius if the area of a circle is 64π64\pi.

Answer: Radius = 8. Use A=πr2A = \pi r^2 and solve for rr.

Flashcard 99: What is the radian measure of a full circle?

Answer: 2π2\pi. Complete rotation in radian measure.

Flashcard 100: If the circumference is 31.4, estimate the radius.

Answer: Radius 5\approx 5. Using C=2πrC = 2\pi r, solve for rr.