Other Matrices - ACT Math

Matrix addition is very easy! All that you need to do is add each correlative member to each other. Think of it like this:

Now, just simplify:

There is your answer!

Matrix addition is really easy—don't overthink it! All you need to do is combine the two matrices in a one-to-one manner for each index:

Then, just simplify all of those simple additions and subtractions:

To add matrices you simply add the numbers in the same position as each other.

Plugging the given values into the above formula, we are able to solve the question.

M2x3 x N3x4 = P2x4

In general matrix notation, Mrxc shows that the matrix is named M and r is the number of rows and c is the number of columns. When multiplying two matrices, the number of columns in the first matrix must match the number of rows in the second matrix. In addition, when adding or subtracting matrices, the matrices must be of the same size.

In order to solve the matrix, the determinant rule "ad-bc" must be used. is in the "a" position, is in the "b" position, is in the "c" position, and is in the "d" position. After plugging the numbers into "ad-bc," we get

To set up and augmented matrix for a 3x3 system of equations, all equations must be in standard form . The third equation is already in standard form; the first two are not and must be rewritten as such.

The system is now

Write the augmented matrix with each row comprising the coefficients of one equation in order:

is the correct choice.

To set up and augmented matrix for a 2x2 system of equations, both equations must be in standard form . The second equation is already in standard form.

Rewrite the first equation in standard form as follows:

The system has been rewritten as

Write the augmented matrix with each row comprising the coefficients of one equation in order:

is the correct choice.

If we let and represent the number of large and small boxes sold, respectively, since 305 boxes were sold, one linear equation of the 2x2 system will be

The money raised from the sale of large boxes of cookies, each of which cost $4.75, is ; the money raised from the sale of small boxes of cookies, each of which cost $3.25, is . The total money raised is $1,196.75, so the other linear equation of the system is

The augmented matrix of this system will comprise the coefficients of these equations, both of which are in standard form, so the matrix will be

If we let and represent the amount of the weaker and stronger solutions, respectively, since the chemist needs 1 liter of the resulting solution, one linear equation of the 2x2 system will be

The amount of alcohol in liters of a 10% solution will be ; the amount of alcohol in liters of a 40% solution will be ; and the total amount of alcohol in the resulting solution will be 20 % of a liter, or 0.20 liters. Therefore, the second linear equation of the system will be

The augmented matrix of this system will comprise the coefficients of these equations, both of which are in standard form, so the matrix will be

,

which is the correct choice.

If we let , , and represent the number of large, medium, and small boxes sold, respectively, since twenty more medium boxes than large were sold, one equation of the 3x3 system will be

or, in standard form,

Since 445 boxes were sold, another linear equation will be

The money raised from the sale of large boxes of cookies, each of which cost $5.75, is ; the money raised from the sale of small boxes of cookies, each of which cost $4.75, is ; and the money raised from the sale of small boxes of cookies, each of which cost $3.25, is .

The total money raised is $1,924.25, so the other linear equation of the system is

The augmented matrix of this system will comprise the coefficients of these equations, all of which are now standard form, so the matrix will be

,

which is the correct choice.

If the barista mixes pounds of Peppermint Nirvana and pounds of Strawberry Fields to make twenty pounds of tea total, then

will be one of the equations in the system.

pounds of Peppermint Nirvana tea for $12 a pound will cost a total of dollars; pounds of Strawberry Fields tea will cost a total of dollars. Tewnty pounds of the Strawberry Peppermint Delight tea for $13 a pound will cost dollars. Since the tea will sell for the same price blended as separate, the other equation of the system will be

The augmented matrix of this system will comprise the coefficients of these equations, both of which are in standard form, so the matrix will be

.

To find the number of blue items Jon has, we sum the entries in the column labelled and get . Recall that matrices are organized by rows and columns where each entry refers to the number of items that are, in this case, both of the same color AND type. All the entries in any one column are of the same color. All of the entries in any row are of the same clothing type.

If Jon has three red shirts and two blue pants. The total number of combinations of one shirt and one pair of pants he can wear is going to be the number of shirts he can wear with the first pair of pants, , plus the number of shirt he can wear with the second pair of pants, also . That sums to total outfits.

When subtracting matrices, you want to subtract each corresponding cell.

Now solve for and

You can treat matrices just like you treat other members of an equation. Therefore, you can subtract the matrix

from both sides of the equation. This gives you:

Now, matrix subtraction is simple. You merely subtract each element, matching the correlative spaces with each other:

Then, you simplify:

Therefore,

Match each term from the first matrix with the corresponding number from the second matrix and subtract.

Simplify.

Each of the numbers in the matrix solution now corresponds to the letters, a through f. Add a (upper left) and f (lower right).

When subtracting matrices, subtracting component-wise.

Matrix addition is very easy! All that you need to do is add each correlative member to each other. Think of it like this:

Now, just simplify:

There is your answer!

Matrix addition is really easy—don't overthink it! All you need to do is combine the two matrices in a one-to-one manner for each index:

Then, just simplify all of those simple additions and subtractions:

To add matrices you simply add the numbers in the same position as each other.

Plugging the given values into the above formula, we are able to solve the question.